Related
How to find number of days between two dates using PHP?
$now = time(); // or your date as well
$your_date = strtotime("2010-01-31");
$datediff = $now - $your_date;
echo round($datediff / (60 * 60 * 24));
If you're using PHP 5.3 >, this is by far the most accurate way of calculating the absolute difference:
$earlier = new DateTime("2010-07-06");
$later = new DateTime("2010-07-09");
$abs_diff = $later->diff($earlier)->format("%a"); //3
If you need a relative (signed) number of days, use this instead:
$earlier = new DateTime("2010-07-06");
$later = new DateTime("2010-07-09");
$pos_diff = $earlier->diff($later)->format("%r%a"); //3
$neg_diff = $later->diff($earlier)->format("%r%a"); //-3
More on php's DateInterval format can be found here: https://www.php.net/manual/en/dateinterval.format.php
From PHP Version 5.3 and up, new date/time functions have been added to get difference:
$datetime1 = new DateTime("2010-06-20");
$datetime2 = new DateTime("2011-06-22");
$difference = $datetime1->diff($datetime2);
echo 'Difference: '.$difference->y.' years, '
.$difference->m.' months, '
.$difference->d.' days';
print_r($difference);
Result as below:
Difference: 1 years, 0 months, 2 days
DateInterval Object
(
[y] => 1
[m] => 0
[d] => 2
[h] => 0
[i] => 0
[s] => 0
[invert] => 0
[days] => 367
)
Hope it helps !
TL;DR do not use UNIX timestamps. Do not use time(). If you do, be prepared should its 98.0825% reliability fail you. Use DateTime (or Carbon).
The correct answer is the one given by Saksham Gupta (other answers are also correct):
$date1 = new DateTime('2010-07-06');
$date2 = new DateTime('2010-07-09');
$days = $date2->diff($date1)->format('%a');
Or procedurally as a one-liner:
/**
* Number of days between two dates.
*
* #param date $dt1 First date
* #param date $dt2 Second date
* #return int
*/
function daysBetween($dt1, $dt2) {
return date_diff(
date_create($dt2),
date_create($dt1)
)->format('%a');
}
With a caveat: the '%a' seems to indicate the absolute number of days. If you want it as a signed integer, i.e. negative when the second date is before the first, then you need to use the '%r' prefix (i.e. format('%r%a')).
If you really must use UNIX timestamps, set the time zone to GMT to avoid most of the pitfalls detailed below.
Long answer: why dividing by 24*60*60 (aka 86400) is unsafe
Most of the answers using UNIX timestamps (and 86400 to convert that to days) make two assumptions that, put together, can lead to scenarios with wrong results and subtle bugs that may be difficult to track, and arise even days, weeks or months after a successful deployment. It's not that the solution doesn't work - it works. Today. But it might stop working tomorrow.
First mistake is not considering that when asked, "How many days passed since yesterday?", a computer might truthfully answer zero if between the present and the instant indicated by "yesterday" less than one whole day has passed.
Usually when converting a "day" to a UNIX timestamp, what is obtained is the timestamp for the midnight of that particular day.
So between the midnights of October 1st and October 15th, fifteen days have elapsed. But between 13:00 of October 1st and 14:55 of October 15th, fifteen days minus 5 minutes have elapsed, and most solutions using floor() or doing implicit integer conversion will report one day less than expected.
So, "how many days ago was Y-m-d H:i:s"? will yield the wrong answer.
The second mistake is equating one day to 86400 seconds. This is almost always true - it happens often enough to overlook the times it doesn't. But the distance in seconds between two consecutive midnights is surely not 86400 at least twice a year when daylight saving time comes into play. Comparing two dates across a DST boundary will yield the wrong answer.
So even if you use the "hack" of forcing all date timestamps to a fixed hour, say midnight (this is also done implicitly by various languages and frameworks when you only specify day-month-year and not also hour-minute-second; same happens with DATE type in databases such as MySQL), the widely used formula
FLOOR((unix_timestamp(DATE2) - unix_timestamp(DATE1)) / 86400)
or
floor((time() - strtotime($somedate)) / 86400)
will return, say, 17 when DATE1 and DATE2 are in the same DST segment of the year; but even if the hour:minute:second part is identical, the argument might be 17.042, and worse still, 16.958 when they are in different DST segments and the time zone is DST-aware. The use of floor() or any implicit truncation to integer will then convert what should have been a 17 to a 16. In other circumstances, expressions like "$days > 17" will return true for 17.042, even if this will look as if the elapsed day count is 18.
And things grow even uglier since such code is not portable across platforms, because some of them may apply leap seconds and some might not. On those platforms that do, the difference between two dates will not be 86400 but 86401, or maybe 86399. So code that worked in May and actually passed all tests will break next June when 12.99999 days are considered 12 days instead of 13. Two dates that worked in 2015 will not work in 2017 -- the same dates, and neither year is a leap year. And between 2018-03-01 and 2017-03-01, on those platforms that care, 366 days will have passed instead of 365, making 2018 a leap year (which it is not).
So if you really want to use UNIX timestamps:
use round() function wisely, not floor().
as an alternative, do not calculate differences between D1-M1-YYY1 and D2-M2-YYY2. Those dates will be really considered as D1-M1-YYY1 00:00:00 and D2-M2-YYY2 00:00:00. Rather, convert between D1-M1-YYY1 22:30:00 and D2-M2-YYY2 04:30:00. You will always get a remainder of about twenty hours. This may become twenty-one hours or nineteen, and maybe eighteen hours, fifty-nine minutes thirty-six seconds. No matter. It is a large margin which will stay there and stay positive for the foreseeable future. Now you can truncate it with floor() in safety.
The correct solution though, to avoid magic constants, rounding kludges and a maintenance debt, is to
use a time library (Datetime, Carbon, whatever); don't roll your own
write comprehensive test cases using really evil date choices - across DST boundaries, across leap years, across leap seconds, and so on, as well as commonplace dates. Ideally (calls to datetime are fast!) generate four whole years' (and one day) worth of dates by assembling them from strings, sequentially, and ensure that the difference between the first day and the day being tested increases steadily by one. This will ensure that if anything changes in the low-level routines and leap seconds fixes try to wreak havoc, at least you will know.
run those tests regularly together with the rest of the test suite. They're a matter of milliseconds, and may save you literally hours of head scratching.
Whatever your solution, test it!
The function funcdiff below implements one of the solutions (as it happens, the accepted one) in a real world scenario.
