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How to find number of days between two dates using PHP?
$now = time(); // or your date as well
$your_date = strtotime("2010-01-31");
$datediff = $now - $your_date;
echo round($datediff / (60 * 60 * 24));
If you're using PHP 5.3 >, this is by far the most accurate way of calculating the absolute difference:
$earlier = new DateTime("2010-07-06");
$later = new DateTime("2010-07-09");
$abs_diff = $later->diff($earlier)->format("%a"); //3
If you need a relative (signed) number of days, use this instead:
$earlier = new DateTime("2010-07-06");
$later = new DateTime("2010-07-09");
$pos_diff = $earlier->diff($later)->format("%r%a"); //3
$neg_diff = $later->diff($earlier)->format("%r%a"); //-3
More on php's DateInterval format can be found here: https://www.php.net/manual/en/dateinterval.format.php
From PHP Version 5.3 and up, new date/time functions have been added to get difference:
$datetime1 = new DateTime("2010-06-20");
$datetime2 = new DateTime("2011-06-22");
$difference = $datetime1->diff($datetime2);
echo 'Difference: '.$difference->y.' years, '
.$difference->m.' months, '
.$difference->d.' days';
print_r($difference);
Result as below:
Difference: 1 years, 0 months, 2 days
DateInterval Object
(
[y] => 1
[m] => 0
[d] => 2
[h] => 0
[i] => 0
[s] => 0
[invert] => 0
[days] => 367
)
Hope it helps !
TL;DR do not use UNIX timestamps. Do not use time(). If you do, be prepared should its 98.0825% reliability fail you. Use DateTime (or Carbon).
The correct answer is the one given by Saksham Gupta (other answers are also correct):
$date1 = new DateTime('2010-07-06');
$date2 = new DateTime('2010-07-09');
$days = $date2->diff($date1)->format('%a');
Or procedurally as a one-liner:
/**
* Number of days between two dates.
*
* #param date $dt1 First date
* #param date $dt2 Second date
* #return int
*/
function daysBetween($dt1, $dt2) {
return date_diff(
date_create($dt2),
date_create($dt1)
)->format('%a');
}
With a caveat: the '%a' seems to indicate the absolute number of days. If you want it as a signed integer, i.e. negative when the second date is before the first, then you need to use the '%r' prefix (i.e. format('%r%a')).
If you really must use UNIX timestamps, set the time zone to GMT to avoid most of the pitfalls detailed below.
Long answer: why dividing by 24*60*60 (aka 86400) is unsafe
Most of the answers using UNIX timestamps (and 86400 to convert that to days) make two assumptions that, put together, can lead to scenarios with wrong results and subtle bugs that may be difficult to track, and arise even days, weeks or months after a successful deployment. It's not that the solution doesn't work - it works. Today. But it might stop working tomorrow.
First mistake is not considering that when asked, "How many days passed since yesterday?", a computer might truthfully answer zero if between the present and the instant indicated by "yesterday" less than one whole day has passed.
Usually when converting a "day" to a UNIX timestamp, what is obtained is the timestamp for the midnight of that particular day.
So between the midnights of October 1st and October 15th, fifteen days have elapsed. But between 13:00 of October 1st and 14:55 of October 15th, fifteen days minus 5 minutes have elapsed, and most solutions using floor() or doing implicit integer conversion will report one day less than expected.
So, "how many days ago was Y-m-d H:i:s"? will yield the wrong answer.
The second mistake is equating one day to 86400 seconds. This is almost always true - it happens often enough to overlook the times it doesn't. But the distance in seconds between two consecutive midnights is surely not 86400 at least twice a year when daylight saving time comes into play. Comparing two dates across a DST boundary will yield the wrong answer.
So even if you use the "hack" of forcing all date timestamps to a fixed hour, say midnight (this is also done implicitly by various languages and frameworks when you only specify day-month-year and not also hour-minute-second; same happens with DATE type in databases such as MySQL), the widely used formula
FLOOR((unix_timestamp(DATE2) - unix_timestamp(DATE1)) / 86400)
or
floor((time() - strtotime($somedate)) / 86400)
will return, say, 17 when DATE1 and DATE2 are in the same DST segment of the year; but even if the hour:minute:second part is identical, the argument might be 17.042, and worse still, 16.958 when they are in different DST segments and the time zone is DST-aware. The use of floor() or any implicit truncation to integer will then convert what should have been a 17 to a 16. In other circumstances, expressions like "$days > 17" will return true for 17.042, even if this will look as if the elapsed day count is 18.
And things grow even uglier since such code is not portable across platforms, because some of them may apply leap seconds and some might not. On those platforms that do, the difference between two dates will not be 86400 but 86401, or maybe 86399. So code that worked in May and actually passed all tests will break next June when 12.99999 days are considered 12 days instead of 13. Two dates that worked in 2015 will not work in 2017 -- the same dates, and neither year is a leap year. And between 2018-03-01 and 2017-03-01, on those platforms that care, 366 days will have passed instead of 365, making 2018 a leap year (which it is not).
So if you really want to use UNIX timestamps:
use round() function wisely, not floor().
as an alternative, do not calculate differences between D1-M1-YYY1 and D2-M2-YYY2. Those dates will be really considered as D1-M1-YYY1 00:00:00 and D2-M2-YYY2 00:00:00. Rather, convert between D1-M1-YYY1 22:30:00 and D2-M2-YYY2 04:30:00. You will always get a remainder of about twenty hours. This may become twenty-one hours or nineteen, and maybe eighteen hours, fifty-nine minutes thirty-six seconds. No matter. It is a large margin which will stay there and stay positive for the foreseeable future. Now you can truncate it with floor() in safety.
The correct solution though, to avoid magic constants, rounding kludges and a maintenance debt, is to
use a time library (Datetime, Carbon, whatever); don't roll your own
write comprehensive test cases using really evil date choices - across DST boundaries, across leap years, across leap seconds, and so on, as well as commonplace dates. Ideally (calls to datetime are fast!) generate four whole years' (and one day) worth of dates by assembling them from strings, sequentially, and ensure that the difference between the first day and the day being tested increases steadily by one. This will ensure that if anything changes in the low-level routines and leap seconds fixes try to wreak havoc, at least you will know.
run those tests regularly together with the rest of the test suite. They're a matter of milliseconds, and may save you literally hours of head scratching.
Whatever your solution, test it!
The function funcdiff below implements one of the solutions (as it happens, the accepted one) in a real world scenario.
