Passing models in array format to views in YII - php

How can I pass the model in array format.
I want to pass models in this format from controller to view:-
Users[user_contact]=Contact
Users[user_contact][contat_city]=City
Users[user_contact][contact_state]=state
This is what I am doing
public function actionCreate() {
$user = new Users;
$presContact = new Contacts;
$presCity = new Cities;
$presState = new States;
$contactArr = array();
// Uncomment the following line if AJAX validation is needed
// $this->performAjaxValidation($model);
if (isset($_POST['Users'])) {
$transaction = CActiveRecord::getDBConnection()->beginTransaction();
$contactArr = CommonFunctions::saveContact($_POST['Users']['user_pres_contact'],'user_pres_contact',$errorArr);
$presContact = $contactArr['contact'];
$presCity = $contactArr['city'];
$presState = $contactArr['state'];
$user->attributes = $_POST['Users'];
$user->user_pres_contact_id = $presContact->contact_id;
if($user->save()){
$transaction->commit();
$this->redirect(array('view', 'id' => $user->user_id));
} else {
$transaction->rollback();
}
}
$this->render('createUser', array(
'Users' => $user,
'Users[\'user_pres_contact\']'=>$presContact,
'Users[\'user_pres_contact\'][\'contact_city\']'=>$presCity,
'Users[\'user_pres_contact\'][\'contact_state\']'=>$presState,
));
}
I am able to access only $users but
I m not able to access $Users['user_pres_contact'] in the view

That's because you are assigning them as strings...
The correct way of doing things would be (btw, what you are asking for can't done literally, it is impossible to assign 2 values to one key):
$user = array(
'user_press_contact' => array(
'contact' => $presContact,
'city' => $presCity,
'state' => $presState,
),
);
$this->render('createUser', array(
'Users' => $user,
));
It will give you $Users['user_press_contact']['contact'] for the name in the view, etc.

You can use
$user->getAttributes() //it returns an array of data.
Hope that's usefull

It is possible to solve this using model relations? You can define a relation from the User model to the City model (e.g. naming it relation_to_city), then you can just assign the user model in the controller
$this->render('view', 'user'=>$user);
and access the city (from the view)
$user->relation_to_city

Related

How can I save model and related models at the same time in Laravel?

My current version below, its work but in my code; first I save the model and after the related model.
// Model
$pdf= new Canvas;
$pdf->numero = $data['number'];
$pdf->project = $data['title'];
$pdf->date = $data['date'];
$pdf->user_id = auth()->id();
$pdf->type = 'type1';
// Related model
$version = new Version;
$version->json = 'teste2.json';
$version->version = 1;
$version->updated_by = auth()->id();
//persist
$canvas->save();
$canvas->versions()->save($version);
What I need is:
how to save both model at the same time?
Create model
Create related model
Persist both model (related model get automatically the model_id)
if any problem happened, both model will not crated.
thanks so much
you can user this
$pdf = Canvas::create([
'numero' => $data['number'],
'project' => $data['title'],
'date' => $data['date'],
...
]);
$pdf->versions()->create([
'json' => 'teste2.json',
'version' => 1,
....
]);