<?php
$tz = 'Europe/Rome';
$yearFrom = 1980;
$yearTo = 2020;
$verbose = false;
function funcdiff($date2, $date1) {
$now = strtotime($date2);
$your_date = strtotime($date1);
$datediff = $now - $your_date;
return floor($datediff / (60 * 60 * 24));
}
########################################
date_default_timezone_set($tz);
$failures = 0;
$tests = 0;
$dom = array ( 0, 31, 28, 31, 30,
31, 30, 31, 31,
30, 31, 30, 31 );
(array_sum($dom) === 365) || die("Thirty days hath September...");
$last = array();
for ($year = $yearFrom; $year < $yearTo; $year++) {
$dom[2] = 28;
// Apply leap year rules.
if ($year % 4 === 0) { $dom[2] = 29; }
if ($year % 100 === 0) { $dom[2] = 28; }
if ($year % 400 === 0) { $dom[2] = 29; }
for ($month = 1; $month <= 12; $month ++) {
for ($day = 1; $day <= $dom[$month]; $day++) {
$date = sprintf("%04d-%02d-%02d", $year, $month, $day);
if (count($last) === 7) {
$tests ++;
$diff = funcdiff($date, $test = array_shift($last));
if ((double)$diff !== (double)7) {
$failures ++;
if ($verbose) {
print "There seem to be {$diff} days between {$date} and {$test}\n";
}
}
}
$last[] = $date;
}
}
}
print "This function failed {$failures} of its {$tests} tests";
print " between {$yearFrom} and {$yearTo}.\n";
The result is,
This function failed 280 of its 14603 tests
Horror Story: the cost of "saving time"
It all began in late 2014. An ingenious programmer decided to save several microseconds off a calculation that took about thirty seconds at most, by plugging in the infamous "(MidnightOfDateB-MidnightOfDateA)/86400" code in several places. It was so obvious an optimization that he did not even document it, and the optimization passed the integration tests and somehow lurked in the code for several months, all unnoticed.
This happened in a program that calculates the wages for several top-selling salesmen, the least of which has a frightful lot more clout than a whole humble five-people programmer team taken together. On March 28th, 2015, the summer time zone engaged, the bug struck -- and some of those guys got shortchanged one whole day of fat commissions. To make things worse, most of them did not work on Sundays and, being near the end of the month, used that day to catch up with their invoicing. They were definitely not amused.
Infinitely worse, they lost the (already very little) faith they had in the program not being designed to surreptitiously shaft them, and pretended - and obtained - a complete, detailed code review with test cases ran and commented in layman's terms (plus a lot of red-carpet treatment in the following weeks).
What can I say: on the plus side, we got rid of a lot of technical debt, and were able to rewrite and refactor several pieces of a spaghetti mess that hearkened back to a COBOL infestation in the swinging '90s. The program undoubtedly runs better now, and there's a lot more debugging information to quickly zero in when anything looks fishy. I estimate that just this last one thing will save perhaps one or two man-days per month for the foreseeable future, so the disaster will have a silver, or even golden, lining.
On the minus side, the whole brouhaha costed the company about €200,000 up front - plus face, plus undoubtedly some bargaining power (and, hence, yet more money).
The guy responsible for the "optimization" had changed job in December 2014, well before the disaster, but still there was talk to sue him for damages. And it didn't go well with the upper echelons that it was "the last guy's fault" - it looked like a set-up for us to come up clean of the matter, and in the end, we remained in the doghouse for the rest of the year, and one of the team resigned at the end of that summer.
Ninety-nine times out of one hundred, the "86400 hack" will work flawlessly. (For example in PHP, strtotime() will ignore DST, and report that between the midnights of the last Saturday of October and that of the following Monday, exactly 2 * 24 * 60 * 60 seconds have passed, even if that is plainly not true... and two wrongs will happily make one right).
This, ladies and gentlemen, was one instance when it did not. As with air-bags and seat belts, you will perhaps never really need the complexity (and ease of use) of DateTime or Carbon. But the day when you might (or the day when you'll have to prove you thought about this) will come as a thief in the night (likely at 02:00 some Sunday in October). Be prepared.
Convert your dates to unix timestamps, then substract one from the another. That will give you the difference in seconds, which you divide by 86400 (amount of seconds in a day) to give you an approximate amount of days in that range.
If your dates are in format 25.1.2010, 01/25/2010 or 2010-01-25, you can use the strtotime function:
$start = strtotime('2010-01-25');
$end = strtotime('2010-02-20');
$days_between = ceil(abs($end - $start) / 86400);
Using ceil rounds the amount of days up to the next full day. Use floor instead if you want to get the amount of full days between those two dates.
If your dates are already in unix timestamp format, you can skip the converting and just do the $days_between part. For more exotic date formats, you might have to do some custom parsing to get it right.
Easy to using date_diff
$from=date_create(date('Y-m-d'));
$to=date_create("2013-03-15");
$diff=date_diff($to,$from);
print_r($diff);
echo $diff->format('%R%a days');
See more at: https://blog.devgenius.io/how-to-find-the-number-of-days-between-two-dates-in-php-1404748b1e84
Object oriented style:
$datetime1 = new DateTime('2009-10-11');
$datetime2 = new DateTime('2009-10-13');
$interval = $datetime1->diff($datetime2);
echo $interval->format('%R%a days');
Procedural style:
$datetime1 = date_create('2009-10-11');
$datetime2 = date_create('2009-10-13');
$interval = date_diff($datetime1, $datetime2);
echo $interval->format('%R%a days');
Used this :)
$days = (strtotime($endDate) - strtotime($startDate)) / (60 * 60 * 24);
print $days;
Now it works
Well, the selected answer is not the most correct one because it will fail outside UTC.
Depending on the timezone (list) there could be time adjustments creating days "without" 24 hours, and this will make the calculation (60*60*24) fail.
Here it is an example of it:
date_default_timezone_set('europe/lisbon');
$time1 = strtotime('2016-03-27');
$time2 = strtotime('2016-03-29');
echo floor( ($time2-$time1) /(60*60*24));
^-- the output will be **1**
So the correct solution will be using DateTime
date_default_timezone_set('europe/lisbon');
$date1 = new DateTime("2016-03-27");
$date2 = new DateTime("2016-03-29");
echo $date2->diff($date1)->format("%a");
^-- the output will be **2**
You can find dates simply by
<?php
$start = date_create('1988-08-10');
$end = date_create(); // Current time and date
$diff = date_diff( $start, $end );
echo 'The difference is ';
echo $diff->y . ' years, ';
echo $diff->m . ' months, ';
echo $diff->d . ' days, ';
echo $diff->h . ' hours, ';
echo $diff->i . ' minutes, ';
echo $diff->s . ' seconds';
// Output: The difference is 28 years, 5 months, 19 days, 20 hours, 34 minutes, 36 seconds
echo 'The difference in days : ' . $diff->days;
// Output: The difference in days : 10398
Calculate the difference between two dates:
$date1=date_create("2013-03-15");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
echo $diff->format("%R%a days");
Output:
+272 days
The date_diff() function returns the difference between two DateTime objects.