<?php
$tz = 'Europe/Rome';
$yearFrom = 1980;
$yearTo = 2020;
$verbose = false;
function funcdiff($date2, $date1) {
$now = strtotime($date2);
$your_date = strtotime($date1);
$datediff = $now - $your_date;
return floor($datediff / (60 * 60 * 24));
}
########################################
date_default_timezone_set($tz);
$failures = 0;
$tests = 0;
$dom = array ( 0, 31, 28, 31, 30,
31, 30, 31, 31,
30, 31, 30, 31 );
(array_sum($dom) === 365) || die("Thirty days hath September...");
$last = array();
for ($year = $yearFrom; $year < $yearTo; $year++) {
$dom[2] = 28;
// Apply leap year rules.
if ($year % 4 === 0) { $dom[2] = 29; }
if ($year % 100 === 0) { $dom[2] = 28; }
if ($year % 400 === 0) { $dom[2] = 29; }
for ($month = 1; $month <= 12; $month ++) {
for ($day = 1; $day <= $dom[$month]; $day++) {
$date = sprintf("%04d-%02d-%02d", $year, $month, $day);
if (count($last) === 7) {
$tests ++;
$diff = funcdiff($date, $test = array_shift($last));
if ((double)$diff !== (double)7) {
$failures ++;
if ($verbose) {
print "There seem to be {$diff} days between {$date} and {$test}\n";
}
}
}
$last[] = $date;
}
}
}
print "This function failed {$failures} of its {$tests} tests";
print " between {$yearFrom} and {$yearTo}.\n";
The result is,
This function failed 280 of its 14603 tests
Horror Story: the cost of "saving time"
It all began in late 2014. An ingenious programmer decided to save several microseconds off a calculation that took about thirty seconds at most, by plugging in the infamous "(MidnightOfDateB-MidnightOfDateA)/86400" code in several places. It was so obvious an optimization that he did not even document it, and the optimization passed the integration tests and somehow lurked in the code for several months, all unnoticed.
This happened in a program that calculates the wages for several top-selling salesmen, the least of which has a frightful lot more clout than a whole humble five-people programmer team taken together. On March 28th, 2015, the summer time zone engaged, the bug struck -- and some of those guys got shortchanged one whole day of fat commissions. To make things worse, most of them did not work on Sundays and, being near the end of the month, used that day to catch up with their invoicing. They were definitely not amused.
Infinitely worse, they lost the (already very little) faith they had in the program not being designed to surreptitiously shaft them, and pretended - and obtained - a complete, detailed code review with test cases ran and commented in layman's terms (plus a lot of red-carpet treatment in the following weeks).
What can I say: on the plus side, we got rid of a lot of technical debt, and were able to rewrite and refactor several pieces of a spaghetti mess that hearkened back to a COBOL infestation in the swinging '90s. The program undoubtedly runs better now, and there's a lot more debugging information to quickly zero in when anything looks fishy. I estimate that just this last one thing will save perhaps one or two man-days per month for the foreseeable future, so the disaster will have a silver, or even golden, lining.
On the minus side, the whole brouhaha costed the company about €200,000 up front - plus face, plus undoubtedly some bargaining power (and, hence, yet more money).
The guy responsible for the "optimization" had changed job in December 2014, well before the disaster, but still there was talk to sue him for damages. And it didn't go well with the upper echelons that it was "the last guy's fault" - it looked like a set-up for us to come up clean of the matter, and in the end, we remained in the doghouse for the rest of the year, and one of the team resigned at the end of that summer.
Ninety-nine times out of one hundred, the "86400 hack" will work flawlessly. (For example in PHP, strtotime() will ignore DST, and report that between the midnights of the last Saturday of October and that of the following Monday, exactly 2 * 24 * 60 * 60 seconds have passed, even if that is plainly not true... and two wrongs will happily make one right).
This, ladies and gentlemen, was one instance when it did not. As with air-bags and seat belts, you will perhaps never really need the complexity (and ease of use) of DateTime or Carbon. But the day when you might (or the day when you'll have to prove you thought about this) will come as a thief in the night (likely at 02:00 some Sunday in October). Be prepared.
Convert your dates to unix timestamps, then substract one from the another. That will give you the difference in seconds, which you divide by 86400 (amount of seconds in a day) to give you an approximate amount of days in that range.
If your dates are in format 25.1.2010, 01/25/2010 or 2010-01-25, you can use the strtotime function:
$start = strtotime('2010-01-25');
$end = strtotime('2010-02-20');
$days_between = ceil(abs($end - $start) / 86400);
Using ceil rounds the amount of days up to the next full day. Use floor instead if you want to get the amount of full days between those two dates.
If your dates are already in unix timestamp format, you can skip the converting and just do the $days_between part. For more exotic date formats, you might have to do some custom parsing to get it right.
Easy to using date_diff
$from=date_create(date('Y-m-d'));
$to=date_create("2013-03-15");
$diff=date_diff($to,$from);
print_r($diff);
echo $diff->format('%R%a days');
See more at: https://blog.devgenius.io/how-to-find-the-number-of-days-between-two-dates-in-php-1404748b1e84
Object oriented style:
$datetime1 = new DateTime('2009-10-11');
$datetime2 = new DateTime('2009-10-13');
$interval = $datetime1->diff($datetime2);
echo $interval->format('%R%a days');
Procedural style:
$datetime1 = date_create('2009-10-11');
$datetime2 = date_create('2009-10-13');
$interval = date_diff($datetime1, $datetime2);
echo $interval->format('%R%a days');
Used this :)
$days = (strtotime($endDate) - strtotime($startDate)) / (60 * 60 * 24);
print $days;
Now it works
Well, the selected answer is not the most correct one because it will fail outside UTC.
Depending on the timezone (list) there could be time adjustments creating days "without" 24 hours, and this will make the calculation (60*60*24) fail.
Here it is an example of it:
date_default_timezone_set('europe/lisbon');
$time1 = strtotime('2016-03-27');
$time2 = strtotime('2016-03-29');
echo floor( ($time2-$time1) /(60*60*24));
^-- the output will be **1**
So the correct solution will be using DateTime
date_default_timezone_set('europe/lisbon');
$date1 = new DateTime("2016-03-27");
$date2 = new DateTime("2016-03-29");
echo $date2->diff($date1)->format("%a");
^-- the output will be **2**
You can find dates simply by
<?php
$start = date_create('1988-08-10');
$end = date_create(); // Current time and date
$diff = date_diff( $start, $end );
echo 'The difference is ';
echo $diff->y . ' years, ';
echo $diff->m . ' months, ';
echo $diff->d . ' days, ';
echo $diff->h . ' hours, ';
echo $diff->i . ' minutes, ';
echo $diff->s . ' seconds';
// Output: The difference is 28 years, 5 months, 19 days, 20 hours, 34 minutes, 36 seconds
echo 'The difference in days : ' . $diff->days;
// Output: The difference in days : 10398
Calculate the difference between two dates:
$date1=date_create("2013-03-15");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
echo $diff->format("%R%a days");
Output:
+272 days
The date_diff() function returns the difference between two DateTime objects.
