if !isset multiple OR conditions - php

Question

I cannot get this to work for the life of me, it is PHP.
<?php
if (!isset($_POST['ign']) || ($_POST['email'])) {
echo "Please enter all of the values!";
}
else {
echo "Thanks, " . $_POST['ign'] . ", you will recieve an email when the site is complete!";
}
?>
I've also tried using !isset twice.

Answer 1

isset() accepts more than just oneparameter, so just pass as many variables as you need to check:
<?php
if (!isset($_POST['ign'], $_POST['email'])) {
echo "Please enter all of the values!";
}else{
echo "Thanks,". $_POST['ign'].", you will receive an email when the site is complete!";
}
?>
You could use empty() as well, but it doesn't accept more than a variable at a time.

Answer 2

This is how I solved this issue:
$expression = $_POST['ign'] || $_POST['email'] ;
if (!isset($expression) {
echo "Please enter all of the values!";
}
else {
echo "Thanks, " . $_POST['ign'] . ", you will recieve an email when the site is
complete!";
}

Answer 3

Simplest way I know of:
<?php
if (isset($_POST['ign'], $_POST['email'])) {//do the fields exist
if($_POST['ign'] && $_POST['email']){ //do the fields contain data
echo ("Thanks, " . $_POST['ign'] . ", you will recieve an email when the site is complete!");
}
else {
echo ("Please enter all of the values!");
}
}
else {
echo ("Error in form data!");
}
?>
Edit: Corrected the code to show the form data and empty values errors seperatly.
Explanation: The first if statement checks that the submitted form contained two fields, ign and email. This is done to stop the second if statement , in the case that ign or email weren't passed in at all, from throwing an error(message would be printed to server logs). The second if statement checks the values of ign and email to see if they contain data.

Answer 4

Try this:
<?php
if (!isset($_POST['ign']) || isset($_POST['email'])) {
echo "Please enter all of the values!";
}
else {
echo "Thanks, " . $_POST['ign'] . ", you will recieve an email when the site is complete!";
}
?>

Answer 5

isset($_POST['ign'],$_POST['email']));
and then check for the empty values.

Answer 6

When you work with POST, use empty(). because when your form send data. It async null for empty input!
best way is that:
if ((!isset($_POST['ign']) || empty($_POST['ign'])) &&
(!isset($_POST['email']) || empty($_POST['email'])) {
YES! It's Ugly...
So you can use:
<?php
if ( checkInput($_POST['ign']) || checkInput($_POST['email']) ) {
echo "Please enter all of the values!";
}
else {
echo "Thanks, " . $_POST['ign'] . ", you will recieve an email when the site is complete!";
}
function checkInput($input){
return ( !isset($input) || empty($input) );
}
?>

Answer 7

You can try this code:
<?php
if(!isset($_POST['ign'], $_POST['email'])) {
echo "Please enter all of the values!";
} else {
echo "Thanks, " . $_POST['ign'] . ", you will receive an email when the site is complete!";
}
?>

Answer 8

// if any of this session is set then
if (isset($_SESSION['tusername']) || isset($_SESSION['student_login'])) {
it will return true;
} else {
it will return false;
}