Pago, model exists in Yii. As I create relationships automatically?..
Example:
$pago = new Pago();
Now I want to show information:
echo $pago->iDTIPOTRAMITE->id;
It is assumed that the information must be loaded by default
thanks.
I think I found the solution here: model init()
With this method, set initial property values.
Example. Pago model.
public function init()
{
$documentos = DocumentacionT::model()->findAll(array(
'condition' => 'ID_TIPOSOLICITUD = :idTipo',
'params' => array(':idTipo' => 5)
));
$pagoDocumento = [];
foreach($documentos as $documento)
{
$pagoDocumento[] = new PagoDocumento();
}
$this->pagoDocumentos = $pagoDocumento;
}
Related
I am new to CakePHP but I have been using PHP for a while. I am trying to create a helper that would provide the level of access of a user (ACL).
Here is my ACLHelper.php so far
<?php
namespace App\View\Helper;
use Cake\View\Helper;
use Cake\ORM\TableRegistry;
class ACLHelper extends Helper{
public function getACL($id, $acl_field, $level){
$members = TableRegistry::get('groups_member');
$group = $members->find()->where(['user_id' => $id]);
$acls = TableRegistry::get('acls');
$acl = $acls->find('all', [ 'fields' => $acl_field ])->where(['group_id' => $group->first()->group_id]);
return $acl->first();
}
}
I call this function in my view this way
<?= $this->ACL->getACL($user->id, 'is_items', '4') ?>
And this is the output
{ "is_items": "4" }
What I need is the function to return true or false if the value of the field equals or is higher then the value of $level provided to the function. Now if I do this :
<?= $this->ACL->getACL($user->id, 'is_items', '4')->is_item ?>
it will return just the value. My problem is that I do not want to specify the field twice.
Thanks in advance for any help
public function getACL($id, $acl_field, $level){
$members = TableRegistry::get('groups_member');
$group = $members->find()->where(['user_id' => $id]);
$acls = TableRegistry::get('acls');
// Get the first ACL record right here
$acl = $acls->find('all', [ 'fields' => $acl_field ])->where(['group_id' => $group->first()->group_id])->first();
// Compare the requested field against the provided level
return $acl->$acl_field >= $level;
}
I am working on my first project using Laravel 5.1. Uses a selectbox in a form.
{!!Form::select('animal_parent[]', array('1' => 'opt1', '2' => 'opt2', '3' => 'opt3', '4' => 'opt4',), null, ['id' => 'animal_parent', 'disabled' => 'disabled', 'multiple' => 'multiple', 'class' => 'form-control'])!!}
Selection limited to two options which need to saved in two columns, male_parent and female_ parent of the animal table.
There are no male_parent and female_ parent element names in the form. Similarly no animal_parent field in animal table.
Values are set as expected in the code given below. However, the insert command does not reflect the newly set values and throws an error.
"ErrorException in helpers.php line 671: preg_replace(): Parameter mismatch, pattern is a string while replacement is an array."
Any help would be much appreciated.
First attempt using mutators
public function setMaleParentAttribute()
{
$parent = Input::get('animal_parent');
$this->attributes['male_parent'] = intval($parent[0]);
}
public function setFemaleParentAttribute(AddAnimalRequest $request)
{
$parent = Input::get('animal_parent);
if (isset($parent[1])) {
$this->attributes['female_parent'] = intval($parent[1]);
} else {
$this->attributes['female_parent'] = intval($parent[0]);
}
unset($request->animal_parent);
}
Second attempt using the store() method in the controller.
$animal = new Animal($request->all());
$parent = Input::get('animal_parent');
$animal['male_parent'] = intval($parent[0]);
if (isset($parent[1])) {
$animal['female_parent'] = intval($parent[1]);
} else {
$animal['female_parent'] = intval($parent[0]);
}
unset($request->animal_parent);
Auth::user()->animals()->save($animal);
return redirect('animals');
The problem was then solved with a change in UI. I feel the problem could have been solved using the below method. Hope that helps someone.
$input = $request->all();
$parent = $input['animal_parent'];
$input['male_parent'] = intval($parent[0]);
if (isset($parent[1])) {
$input['female_parent'] = intval($parent[1]);
} else {
$input['female_parent'] = intval($parent[0]);
}
unset($input['animal_parent']);
$animal = new Animal($input);
$animal->save();`
I am working on my first Zend Framework 2 Project. I needed a User Module and integrated ZfcUser for this. Because I have a slight difference in my User Table, I had to use my own User Entity and User Mapper. I created a new Module called ZfcUserExtension.