Laravel and a While Loop

I'm new to Laravel and at the moment I have a piece of code in a Controller which without the while loop it works, it retrieves my query from the database.
public function dash($id, Request $request) {
$user = JWTAuth::parseToken()->authenticate();
$postdata = $request->except('token');
$q = DB::select('SELECT * FROM maps WHERE user_id = :id', ['id' => $id]);
if($q->num_rows > 0){
$check = true;
$maps = array();
while($row = mysqli_fetch_array($q)) {
$product = array(
'auth' => 1,
'id' => $row['id'],
'url' => $row['url'],
'locationData' => json_decode($row['locationData']),
'userData' => json_decode($row['userData']),
'visible' => $row['visible'],
'thedate' => $row['thedate']
);
array_push($maps, $product);
}
} else {
$check = false;
}
return response()->json($maps);
}
I am trying to loop through the returned data from $q and use json_decode on 2 key/val pairs but I can't even get this done right.
Don't use mysqli to iterate over the results (Laravel doesn't use mysqli). Results coming back from Laravel's query builder are Traversable, so you can simply use a foreach loop:
$q = DB::select('...');
foreach($q as $row) {
// ...
}
Each $row is going to be an object and not an array:
$product = array(
'auth' => 1,
'id' => $row->id,
'url' => $row->url,
'locationData' => json_decode($row->locationData),
'userData' => json_decode($row->userData),
'visible' => $row->visible,
'thedate' => $row->thedate
);
You're not using $postdata in that function so remove it.
Do not use mysqli in Laravel. Use models and/or the DB query functionality built in.
You're passing the wrong thing to mysqli_fetch_array. It's always returning a non-false value and that's why the loop never ends.
Why are you looping over the row data? Just return the query results-- they're already an array. If you want things like 'locationData' and 'userData' to be decoded JSON then use a model with methods to do this stuff for you. Remember, with MVC you should always put anything data related into models.
So a better way to do this is with Laravel models and relationships:
// put this with the rest of your models
// User.php
class User extends Model
{
function maps ()
{
return $this->hasMany ('App\Map');
}
}
// Maps.php
class Map extends Model
{
// you're not using this right now, but in case your view needs to get
// this stuff you can use these functions
function getLocationData ()
{
return json_decode ($this->locationData);
}
function getUserData ()
{
return json_decode ($this->userData);
}
}
// now in your controller:
public function dash ($id, Request $request) {
// $user should now be an instance of the User model
$user = JWTAuth::parseToken()->authenticate();
// don't use raw SQL if at all possible
//$q = DB::select('SELECT * FROM maps WHERE user_id = :id', ['id' => $id]);
// notice that User has a relationship to Maps defined!
// and it's a has-many relationship so maps() returns an array
// of Map models
$maps = $user->maps ();
return response()->json($maps);
}
You can loop over $q using a foreach:
foreach ($q as $row) {
// Do work here
}
See the Laravel docs for more information.

how to get data from other tables in grid view in yii

I have a module named attendance but value in it is comes from other tables with some conditions. so how can i get id of other tables. my code is like below:
models are:
if($type == 2)
{
$model = new Supplier();
}
elseif($type==3)
{
$model = new TruckingCompany();
}
elseif($type==4)
{
$model = new ServiceProvider();
}
elseif($type==5)
{
$model = new Landowner();
}
elseif($type==6)
{
$model = new Refiner();
}
elseif($type==8)
{
$model = new Worker();
}
elseif($type==9)
{
$model = new Trainer();
}
now i want to update this record
array(
'header'=>'Action',
'class' => 'CButtonColumn',
'template'=>'{update}',
'updateButtonUrl'=>'Yii::app()->createUrl("attendance/update", array("id"=>$data->id))',
);
now i want to get id of these diffent table for update record and these are different in all tables. i can get it by below line:
'updateButtonUrl'=> 'Yii::app()->createUrl("attendance/update", array("id"=>$data->supplier_master_id))';
but it is not a proper way to define by these for all tables so what to do in this case... any idea... i am new in yii.
Why do not you create the URL along with the models like
if($type == 2)
{
$model = new Supplier();
$updateUrl = 'Yii::app()->createUrl("attendance/update", array("id"=>$data->id))';
}
elseif($type==3)
{
$model = new TruckingCompany();
$updateUrl = 'Yii::app()->createUrl("attendance/update", array("id"=>$data->supplier_master_id))';
}
Pass it to the view while rendering
$this->render('view',array('updateUrl'=>$updateUrl));
And then finally use it in view file like
array(
'header'=>'Action',
'class' => 'CButtonColumn',
'template'=>'{update}',
'updateButtonUrl'=>$updateUrl,
);
In addition to let me see's answer. I would put it in array form:
$types = array(
1 => array("modelName"=>"Supplier","url"=>'Yii::app()->createUrl("attendance/update", array("id"=>$data->id))'),
2 => array("modelName"=>"TruckingCompany","url"=>'Yii::app()->createUrl("attendance/update", array("id"=>$data->supplier_master_id))'),
);
Of course you can improve on this by dividing the "url" key for example like this:
"url"=>array(
"route"=>"attendance/update",
"params"=>'"id"=>$data->id',
)
This way you can pass it like this:
if(array_key_exists($type,$types)){ //Checks if you've defined the type.
$this->render('view',array(
'updateUrl'=>$types[$type]['url'],
'model'=>new $types[$type]['modelName'](), //Creates your object.
)
);
return; //just to be sure.
}
throw new CHTTPException(404, "Type not Found!");
Your view would look something like this with the improved "url" key:
array(
'header'=>'Action',
'class' => 'CButtonColumn',
'template'=>'{update}',
'updateButtonUrl'=>'Yii::app()->createUrl(' . $updateUrl['route'] . ', array(' . $updateUrl['params'] . '))',
);
This clears up your code a bit and gets rid of the huge if statement/switch.
The createUrl string is still a bit ugly, so you can improve on that further if you would like.