$start = '2013-09-08';
$end = '2013-09-15';
$diff = (strtotime($end)- strtotime($start))/24/3600;
echo $diff;
I'm using Carbon in my composer projects for this and similar purposes.
It'd be as easy as this:
$dt = Carbon::parse('2010-01-01');
echo $dt->diffInDays(Carbon::now());
You can try the code below:
$dt1 = strtotime("2019-12-12"); //Enter your first date
$dt2 = strtotime("12-12-2020"); //Enter your second date
echo abs(($dt1 - $dt2) / (60 * 60 * 24));
number of days between two dates in PHP
function dateDiff($date1, $date2) //days find function
{
$diff = strtotime($date2) - strtotime($date1);
return abs(round($diff / 86400));
}
//start day
$date1 = "11-10-2018";
// end day
$date2 = "31-10-2018";
// call the days find fun store to variable
$dateDiff = dateDiff($date1, $date2);
echo "Difference between two dates: ". $dateDiff . " Days ";
If you have the times in seconds (I.E. unix time stamp) , then you can simply subtract the times and divide by 86400 (seconds per day)
$datediff = floor(strtotime($date1)/(60*60*24)) - floor(strtotime($date2)/(60*60*24));
and, if needed:
$datediff=abs($datediff);
Easiest way to find the days difference between two dates
$date1 = strtotime("2019-05-25");
$date2 = strtotime("2010-06-23");
$date_difference = $date2 - $date1;
$result = round( $date_difference / (60 * 60 * 24) );
echo $result;
$diff = strtotime('2019-11-25') - strtotime('2019-11-10');
echo abs(round($diff / 86400));
function howManyDays($startDate,$endDate) {
$date1 = strtotime($startDate." 0:00:00");
$date2 = strtotime($endDate." 23:59:59");
$res = (int)(($date2-$date1)/86400);
return $res;
}
If you want to echo all days between the start and end date, I came up with this :
$startdatum = $_POST['start']; // starting date
$einddatum = $_POST['eind']; // end date
$now = strtotime($startdatum);
$your_date = strtotime($einddatum);
$datediff = $your_date - $now;
$number = floor($datediff/(60*60*24));
for($i=0;$i <= $number; $i++)
{
echo date('d-m-Y' ,strtotime("+".$i." day"))."<br>";
}
This code worked for me and tested with PHP 8 version :
function numberOfDays($startDate, $endDate)
{
//1) converting dates to timestamps
$startSeconds = strtotime($startDate);
$endSeconds = strtotime($endDate);
//2) Calculating the difference in timestamps
$diffSeconds = $startSeconds - $endSeconds;
//3) converting timestamps to days
$days=round($diffSeconds / 86400);
/* note :
1 day = 24 hours
24 * 60 * 60 = 86400 seconds
*/
//4) printing the number of days
printf("Difference between two dates: ". abs($days) . " Days ");
return abs($days);
}
Here is my improved version which shows 1 Year(s) 2 Month(s) 25 day(s) if the 2nd parameter is passed.
class App_Sandbox_String_Util {
/**
* Usage: App_Sandbox_String_Util::getDateDiff();
* #param int $your_date timestamp
* #param bool $hr human readable. e.g. 1 year(s) 2 day(s)
* #see http://stackoverflow.com/questions/2040560/finding-the-number-of-days-between-two-dates
* #see http://qSandbox.com
*/
static public function getDateDiff($your_date, $hr = 0) {
$now = time(); // or your date as well
$datediff = $now - $your_date;
$days = floor( $datediff / ( 3600 * 24 ) );
$label = '';
if ($hr) {
if ($days >= 365) { // over a year
$years = floor($days / 365);
$label .= $years . ' Year(s)';
$days -= 365 * $years;
}
if ($days) {
$months = floor( $days / 30 );
$label .= ' ' . $months . ' Month(s)';
$days -= 30 * $months;
}
if ($days) {
$label .= ' ' . $days . ' day(s)';
}
} else {
$label = $days;
}
return $label;
}
}
$early_start_date = date2sql($_POST['early_leave_date']);
$date = new DateTime($early_start_date);
$date->modify('+1 day');
$date_a = new DateTime($early_start_date . ' ' . $_POST['start_hr'] . ':' . $_POST['start_mm']);
$date_b = new DateTime($date->format('Y-m-d') . ' ' . $_POST['end_hr'] . ':' . $_POST['end_mm']);
$interval = date_diff($date_a, $date_b);
$time = $interval->format('%h:%i');
$parsed = date_parse($time);
$seconds = $parsed['hour'] * 3600 + $parsed['minute'] * 60;
// display_error($seconds);
$second3 = $employee_information['shift'] * 60 * 60;
if ($second3 < $seconds)
display_error(_('Leave time can not be greater than shift time.Please try again........'));
set_focus('start_hr');
set_focus('end_hr');
return FALSE;
}
<?php
$date1=date_create("2013-03-15");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
echo $diff->format("%R%a days");
?>
used the above code very simple. Thanks.
function get_daydiff($end_date,$today)
{
if($today=='')
{
$today=date('Y-m-d');
}
$str = floor(strtotime($end_date)/(60*60*24)) - floor(strtotime($today)/(60*60*24));
return $str;
}
$d1 = "2018-12-31";
$d2 = "2018-06-06";
echo get_daydiff($d1, $d2);
Using this simple function. Declare function
<?php
function dateDiff($firstDate,$secondDate){
$firstDate = strtotime($firstDate);
$secondDate = strtotime($secondDate);
$datediff = $firstDate - $secondDate;
$output = round($datediff / (60 * 60 * 24));
return $output;
}
?>
and call this function like this where you want
<?php
echo dateDiff("2018-01-01","2018-12-31");
// OR
$firstDate = "2018-01-01";
$secondDate = "2018-01-01";
echo dateDiff($firstDate,$secondDate);
?>
// Change this to the day in the future
$day = 15;
// Change this to the month in the future
$month = 11;
// Change this to the year in the future
$year = 2012;
// $days is the number of days between now and the date in the future
$days = (int)((mktime (0,0,0,$month,$day,$year) - time(void))/86400);
echo "There are $days days until $day/$month/$year";
If you are using MySql
function daysSince($date, $date2){
$q = "SELECT DATEDIFF('$date','$date2') AS days;";
$result = execQ($q);
$row = mysql_fetch_array($result,MYSQL_BOTH);
return ($row[0]);
}
function execQ($q){
$result = mysql_query( $q);
if(!$result){echo ('Database error execQ' . mysql_error());echo $q;}
return $result;
}
Try using Carbon
$d1 = \Carbon\Carbon::now()->subDays(92);
$d2 = \Carbon\Carbon::now()->subDays(10);
$days_btw = $d1->diffInDays($d2);
Also you can use
\Carbon\Carbon::parse('')
to create an object of Carbon date using given timestamp string.
