I'm pretty sure i'm doing an extra loop here:
$q = "SELECT * FROM genres WHERE genre.g_url = '$genre_url' LIMIT 1";
$res = mysql_query($q);
while ($r = mysql_fetch_array($res, MYSQL_ASSOC)){
foreach( array_keys($r) as $k ){
$g[$k] = $r[$k];
}
}
return $g;
$q = "SELECT
columns,
you,
want,
to,
read
FROM
genres
WHERE
genre.g_url = '".mysql_real_escape_string($genre_url)."'
LIMIT 1";
$result = mysql_query($q) or die(mysql_error());
return mysql_fetch_assoc($result);
If there is no row in the database this will return false, otherwise the data of the row. And don't forget to escape user inputs...
Related
$frame_type = '';
$ret = mysqli_query($con, "select * from products where status='1' AND frame_type = '$frame_type' ");
while ($row = mysqli_fetch_array($ret)) {
$emparray[] = $row;
}
Get All Rows If The $frame_type Is Empty I am trying this way but i get zero rows , How to fix that Where $frame_type has value then send to query else not
There are a some of things that is wrong with your question (code). But if you only want answer. Just copy this
$frame_type = '';
$query = "select * from products where status='1' ";
// strlen has value
if(strlen($frame_type)) {
$query .= "AND frame_type = '$frame_type'";
}
$ret = mysqli_query($con, $query);
while ($row = mysqli_fetch_array($ret)) {
$emparray[] = $row;
}
PS: It's never a safe idea to pass everything to the query. Use prepared statement if you can.
Based on my codes, i need to restrict the insertion of the data by 3, i mean is like after the insertion of 3 data row, it will be restricted from inserting in data. Is that possible? For more information, is like the borrow inserting 3 times, then it cannot be inserted anymore. Is there anyway to do so? I am still learning php by the way, thank you.
if(isset($_POST['selector']))
$id=$_POST['selector'];
else
$id = '';
$member_id = $_POST['member_id'];
$due_date = $_POST['due_date'];
$isbn = $_POST['due_date'];
if ($id == '' ){
//header("location: borrow.php");
if(isset($_POST['isbn'])){
$isbn = $_POST['isbn'];
$query = mysql_query("select book_id from book WHERE isbn = '$isbn'")or die(mysql_error());
$count = mysql_num_rows($query);
if($count > 0){
$row = mysql_fetch_array($query);
$bookid = $row['book_id'];
$date = date('Y-m-d');
}
mysql_query("insert into borrow (member_id,book_id,date_borrow,due_date) values ('$member_id','$bookid','$date','$due_date')")or die(mysql_error());
}
else{
header("location: borrow.php");
}
}else{
mysql_query("insert into borrow (member_id,date_borrow,due_date) values ('$member_id',NOW(),'$due_date')")or die(mysql_error());
$query = mysql_query("select * from borrow order by borrow_id DESC")or die(mysql_error());
$row = mysql_fetch_array($query);
$borrow_id = $row['borrow_id'];
}else{
mysql_query("insert into borrow (member_id,date_borrow,due_date) values ('$member_id',NOW(),'$due_date')")or die(mysql_error());
$query = mysql_query("select * from borrow order by borrow_id DESC")or die(mysql_error());
$row = mysql_fetch_array($query);
$borrow_id = $row['borrow_id'];
$N = count($id);
for($i=0; $i < $N; $i++)
{
mysql_query("insert borrowdetails (book_id,borrow_id,borrow_status)
values('$id[$i]','$borrow_id','pending')")or die(mysql_error());
}
header("location: borrow.php");
}
You just have to count number of user row before to make a new insert :
$query = mysql_query("SELECT COUNT(*) AS count FROM borrow WHERE member_id = '".$member_id."'");
$row = mysql_fetch_assoc($query);
if ( $row['count'] >= 3 )
echo('Max insert');
Also, check this : Why shouldn't I use mysql_* functions in PHP?
I'm not sure I understand you correctly.
You can restrict the number of rows returned by SELECT query using the LIMIT clause.
Make sure you either put an ORDER BY clause in there or determine that you don't care 'which' 3 rows will get inserted.
See here:
http://dev.mysql.com/doc/refman/5.0/en/select.html
I have a query that gets 5 lines of data like this example below
$query = "SELECT ref,user,id FROM table LIMIT 0, 5";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result))
{
$ref = $row['ref'];
}
I want to run a query inside each results like this below
$query = "SELECT ref,user,id FROM table LIMIT 0, 5";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result))
{
$ref = $row['ref'];
$query = "SELECT domain,title FROM anothertable WHERE domain = '$ref'";
$result = mysql_query($query) or die(mysql_error());
if (mysql_num_rows($result) )
{
$title = $row['title'];
} else {
$title = "No Title";
}
echo "$ref - $tile";
}
but for some reason it's only display the first line when I add the query inside it. I can seem to make it run all 5 queries.