Yii 1.1 create relationships automatically

Pago, model exists in Yii. As I create relationships automatically?..
Example:
$pago = new Pago();
Now I want to show information:
echo $pago->iDTIPOTRAMITE->id;
It is assumed that the information must be loaded by default
thanks.
I think I found the solution here: model init()
With this method, set initial property values.
Example. Pago model.
public function init()
{
$documentos = DocumentacionT::model()->findAll(array(
'condition' => 'ID_TIPOSOLICITUD = :idTipo',
'params' => array(':idTipo' => 5)
));
$pagoDocumento = [];
foreach($documentos as $documento)
{
$pagoDocumento[] = new PagoDocumento();
}
$this->pagoDocumentos = $pagoDocumento;
}

Get the Last Inserted Id Using Laravel Eloquent

I'm currently using the below code to insert data in a table:
<?php
public function saveDetailsCompany()
{
$post = Input::All();
$data = new Company;
$data->nombre = $post['name'];
$data->direccion = $post['address'];
$data->telefono = $post['phone'];
$data->email = $post['email'];
$data->giro = $post['type'];
$data->fecha_registro = date("Y-m-d H:i:s");
$data->fecha_modificacion = date("Y-m-d H:i:s");
if ($data->save()) {
return Response::json(array('success' => true), 200);
}
}
I want to return the last ID inserted but I don't know how to get it.
Kind regards!
After save, $data->id should be the last id inserted.
$data->save();
$data->id;
Can be used like this.
return Response::json(array('success' => true, 'last_insert_id' => $data->id), 200);
For updated laravel version try this
return response()->json(array('success' => true, 'last_insert_id' => $data->id), 200);
xdazz is right in this case, but for the benefit of future visitors who might be using DB::statement or DB::insert, there is another way:
DB::getPdo()->lastInsertId();
If the table has an auto-incrementing id, use the insertGetId method to insert a record and then retrieve the ID:
$id = DB::table('users')->insertGetId([
'email' => 'john#example.com',
'votes' => 0
]);
Refer: https://laravel.com/docs/5.1/queries#inserts
For anyone who also likes how Jeffrey Way uses Model::create() in his Laracasts 5 tutorials, where he just sends the Request straight into the database without explicitly setting each field in the controller, and using the model's $fillable for mass assignment (very important, for anyone new and using this way): I read a lot of people using insertGetId() but unfortunately this does not respect the $fillable whitelist so you'll get errors with it trying to insert _token and anything that isn't a field in the database, end up setting things you want to filter, etc. That bummed me out, because I want to use mass assignment and overall write less code when possible. Fortunately Eloquent's create method just wraps the save method (what #xdazz cited above), so you can still pull the last created ID...
public function store() {
$input = Request::all();
$id = Company::create($input)->id;
return redirect('company/'.$id);
}
**** For Laravel ****
Firstly create an object, Then set attributes value for that object, Then save the object record, and then get the last inserted id. such as
$user = new User();
$user->name = 'John';
$user->save();
// Now Getting The Last inserted id
$insertedId = $user->id;
echo $insertedId ;
There are several ways to get the last inserted id. All are based on what method do you used when inserting. In your case you can get last Id like the following:
$data->save();
$data->id;
For others who need to know how can they get last inserted id if they use other insert methods here is how:
Using create() method
$book = Book::create(['name'=>'Laravel Warrior']);