$start = '2013-09-08';
$end = '2013-09-15';
$diff = (strtotime($end)- strtotime($start))/24/3600;
echo $diff;
I'm using Carbon in my composer projects for this and similar purposes.
It'd be as easy as this:
$dt = Carbon::parse('2010-01-01');
echo $dt->diffInDays(Carbon::now());
You can try the code below:
$dt1 = strtotime("2019-12-12"); //Enter your first date
$dt2 = strtotime("12-12-2020"); //Enter your second date
echo abs(($dt1 - $dt2) / (60 * 60 * 24));
number of days between two dates in PHP
function dateDiff($date1, $date2) //days find function
{
$diff = strtotime($date2) - strtotime($date1);
return abs(round($diff / 86400));
}
//start day
$date1 = "11-10-2018";
// end day
$date2 = "31-10-2018";
// call the days find fun store to variable
$dateDiff = dateDiff($date1, $date2);
echo "Difference between two dates: ". $dateDiff . " Days ";
If you have the times in seconds (I.E. unix time stamp) , then you can simply subtract the times and divide by 86400 (seconds per day)
$datediff = floor(strtotime($date1)/(60*60*24)) - floor(strtotime($date2)/(60*60*24));
and, if needed:
$datediff=abs($datediff);
Easiest way to find the days difference between two dates
$date1 = strtotime("2019-05-25");
$date2 = strtotime("2010-06-23");
$date_difference = $date2 - $date1;
$result = round( $date_difference / (60 * 60 * 24) );
echo $result;
$diff = strtotime('2019-11-25') - strtotime('2019-11-10');
echo abs(round($diff / 86400));
function howManyDays($startDate,$endDate) {
$date1 = strtotime($startDate." 0:00:00");
$date2 = strtotime($endDate." 23:59:59");
$res = (int)(($date2-$date1)/86400);
return $res;
}
If you want to echo all days between the start and end date, I came up with this :
$startdatum = $_POST['start']; // starting date
$einddatum = $_POST['eind']; // end date
$now = strtotime($startdatum);
$your_date = strtotime($einddatum);
$datediff = $your_date - $now;
$number = floor($datediff/(60*60*24));
for($i=0;$i <= $number; $i++)
{
echo date('d-m-Y' ,strtotime("+".$i." day"))."<br>";
}
This code worked for me and tested with PHP 8 version :
function numberOfDays($startDate, $endDate)
{
//1) converting dates to timestamps
$startSeconds = strtotime($startDate);
$endSeconds = strtotime($endDate);
//2) Calculating the difference in timestamps
$diffSeconds = $startSeconds - $endSeconds;
//3) converting timestamps to days
$days=round($diffSeconds / 86400);
/* note :
1 day = 24 hours
24 * 60 * 60 = 86400 seconds
*/
//4) printing the number of days
printf("Difference between two dates: ". abs($days) . " Days ");
return abs($days);
}
Here is my improved version which shows 1 Year(s) 2 Month(s) 25 day(s) if the 2nd parameter is passed.
class App_Sandbox_String_Util {
/**
* Usage: App_Sandbox_String_Util::getDateDiff();
* #param int $your_date timestamp
* #param bool $hr human readable. e.g. 1 year(s) 2 day(s)
* #see http://stackoverflow.com/questions/2040560/finding-the-number-of-days-between-two-dates
* #see http://qSandbox.com
*/
static public function getDateDiff($your_date, $hr = 0) {
$now = time(); // or your date as well
$datediff = $now - $your_date;
$days = floor( $datediff / ( 3600 * 24 ) );
$label = '';
if ($hr) {
if ($days >= 365) { // over a year
$years = floor($days / 365);
$label .= $years . ' Year(s)';
$days -= 365 * $years;
}
if ($days) {
$months = floor( $days / 30 );
$label .= ' ' . $months . ' Month(s)';
$days -= 30 * $months;
}
if ($days) {
$label .= ' ' . $days . ' day(s)';
}
} else {
$label = $days;
}
return $label;
}
}
$early_start_date = date2sql($_POST['early_leave_date']);
$date = new DateTime($early_start_date);
$date->modify('+1 day');
$date_a = new DateTime($early_start_date . ' ' . $_POST['start_hr'] . ':' . $_POST['start_mm']);
$date_b = new DateTime($date->format('Y-m-d') . ' ' . $_POST['end_hr'] . ':' . $_POST['end_mm']);
$interval = date_diff($date_a, $date_b);
$time = $interval->format('%h:%i');
$parsed = date_parse($time);
$seconds = $parsed['hour'] * 3600 + $parsed['minute'] * 60;
// display_error($seconds);
$second3 = $employee_information['shift'] * 60 * 60;
if ($second3 < $seconds)
display_error(_('Leave time can not be greater than shift time.Please try again........'));
set_focus('start_hr');
set_focus('end_hr');
return FALSE;
}
<?php
$date1=date_create("2013-03-15");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
echo $diff->format("%R%a days");
?>
used the above code very simple. Thanks.
function get_daydiff($end_date,$today)
{
if($today=='')
{
$today=date('Y-m-d');
}
$str = floor(strtotime($end_date)/(60*60*24)) - floor(strtotime($today)/(60*60*24));
return $str;
}
$d1 = "2018-12-31";
$d2 = "2018-06-06";
echo get_daydiff($d1, $d2);
Using this simple function. Declare function
<?php
function dateDiff($firstDate,$secondDate){
$firstDate = strtotime($firstDate);
$secondDate = strtotime($secondDate);
$datediff = $firstDate - $secondDate;
$output = round($datediff / (60 * 60 * 24));
return $output;
}
?>
and call this function like this where you want
<?php
echo dateDiff("2018-01-01","2018-12-31");
// OR
$firstDate = "2018-01-01";
$secondDate = "2018-01-01";
echo dateDiff($firstDate,$secondDate);
?>
// Change this to the day in the future
$day = 15;
// Change this to the month in the future
$month = 11;
// Change this to the year in the future
$year = 2012;
// $days is the number of days between now and the date in the future
$days = (int)((mktime (0,0,0,$month,$day,$year) - time(void))/86400);
echo "There are $days days until $day/$month/$year";
If you are using MySql
function daysSince($date, $date2){
$q = "SELECT DATEDIFF('$date','$date2') AS days;";
$result = execQ($q);
$row = mysql_fetch_array($result,MYSQL_BOTH);
return ($row[0]);
}
function execQ($q){
$result = mysql_query( $q);
if(!$result){echo ('Database error execQ' . mysql_error());echo $q;}
return $result;
}
Try using Carbon
$d1 = \Carbon\Carbon::now()->subDays(92);
$d2 = \Carbon\Carbon::now()->subDays(10);
$days_btw = $d1->diffInDays($d2);
Also you can use
\Carbon\Carbon::parse('')
to create an object of Carbon date using given timestamp string.