SELECT
t1.ref,
t1.user,
t1.id,
t2.domain,
t2.title
FROM
table AS t1
LEFT JOIN anothertable AS t2 ON
t2.domain = t1.ref
LIMIT
0, 5
The problem is that inside the while-cycle you use the same variable $result, which then gets overridden. Use another variable name for the $result in the while cycle.
You change the value of your $query in your while loop.
Change the variable name to something different.
Ex:
$query = "SELECT ref,user,id FROM table LIMIT 0, 5";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result))
{
$ref = $row['ref'];
$qry = "SELECT domain,title FROM anothertable WHERE domain = '$ref'";
$rslt = mysql_query($qry) or die(mysql_error());
if (mysql_num_rows($rslt) )
{
$title = $row['title'];
} else {
$title = "No Title";
}
echo "$ref - $tile";
}
Use the following :
$query = "SELECT ref,user,id FROM table LIMIT 0, 5";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result))
{
$ref = $row['ref'];
$query_domain = "SELECT domain,title FROM anothertable WHERE domain = '$ref'";
$result_domain = mysql_query($query_domain) or die(mysql_error());
if (mysql_num_rows($result_domain) )
{
$row_domain = mysql_fetch_row($result_domain);
$title = $row_domain['title'];
} else {
$title = "No Title";
}
echo "$ref - $title";
}
This is a logical problem. It happens that way, because you are same variable names outside and inside the loop.
Explanation:
$query = "SELECT ref,user,id FROM table LIMIT 0, 5";
$result = mysql_query($query) or die(mysql_error());
// Now $results hold the result of the first query
while($row = mysql_fetch_array($result))
{
$ref = $row['ref'];
//Using same $query does not affect that much
$query = "SELECT domain,title FROM anothertable WHERE domain = '$ref'";
//But here you are overriding the previous result set of first query with a new result set
$result = mysql_query($query) or die(mysql_error());
//^ Due to this, next time the loop continues, the $result on whose basis it would loop will already be modified
//..............
Solution 1:
Avoid using same variable names for inner result set
$query = "SELECT ref,user,id FROM table LIMIT 0, 5";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result))
{
$ref = $row['ref'];
$query = "SELECT domain,title FROM anothertable WHERE domain = '$ref'";
$sub_result = mysql_query($query) or die(mysql_error());
// ^ Change this variable so that it does not overrides previous result set
Solution 2:
Avoid the double query situation. Use joins to get the data in one query call. (Note: You should always try to optimize your query so that you will minimize the number of your queries on the server.)
SELECT
ref,user,id
FROM
table t
INNER JOIN
anothertable t2 on t.ref t2.domain
LIMIT 0, 5
Learn about SQL joins:
SELECT table.ref, table.user, table.id, anothertable.title
FROM table LEFT JOIN anothertable ON anothertable.domain = table.ref
LIMIT 5
You're changing the value of $result in your loop. Change your second query to use a different variable.
it is not give proper result because you have used same name twice, use different name like this edit.
$query = "SELECT ref,user,id FROM table LIMIT 0, 5";
$result = mysql_query($query) or die(mysql_error());
while($row = mysql_fetch_array($result))
{
$ref = $row['ref'];
$query1 = "SELECT domain,title FROM anothertable WHERE domain = '$ref'";
$result1 = mysql_query($query1) or die(mysql_error());
if (mysql_num_rows($result1) )
{
$title = $row['title'];
} else {
$title = "No Title";
}
echo "$ref - $tile";
}
Im trying to generate an array but not sure how to go about it.