$lastId = $book->id;
Using insertGetId()
$id = DB::table('books')->insertGetId( ['name' => 'Laravel warrior'] ); $lastId = $id;
Using lastInsertId() method
$lastId = DB::getPdo()->lastInsertId();
Reference https://easycodesolution.com/2020/08/22/last-inserted-id-in-laravel/
In laravel 5: you can do this:
use App\Http\Requests\UserStoreRequest;
class UserController extends Controller {
private $user;
public function __construct( User $user )
{
$this->user = $user;
}
public function store( UserStoreRequest $request )
{
$user= $this->user->create([
'name' => $request['name'],
'email' => $request['email'],
'password' => Hash::make($request['password'])
]);
$lastInsertedId= $user->id;
}
}
This worked for me in laravel 4.2
$id = User::insertGetId([
'username' => Input::get('username'),
'password' => Hash::make('password'),
'active' => 0
]);
Here's an example:
public static function saveTutorial(){
$data = Input::all();
$Tut = new Tutorial;
$Tut->title = $data['title'];
$Tut->tutorial = $data['tutorial'];
$Tut->save();
$LastInsertId = $Tut->id;
return Response::json(array('success' => true,'last_id'=>$LastInsertId), 200);
}
Use insertGetId to insert and get inserted id at the same time
From doc
If the table has an auto-incrementing id, use the insertGetId method
to insert a record and then retrieve the ID:
By Model
$id = Model::insertGetId(["name"=>"Niklesh","email"=>"myemail#gmail.com"]);
By DB
$id = DB::table('users')->insertGetId(["name"=>"Niklesh","email"=>"myemail#gmail.com"]);
For more details : https://laravel.com/docs/5.5/queries#inserts
For insert()
Example:
$data1 = array(
'company_id' => $company_id,
'branch_id' => $branch_id
);
$insert_id = CreditVoucher::insert($data1);
$id = DB::getPdo()->lastInsertId();
dd($id);
Here is how we can get last inserted id in Laravel 4
public function store()
{
$input = Input::all();
$validation = Validator::make($input, user::$rules);
if ($validation->passes())
{
$user= $this->user->create(array(
'name' => Input::get('name'),
'email' => Input::get('email'),
'password' => Hash::make(Input::get('password')),
));
$lastInsertedId= $user->id; //get last inserted record's user id value
$userId= array('user_id'=>$lastInsertedId); //put this value equal to datatable column name where it will be saved
$user->update($userId); //update newly created record by storing the value of last inserted id
return Redirect::route('users.index');
}
return Redirect::route('users.create')->withInput()->withErrors($validation)->with('message', 'There were validation errors.');
}
Although this question is a bit dated. My quick and dirty solution would look like this:
$last_entry = Model::latest()->first();
But I guess it's vulnerable to race conditions on highly frequented databases.
After saving model, the initialized instance has the id:
$report = new Report();
$report->user_id = $request->user_id;
$report->patient_id = $request->patient_id;
$report->diseases_id = $request->modality;
$isReportCreated = $report->save();
return $report->id; // this will return the saved report id
You can easily fetch last inserted record Id
$user = User::create($userData);
$lastId = $user->value('id');
It's an awesome trick to fetch Id from the last inserted record in the DB.
After
$data->save()
$data->id will give you the inserted id,
Note: If your autoincrement column name is sno then you should use
$data->sno and not $data->id
After saving a record in database, you can access id by $data->id
return Response::json(['success' => true, 'last_insert_id' => $data->id], 200)
In Laravel 5.2 i would make it as clean as possible:
public function saveContact(Request $request, Contact $contact)
