Filed name appearing on same line - php

Question

Some code to fetch the field names by connecting it with db:
<?php
#mysql_connect("localhost", "root", "") or die(mysql_error());
mysql_select_db("test") or die(mysql_error());
$result = mysql_query("SELECT * FROM sample");
$storeArray = Array();
while ($row = mysql_fetch_array($result)) {
if (mysql_num_rows($result) > 0) {
$storeArray = $row['name'];
echo $storeArray;
}
}
?>
The above code works just fine but when it runs it gives me ramuraja. Here ramu and raja are seperate fields. But its giving me a joined output.
How can i get the two field value seperately like ramu and raja.

Answer 1

You print / echo the values directly after one another. Using echo $storeArray.'<br>'; would print a linebreak additionally, thus printing
ramu
Raja
However, you could also store all the variables in an array, for example with $storeArray[] = $row['name']; instead of $storeArray = $row['name'];. That would create a new array element, the value being $row['name'], while the key is incrementing for every element being added.
After having received all rows that match the query, you could loop through the array and Display the answers.
EDIT: Please check out mysqli or PDO; those PHP extensions are standard with newer versions and should be used instead of the old (and now deprecated) mysqli solution. Don't worry, they can do the same (and much more).

Answer 2

You need to do a for each statement to iterate through the array and echo the field along with a line break

Answer 3

First of all, you're declaring $storeArray as an array in this line: $storeArray = Array();, but later you replace it with a string $storeArray = $row['name'];
If you want to use $storeArray as an array, change this line:
$storeArray = $row['name'];
into
$storeArray[] = $row['name']; //add element to the array
Now loop all the results (remove echo $storeArray;)
After you've fetched all the results you kan echo them like:
foreach($storeArray as $name){
echo $name.'<br>';
}

Answer 4

Some confusion in code ....
first check ifthere are results:
if (mysql_num_rows($result) > 0) {
while ($row = mysql_fetch_array($result)) {
....
}
}
than be more clear about what you wont:
an array :
$storeArray = Array();
or a string:
$storeArray = $row['name'];
I would so like this:
$storeArray = Array();
if (mysql_num_rows($result) > 0) {
while ($row = mysql_fetch_array($result)) {
$storeArray[] = $row['name'];
}
}
// array
print_r($storeArray);
// string
echo implode(',', $storeArray);