I have something like that for example: 01:06:22 this represents 1hour, 6minutes and 22seconds. I want to take that, and multiple it by 6 and add it to some other hour such as 04:23 which is 4AM and 23Minutes not 4hours and 23 minutes.
Basically, as a result I expect that:
01:06:22
* 6 = 6hours 38minutes canceling the remaining seconds which are 12 in this case
Now, I want to take that and append it to other hour, 04:23 in this case, so the result would be:
11:01.
I have no clue how to start and do it, unfortunately.
Any help is appriciated!
Clarifications
The time that I have to multiple by 6 will never exceed 2 hours.
All the times are in the same format.
With DateTime it is simple:
$time = '01:06:22';
$dateSeconds = new DateTime("1970-01-01 $time UTC");
$seconds = $dateSeconds->getTimestamp() * 6;
$interval = new DateInterval('PT'.$seconds.'S');
$date = new DateTime('1970-01-01 04:23:00 UTC');
$date->add($interval);
echo $date->format('H:i:s');
Other solution with strtotime and gmdate. (Similar to Suresh but working):
$date = strtotime('1970-01-01 01:06:22 UTC');
$add = strtotime('1970-01-01 04:23:00 UTC');
$date = (($date*6)+$add);
echo gmdate('H:i:s', $date);
This is a solution if you want to implement it yourself.
The thing about timecode is that it can become really heavy with the if the if conditions etc if you don't do it right.
The best Way I thought of to deal with this is to convert everything to second.
so 01:06:22 would become:
numberOfSecond = 22 + 06 * 60 + 01 * 60 * 60
How to get the 22, 06 etc from the String? You can use Regex.
What you will need:
a function to extract the different values (hours, minute, second)
a function to convert the timecode into second
a function to convert back into timecode
the functions to multiply, add etc...
You might want to create a class for it.
You can try like this:
$date = strtotime('01:06:22');
$add = strtotime('00:04:23');
$date = ($date*6)+$add;
echo date('H:i:s', $date);
Note: Code is not tested.
First of all you want to multiply a time span by a factor. The easiest way to do this is to convert the span to seconds and do a straight multiply:
$date =DateTime::createFromFormat('!H:i:s', '01:06:22', new DateTimeZone('UTC'));
$seconds = $date->getTimestamp();
This code works by pretending that the time is a moment during the Unix epoch start so that it can then get the number of seconds elapsed since the epoch (the timestamp). That number is equal to the duration of the time span in seconds. However, it is vitally important that the input is interpreted as UTC time and not as something in your local time zone.
An equivalent way of doing things (as long as the input is in the correct format) which is lower-tech but perhaps less prone to bugs would be
list($h, $m, $s) = explode(':', '01:06:22');
$seconds = $h * 3600 + $m * 60 + $s;
Now the multiplication:
$seconds = $seconds * 6;
If you want to only keep whole minutes from the time you can do so at this stage:
$seconds = $seconds - $seconds % 60;
The final step of adding the result to a given "time" is not clearly specified yet -- does the reference time contain date information? What happens if adding to it goes over 24 hours?
Self explanatory :
$initialTime = '01:06:22';
$timeToAdd = '04:23';
$initialTimeExploded = explode( ':' ,$initialTime );
$initialTimeInMintues = ( $initialTimeExploded[0] * 60 ) + $initialTimeExploded[1];
$initialTimeInMintuesMultipliedBySix = $initialTimeInMintues * 6;
$timeToAddExploded = explode( ':' ,$timeToAdd );
$timeToAddExplodedInMintues = ( $timeToAddExploded[0] * 60 ) + $timeToAddExploded[1];
$newTimeInMinutes = $initialTimeInMintuesMultipliedBySix + $timeToAddExplodedInMintues;
$newTime = floor( $newTimeInMinutes / 60 ) .':' .($newTimeInMinutes % 60);
echo $newTime;
Result :
10:59
Is there a painless way to convert unix timestamps, MySQL timestamps, MySQL datetimes (or any other standard date and time format) into strings in the following form:
Today, 6:00pm
Tomorrow, 12:30pm
Wednesday, 4:00pm
Next friday, 11:00am
I'm not sure what to call these - I guess conversational-style, current time sensitive date formats?
As best I can tell, there is no native function for this. I have created (the start of) a function to do what you are wanting.
function timeToString( $inTimestamp ) {
$now = time();
if( abs( $inTimestamp-$now )<86400 ) {
$t = date('g:ia',$inTimestamp);
if( date('zY',$now)==date('zY',$inTimestamp) )
return 'Today, '.$t;
if( $inTimestamp>$now )
return 'Tomorrow, '.$t;
return 'Yesterday, '.$t;
}
if( ( $inTimestamp-$now )>0 ) {
if( $inTimestamp-$now < 604800 ) # Within the next 7 days
return date( 'l, g:ia' , $inTimestamp );
if( $inTimestamp-$now < 1209600 ) # Within the next 14, but after the next 7 days
return 'Next '.date( 'l, g:ia' , $inTimestamp );
} else {
if( $now-$inTimestamp < 604800 ) # Within the last 7 days
return 'Last '.date( 'l, g:ia' , $inTimestamp );
}
# Some other day
return date( 'l jS F, g:ia' , $inTimestamp );
}
Hope that helps.
You should read the docs for strftime and strtotime
An example of converting UNIX timestamp to your format:
$time = time(); // UNIX timestamp for current time
echo strftime("%A, %l:%M %P"); // "Thursday, 12:41 pm"
To get a MySQL datetime value, assuming it comes out of the database as "2010-07-15 12:42:34", try this:
$time = "2010-07-15 12:42:34";
echo strftime("%A, %l:%M %P"); // "Thursday, 12:42 pm"
Now, in order to print the word "today" instead of the day name you will have to do some additional logic to check if the date is today:
$time = "2010-07-15 12:42:34";
$today = strftime("%Y-%m-%d");
// compare if $time strftime's to the same date as $today
if(strftime("%Y-%m-%d", $time) == $today) {
echo strftime("Today, %l:%M %P", $time);
} else {
echo strftime("%A, %l:%M %P", $time);
}
The strtotime shoule be useful for that.