{
$create = $contact->create($request->all());
return response()->json($create->id, 201);
}
For Laravel, If you insert a new record and call $data->save() this function executes an INSERT query and returns the primary key value (i.e. id by default).
You can use following code:
if($data->save()) {
return Response::json(array('status' => 1, 'primary_id'=>$data->id), 200);
}
You can do this:
$result=app('db')->insert("INSERT INTO table...");
$lastInsertId=app('db')->getPdo()->lastInsertId();
$objPost = new Post;
$objPost->title = 'Title';
$objPost->description = 'Description';
$objPost->save();
$recId = $objPost->id; // If Id in table column name if other then id then user the other column name
return Response::json(['success' => true,'id' => $recId], 200);
For get last inserted id in database
You can use
$data = new YourModelName;
$data->name = 'Some Value';
$data->email = 'abc#mail.com';
$data->save();
$lastInsertedId = $data->id;
here $lastInsertedId will gives you last inserted auto increment id.
The shortest way is probably a call of the refresh() on the model:
public function create(array $data): MyModel
{
$myModel = new MyModel($dataArray);
$myModel->saveOrFail();
return $myModel->refresh();
}
You can also try like this:
public function storeAndLastInrestedId() {
$data = new ModelName();
$data->title = $request->title;
$data->save();
$last_insert_id = $data->id;
return $last_insert_id;
}
Here it is how it worked for me, family_id is the primary key with auto increment I am using Laravel7
public function store(Request $request){
$family = new Family();
$family->family_name = $request->get('FamilyName');
$family->family_no = $request->get('FamilyNo');
$family->save();
//family_id is the primary key and auto increment
return redirect('/family/detail/' . $family->family_id);
}
Also in the Model Family file which extends Model, should have the increment set to true otherwise the above $family-->family_id will return empty
public $incrementing = true;
Using Eloquent Model
$user = new Report();
$user->email= 'johndoe#example.com';
$user->save();
$lastId = $user->id;
Using Query Builder
$lastId = DB::table('reports')->insertGetId(['email' => 'johndoe#example.com']);
After Saving $data->save(). all data is pushed inside $data. As this is an object and the current row is just saved recently inside $data. so last insertId will be found inside $data->id.
Response code will be:
return Response::json(array('success' => true, 'last_insert_id' => $data->id), 200);
You can get last inserted id with same object you call save method;
$data->save();
$inserted_id = $data->id;
So you can simply write:
if ($data->save()) {
return Response::json(array('success' => true,'inserted_id'=>$data->id), 200);
}
public function store( UserStoreRequest $request ) {
$input = $request->all();
$user = User::create($input);
$userId=$user->id
}
Using Eloquent Model
use App\Company;
public function saveDetailsCompany(Request $request)
{
$createcompany=Company::create(['nombre'=>$request->input('name'),'direccion'=>$request->input('address'),'telefono'=>$request->input('phone'),'email'=>$request->input('emaile'),'giro'=>$request->input('type')]);
// Last Inserted Row ID
echo $createcompany->id;
}
Using Query Builder
$createcompany=DB::table('company')->create(['nombre'=>$request->input('name'),'direccion'=>$request->input('address'),'telefono'=>$request->input('phone'),'email'=>$request->input('emaile'),'giro'=>$request->input('type')]);
echo $createcompany->id;
For more methods to get Last Inserted Row id in Laravel : http://phpnotebook.com/95-laravel/127-3-methods-to-get-last-inserted-row-id-in-laravel

Categories