$frame_type = '';
$ret = mysqli_query($con, "select * from products where status='1' AND frame_type = '$frame_type' ");
while ($row = mysqli_fetch_array($ret)) {
$emparray[] = $row;
}
Get All Rows If The $frame_type Is Empty I am trying this way but i get zero rows , How to fix that Where $frame_type has value then send to query else not
There are a some of things that is wrong with your question (code). But if you only want answer. Just copy this
$frame_type = '';
$query = "select * from products where status='1' ";
// strlen has value
if(strlen($frame_type)) {
$query .= "AND frame_type = '$frame_type'";
}
$ret = mysqli_query($con, $query);
while ($row = mysqli_fetch_array($ret)) {
$emparray[] = $row;
}
PS: It's never a safe idea to pass everything to the query. Use prepared statement if you can.
Related
How would I get this to work, because I am just getting errors right now.
$_GET['providers'] is an array of DB column names, which I am checking if = 1 in the below query.
foreach ($_GET['providers'] as $providers) {
$statement = "AND ".$providers."= '1' ";
}
$sql = "select * from users where user_id ='1' ".$statement." ";
$result = mysqli_query($con, $sql);
$row = mysqli_fetch_assoc($result);
if(isset($row['user_id'])){
echo "It worked";
}
You should use a whitelist to check if the $providers are known column names. You then should concatenate the $statement, otherwise you overwrite that variable on every iteration.
$statement = '';
$columns = array('known', 'columns', 'go', 'here');
foreach ($_GET['providers'] as $providers) {
if(in_array($providers, $columns)) {
$statement .= " AND $providers = 1 ";
}
}
$sql = "select user_id from users where user_id =1 $statement limit 1";
$result = mysqli_query($con, $sql);
$row = mysqli_fetch_assoc($result);
if(isset($row['user_id'])){
echo "It worked";
}
You also shouldn't use * unless you really want every column. If you just want to see if a row is returned you also can use limit 1 because you don't care about other rows.
You are overwriting $statement every time the loop is running.
$statement = "";
foreach ($_GET['providers'] as $providers) {
$statement .= "AND ".$providers."= '1' "; // note the ".=" to append
}
$sql = "select * from users where user_id ='1' ".$statement." ";
// to debug: echo "Query :: $sql";
$result = mysqli_query($con, $sql);
$row = mysqli_fetch_assoc($result);
if(isset($row['user_id'])){
echo "It worked";
}
I have this code
$query = "SELECT `subscriberid`,`data` FROM `****table_name*****`"
. "WHERE `subscriberid` IN (123,456,789,101)";
$result = $cxn->query($query);
$Points = array();
while ($row = $result->fetch_assoc()) {
$Points[$row['subscriberid']] = $row['data'];
}
I want the keys for $Points to be the subscriberid, but when I print out $Points I keep getting default keys 0-3 and I can't see any reason for this to be happening.
Credits to #Jongosi's Comment, about the if ($result = $cxn->query($query)) part.
Your query is currently as follows:
$query = "SELECT `subscriberid`,`data` FROM `****table_name*****`"
. "WHERE `subscriberid` IN (123,456,789,101)";
If you only edited ****table_name*****, you are missing a space ( between * and WHERE).
Your result will be nothing or an error.
$query = "SELECT `subscriberid`,`data` FROM `****table_name*****`"
. " WHERE `subscriberid` IN (123,456,789,101)";
In the below code i want to join or implode all arrays of $trackersurl in a single line. i am getting the results in different lines, so i want to join in a single line.
Can anyone help me out?
I am searching results in stackoverflow, but could not follow.
My code is in below:
$sql = "SELECT * FROM announce WHERE torrent = $id ORDER BY seeders DESC";
$query = #mysql_query($sql);
while ($result = #mysql_fetch_array($query)) {
$trackersurl1 = $result['url'];
$trackersurl2 = "&tr=".$trackersurl1;
$trackersurl = array($trackersurl2);
}
Results of [var.trackersurl] in html page is below:
&tr=http:ajgdsjhg/ann
&tr=udp://iuysidfu/ann
&tr=udp:wutefghgw/ann
&tr=http://sdhgsjdhgj/ann
I want to join them in a single line below
&tr=http:ajgdsjhg/ann&tr=udp://iuysidfu/ann&tr=udp:wutefghgw/ann&tr=http://sdhgsjdhgj/ann
You should be careful of sql injection.
Are you looking to create an array['trackers'] with a string of all the trackers for a magnet link?
<?php
$sql = "SELECT * FROM announce WHERE torrent = ".mysql_real_escape_string($id)." ORDER BY seeders DESC";
$query = mysql_query($sql);
$tracker = null;
if(mysql_num_rows($query)>=1){
while ($result = mysql_fetch_array($query)) {
$tracker .= "&tr=".$result['url'];
}
}
$tracker = array('trackers'=>$tracker);
//$tracker['trackers'] = "&tr=a.com&tr=b.com&tr=c.com";
?>
Try this code
$newArray=array();
while ($result = #mysql_fetch_array($query)) {
$trackersurl1 = $result['title'];
$newArray[] = "&tr=".$trackersurl1;
}
$urlString=implode('',$newArray);
Im trying to generate an array but not sure how to go about it.