Example:
echo date('d, h:i:sa', strtotime($date_orig));
PHP date funcs are kind of messy because they have so many different ways, and even new classes were built over the old ones. For that type of formatting, what I call human-friendly formatting, you're going to have to write your own function that does it.
For conversion, you can use strtotime() as mentioned, but if you're dealing with epoch times and need utc GMT times, heres some functions for that. strtotime() would convert the epoch time to the local server time... this was something I don't want on my projects.
/**
* Converts a GMT date in UTC format (ie. 2010-05-05 12:00:00)
* Into the GMT epoch equivilent
* The reason why this doesnt work: strtotime("2010-05-05 12:00:00")
* Is because strtotime() takes the servers timezone into account
*/
function utc2epoch($str_date)
{
$time = strtotime($str_date);
//now subtract timezone from it
return strtotime(date("Z")." sec", $time);
}
function epoch2utc($epochtime, $timezone="GMT")
{
$d=gmt2timezone($epochtime, $timezone);
return $d->format('Y-m-d H:i:s');
}
If you are pulling this type of data out of your database
$time = "2010-07-15 12:42:34";
then do this
$this->db->select('DATE_FORMAT(date, "%b %D %Y")AS date');
Look here for info to display your data any way you want in human form
http://www.w3schools.com/SQL/func_date_format.asp
The above code is in codeigniter format, but you can just convert it to a SELECT statement for MYSQL
$query = "SELECT `title`,`post`, DATE_FORMAT(date, "%a, %d %b %Y %T") AS date FROM `posts` LIMIT 0, 8 ";
You will want to change the %a letters to fit your needs.
you will get exact result::
output // 28 years 7 months 7 days
function getAge(dateVal) {
var
birthday = new Date(dateVal.value),
today = new Date(),
ageInMilliseconds = new Date(today - birthday),
years = ageInMilliseconds / (24 * 60 * 60 * 1000 * 365.25 ),
months = 12 * (years % 1),
days = Math.floor(30 * (months % 1));
return Math.floor(years) + ' years ' + Math.floor(months) + ' months ' + days + ' days';
}
How to find number of days between two dates using PHP?
$now = time(); // or your date as well
$your_date = strtotime("2010-01-31");
$datediff = $now - $your_date;
echo round($datediff / (60 * 60 * 24));
If you're using PHP 5.3 >, this is by far the most accurate way of calculating the absolute difference:
$earlier = new DateTime("2010-07-06");
$later = new DateTime("2010-07-09");
$abs_diff = $later->diff($earlier)->format("%a"); //3
If you need a relative (signed) number of days, use this instead:
$earlier = new DateTime("2010-07-06");
$later = new DateTime("2010-07-09");
$pos_diff = $earlier->diff($later)->format("%r%a"); //3
$neg_diff = $later->diff($earlier)->format("%r%a"); //-3
More on php's DateInterval format can be found here: https://www.php.net/manual/en/dateinterval.format.php
From PHP Version 5.3 and up, new date/time functions have been added to get difference:
$datetime1 = new DateTime("2010-06-20");
$datetime2 = new DateTime("2011-06-22");
$difference = $datetime1->diff($datetime2);
echo 'Difference: '.$difference->y.' years, '
.$difference->m.' months, '
.$difference->d.' days';
print_r($difference);
Result as below:
Difference: 1 years, 0 months, 2 days
DateInterval Object
(
[y] => 1
[m] => 0
[d] => 2
[h] => 0
[i] => 0
[s] => 0
[invert] => 0
[days] => 367
)
Hope it helps !
TL;DR do not use UNIX timestamps. Do not use time(). If you do, be prepared should its 98.0825% reliability fail you. Use DateTime (or Carbon).
The correct answer is the one given by Saksham Gupta (other answers are also correct):
$date1 = new DateTime('2010-07-06');
$date2 = new DateTime('2010-07-09');
$days = $date2->diff($date1)->format('%a');
Or procedurally as a one-liner:
/**
* Number of days between two dates.
*
* #param date $dt1 First date
* #param date $dt2 Second date
* #return int
*/
function daysBetween($dt1, $dt2) {
return date_diff(
date_create($dt2),
date_create($dt1)
)->format('%a');
}
With a caveat: the '%a' seems to indicate the absolute number of days. If you want it as a signed integer, i.e. negative when the second date is before the first, then you need to use the '%r' prefix (i.e. format('%r%a')).
If you really must use UNIX timestamps, set the time zone to GMT to avoid most of the pitfalls detailed below.
Long answer: why dividing by 24*60*60 (aka 86400) is unsafe
Most of the answers using UNIX timestamps (and 86400 to convert that to days) make two assumptions that, put together, can lead to scenarios with wrong results and subtle bugs that may be difficult to track, and arise even days, weeks or months after a successful deployment. It's not that the solution doesn't work - it works. Today. But it might stop working tomorrow.
First mistake is not considering that when asked, "How many days passed since yesterday?", a computer might truthfully answer zero if between the present and the instant indicated by "yesterday" less than one whole day has passed.
Usually when converting a "day" to a UNIX timestamp, what is obtained is the timestamp for the midnight of that particular day.
So between the midnights of October 1st and October 15th, fifteen days have elapsed. But between 13:00 of October 1st and 14:55 of October 15th, fifteen days minus 5 minutes have elapsed, and most solutions using floor() or doing implicit integer conversion will report one day less than expected.
So, "how many days ago was Y-m-d H:i:s"? will yield the wrong answer.
The second mistake is equating one day to 86400 seconds. This is almost always true - it happens often enough to overlook the times it doesn't. But the distance in seconds between two consecutive midnights is surely not 86400 at least twice a year when daylight saving time comes into play. Comparing two dates across a DST boundary will yield the wrong answer.
So even if you use the "hack" of forcing all date timestamps to a fixed hour, say midnight (this is also done implicitly by various languages and frameworks when you only specify day-month-year and not also hour-minute-second; same happens with DATE type in databases such as MySQL), the widely used formula
FLOOR((unix_timestamp(DATE2) - unix_timestamp(DATE1)) / 86400)
or
floor((time() - strtotime($somedate)) / 86400)
will return, say, 17 when DATE1 and DATE2 are in the same DST segment of the year; but even if the hour:minute:second part is identical, the argument might be 17.042, and worse still, 16.958 when they are in different DST segments and the time zone is DST-aware. The use of floor() or any implicit truncation to integer will then convert what should have been a 17 to a 16. In other circumstances, expressions like "$days > 17" will return true for 17.042, even if this will look as if the elapsed day count is 18.