I'm not trying to do this with MySQL as I see is common. I am merely trying to create a PHP Script that will display information like this using the servers time and date as a reference:
Monday 2:30am to Tuesday 2:29am - Content A
Tuesday 2:30am to Wednesday 2:29am - Content B
Wednesday 2:30am to Thursday 2:29am - Content C
and so on....
Until every day of the week in covered, for some reason I can't seem to nail this and there doesn't seem to be and examples to build from. Is this for some reason not possible?
Edit
I've used the following code and it's proving to not be as reliable as it should be.
function isInTimeWindow($dayName, $startHour, $startMinute, $endHour, $endMinute)
{
$dayName = ucfirst($dayName);
list($dayNow, $timeNow) = explode('|', date('l|Hi'));
return (
ucfirst($dayName) == $dayNow and
$timeNow >= sprintf('%02d%02d', $startHour, $startMinute) and
$timeNow <= sprintf('%02d%02d', $endHour, $endMinute)
);
}
// tuesdays during day
if(isInTimeWindow('tuesday', 02, 30, 23, 00)) {
?>
CONTENT
<?php } ?>
you could use date(l) php manual date() function function to get the actual weekday in words (Monday, Tuesday, ... ) so you can check the weekday.
Use mktime function php manual mktime() function to convert your times ( Monday, 2:30am for example ) into timestamps and check if it is between current time by using time function php manual time() function
EDIT: Here's an example:
$today_start = mktime(2, 30, 0, date('m'), date('d'), date('Y'));
$today_end = mktime(2, 29, 0, date('m'), (date('d') + 1), date('Y'));
if ( $today_start < time() && $today_end > time() )
// code
mktime works like this: mktime( hour, minutes, seconds, month, day, year )
So long as you're happy using the server's time rather than the client's time this can be done using the getdate() function.
For example, if you just wanted to do it based on day of the week:
<?php
$now = getdate();
switch($now['wday']) {
case 0:
?>
Content A
<?
break;
etc.
Edit: here is how to do it in more detail:
getdate() provides you with information about the hour and minute parts too.
You could have a function like :
// Get's the 0-indexed day of the week offset so each "day" starts and 2:30am
function get_offset_day() {
$now = getdate();
if ($now['hours']*60 + $now['minutes'] < 150) { // less 2h 30m after midnight => still "yesterday"
$answer = $now['wday']-1;
}
else {
$answer = $now['wday'];
}
if ($answer < 0) return 6;
return $answer;
}
What would be the best way of converting UK date and time in the format:
30/01/2013 13:30:06
which is d/m/Y H:i:s in PHP noation to relative time (i.e. just now, few minutes ago, 30 minutes ago, 3 hours ago, 1 day ago.. and so on). I've seen several tutorials on the subject but they all revolve around creating functions without any clear explanations. I would appreciate some assistance on the matter.
Hope This helps
function timeSince($ptime){
$etime = time() - strtotime($ptime);
if( $etime < 1 ){
return 'less than 1 second ago';
}
$a = array( 12 * 30 * 24 * 60 * 60 => 'year',
30 * 24 * 60 * 60 => 'month',
24 * 60 * 60 => 'day',
60 * 60 => 'hour',
60 => 'minute',
1 => 'second'
);
foreach( $a as $secs => $str ){
$d = $etime / $secs;
if( $d >= 1 ){
$r = round( $d );
return ' <font style="color:#0099ff"> ' . $r . ' ' . $str . ( $r > 1 ? 's' : '' ) . ' ago</font>';
}
}
}
Writing a custom function might help. Cut the string and convert to numbers. Use mktime() to create a timestamp, compare it to time() current timestamp and switch (case) through various relative time possibilities.
Use mktime(); and date();
For example if you have a specific time in the format d/m/Y H:i:s, and you want it as d-m-Y H:s:i, you would explode the time into chunks using explode(); and then use date(new_format, mktime(current_format_chunks))
dd/mm/yyyy needs to be changed to dd.mm.yyyy according to the formatting rules otherwise it will be treated as mm/dd/yyyy
$dateString = '30/01/2013 13:30:06';
$dateObject = new DateTime(str_replace('/', '.', $dateString));
with the optional addition of a DateTimezone as a second argument to the DateTime constructor.
Then you can do a diff with the current date, and use dateintervals to get the relative time
The most straight-forward and friendly way of parsing dates is the DateTime extension. It has a static method called createFromFormat:
$date = '30/01/2013 13:30:06';
$format = 'j/m/Y G:i:s';
$time = DateTime::createFromFormat($format, $date);
echo $time->format('l dS F \'y at H.i.s');
The method takes a custom format and a date string. Because you can define the format yourself it is much easier than parsing it "manually".
In order to adjust the date you can use the add(), sub() and modify() methods:
$time->add(new DateInterval('P3DT5H')); // 3 days and 5 hours
echo $time->format('l dS F \'y at H.i.s');
$time->sub(new DateInterval('P9DT1H')); // 9 days and 1 hours
echo $time->format('l dS F \'y at H.i.s');
$time->modify('-1 year -35 days');
echo $time->format('l dS F \'y at H.i.s');
As you can see the modify() method is slightly easier to use. The two other methods use the DateInterval class and an awkward format. It is not difficult (just read the documentation and do as it says), but using actual words (i.e. "-3 days -7 hours") is easier to understand.
I have been developing on php 5.3.
However our production server is 5.2.6.
