Much like this previous question, I wish to store a MySQL column in a php array (as opposed to storing by row). However, I want the array indexes to match those of the database's primary key.
For instance, for the following database:
id name
1 Joe
2 Mary
9 Tony
$name['9'] == "Tony"
Is such a thing possible?
Thanks!
$result = mysql_query($q);
while ($row = mysql_fetch_assoc($result)) {
$array[$row["id"]] = $row["name"];
}
yes,
$names = array();
foreach ($rows as $r) {
$names[$r['id']] = $r['name'];
}
A wrapper library can make this easier, e.g. with ADODb:
$array = $db->GetAssoc("select id,name from mytable");
Once I have my row results as arrays, I use this method:
function convertArrayToMap(&$list, $attribute, $use_reference=FALSE) {
$result = array();
for ($i=0; $i < count($list); $i++) {
if ($use_reference) $result[$list[$i][$attribute]] = &$list[$i];
else $result[$list[$i][$attribute]] = $list[$i];
}
return $result;
}
And the method call:
$mapOfData = convertArrayToMap($mysql_results, 'ID');
Related
I have a table with par_id and columns (par1-5) 1 up to 5, but I'm trying to have my php function below to echo any number of columns
//-------------------------------------- get about ----------------------------------------------
function getAbout($option){
$div = array();
$sql_st = "undefined";
if($option == "about")
$sql_st = "SELECT * FROM `about` where par_id='1'";
// connect to database
mysql_connect($_SESSION['dbSever'],$_SESSION['dbUser'],$_SESSION['dbPass']) or die(mysql_error());
mysql_select_db($_SESSION['tblName']) or die(mysql_error());
$result = mysql_query($sql_st) or die(mysql_error()."<br/>".$sql_st);
$num_rows = mysql_num_rows($result);
while ($row = mysql_fetch_array($result) ){
// not sure what to do here
}
// disconnect
mysql_close();
return $div;
}
From your question title I'm assuming you have an ID maybe in your first column and you want to keep that from being printed. You could try something like:
$numberOfColumns = mysql_num_fields($result);
while ($row = mysql_fetch_array($result) ){
for ($i = 1; $i < $numberOfColumns; $i++){
echo $row[$i];
}
}
The $i iterator in the for loop is initiated with value of 1 because PHP handles (like many languages) arrays as zero-based, which means that the first element is referenced by $row[0] (as in this example) - by starting the loop at one and going for as many elements there are in the array, you're effectively grabbing all elements except for the first one.
A really simple one would be to have a flag like so:
$skippedFirstRow = false;
while ($row = mysql_fetch_array($result)){
if(!$skippedFirstRow) {
//do whatever you want here
}
$skippedFirstRow = true;
}
However, keep in mind that this is just a quick hack for what you want and considering your code, but it is not an elegant solution.
$result = mysql_query("SELECT * FROM Race");
$rows = mysql_num_rows($result);
for ($i = 0 ; $i < $rows ; ++$i)
{
$row = mysql_fetch_row($result);
echo $row[0];
}
above is probably an awkward method but it'll print out all datas stored in first column, which is good but now, I want to store each one of them into an array...
I tried
$array[$i]=$row[0];
and echoed it out, but it just prints"Array"...
I tried
$result = mysql_query("SELECT raceid FROM Race");
while ($row = mysql_fetch_array($result)) {
$array[]=$row[0];
}
...which does the same as code written before, i guess, since it too just print "Array".
Please help! Thank you!!
Do you use simple echo $array;? It's wrong. You can't output array this way.
Use this:
$array = array();
$result = mysql_query("SELECT raceid FROM Race");
while ($row = mysql_fetch_array($result)) {
$array[]=$row[0];
}
foreach($item in $array) {
echo $item."<br>"; // and more format
}
If you want to watch array contents without any format use (e.g. for debugging) print_r or var_dump:
print_r($array);
var_dump($array);
Advice: better to use assoc array.
$array = array();
$result = mysql_query("SELECT raceid FROM Race");
while ($row = mysql_fetch_array($result)) {
$array[]=$row['raceid'];
}
Advanced advice: better to use PDO and object results.
You SQL code will be invulnerable to SQL injections
Code will be more modern and readable.
I've looked for something similar on stack but nothing exactly as this.
I (think I) need to generate a unique MySQL query inside a loop as each iteration needs to look up a different table. the loop is from an exploded $_GET array.
The problem is creating a differently named mysql query based on the loop iteration. I've done it where the $var name is different but it doesn't work, I think because it is a string not a variable?