And things grow even uglier since such code is not portable across platforms, because some of them may apply leap seconds and some might not. On those platforms that do, the difference between two dates will not be 86400 but 86401, or maybe 86399. So code that worked in May and actually passed all tests will break next June when 12.99999 days are considered 12 days instead of 13. Two dates that worked in 2015 will not work in 2017 -- the same dates, and neither year is a leap year. And between 2018-03-01 and 2017-03-01, on those platforms that care, 366 days will have passed instead of 365, making 2018 a leap year (which it is not).
So if you really want to use UNIX timestamps:
use round() function wisely, not floor().
as an alternative, do not calculate differences between D1-M1-YYY1 and D2-M2-YYY2. Those dates will be really considered as D1-M1-YYY1 00:00:00 and D2-M2-YYY2 00:00:00. Rather, convert between D1-M1-YYY1 22:30:00 and D2-M2-YYY2 04:30:00. You will always get a remainder of about twenty hours. This may become twenty-one hours or nineteen, and maybe eighteen hours, fifty-nine minutes thirty-six seconds. No matter. It is a large margin which will stay there and stay positive for the foreseeable future. Now you can truncate it with floor() in safety.
The correct solution though, to avoid magic constants, rounding kludges and a maintenance debt, is to
use a time library (Datetime, Carbon, whatever); don't roll your own
write comprehensive test cases using really evil date choices - across DST boundaries, across leap years, across leap seconds, and so on, as well as commonplace dates. Ideally (calls to datetime are fast!) generate four whole years' (and one day) worth of dates by assembling them from strings, sequentially, and ensure that the difference between the first day and the day being tested increases steadily by one. This will ensure that if anything changes in the low-level routines and leap seconds fixes try to wreak havoc, at least you will know.
run those tests regularly together with the rest of the test suite. They're a matter of milliseconds, and may save you literally hours of head scratching.
Whatever your solution, test it!
The function funcdiff below implements one of the solutions (as it happens, the accepted one) in a real world scenario.
<?php
$tz = 'Europe/Rome';
$yearFrom = 1980;
$yearTo = 2020;
$verbose = false;
function funcdiff($date2, $date1) {
$now = strtotime($date2);
$your_date = strtotime($date1);
$datediff = $now - $your_date;
return floor($datediff / (60 * 60 * 24));
}
########################################
date_default_timezone_set($tz);
$failures = 0;
$tests = 0;
$dom = array ( 0, 31, 28, 31, 30,
31, 30, 31, 31,
30, 31, 30, 31 );
(array_sum($dom) === 365) || die("Thirty days hath September...");
$last = array();
for ($year = $yearFrom; $year < $yearTo; $year++) {
$dom[2] = 28;
// Apply leap year rules.
if ($year % 4 === 0) { $dom[2] = 29; }
if ($year % 100 === 0) { $dom[2] = 28; }
if ($year % 400 === 0) { $dom[2] = 29; }
for ($month = 1; $month <= 12; $month ++) {
for ($day = 1; $day <= $dom[$month]; $day++) {
$date = sprintf("%04d-%02d-%02d", $year, $month, $day);
if (count($last) === 7) {
$tests ++;
$diff = funcdiff($date, $test = array_shift($last));
if ((double)$diff !== (double)7) {
$failures ++;
if ($verbose) {
print "There seem to be {$diff} days between {$date} and {$test}\n";
}
}
}
$last[] = $date;
}
}
}
print "This function failed {$failures} of its {$tests} tests";
print " between {$yearFrom} and {$yearTo}.\n";
The result is,
This function failed 280 of its 14603 tests
Horror Story: the cost of "saving time"
It all began in late 2014. An ingenious programmer decided to save several microseconds off a calculation that took about thirty seconds at most, by plugging in the infamous "(MidnightOfDateB-MidnightOfDateA)/86400" code in several places. It was so obvious an optimization that he did not even document it, and the optimization passed the integration tests and somehow lurked in the code for several months, all unnoticed.
This happened in a program that calculates the wages for several top-selling salesmen, the least of which has a frightful lot more clout than a whole humble five-people programmer team taken together. On March 28th, 2015, the summer time zone engaged, the bug struck -- and some of those guys got shortchanged one whole day of fat commissions. To make things worse, most of them did not work on Sundays and, being near the end of the month, used that day to catch up with their invoicing. They were definitely not amused.
Infinitely worse, they lost the (already very little) faith they had in the program not being designed to surreptitiously shaft them, and pretended - and obtained - a complete, detailed code review with test cases ran and commented in layman's terms (plus a lot of red-carpet treatment in the following weeks).
What can I say: on the plus side, we got rid of a lot of technical debt, and were able to rewrite and refactor several pieces of a spaghetti mess that hearkened back to a COBOL infestation in the swinging '90s. The program undoubtedly runs better now, and there's a lot more debugging information to quickly zero in when anything looks fishy. I estimate that just this last one thing will save perhaps one or two man-days per month for the foreseeable future, so the disaster will have a silver, or even golden, lining.
On the minus side, the whole brouhaha costed the company about €200,000 up front - plus face, plus undoubtedly some bargaining power (and, hence, yet more money).
The guy responsible for the "optimization" had changed job in December 2014, well before the disaster, but still there was talk to sue him for damages. And it didn't go well with the upper echelons that it was "the last guy's fault" - it looked like a set-up for us to come up clean of the matter, and in the end, we remained in the doghouse for the rest of the year, and one of the team resigned at the end of that summer.
Ninety-nine times out of one hundred, the "86400 hack" will work flawlessly. (For example in PHP, strtotime() will ignore DST, and report that between the midnights of the last Saturday of October and that of the following Monday, exactly 2 * 24 * 60 * 60 seconds have passed, even if that is plainly not true... and two wrongs will happily make one right).
This, ladies and gentlemen, was one instance when it did not. As with air-bags and seat belts, you will perhaps never really need the complexity (and ease of use) of DateTime or Carbon. But the day when you might (or the day when you'll have to prove you thought about this) will come as a thief in the night (likely at 02:00 some Sunday in October). Be prepared.
Convert your dates to unix timestamps, then substract one from the another. That will give you the difference in seconds, which you divide by 86400 (amount of seconds in a day) to give you an approximate amount of days in that range.
If your dates are in format 25.1.2010, 01/25/2010 or 2010-01-25, you can use the strtotime function:
$start = strtotime('2010-01-25');
$end = strtotime('2010-02-20');
$days_between = ceil(abs($end - $start) / 86400);
Using ceil rounds the amount of days up to the next full day. Use floor instead if you want to get the amount of full days between those two dates.