I then copied a lot of files from the original ZfcUSer Module like:
Entity/User.php
Entity/UserInterface.php
Factory/Entity/IndexControllerFactory.php
Factory/Mapper/UserHydratorFactory.php
Mapper/Exeption/ExceptionInterface
Mapper/Exeption/InvalidArgumentException.php
Mapper/Exeption/RuntimeException.php Mapper/HydratorInterface.php
Mapper/User.php Mapper/UserHydrator.php Mapper/UserHydrator.php
Mapper/UserInterface.php
In zfcuser.global.php I set the user_entity_class to use my own Entity.
'user_entity_class' => 'ZfcUserExtension\Entity\User',
In the module.config.php from the ZfcUserExtension I add the below to make sure that I use my own User Mapper and UserHydrator. The reason for that was that I use "id" as a Primary Key in my User table instead of "user_id", so I had to make sure that this gets overwritten as well.
<?php
return array(
'controllers' => array(
'factories' => array(
'ZfcUserExtension\Controller\Index' => function(Zend\Mvc \Controller\ControllerManager $cm) {
$sm = $cm->getServiceLocator();
return new \ZfcUserExtension\Controller\IndexController(
$sm->get("doctrine.entitymanager.orm_default")
);
}
),
),
'service_manager' => array(
'factories' => array(
'zfcuser_user_mapper' => function ($sm) {
$options = $sm->get('zfcuser_module_options');
$mapper = new \ZfcUserExtension\Mapper\User();
// No db adapter present add below line
$mapper->setDbAdapter($sm->get('zfcuser_zend_db_adapter'));
$entityClass = $options->getUserEntityClass();
// No entity prototype set add below line
$mapper->setEntityPrototype(new $entityClass);
$mapper->setHydrator($sm->get('zfcuser_user_hydrator'));
$mapper->setTableName($options->getTableName());
return $mapper;
},
// 'zfcuserextension_change_password_form' => 'ZfcUserExtension\Factory\Form\ChangePhoneFormFactory',
),
),
I finally got all this to work, till I now run into another problem. I want some additional fields for the User like Phone Number. How would I approach this? I know there are some ideas on the Internet, but I am mainly interested to know how I would actually offer the option to have a "Change Phone" Form. I have created a Form, similar to the "Change Password and "Change Email". I have then created a IndexController.php in my ZfcUSerExtension, again followed the set-up of the UserController from the ZfcUser Module
class IndexController extends AbstractActionController {
const ROUTE_LOGIN = 'zfcuser/login';
/**
* #var \Doctrine\ORM\EntityManager
*/
protected $em;
public function __construct(\Doctrine\ORM\EntityManager $em)
{
$this->em = $em;
}
/**
* #var Form
*/
protected $changeEmailForm;
public function indexAction() {
if (!$this->zfcUserAuthentication()->hasIdentity()) {
return $this->redirect()->toRoute(static::ROUTE_LOGIN);
}
return new ViewModel();
}
public function changephoneAction() {
// if the user isn't logged in, we can't change phone
if (!$this->zfcUserAuthentication()->hasIdentity()) {
return $this->redirect()->toRoute(static::ROUTE_LOGIN);
}
$form = $this->getChangePhoneForm();
$request = $this->getRequest();
$request->getPost()->set('PrevPhone', $this->getUserService()->getAuthService()->getIdentity()->getPrevPhone());
return array(
'status' => false,
'changePhoneForm' => $form,
);
$fm = $this->flashMessenger()->setNamespace('change-phone')->getMessages();
if (isset($fm[0])) {
$status = $fm[0];
} else {
$status = null;
}
$prg = $this->prg(static::ROUTE_LOGIN);
if ($prg instanceof Response) {
return $prg;
} elseif ($prg === false) {
return array(
'status' => $status,
'changePhoneForm' => $form,
);
}
$form->setData($prg);
if (!$form->isValid()) {
return array(
'status' => false,
'changePhoneForm' => $form,
);
}
$change = $this->getUserService()->changeEmail($prg);
if (!$change) {
$this->flashMessenger()->setNamespace('change-email')->addMessage(false);
return array(
'status' => false,
'changeEmailForm' => $form,
);
}
$this->flashMessenger()->setNamespace('change-email')->addMessage(true);
return $this->redirect()->toRoute(static::ROUTE_CHANGEEMAIL);
}
public function getChangePhoneForm()
{
$sl = $this->getServiceLocator();
$this->setChangePhoneForm($sl->get('zfcuserextension_change_phone_form'));
return $this->changePhoneForm;
}
public function setChangePhoneForm($changePhoneForm)
{
$this->changePhoneForm = $changePhoneForm;
return $this;
}
I now noticed that I will face a problem with the User Service Service/User.php. The Service offers a changePassword() and changeEmail() Method. I now thought that I need to copy this file into my own Modules. Am I right that if I extend the User Service from ZfcUser then the Methods changePassword() and changeEmail() will still be available, so I would delete it from the just copied file and just add changePhone()?