I'm currently getting my data like so:
$query = mysql_query("SELECT * FROM users WHERE userEmail LIKE 'test#test.com'");
$row = mysql_fetch_array($query);
$query1 = mysql_query("SELECT * FROM categories");
while($row1 = mysql_fetch_array($query1)){
$query2 = mysql_query("SELECT * FROM usersettings WHERE userId = ".$row['userId']." AND usersettingCategory".$row1['categoryId']." LIKE 'y'");
$isyes = mysql_num_rows($query2);
if($isyes > 0){
$cat1 = mysql_query("SELECT * FROM shops WHERE shopstateId = 1 AND (categoryId1 = ".$row1['categoryId']." OR categoryId2 = ".$row1['categoryId']." OR categoryId3 = ".$row1['categoryId'].")");
$cat1match = mysql_num_rows($cat1);
if($cat1match > 0){
while($cat1shop = mysql_fetch_array($cat1)){
$cat1msg = mysql_query("SELECT * FROM messages WHERE shopId = ".$cat1shop['shopId']." and messagestateId = 1");
while($cat1msgrow = mysql_fetch_array($cat1msg)){
echo $cat1msgrow['messageContent']." - ".$cat1msgrow['messageCode'];
$cat1img = mysql_query("SELECT shopimagePath FROM shopimages WHERE shopimageId = ".$cat1shop['shopimageId']);
$imgpath = mysql_fetch_array($cat1img);
echo " - ".$imgpath['shopimagePath']."<br/>";
}
}
}
}
}
But this can cause duplicates when a user has all 3 of a shops categories picked in their preferences. I am trying to find a way to just pull the message ID out instead of the whole thing and put it into an array giving me, for example:
1,3,5,7,1,3,5,2,4,7,8
Then I can just run a separate query to say get me all messages where the ID is in the array, but i am unsure of the most constructive way to build such an array and examples of array from a while loop I have seen do not seem to be what I am looking for.
Is there anyone out there that can push me in the right direction?
Can't help with this code. But if you want an array from a query without duplicate result, you can use " select DISTINCT (id) " in your query or for more simple solution :
$id_arr = array();
$sql = mysql_query("select id from id_table");
while ($id_result = mysql_fetch_array($sql) {
$id = $id_result['id'];
if (!in_array($id, $id_arr)) {
$id_arr[] = $id;
}
}
I have found a much easier way to create the required result. I think at 6am after a hard night coding my brain was fried and I was making things a lot more complicated than I needed to. A simple solution to my issue is as follows:
$query = mysql_query("SELECT * FROM users WHERE userEmail LIKE 'test2#test2.com'");
$row = mysql_fetch_array($query);
$categories = "(";
$query1 = mysql_query("SELECT * FROM categories");
while($row1 = mysql_fetch_array($query1)){
$query2 = mysql_query("SELECT usersettingCategory".$row1['categoryId']." FROM usersettings WHERE userId = ".$row['userId']);
$row2 = mysql_fetch_array($query2);
if($row2['usersettingCategory'.$row1['categoryId']] == y){
$categories .= $row1['categoryId'].",";
}
}
$categories = substr_replace($categories ,")",-1);
echo $categories."<br />";
$query3 = mysql_query("SELECT * FROM shops,messages WHERE shops.shopId = messages.shopId AND messages.messagestateId = 1 AND (shops.categoryId1 IN $categories OR shops.categoryId2 IN $categories OR shops.categoryId3 IN $categories)");
while($row3 = mysql_fetch_array($query3)){
$query4 = mysql_query("SELECT shopimagePath FROM shopimages WHERE shopimageId = ".$row3['shopimageId']);
$row4 = mysql_fetch_array($query4);
echo $row3['messageContent']." - ".$row3['messageCode']." - ".$row4['shopimagePath']."<br />";
}
$query = "SELECT * FROM `table`";
$results = mysql_query($query, $connection);
If 'table' has no rows. whats the easiest way to check for this.?
Jeremy Ruten's answer above is good and executes quickly; on the other hand, it only gives you the number of rows and nothing else (if you want the result data, you have to query the database again). What I use:
// only ask for the columns that interest you (SELECT * can slow down the query)
$query = "SELECT some_column, some_other_column, yet_another_column FROM `table`";
$results = mysql_query($query, $connection);
$numResults = mysql_num_rows($results);
if ($numResults > 0) {
// there are some results, retrieve them normally (e.g. with mysql_fetch_assoc())
} else {
// no data from query, react accordingly
}
You could use mysql_num_rows($results) to check if 0 rows were returned, or use this faster alternative:
$query = "SELECT COUNT(*) AS total FROM table";
$results = mysql_query($query, $connection);
$values = mysql_fetch_assoc($results);
$num_rows = $values['total'];
Alternatively you can simply check if the result of mysql_fetch_assoc is false.
$query = "SELECT * FROM `table`";
$results = mysql_query($query, $connection);
$Row = mysql_fetch_assoc($results);
if ($Row == false)
{
$Msg = 'Table is empty';
}
One thing i noticed that was missed was the fact that the query might not succeed, so you do need to check if the $results variable is set. I'll use the answer given by yjerem as an example.
$query = "SELECT COUNT(*) AS total FROM table";
$results = mysql_query($query, $connection);
if ($results) { // or use isset($results)
$values = mysql_fetch_assoc($results);
$num_rows = $values['total'];
}
If you loop through the results, you can have a counter and check that.
$x = 1;
$query = mysql_query("SELECT * FROM table");
while($row = mysql_fetch_assoc($query))
{
$x++;
}
if($x == 1)
{
//No rows
}