I have been using
$schedule = '31/03/2011 01:22 pm'; // example input
if (empty($schedule))
$schedule = date('Y-m-d H:i:s');
else {
$schedule = dateTime::createFromFormat('d/m/Y h:i a', $schedule);
$schedule = $schedule->format('Y-m-d H:i:s');
}
echo $schedule;
However that function is not available in 5.2
What is the easiest way to get around this (no chance of a php upgrade).
just include the next code
function DEFINE_date_create_from_format()
{
function date_create_from_format( $dformat, $dvalue )
{
$schedule = $dvalue;
$schedule_format = str_replace(array('Y','m','d', 'H', 'i','a'),array('%Y','%m','%d', '%I', '%M', '%p' ) ,$dformat);
// %Y, %m and %d correspond to date()'s Y m and d.
// %I corresponds to H, %M to i and %p to a
$ugly = strptime($schedule, $schedule_format);
$ymd = sprintf(
// This is a format string that takes six total decimal
// arguments, then left-pads them with zeros to either
// 4 or 2 characters, as needed
'%04d-%02d-%02d %02d:%02d:%02d',
$ugly['tm_year'] + 1900, // This will be "111", so we need to add 1900.
$ugly['tm_mon'] + 1, // This will be the month minus one, so we add one.
$ugly['tm_mday'],
$ugly['tm_hour'],
$ugly['tm_min'],
$ugly['tm_sec']
);
$new_schedule = new DateTime($ymd);
return $new_schedule;
}
}
if( !function_exists("date_create_from_format") )
DEFINE_date_create_from_format();
Because strtotime does poorly when confronted with D/M/Y and date_create_from_format isn't available, strptime may be your only hope here. It does some pretty oldschool things, like deal with years as if they are the number of years since 1900 and deal with months as if January was month zero. Here's some horrible example code that uses sprintf to reassemble the date into something DateTime understands:
$schedule = '31/03/2011 01:22 pm';
// %Y, %m and %d correspond to date()'s Y m and d.
// %I corresponds to H, %M to i and %p to a
$ugly = strptime($schedule, '%d/%m/%Y %I:%M %p');
$ymd = sprintf(
// This is a format string that takes six total decimal
// arguments, then left-pads them with zeros to either
// 4 or 2 characters, as needed
'%04d-%02d-%02d %02d:%02d:%02d',
$ugly['tm_year'] + 1900, // This will be "111", so we need to add 1900.
$ugly['tm_mon'] + 1, // This will be the month minus one, so we add one.
$ugly['tm_mday'],
$ugly['tm_hour'],
$ugly['tm_min'],
$ugly['tm_sec']
);
echo $ymd;
$new_schedule = new DateTime($ymd);
echo $new_schedule->format('Y-m-d H:i:s');
If it works, you should see the same, correct date and time printed twice.
I think it is much cleaner to extend the DateTime class and implement createFromFormat() yourself like this:-
class MyDateTime extends DateTime
{
public static function createFromFormat($format, $time, $timezone = null)
{
if(!$timezone) $timezone = new DateTimeZone(date_default_timezone_get());
$version = explode('.', phpversion());
if(((int)$version[0] >= 5 && (int)$version[1] >= 2 && (int)$version[2] > 17)){
return parent::createFromFormat($format, $time, $timezone);
}
return new DateTime(date($format, strtotime($time)), $timezone);
}
}
$dateTime = MyDateTime::createFromFormat('Y-m-d', '2013-6-13');
var_dump($dateTime);
var_dump($dateTime->format('Y-m-d'));
This will work in all versions of PHP >= 5.2.0.
See here for a demo http://3v4l.org/djucq
Since this is not really showing how to convert YYYY:DDD:HH:MM:SS time to unix seconds using the "z" option you have to create you own functions to convert the DOY to month and day of month. This is what I did:
function _IsLeapYear ($Year)
{
$LeapYear = 0;
# Leap years are divisible by 4, but not by 100, unless by 400
if ( ( $Year % 4 == 0 ) || ( $Year % 100 == 0 ) || ( $Year % 400 == 0 ) ) {
$LeapYear = 1;
}
return $LeapYear;
}
function _DaysInMonth ($Year, $Month)
{
$DaysInMonth = array(31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31);
return ((_IsLeapYear($Year) && $Month == 2) ? 29 : $DaysInMonth[$Month - 1]);
}
function yydddhhssmmToTime($Year, $DOY, $Hour, $Min, $Sec)
{
$Day = $DOY;
for ($Month = 1; $Day > _DaysInMonth($Year, $Month); $Month++) {
$Day -= _DaysInMonth($Year, $Month);
}
$DayOfMonth = $Day;
return mktime($Hour, $Min, $Sec, $Month, $DayOfMonth, $Year);
}
$timeSec = yydddhhssmmToTime(2016, 365, 23, 23, 23);
$str = date("m/d/Y H:i:s", $timeSec);
echo "unix seconds: " . $timeis . " " . $str ."<br>";
The output on the page shows its working since I can convert back the seconds back to the original input values.
unix seconds: 1483140203 12/30/2016 23:23:23
$your_datetime_object=new DateTime($date);
$date_format_modified=date_format($your_datetime_object,'D M d Y');//Change the format of date time
I had the similar problem with the production server at 5.2, so I used the above datetime to create an object and then change the format to my liking as above.
Date and Time only
$dateTime = DateTime::createFromFormat('Y-m-d\TH:i:s', '2015-04-20T18:56:42');
ISO8601 no colons
$dateTime = DateTime::createFromFormat('Y-m-d\TH:i:sO', '2015-04-20T18:56:42+0000');
ISO8601 with colons
$date = $dateTime->format('c');
Salesforce ISO8601 format
DateTime::createFromFormat('Y-m-d\TH:i:s.uO', '2015-04-20T18:56:42.000+0000');
Hope this saves someone time!
How to find number of days between two dates using PHP?
$now = time(); // or your date as well
$your_date = strtotime("2010-01-31");
$datediff = $now - $your_date;
echo round($datediff / (60 * 60 * 24));
If you're using PHP 5.3 >, this is by far the most accurate way of calculating the absolute difference:
$earlier = new DateTime("2010-07-06");
$later = new DateTime("2010-07-09");
$abs_diff = $later->diff($earlier)->format("%a"); //3
If you need a relative (signed) number of days, use this instead:
$earlier = new DateTime("2010-07-06");
$later = new DateTime("2010-07-09");
$pos_diff = $earlier->diff($later)->format("%r%a"); //3
$neg_diff = $later->diff($earlier)->format("%r%a"); //-3
More on php's DateInterval format can be found here: https://www.php.net/manual/en/dateinterval.format.php
From PHP Version 5.3 and up, new date/time functions have been added to get difference:
$datetime1 = new DateTime("2010-06-20");
$datetime2 = new DateTime("2011-06-22");
$difference = $datetime1->diff($datetime2);
echo 'Difference: '.$difference->y.' years, '
.$difference->m.' months, '
.$difference->d.' days';
print_r($difference);
Result as below:
Difference: 1 years, 0 months, 2 days
DateInterval Object
(
[y] => 1
[m] => 0
[d] => 2
[h] => 0
[i] => 0
[s] => 0
[invert] => 0
[days] => 367
)
Hope it helps !
