if else statements php - php

Question

How do I get this to not display when you first go to the page???
if ($error) {
echo "Error: $error<br/>";
}
if ($keycode) {
echo "Keycode: $keycode<br/>";
}

Answer 1

<?php
session_start();
if ($_SESSION['been_here'] == true) {
// show what you need to show
}
else {
// don't show it
$_SESSION['been_here'] = true;
}
?>
The point here is that $_SESSION-variables "last" (as long as you session_start()).
Google "php sessions" for more information, and ask more questions on SO if necessary. :)
Use session_destroy(); to destroy the session.

Answer 2

<?php
if ($error){ echo "Error: $error
"; } if ($keycode) { echo "Keycode: $keycode
"; }

Answer 3

Based on the comments, it seems that your conditional is evaluating to true before you expect it to. Without seeing more of your code, this is only a guess, but I believe your problem is that you're giving the variable $error a default/temporary value when you create it that doesn't mean false. For example:
$error = "default error message, change me later";
// Later...
if ($error) { // This evaluates to true
echo "Error: $error<br/>";
}
If so, you'll want to check out PHP's documentation on casting to booleans, and maybe use something like this (with contribution from Christian's answer):
$error = "0"; // Default error message, change it later
// Later...
if($_SESSION['been_here'] == true)
$error = "This is the real error message.";
// Even later...
if ($error) {
echo "Error: $error<br/>";
}

Answer 4

This probably works for you:
if (isset($error) && !empty($error)) {
echo "Error: $error<br/>";
}
I cannot say more, because you have not specified what the value of $error might be.
Or you just have to introduce a flag that indicates that an error occurred:
$error = 'Error message.';
$has_error = false;
if(!empty($_POST) && some_condition) { // means it is a POST request
$has_error = true;
}
if($has_error) {
echo "Error: $error<br/>";
}