Any help appreciated
$temps = explode(",", $_GET['temps']);
$tempCount = count($temps);
for ($i=0; $i<$tempCount; $i++)
{
/*'normal' database lookup
$check = mysql_query("SELECT * FROM _db_".$temps[$i]."");
$checks = array();
while ($row = mysql_fetch_assoc($check)) {
$checks[] = $row;
}*/
//here's where I'm trying to build a 'dynamic' lookup for each loop iteration
$checkTemp=$check.$temps[$i];
$checkTempArray=$check.$temps[$i].'Array';
$checkTemp = mysql_query("SELECT * FROM _db_".$temps[$i]."");
$checkTempArray = array();
while ($row = mysql_fetch_assoc($checkTemp)) {
$checkTempArray[] = $row;
}
}
If I understand correctly you're trying to SELECT * from all tables seperated by , in the $_GET["temps"]
$temps = explode(",", $_GET['temps']);
$tempCount = count($temps);
$allResults = array();
for ($i=0; $i<$tempCount; $i++)
{
$checkTemp = mysql_query("SELECT * FROM _db_".mysql_real_escape_string($temps[$i]));
$allResults[$temps[$i]] = array();
while ($row = mysql_fetch_assoc($checkTemp))
{
$allResults[$temps[$i]][] = $row;
}
}
// Now for example $allResults["john"][3] contains the fourth row in the table _db_john
print_r($allResults["sally"][2]); // print the third row in _db_sally
Seems like a typo in your code
$checkTemp = mysql_query("SELECT * FROM db".$temp[$i]."");
either use
$temps[$i] or just $temp
$temp[$i] doesn't makes any sense
so your query should be instead
$checkTemp = mysql_query("SELECT * FROM db".$temps[$i]."");
EDIT:
for your array part you can use
$$temp = array();
while ($row = mysql_fetch_assoc($checkTemp)) {
$$temp[] = $row;
}
I have an MSSQL query where it SELECTS all rows that meet a specific criteria. In PHP I want to fetch that array, but then I want to convert it into one array per row. So if my query returns 3 rows, I want to have 3 unique arrays that I can work with.
I'm not sure how to go about this. Any help would be greatly appreciated!
Thanks, Nathan
EDIT:
$query = "SELECT * FROM applicants WHERE applicants.user_id ='{$_SESSION['user_id']}'";
$query_select = mssql_query($query , $connection);
if (mssql_num_rows($query_select) == 2){
$message = '2 students created successfully';
}
$i = 0;
while($row = mssql_fetch_array($query_select)) {
$student.$i['child_fname'][$i] = $row['child_fname'];
$student.$i['child_lname'][$i] = $row['child_lname'];
$i++;
}
$query_array1 = $student0;
$query_array2 = $student1;
You will notice from the code above that I am expecting two rows to be returned. Now, I want to take those two rows and create two arrays from the results. I tried using the solution that was give below. Perhaps my syntax is incorrect or I didn't understand how to properly implement his solution. But any help would be greatly appreciated.
$query = mssql_query('SELECT * FROM mytable');
$result = array();
if (mssql_num_rows($query)) {
while ($row = mssql_fetch_assoc($query)) {
$result[] = $row;
}
}
mssql_free_result($query);
Now you can work with array like you want:
print_r($result[0]); //first row
print_r($result[1]); //second row
...
$i=0;
while( $row = mysql_fetch_array(query){
$field1['Namefield1'][$i] = $row['Namefield1'];
$field2['Namefield2'][$i] = $row['Namefield2'];
$field3['Namefield3'][$i] = $row['Namefield3'];
$i++;
}
or if you preffer an bidimensional array:
$i=0;
while( $row = mysql_fetch_array(query){
$result['Namefield1'][$i] = $row['Namefield1'];
$result['Namefield2'][$i] = $row['Namefield2'];
$result['Namefield3'][$i] = $row['Namefield3'];
$i++
}
I feel incredibly stupid for not being able to figure this out, but I guess that's what Stackoverflow is for. If someone could point me to helpful resources or explain to me how to solve this, I would be very appreciative.
Basically I'm fetching a couple of rows from a table, and now I need to be able to print them out the value of each row's field, followed by the values of each row from a different field, and so on. It's hard to explain, but let me give you an example.
Let's say we have a table with three fields: id - name - url. Now I want to be able to output the result in this order:
1
2
3
John
Steven
Patrick
http://google.com/
http://stackoverflow.com/
http://php.net/
How do I loop through the results of my query in order to achieve this?
Well you should make an array and then spew it out:
$ids = array();
$names = array();
$urls = array();
while($row = ...){
$ids[] = $row['id'];
$names[] = $row['name'];
$urls[] = $row['url'];
}
foreach($ids as $id) {
echo $id . PHP_EOL;
}
//do the same for the other 2
You can do this via union. The only tricky part is making sure to cast all of the fields to a common data type (in this case, text). Also, each subquery is ordered by id to make sure that the ordering is consistent.
select id::text
from table
order by id
union
select name::text
from table
order by id
union
select url::text
from table
order by id
$result = mysql_query("SELECT id, name, url FROM yourtable") or die(mysql_error());
$data = array()
while($row = mysql_fetch_asssoc($result)) {
$data[] = $row;
}
foreach(array('id', 'name', 'url') as $key) {
foreach($data as $idx => $val) {
echo $val[$key], "\n";
}
}
The simplest way is
while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) {
$ids[] = $row['id'];
$names[] = $row['names'];
$wwws[] = $row['website'];
}
Then you iterate over the three arrays. There are surely better methods for doing this!