TL;DR do not use UNIX timestamps. Do not use time(). If you do, be prepared should its 98.0825% reliability fail you. Use DateTime (or Carbon).
The correct answer is the one given by Saksham Gupta (other answers are also correct):
$date1 = new DateTime('2010-07-06');
$date2 = new DateTime('2010-07-09');
$days = $date2->diff($date1)->format('%a');
Or procedurally as a one-liner:
/**
* Number of days between two dates.
*
* #param date $dt1 First date
* #param date $dt2 Second date
* #return int
*/
function daysBetween($dt1, $dt2) {
return date_diff(
date_create($dt2),
date_create($dt1)
)->format('%a');
}
With a caveat: the '%a' seems to indicate the absolute number of days. If you want it as a signed integer, i.e. negative when the second date is before the first, then you need to use the '%r' prefix (i.e. format('%r%a')).
If you really must use UNIX timestamps, set the time zone to GMT to avoid most of the pitfalls detailed below.
Long answer: why dividing by 24*60*60 (aka 86400) is unsafe
Most of the answers using UNIX timestamps (and 86400 to convert that to days) make two assumptions that, put together, can lead to scenarios with wrong results and subtle bugs that may be difficult to track, and arise even days, weeks or months after a successful deployment. It's not that the solution doesn't work - it works. Today. But it might stop working tomorrow.
First mistake is not considering that when asked, "How many days passed since yesterday?", a computer might truthfully answer zero if between the present and the instant indicated by "yesterday" less than one whole day has passed.
Usually when converting a "day" to a UNIX timestamp, what is obtained is the timestamp for the midnight of that particular day.
So between the midnights of October 1st and October 15th, fifteen days have elapsed. But between 13:00 of October 1st and 14:55 of October 15th, fifteen days minus 5 minutes have elapsed, and most solutions using floor() or doing implicit integer conversion will report one day less than expected.
So, "how many days ago was Y-m-d H:i:s"? will yield the wrong answer.
The second mistake is equating one day to 86400 seconds. This is almost always true - it happens often enough to overlook the times it doesn't. But the distance in seconds between two consecutive midnights is surely not 86400 at least twice a year when daylight saving time comes into play. Comparing two dates across a DST boundary will yield the wrong answer.
So even if you use the "hack" of forcing all date timestamps to a fixed hour, say midnight (this is also done implicitly by various languages and frameworks when you only specify day-month-year and not also hour-minute-second; same happens with DATE type in databases such as MySQL), the widely used formula
FLOOR((unix_timestamp(DATE2) - unix_timestamp(DATE1)) / 86400)
or
floor((time() - strtotime($somedate)) / 86400)
will return, say, 17 when DATE1 and DATE2 are in the same DST segment of the year; but even if the hour:minute:second part is identical, the argument might be 17.042, and worse still, 16.958 when they are in different DST segments and the time zone is DST-aware. The use of floor() or any implicit truncation to integer will then convert what should have been a 17 to a 16. In other circumstances, expressions like "$days > 17" will return true for 17.042, even if this will look as if the elapsed day count is 18.
And things grow even uglier since such code is not portable across platforms, because some of them may apply leap seconds and some might not. On those platforms that do, the difference between two dates will not be 86400 but 86401, or maybe 86399. So code that worked in May and actually passed all tests will break next June when 12.99999 days are considered 12 days instead of 13. Two dates that worked in 2015 will not work in 2017 -- the same dates, and neither year is a leap year. And between 2018-03-01 and 2017-03-01, on those platforms that care, 366 days will have passed instead of 365, making 2018 a leap year (which it is not).
So if you really want to use UNIX timestamps:
use round() function wisely, not floor().
as an alternative, do not calculate differences between D1-M1-YYY1 and D2-M2-YYY2. Those dates will be really considered as D1-M1-YYY1 00:00:00 and D2-M2-YYY2 00:00:00. Rather, convert between D1-M1-YYY1 22:30:00 and D2-M2-YYY2 04:30:00. You will always get a remainder of about twenty hours. This may become twenty-one hours or nineteen, and maybe eighteen hours, fifty-nine minutes thirty-six seconds. No matter. It is a large margin which will stay there and stay positive for the foreseeable future. Now you can truncate it with floor() in safety.
The correct solution though, to avoid magic constants, rounding kludges and a maintenance debt, is to
use a time library (Datetime, Carbon, whatever); don't roll your own
write comprehensive test cases using really evil date choices - across DST boundaries, across leap years, across leap seconds, and so on, as well as commonplace dates. Ideally (calls to datetime are fast!) generate four whole years' (and one day) worth of dates by assembling them from strings, sequentially, and ensure that the difference between the first day and the day being tested increases steadily by one. This will ensure that if anything changes in the low-level routines and leap seconds fixes try to wreak havoc, at least you will know.
run those tests regularly together with the rest of the test suite. They're a matter of milliseconds, and may save you literally hours of head scratching.
Whatever your solution, test it!
The function funcdiff below implements one of the solutions (as it happens, the accepted one) in a real world scenario.