If your dates are already in unix timestamp format, you can skip the converting and just do the $days_between part. For more exotic date formats, you might have to do some custom parsing to get it right.
Easy to using date_diff
$from=date_create(date('Y-m-d'));
$to=date_create("2013-03-15");
$diff=date_diff($to,$from);
print_r($diff);
echo $diff->format('%R%a days');
See more at: https://blog.devgenius.io/how-to-find-the-number-of-days-between-two-dates-in-php-1404748b1e84
Object oriented style:
$datetime1 = new DateTime('2009-10-11');
$datetime2 = new DateTime('2009-10-13');
$interval = $datetime1->diff($datetime2);
echo $interval->format('%R%a days');
Procedural style:
$datetime1 = date_create('2009-10-11');
$datetime2 = date_create('2009-10-13');
$interval = date_diff($datetime1, $datetime2);
echo $interval->format('%R%a days');
Used this :)
$days = (strtotime($endDate) - strtotime($startDate)) / (60 * 60 * 24);
print $days;
Now it works
Well, the selected answer is not the most correct one because it will fail outside UTC.
Depending on the timezone (list) there could be time adjustments creating days "without" 24 hours, and this will make the calculation (60*60*24) fail.
Here it is an example of it:
date_default_timezone_set('europe/lisbon');
$time1 = strtotime('2016-03-27');
$time2 = strtotime('2016-03-29');
echo floor( ($time2-$time1) /(60*60*24));
^-- the output will be **1**
So the correct solution will be using DateTime
date_default_timezone_set('europe/lisbon');
$date1 = new DateTime("2016-03-27");
$date2 = new DateTime("2016-03-29");
echo $date2->diff($date1)->format("%a");
^-- the output will be **2**
You can find dates simply by
<?php
$start = date_create('1988-08-10');
$end = date_create(); // Current time and date
$diff = date_diff( $start, $end );
echo 'The difference is ';
echo $diff->y . ' years, ';
echo $diff->m . ' months, ';
echo $diff->d . ' days, ';
echo $diff->h . ' hours, ';
echo $diff->i . ' minutes, ';
echo $diff->s . ' seconds';
// Output: The difference is 28 years, 5 months, 19 days, 20 hours, 34 minutes, 36 seconds
echo 'The difference in days : ' . $diff->days;
// Output: The difference in days : 10398
Calculate the difference between two dates:
$date1=date_create("2013-03-15");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
echo $diff->format("%R%a days");
Output:
+272 days
The date_diff() function returns the difference between two DateTime objects.
$start = '2013-09-08';
$end = '2013-09-15';
$diff = (strtotime($end)- strtotime($start))/24/3600;
echo $diff;
I'm using Carbon in my composer projects for this and similar purposes.
It'd be as easy as this:
$dt = Carbon::parse('2010-01-01');
echo $dt->diffInDays(Carbon::now());
You can try the code below:
$dt1 = strtotime("2019-12-12"); //Enter your first date
$dt2 = strtotime("12-12-2020"); //Enter your second date
echo abs(($dt1 - $dt2) / (60 * 60 * 24));
number of days between two dates in PHP
function dateDiff($date1, $date2) //days find function
{
$diff = strtotime($date2) - strtotime($date1);
return abs(round($diff / 86400));
}
//start day
$date1 = "11-10-2018";
// end day
$date2 = "31-10-2018";
// call the days find fun store to variable
$dateDiff = dateDiff($date1, $date2);
echo "Difference between two dates: ". $dateDiff . " Days ";
If you have the times in seconds (I.E. unix time stamp) , then you can simply subtract the times and divide by 86400 (seconds per day)
$datediff = floor(strtotime($date1)/(60*60*24)) - floor(strtotime($date2)/(60*60*24));
and, if needed:
$datediff=abs($datediff);
Easiest way to find the days difference between two dates
$date1 = strtotime("2019-05-25");
$date2 = strtotime("2010-06-23");
$date_difference = $date2 - $date1;
$result = round( $date_difference / (60 * 60 * 24) );
echo $result;
$diff = strtotime('2019-11-25') - strtotime('2019-11-10');
echo abs(round($diff / 86400));
function howManyDays($startDate,$endDate) {
$date1 = strtotime($startDate." 0:00:00");
$date2 = strtotime($endDate." 23:59:59");
$res = (int)(($date2-$date1)/86400);
return $res;
}
If you want to echo all days between the start and end date, I came up with this :
$startdatum = $_POST['start']; // starting date
$einddatum = $_POST['eind']; // end date
$now = strtotime($startdatum);
$your_date = strtotime($einddatum);
$datediff = $your_date - $now;
$number = floor($datediff/(60*60*24));
for($i=0;$i <= $number; $i++)
{
echo date('d-m-Y' ,strtotime("+".$i." day"))."<br>";
}
This code worked for me and tested with PHP 8 version :
function numberOfDays($startDate, $endDate)
{
//1) converting dates to timestamps
$startSeconds = strtotime($startDate);
$endSeconds = strtotime($endDate);
//2) Calculating the difference in timestamps
$diffSeconds = $startSeconds - $endSeconds;
//3) converting timestamps to days
$days=round($diffSeconds / 86400);
/* note :
1 day = 24 hours
24 * 60 * 60 = 86400 seconds
*/
//4) printing the number of days
printf("Difference between two dates: ". abs($days) . " Days ");
return abs($days);
}
Here is my improved version which shows 1 Year(s) 2 Month(s) 25 day(s) if the 2nd parameter is passed.
class App_Sandbox_String_Util {
/**
* Usage: App_Sandbox_String_Util::getDateDiff();
* #param int $your_date timestamp
* #param bool $hr human readable. e.g. 1 year(s) 2 day(s)
* #see http://stackoverflow.com/questions/2040560/finding-the-number-of-days-between-two-dates
* #see http://qSandbox.com
*/
static public function getDateDiff($your_date, $hr = 0) {
$now = time(); // or your date as well
$datediff = $now - $your_date;
$days = floor( $datediff / ( 3600 * 24 ) );
$label = '';
if ($hr) {
if ($days >= 365) { // over a year
$years = floor($days / 365);
$label .= $years . ' Year(s)';
$days -= 365 * $years;
}
if ($days) {
$months = floor( $days / 30 );
$label .= ' ' . $months . ' Month(s)';
$days -= 30 * $months;
}
if ($days) {
$label .= ' ' . $days . ' day(s)';
}
} else {
$label = $days;
}
return $label;
}
}
$early_start_date = date2sql($_POST['early_leave_date']);
$date = new DateTime($early_start_date);
$date->modify('+1 day');
$date_a = new DateTime($early_start_date . ' ' . $_POST['start_hr'] . ':' . $_POST['start_mm']);
$date_b = new DateTime($date->format('Y-m-d') . ' ' . $_POST['end_hr'] . ':' . $_POST['end_mm']);
$interval = date_diff($date_a, $date_b);
$time = $interval->format('%h:%i');
$parsed = date_parse($time);
$seconds = $parsed['hour'] * 3600 + $parsed['minute'] * 60;
// display_error($seconds);
$second3 = $employee_information['shift'] * 60 * 60;
if ($second3 < $seconds)
display_error(_('Leave time can not be greater than shift time.Please try again........'));
set_focus('start_hr');
set_focus('end_hr');
return FALSE;
}
<?php
$date1=date_create("2013-03-15");
$date2=date_create("2013-12-12");
$diff=date_diff($date1,$date2);
echo $diff->format("%R%a days");
?>
used the above code very simple. Thanks.
