$result = mysql_query("SELECT * FROM Race");
$rows = mysql_num_rows($result);
for ($i = 0 ; $i < $rows ; ++$i)
{
$row = mysql_fetch_row($result);
echo $row[0];
}
above is probably an awkward method but it'll print out all datas stored in first column, which is good but now, I want to store each one of them into an array...
I tried
$array[$i]=$row[0];
and echoed it out, but it just prints"Array"...
I tried
$result = mysql_query("SELECT raceid FROM Race");
while ($row = mysql_fetch_array($result)) {
$array[]=$row[0];
}
...which does the same as code written before, i guess, since it too just print "Array".
Please help! Thank you!!
Do you use simple echo $array;? It's wrong. You can't output array this way.
Use this:
$array = array();
$result = mysql_query("SELECT raceid FROM Race");
while ($row = mysql_fetch_array($result)) {
$array[]=$row[0];
}
foreach($item in $array) {
echo $item."<br>"; // and more format
}
If you want to watch array contents without any format use (e.g. for debugging) print_r or var_dump:
print_r($array);
var_dump($array);
Advice: better to use assoc array.
$array = array();
$result = mysql_query("SELECT raceid FROM Race");
while ($row = mysql_fetch_array($result)) {
$array[]=$row['raceid'];
}
Advanced advice: better to use PDO and object results.
You SQL code will be invulnerable to SQL injections
Code will be more modern and readable.
Related
if I have a query that looks like this in php...
if ($result3 = $connuser->query("SELECT * FROM devices WHERE uid='".$username."'")){
}
How can I turn $result3 into an array?
Also, separate question, I tried doing
echo $result3;
but it doesn't work. Is there a way to view $result3 so I can see what it looks like?
You can do:
$rows = [];
while($row = mysqli_fetch_array($result3))
{
$rows[] = $row;
}
Some code to fetch the field names by connecting it with db:
<?php
#mysql_connect("localhost", "root", "") or die(mysql_error());
mysql_select_db("test") or die(mysql_error());
$result = mysql_query("SELECT * FROM sample");
$storeArray = Array();
while ($row = mysql_fetch_array($result)) {
if (mysql_num_rows($result) > 0) {
$storeArray = $row['name'];
echo $storeArray;
}
}
?>
The above code works just fine but when it runs it gives me ramuraja. Here ramu and raja are seperate fields. But its giving me a joined output.
How can i get the two field value seperately like ramu and raja.
You print / echo the values directly after one another. Using echo $storeArray.'<br>'; would print a linebreak additionally, thus printing
ramu
Raja
However, you could also store all the variables in an array, for example with $storeArray[] = $row['name']; instead of $storeArray = $row['name'];. That would create a new array element, the value being $row['name'], while the key is incrementing for every element being added.
After having received all rows that match the query, you could loop through the array and Display the answers.
EDIT: Please check out mysqli or PDO; those PHP extensions are standard with newer versions and should be used instead of the old (and now deprecated) mysqli solution. Don't worry, they can do the same (and much more).
You need to do a for each statement to iterate through the array and echo the field along with a line break
First of all, you're declaring $storeArray as an array in this line: $storeArray = Array();, but later you replace it with a string $storeArray = $row['name'];
If you want to use $storeArray as an array, change this line:
$storeArray = $row['name'];
into
$storeArray[] = $row['name']; //add element to the array
Now loop all the results (remove echo $storeArray;)
After you've fetched all the results you kan echo them like:
foreach($storeArray as $name){
echo $name.'<br>';
}
Some confusion in code ....
first check ifthere are results:
if (mysql_num_rows($result) > 0) {
while ($row = mysql_fetch_array($result)) {
....
}
}
than be more clear about what you wont:
an array :
$storeArray = Array();
or a string:
$storeArray = $row['name'];
I would so like this:
$storeArray = Array();
if (mysql_num_rows($result) > 0) {
while ($row = mysql_fetch_array($result)) {
$storeArray[] = $row['name'];
}
}
// array
print_r($storeArray);
// string
echo implode(',', $storeArray);
I am making a mysql query . I want to add result to an array. suppose I am selecting all user from user table. I want to get everyones name. if the row=5 i want to save every name according to the row index.
if (mysql_num_rows($query) > 0)
{
$row = mysql_fetch_array($query);
//echo ($row);
$num=mysql_num_rows($query);
echo ($num);
for ($i=1; $i<=$num;$i++){
//here I want to save all name to an array.
}
Please help.
You might be looking for something like this:
$rows = array();
// while there are more records, add them to `$rows`
while($row = mysql_fetch_assoc($result)) {
$rows []= $row;
}
Note that mysql_fetch_assoc() will just return false if there are no (more) records in the result set. So you don't need the call to mysql_num_rows()
$num = mysql_num_rows($query);
if($num > 0)
{
while($row = mysql_fetch_array($query)
{
$names[] = $row['name'];
}
}
That will create an array called $names which you can loop through later. Also, it's a good time to look into mysqli_* functions, or PDO.
I am querying a database to get 6 values in my params table suing this;
$result = mysql_query("SELECT * FROM params");
while($row = mysql_fetch_array($result))
{
$param = $row['value'] ;
}
is this right, if so is their away i can add one to the variable name each time round so i get $param1, $param2....
I dont want to have to send a query to the database for each param, is it possible to get them all like this?
The simpliest way is to use an array:
$result = mysql_query("SELECT * FROM params");
$param = array();
$i = 0;
while($row = mysql_fetch_array($result)) {
$param[$i] = $row['value'] ;
$i++;
}
Than you get $param[0], $param[1], ...
You can create variable names like this:
${'var'.1}
${'var'.'1.cat'}
${'var'.$x}
${$y.$x}
and so on.
This seems like a design flaw. But what you can do is:
$count = 1;
$result = mysql_query("SELECT * FROM params");
while($row = mysql_fetch_array($result))
{
$paramname = 'param' . $count++;
$$paramname = $row['value'] ;
}
You may find the list function useful - http://php.net/manual/en/function.list.php
list($param1,$param2,$param3,$param4,$param5,$param6) = mysql_fetch_row($result);
Probably more use when using descriptive variables, just a thought.
I'm having trouble getting my data from fetchAll to print selectively.
In normal mysql I do it this way:
$rs = mysql_query($sql);
while ($row = mysql_fetch_array($rs)){
$id = $row['id'];
$n = $row['n'];
$k = $row['k'];
}
In PDO, I'm having trouble. I bound the params, then I'm saving the fetched data into $rs like above, with the purpose of looping through it the same way..
$sth->execute();
$rs = $query->fetchAll();
Now comes the trouble part. What do I do PDO-wise to get something matching the while loop above?! I know I can use print_r() or dump_var, but that's not what I want. I need to do what I used to be able to do with regular mysql, like grabbing $id, $n, $k individually as needed. Is it possible?
Thanks in advance..
It should be
while ($row = $query->fetch(PDO::FETCH_ASSOC)) {
$id = $row['id'];
$n = $row['n'];
$k = $row['k'];
}
If you insist on fetchAll, then
$results = $query->fetchAll(PDO::FETCH_ASSOC);
foreach($results as $row) {
$id = $row['id'];
$n = $row['n'];
$k = $row['k'];
}
PDO::FETCH_ASSOC fetches only column names and omits the numeric index.