I'm currently getting my data like so:
$query = mysql_query("SELECT * FROM users WHERE userEmail LIKE 'test#test.com'");
$row = mysql_fetch_array($query);
$query1 = mysql_query("SELECT * FROM categories");
while($row1 = mysql_fetch_array($query1)){
$query2 = mysql_query("SELECT * FROM usersettings WHERE userId = ".$row['userId']." AND usersettingCategory".$row1['categoryId']." LIKE 'y'");
$isyes = mysql_num_rows($query2);
if($isyes > 0){
$cat1 = mysql_query("SELECT * FROM shops WHERE shopstateId = 1 AND (categoryId1 = ".$row1['categoryId']." OR categoryId2 = ".$row1['categoryId']." OR categoryId3 = ".$row1['categoryId'].")");
$cat1match = mysql_num_rows($cat1);
if($cat1match > 0){
while($cat1shop = mysql_fetch_array($cat1)){
$cat1msg = mysql_query("SELECT * FROM messages WHERE shopId = ".$cat1shop['shopId']." and messagestateId = 1");
while($cat1msgrow = mysql_fetch_array($cat1msg)){
echo $cat1msgrow['messageContent']." - ".$cat1msgrow['messageCode'];
$cat1img = mysql_query("SELECT shopimagePath FROM shopimages WHERE shopimageId = ".$cat1shop['shopimageId']);
$imgpath = mysql_fetch_array($cat1img);
echo " - ".$imgpath['shopimagePath']."<br/>";
}
}
}
}
}
But this can cause duplicates when a user has all 3 of a shops categories picked in their preferences. I am trying to find a way to just pull the message ID out instead of the whole thing and put it into an array giving me, for example:
1,3,5,7,1,3,5,2,4,7,8
Then I can just run a separate query to say get me all messages where the ID is in the array, but i am unsure of the most constructive way to build such an array and examples of array from a while loop I have seen do not seem to be what I am looking for.
Is there anyone out there that can push me in the right direction?
Can't help with this code. But if you want an array from a query without duplicate result, you can use " select DISTINCT (id) " in your query or for more simple solution :
$id_arr = array();
$sql = mysql_query("select id from id_table");
while ($id_result = mysql_fetch_array($sql) {
$id = $id_result['id'];
if (!in_array($id, $id_arr)) {
$id_arr[] = $id;
}
}
I have found a much easier way to create the required result. I think at 6am after a hard night coding my brain was fried and I was making things a lot more complicated than I needed to. A simple solution to my issue is as follows:
$query = mysql_query("SELECT * FROM users WHERE userEmail LIKE 'test2#test2.com'");
$row = mysql_fetch_array($query);
$categories = "(";
$query1 = mysql_query("SELECT * FROM categories");
while($row1 = mysql_fetch_array($query1)){
$query2 = mysql_query("SELECT usersettingCategory".$row1['categoryId']." FROM usersettings WHERE userId = ".$row['userId']);
$row2 = mysql_fetch_array($query2);
if($row2['usersettingCategory'.$row1['categoryId']] == y){
$categories .= $row1['categoryId'].",";
}
}
$categories = substr_replace($categories ,")",-1);
echo $categories."<br />";
$query3 = mysql_query("SELECT * FROM shops,messages WHERE shops.shopId = messages.shopId AND messages.messagestateId = 1 AND (shops.categoryId1 IN $categories OR shops.categoryId2 IN $categories OR shops.categoryId3 IN $categories)");
while($row3 = mysql_fetch_array($query3)){
$query4 = mysql_query("SELECT shopimagePath FROM shopimages WHERE shopimageId = ".$row3['shopimageId']);
$row4 = mysql_fetch_array($query4);
echo $row3['messageContent']." - ".$row3['messageCode']." - ".$row4['shopimagePath']."<br />";
}
$query = "SELECT * FROM `table`";
$results = mysql_query($query, $connection);
If 'table' has no rows. whats the easiest way to check for this.?
Jeremy Ruten's answer above is good and executes quickly; on the other hand, it only gives you the number of rows and nothing else (if you want the result data, you have to query the database again). What I use:
// only ask for the columns that interest you (SELECT * can slow down the query)
$query = "SELECT some_column, some_other_column, yet_another_column FROM `table`";
$results = mysql_query($query, $connection);
$numResults = mysql_num_rows($results);
if ($numResults > 0) {
// there are some results, retrieve them normally (e.g. with mysql_fetch_assoc())
} else {
// no data from query, react accordingly
}
You could use mysql_num_rows($results) to check if 0 rows were returned, or use this faster alternative:
$query = "SELECT COUNT(*) AS total FROM table";
$results = mysql_query($query, $connection);
$values = mysql_fetch_assoc($results);
$num_rows = $values['total'];
Alternatively you can simply check if the result of mysql_fetch_assoc is false.
$query = "SELECT * FROM `table`";
$results = mysql_query($query, $connection);
$Row = mysql_fetch_assoc($results);
if ($Row == false)
{
$Msg = 'Table is empty';
}
One thing i noticed that was missed was the fact that the query might not succeed, so you do need to check if the $results variable is set. I'll use the answer given by yjerem as an example.
$query = "SELECT COUNT(*) AS total FROM table";
$results = mysql_query($query, $connection);
if ($results) { // or use isset($results)
$values = mysql_fetch_assoc($results);
$num_rows = $values['total'];
}
If you loop through the results, you can have a counter and check that.
$x = 1;
$query = mysql_query("SELECT * FROM table");
while($row = mysql_fetch_assoc($query))
{
$x++;
}
if($x == 1)
{
//No rows
}