And if I am right with my thoughts, the User Service currently starts like this:
class User extends EventProvider implements ServiceManagerAwareInterface
How would I have to change it that I extend the original User Service? I hope somebody can help, I am still rather confused with all this. Thanky you very much in advance.
There are two possible methods:
Build custom classes extending ZfcUser's entity, form and input filter and add your custom fields. In the ZfcUser configuration change aliases or override factories to ensure your custom classes are instantiated rather than the built in ones.
If you are OK with having the custom profile fields stored and accessed separately from the ZfcUser user entity, check out my module on GitHub: LdcUserProfile. It provides a profile system for ZfcUser but also makes it easy to add your own custom profile fieldsets linked to a user.
i am developing with cakephp (2.4.7) and i have problems with organizing my controllers and models to use pagination.
So far i put the most logic into the models (thin controller, big model). There i returned the results to the controller where i set the variables to display it on the view.
But now i want to use pagination. This break my concept because i can not use pagination inside the models.
Whats the best solution to solve this problem? I do not want to reorganzie my whole structure, because i need pagination in a lot of different actions and models.
For example:
Controller Users, action friends
public function friends($userid = null, $slug = null) {
$this->layout = 'userprofile';
$this->User->id = $userid;
if (!$this->User->exists()) {
throw new NotFoundException(__('Invalid User'));
}
$this->set('friends', $this->User->getFriendsFrom($userid));
}
User Model, function getFriendsFrom($user_from).. i need this method in different actions.
public function getFriendsFrom($user_from) {
$idToFind = $user_from;
$data = $this->FriendFrom->find('all',
array(
'conditions'=>array(
'OR'=> array(
array('user_to'=> $idToFind),
array('user_from'=> $idToFind)
),
'AND' => array(
'friendship_status' => 1
)
),
'contain' => array('UserFrom.Picture', 'UserTo.Picture')
)
);
$friendslist = array();
foreach ($data as $i) {
if ($i['FriendFrom']['user_from'] == $idToFind){
$friendslist[] = $i['UserTo'];
}
elseif ($i['FriendFrom']['user_to'] == $idToFind){
$friendslist[] = $i['UserFrom'];
}
}
return $friendslist;
}
Whats the best way to design this concept to use pagination?
Thanks
in Controller Users use cakephp Paginator
var $helpers = array('Paginator');
Now you call the following method
function index() {
$result = array(
'recursive' => -1,
'conditions' => array(...),
'contain' => array(...),
'limit' => '2'
);
// you can write the above code in your model
$this->paginate = $result;
$users = $this->paginate('User');
// Re-arrage $users
$this->set(compact('users'));
}
If any problem, let me know.
How can I pass the model in array format.
I want to pass models in this format from controller to view:-
Users[user_contact]=Contact
Users[user_contact][contat_city]=City
Users[user_contact][contact_state]=state
This is what I am doing
public function actionCreate() {
$user = new Users;
$presContact = new Contacts;
$presCity = new Cities;
$presState = new States;
$contactArr = array();
// Uncomment the following line if AJAX validation is needed
// $this->performAjaxValidation($model);
if (isset($_POST['Users'])) {
$transaction = CActiveRecord::getDBConnection()->beginTransaction();
$contactArr = CommonFunctions::saveContact($_POST['Users']['user_pres_contact'],'user_pres_contact',$errorArr);
$presContact = $contactArr['contact'];
$presCity = $contactArr['city'];
$presState = $contactArr['state'];
$user->attributes = $_POST['Users'];
$user->user_pres_contact_id = $presContact->contact_id;
if($user->save()){
$transaction->commit();
$this->redirect(array('view', 'id' => $user->user_id));
} else {
$transaction->rollback();
}
}
$this->render('createUser', array(
'Users' => $user,
'Users[\'user_pres_contact\']'=>$presContact,
'Users[\'user_pres_contact\'][\'contact_city\']'=>$presCity,
'Users[\'user_pres_contact\'][\'contact_state\']'=>$presState,
));
}
I am able to access only $users but
I m not able to access $Users['user_pres_contact'] in the view
That's because you are assigning them as strings...
The correct way of doing things would be (btw, what you are asking for can't done literally, it is impossible to assign 2 values to one key):
$user = array(
'user_press_contact' => array(
'contact' => $presContact,
'city' => $presCity,
'state' => $presState,
),
);
$this->render('createUser', array(
'Users' => $user,
));
It will give you $Users['user_press_contact']['contact'] for the name in the view, etc.
You can use
$user->getAttributes() //it returns an array of data.
Hope that's usefull
It is possible to solve this using model relations? You can define a relation from the User model to the City model (e.g. naming it relation_to_city), then you can just assign the user model in the controller
$this->render('view', 'user'=>$user);
and access the city (from the view)
$user->relation_to_city