function get_daydiff($end_date,$today)
{
if($today=='')
{
$today=date('Y-m-d');
}
$str = floor(strtotime($end_date)/(60*60*24)) - floor(strtotime($today)/(60*60*24));
return $str;
}
$d1 = "2018-12-31";
$d2 = "2018-06-06";
echo get_daydiff($d1, $d2);
Using this simple function. Declare function
<?php
function dateDiff($firstDate,$secondDate){
$firstDate = strtotime($firstDate);
$secondDate = strtotime($secondDate);
$datediff = $firstDate - $secondDate;
$output = round($datediff / (60 * 60 * 24));
return $output;
}
?>
and call this function like this where you want
<?php
echo dateDiff("2018-01-01","2018-12-31");
// OR
$firstDate = "2018-01-01";
$secondDate = "2018-01-01";
echo dateDiff($firstDate,$secondDate);
?>
// Change this to the day in the future
$day = 15;
// Change this to the month in the future
$month = 11;
// Change this to the year in the future
$year = 2012;
// $days is the number of days between now and the date in the future
$days = (int)((mktime (0,0,0,$month,$day,$year) - time(void))/86400);
echo "There are $days days until $day/$month/$year";
If you are using MySql
function daysSince($date, $date2){
$q = "SELECT DATEDIFF('$date','$date2') AS days;";
$result = execQ($q);
$row = mysql_fetch_array($result,MYSQL_BOTH);
return ($row[0]);
}
function execQ($q){
$result = mysql_query( $q);
if(!$result){echo ('Database error execQ' . mysql_error());echo $q;}
return $result;
}
Try using Carbon
$d1 = \Carbon\Carbon::now()->subDays(92);
$d2 = \Carbon\Carbon::now()->subDays(10);
$days_btw = $d1->diffInDays($d2);
Also you can use
\Carbon\Carbon::parse('')
to create an object of Carbon date using given timestamp string.
2009-10-05 18:11:08
2009-10-05 18:07:13
This should generate 235,how to do it ?
With DateTime objects, you can do it like this:
$date = new DateTime( '2009-10-05 18:07:13' );
$date2 = new DateTime( '2009-10-05 18:11:08' );
$diffInSeconds = $date2->getTimestamp() - $date->getTimestamp();
You can use strtotime() to do that:
$diff = strtotime('2009-10-05 18:11:08') - strtotime('2009-10-05 18:07:13')
A similar approach is possible with DateTime objects, e.g.
$date = new DateTime( '2009-10-05 18:07:13' );
$date2 = new DateTime( '2009-10-05 18:11:08' );
$diff = $date2->getTimestamp() - $date->getTimestamp();
PHP Date Time reference is helpful for things like this: PHP Date Time Functions
strtotime() is probably the best way.
$seconds = strtotime('2009-10-05 18:11:08') - strtotime('2009-10-05 18:07:13')
For those worrying about the limitations of using timestamps (i.e. using dates before 1970 and beyond 2038), you can simply calculate the difference in seconds like so:
$start = new DateTime('2009-10-05 18:11:08');
$end = new DateTime('2009-10-05 18:07:13');
$diff = $end->diff($start);
$daysInSecs = $diff->format('%r%a') * 24 * 60 * 60;
$hoursInSecs = $diff->h * 60 * 60;
$minsInSecs = $diff->i * 60;
$seconds = $daysInSecs + $hoursInSecs + $minsInSecs + $diff->s;
echo $seconds; // output: 235
Wrote a blog post for those interested in reading more.
Because of unix epoch limitations, you could have problems compairing dates before 1970 and after 2038. I choose to loose precision (=don't look at the single second) but avoid to pass trough unix epoch conversions (getTimestamp). It depends on what you are doing to do...
In my case, using 365 instead (12*30) and "30" as mean month lenght, reduced the error in an usable output.
function DateIntervalToSec($start,$end){ // as datetime object returns difference in seconds
$diff = $end->diff($start);
$diff_sec = $diff->format('%r').( // prepend the sign - if negative, change it to R if you want the +, too
($diff->s)+ // seconds (no errors)
(60*($diff->i))+ // minutes (no errors)
(60*60*($diff->h))+ // hours (no errors)
(24*60*60*($diff->d))+ // days (no errors)
(30*24*60*60*($diff->m))+ // months (???)
(365*24*60*60*($diff->y)) // years (???)
);
return $diff_sec;
}
Note that the error could be 0, if "mean" quantities are intended for diff. The PHP docs don't speaks about this...
In a bad case, error could be:
0 seconds if diff is applied to time gaps < 1 month
0 to 3 days if diff is applied to time gaps > 1 month
0 to 14 days if diff is applied to time gaps > 1 year
I prefer to suppose that somebody decided to consider "m" as 30 days and "y" as 365, charging "d" with the difference when "diff" walk trough non-30-days months...
If somebody knows something more about this and can provide official documentation, is welcome!
strtotime("2009-10-05 18:11:08") - strtotime("2009-10-05 18:07:13")
The solution proposed by #designcise is wrong when "end date" is before "start date".
Here is the corrected calculation
$diff = $start->diff($end);
$daysInSecs = $diff->format('%r%a') * 24 * 60 * 60;
$hoursInSecs = $diff->format('%r%h') * 60 * 60;
$minsInSecs = $diff->format('%r%i') * 60;
$seconds = $daysInSecs + $hoursInSecs + $minsInSecs + $diff->format('%r%s');
A simple and exact solution (exemplifying Nilz11's comment):
$hiDate = new DateTime("2310-05-22 08:33:26");
$loDate = new DateTime("1910-11-03 13:00:01");
$diff = $hiDate->diff($loDate);
$secs = ((($diff->format("%a") * 24) + $diff->format("%H")) * 60 +
$diff->format("%i")) * 60 + $diff->format("%s");