<?php
$tz = 'Europe/Rome';
$yearFrom = 1980;
$yearTo = 2020;
$verbose = false;
function funcdiff($date2, $date1) {
$now = strtotime($date2);
$your_date = strtotime($date1);
$datediff = $now - $your_date;
return floor($datediff / (60 * 60 * 24));
}
########################################
date_default_timezone_set($tz);
$failures = 0;
$tests = 0;
$dom = array ( 0, 31, 28, 31, 30,
31, 30, 31, 31,
30, 31, 30, 31 );
(array_sum($dom) === 365) || die("Thirty days hath September...");
$last = array();
for ($year = $yearFrom; $year < $yearTo; $year++) {
$dom[2] = 28;
// Apply leap year rules.
if ($year % 4 === 0) { $dom[2] = 29; }
if ($year % 100 === 0) { $dom[2] = 28; }
if ($year % 400 === 0) { $dom[2] = 29; }
for ($month = 1; $month <= 12; $month ++) {
for ($day = 1; $day <= $dom[$month]; $day++) {
$date = sprintf("%04d-%02d-%02d", $year, $month, $day);
if (count($last) === 7) {
$tests ++;
$diff = funcdiff($date, $test = array_shift($last));
if ((double)$diff !== (double)7) {
$failures ++;
if ($verbose) {
print "There seem to be {$diff} days between {$date} and {$test}\n";
}
}
}
$last[] = $date;
}
}
}
print "This function failed {$failures} of its {$tests} tests";
print " between {$yearFrom} and {$yearTo}.\n";
The result is,
This function failed 280 of its 14603 tests
Horror Story: the cost of "saving time"
It all began in late 2014. An ingenious programmer decided to save several microseconds off a calculation that took about thirty seconds at most, by plugging in the infamous "(MidnightOfDateB-MidnightOfDateA)/86400" code in several places. It was so obvious an optimization that he did not even document it, and the optimization passed the integration tests and somehow lurked in the code for several months, all unnoticed.
This happened in a program that calculates the wages for several top-selling salesmen, the least of which has a frightful lot more clout than a whole humble five-people programmer team taken together. On March 28th, 2015, the summer time zone engaged, the bug struck -- and some of those guys got shortchanged one whole day of fat commissions. To make things worse, most of them did not work on Sundays and, being near the end of the month, used that day to catch up with their invoicing. They were definitely not amused.
Infinitely worse, they lost the (already very little) faith they had in the program not being designed to surreptitiously shaft them, and pretended - and obtained - a complete, detailed code review with test cases ran and commented in layman's terms (plus a lot of red-carpet treatment in the following weeks).
What can I say: on the plus side, we got rid of a lot of technical debt, and were able to rewrite and refactor several pieces of a spaghetti mess that hearkened back to a COBOL infestation in the swinging '90s. The program undoubtedly runs better now, and there's a lot more debugging information to quickly zero in when anything looks fishy. I estimate that just this last one thing will save perhaps one or two man-days per month for the foreseeable future, so the disaster will have a silver, or even golden, lining.
On the minus side, the whole brouhaha costed the company about €200,000 up front - plus face, plus undoubtedly some bargaining power (and, hence, yet more money).
The guy responsible for the "optimization" had changed job in December 2014, well before the disaster, but still there was talk to sue him for damages. And it didn't go well with the upper echelons that it was "the last guy's fault" - it looked like a set-up for us to come up clean of the matter, and in the end, we remained in the doghouse for the rest of the year, and one of the team resigned at the end of that summer.
Ninety-nine times out of one hundred, the "86400 hack" will work flawlessly. (For example in PHP, strtotime() will ignore DST, and report that between the midnights of the last Saturday of October and that of the following Monday, exactly 2 * 24 * 60 * 60 seconds have passed, even if that is plainly not true... and two wrongs will happily make one right).
This, ladies and gentlemen, was one instance when it did not. As with air-bags and seat belts, you will perhaps never really need the complexity (and ease of use) of DateTime or Carbon. But the day when you might (or the day when you'll have to prove you thought about this) will come as a thief in the night (likely at 02:00 some Sunday in October). Be prepared.
Convert your dates to unix timestamps, then substract one from the another. That will give you the difference in seconds, which you divide by 86400 (amount of seconds in a day) to give you an approximate amount of days in that range.
If your dates are in format 25.1.2010, 01/25/2010 or 2010-01-25, you can use the strtotime function:
$start = strtotime('2010-01-25');
$end = strtotime('2010-02-20');
$days_between = ceil(abs($end - $start) / 86400);
Using ceil rounds the amount of days up to the next full day. Use floor instead if you want to get the amount of full days between those two dates.
If your dates are already in unix timestamp format, you can skip the converting and just do the $days_between part. For more exotic date formats, you might have to do some custom parsing to get it right.
Easy to using date_diff
$from=date_create(date('Y-m-d'));
$to=date_create("2013-03-15");
$diff=date_diff($to,$from);
print_r($diff);
echo $diff->format('%R%a days');
See more at: https://blog.devgenius.io/how-to-find-the-number-of-days-between-two-dates-in-php-1404748b1e84
Object oriented style:
$datetime1 = new DateTime('2009-10-11');
$datetime2 = new DateTime('2009-10-13');
$interval = $datetime1->diff($datetime2);
echo $interval->format('%R%a days');
Procedural style:
$datetime1 = date_create('2009-10-11');
$datetime2 = date_create('2009-10-13');
$interval = date_diff($datetime1, $datetime2);
echo $interval->format('%R%a days');
Used this :)
$days = (strtotime($endDate) - strtotime($startDate)) / (60 * 60 * 24);
print $days;
Now it works
Well, the selected answer is not the most correct one because it will fail outside UTC.
Depending on the timezone (list) there could be time adjustments creating days "without" 24 hours, and this will make the calculation (60*60*24) fail.
Here it is an example of it:
date_default_timezone_set('europe/lisbon');
$time1 = strtotime('2016-03-27');
$time2 = strtotime('2016-03-29');
echo floor( ($time2-$time1) /(60*60*24));
^-- the output will be **1**
So the correct solution will be using DateTime
date_default_timezone_set('europe/lisbon');
$date1 = new DateTime("2016-03-27");
$date2 = new DateTime("2016-03-29");
echo $date2->diff($date1)->format("%a");
^-- the output will be **2**
You can find dates simply by
<?php
$start = date_create('1988-08-10');
$end = date_create(); // Current time and date
$diff = date_diff( $start, $end );
echo 'The difference is ';
echo $diff->y . ' years, ';
echo $diff->m . ' months, ';
echo $diff->d . ' days, ';
echo $diff->h . ' hours, ';
echo $diff->i . ' minutes, ';
echo $diff->s . ' seconds';
// Output: The difference is 28 years, 5 months, 19 days, 20 hours, 34 minutes, 36 seconds
echo 'The difference in days : ' . $diff->days;
// Output: The difference in days : 10398
Calculate the difference between two dates:
$date1=date_create("2013-03-15");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
echo $diff->format("%R%a days");
Output:
+272 days
The date_diff() function returns the difference between two DateTime objects.
$start = '2013-09-08';
$end = '2013-09-15';
$diff = (strtotime($end)- strtotime($start))/24/3600;
echo $diff;
I'm using Carbon in my composer projects for this and similar purposes.
It'd be as easy as this:
$dt = Carbon::parse('2010-01-01');
echo $dt->diffInDays(Carbon::now());
You can try the code below:
$dt1 = strtotime("2019-12-12"); //Enter your first date
$dt2 = strtotime("12-12-2020"); //Enter your second date
echo abs(($dt1 - $dt2) / (60 * 60 * 24));
number of days between two dates in PHP
function dateDiff($date1, $date2) //days find function
{
$diff = strtotime($date2) - strtotime($date1);
return abs(round($diff / 86400));
}
//start day
$date1 = "11-10-2018";
// end day
$date2 = "31-10-2018";
// call the days find fun store to variable
$dateDiff = dateDiff($date1, $date2);
echo "Difference between two dates: ". $dateDiff . " Days ";
If you have the times in seconds (I.E. unix time stamp) , then you can simply subtract the times and divide by 86400 (seconds per day)
$datediff = floor(strtotime($date1)/(60*60*24)) - floor(strtotime($date2)/(60*60*24));
and, if needed:
$datediff=abs($datediff);
Easiest way to find the days difference between two dates
$date1 = strtotime("2019-05-25");
$date2 = strtotime("2010-06-23");
$date_difference = $date2 - $date1;
$result = round( $date_difference / (60 * 60 * 24) );
echo $result;
$diff = strtotime('2019-11-25') - strtotime('2019-11-10');
echo abs(round($diff / 86400));
function howManyDays($startDate,$endDate) {
$date1 = strtotime($startDate." 0:00:00");
$date2 = strtotime($endDate." 23:59:59");
$res = (int)(($date2-$date1)/86400);
return $res;
}
If you want to echo all days between the start and end date, I came up with this :
$startdatum = $_POST['start']; // starting date
$einddatum = $_POST['eind']; // end date
$now = strtotime($startdatum);
$your_date = strtotime($einddatum);
$datediff = $your_date - $now;
$number = floor($datediff/(60*60*24));
for($i=0;$i <= $number; $i++)
{
echo date('d-m-Y' ,strtotime("+".$i." day"))."<br>";
}
This code worked for me and tested with PHP 8 version :
function numberOfDays($startDate, $endDate)
{
//1) converting dates to timestamps
$startSeconds = strtotime($startDate);
$endSeconds = strtotime($endDate);
//2) Calculating the difference in timestamps
$diffSeconds = $startSeconds - $endSeconds;
//3) converting timestamps to days
$days=round($diffSeconds / 86400);
/* note :
1 day = 24 hours
24 * 60 * 60 = 86400 seconds
*/
//4) printing the number of days
printf("Difference between two dates: ". abs($days) . " Days ");
return abs($days);
}
Here is my improved version which shows 1 Year(s) 2 Month(s) 25 day(s) if the 2nd parameter is passed.
class App_Sandbox_String_Util {
/**
* Usage: App_Sandbox_String_Util::getDateDiff();
* #param int $your_date timestamp
* #param bool $hr human readable. e.g. 1 year(s) 2 day(s)
* #see http://stackoverflow.com/questions/2040560/finding-the-number-of-days-between-two-dates
* #see http://qSandbox.com
*/
static public function getDateDiff($your_date, $hr = 0) {
$now = time(); // or your date as well
$datediff = $now - $your_date;
$days = floor( $datediff / ( 3600 * 24 ) );
$label = '';
if ($hr) {
if ($days >= 365) { // over a year
$years = floor($days / 365);
$label .= $years . ' Year(s)';
$days -= 365 * $years;
}
if ($days) {
$months = floor( $days / 30 );
$label .= ' ' . $months . ' Month(s)';
$days -= 30 * $months;
}
if ($days) {
$label .= ' ' . $days . ' day(s)';
}
} else {
$label = $days;
}
return $label;
}
}
$early_start_date = date2sql($_POST['early_leave_date']);
$date = new DateTime($early_start_date);
$date->modify('+1 day');
$date_a = new DateTime($early_start_date . ' ' . $_POST['start_hr'] . ':' . $_POST['start_mm']);
$date_b = new DateTime($date->format('Y-m-d') . ' ' . $_POST['end_hr'] . ':' . $_POST['end_mm']);
$interval = date_diff($date_a, $date_b);
$time = $interval->format('%h:%i');
$parsed = date_parse($time);
$seconds = $parsed['hour'] * 3600 + $parsed['minute'] * 60;
// display_error($seconds);
$second3 = $employee_information['shift'] * 60 * 60;
if ($second3 < $seconds)
display_error(_('Leave time can not be greater than shift time.Please try again........'));
set_focus('start_hr');
set_focus('end_hr');
return FALSE;
}
<?php
$date1=date_create("2013-03-15");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
echo $diff->format("%R%a days");
?>
used the above code very simple. Thanks.
function get_daydiff($end_date,$today)
{
if($today=='')
{
$today=date('Y-m-d');
}
$str = floor(strtotime($end_date)/(60*60*24)) - floor(strtotime($today)/(60*60*24));
return $str;
}
$d1 = "2018-12-31";
$d2 = "2018-06-06";
echo get_daydiff($d1, $d2);
Using this simple function. Declare function
<?php
function dateDiff($firstDate,$secondDate){
$firstDate = strtotime($firstDate);
$secondDate = strtotime($secondDate);
$datediff = $firstDate - $secondDate;
$output = round($datediff / (60 * 60 * 24));
return $output;
}
?>
and call this function like this where you want
<?php
echo dateDiff("2018-01-01","2018-12-31");
// OR
$firstDate = "2018-01-01";
$secondDate = "2018-01-01";
echo dateDiff($firstDate,$secondDate);
?>
// Change this to the day in the future
$day = 15;
// Change this to the month in the future
$month = 11;
// Change this to the year in the future
$year = 2012;
// $days is the number of days between now and the date in the future
$days = (int)((mktime (0,0,0,$month,$day,$year) - time(void))/86400);
echo "There are $days days until $day/$month/$year";
If you are using MySql
function daysSince($date, $date2){
$q = "SELECT DATEDIFF('$date','$date2') AS days;";
$result = execQ($q);
$row = mysql_fetch_array($result,MYSQL_BOTH);
return ($row[0]);
}
function execQ($q){
$result = mysql_query( $q);
if(!$result){echo ('Database error execQ' . mysql_error());echo $q;}
return $result;
}
Try using Carbon
$d1 = \Carbon\Carbon::now()->subDays(92);
$d2 = \Carbon\Carbon::now()->subDays(10);
$days_btw = $d1->diffInDays($d2);
Also you can use
\Carbon\Carbon::parse('')
to create an object of Carbon date using given timestamp string.