I´m fetching my database for images to create a gallery. Every row appear inside a <li>. My question is, is it possible, that the first <li> have a class (for example, "visible"), and all the other <li> have a class named "hidden". So the first $row would have a different class than the following...
Hope I made myself clear!
Thanks
Well thats easy! Just track the row number, if it is the first row then echo out class="visible" else class='hidden"
It can be done more shortlier like this:
$i = 1;
while ($row = mysql_fetch_assoc($result)) {
echo '<li class="' . (($i == 1) ? 'visible' : 'hidden') . '">';
$i++;
}
How about something like
$visible = true;
while(...) {
if($visible) {
echo "<li class='visible'>";
else {
echo "<li class='hidden'>";
}
$visible = false; // Every loop sets it to false, which after the first one will make no difference.
}
Related
I have a question and answer forum. A user may browse responses to questions and promote them if they wish. The code below outputs the different users that have promoted a given question - the users are in the array '$promoters' that is returned from the line $promoters = Promotion::find_all_promotions_for_response($response->response_id); . The foreach loop then goes through each and outputs them, styles by the css class "promoter list". Problem is this.....if I have one promoter I just want their name outputed (no problem with this). But if I have many I want to put a comma between each name and then none after the last name in the foreach loop. Straightforward problem but I failed to achieve this....I tried to add a count($promoters) line in an elseif condition so that if the array $promoters has more than one value, then it outputs the users fullname and then a comma, but of course the last name also has a comma after it which is wrong. How do you indentify the last iteration in a foreach loop and ask it to do something different with this.....
Many thanks guys...
<?php
$promoters = Promotion::find_all_promotions_for_response($response->response_id);
if(!empty($promoters)){
echo "<span class=\"promoted_by\">Promoted by </span>";
foreach($promoters as $promoter){
echo "<span class=\"promoter_list\">" . User::full_name($promoter->user_id) . ", </span>";
}
} else {
echo "";
};
?>
<?php
$promoters = Promotion::find_all_promotions_for_response($response->response_id);
if(!empty($promoters)){
echo "<span class=\"promoted_by\">Promoted by </span>";
foreach($promoters as $idx=>$promoter){
echo "<span class=\"promoter_list\">" . User::full_name($promoter->user_id);
if($idx < count($promoters) - 1) {
echo ", ";
}
echo "</span>";
}
} else {
echo "";
}
?>
UPDATE:
This is another way to do it using implode as suggested by #deceze:
<?php
$promoters = Promotion::find_all_promotions_for_response($response->response_id);
if(!empty($promoters)){
echo "<span class=\"promoted_by\">Promoted by </span>";
$htmlParts = array();
foreach($promoters as $idx=>$promoter){
$htmlParts[] = "<span class=\"promoter_list\">" . User::full_name($promoter->user_id);
}
echo implode(', </span>', $htmlParts) . '</span>';
} else {
echo "";
}
?>
Basically by clicking the "comment" link the last result of the query should show and by clicking again it should be hidden. I have tried Rocket's code as well but I get an error message in the bottom of the browser and when I click "comments" it just takes me to the top of the page. I would apprieciate some advice on this
$i = 1; // ID Counter
while($row = mysql_fetch_array($result))
{
echo "<h1>$row[title]</h1>";
echo "<p class ='second'>$row[blog_content]</p> ";
echo "<p class='meta'>Posted by .... • $row[date] • Comments<div id='something$i' style='display: none;'>$row[comment]</div>";
$i++; // Increment counter
}
This is a loop, echoing the same thing over and over, thus making all the divs have the same ID, something2.
IDs need to be unique, you gonna have to make unique IDs for each div.
Something like: <div id='something$i' style='display: none;'> (remembering to increment $i).
Also, you're gonna to escape the quotes in your onclick attribute.
<a href='#' onclick=\"toggle_visibility('something$i');\">
The code should look something like this:
$i = 1; // ID Counter
while($row = mysql_fetch_array($result))
{
echo "<h1>$row[title]</h1>";
echo "<p class ='second'>$row[blog_content]</p> ";
echo "<p class='meta'>Posted by .... • $row[date] • Comments<div id='something$i' style='display: none;'>$row[comment]</div>";
$i++; // Increment counter
}
Escape the quotes :
$blah = "onclick='toggle_visibility(\"something2\");'>Comments</a>"
There is an easier way to hiding / showing the next sibling ....
try this
<div style="display:none">some hidden content</div>
function toggle(el,ev) {
ev.preventDefault(); // prevent the link from being followed
el = next(el); // get the next element
if (el.style.display == "none") { // toggle the display
el.style.display = "block";
} else {
el.style.display = "none";
}
}
/*
Credit to John Resig for this function
taken from Pro JavaScript techniques
*/
function next(elem) {
do {
elem = elem.nextSibling;
} while (elem && elem.nodeType != 1);
return elem;
}
Working example
You can throw in a counter into your code as the while loop is executing to dynamically generate unique id's for each comment div. Or, you can pull a unique field out of the query result for the id's, as long as you hook up to it appropriately later if it ends up being used and remain consistent in the rest of the code.
either
$count = count($result);
...
while (...){
$count--;
echo '... id="something'. $count .'" ...'
}
or...
while (...){
echo '... id="something'. $row['ID'] .'" ...'
}
i am trying to get my data from the database and wrap it with html tags. here is the working code so far:
function homethumb(){ $this->count; $i = 0;
while($row = mysqli_fetch_object($this->result))
{
$this->count++; $i++;
if($i == 1){echo '<div class="gal1">';}
echo ' <div class="gal"><img src="img/' . $row->thumb2 . '.jpg"></div>';
if($i == 2){
echo '</div> <!-- gal1 -->';
$i=0;
}
}
}
Here I am getting everything from the database (Select * from portfolio), but in the portfolio I have, websites, demos and graphics; so I wanted to get only the data where category = "web" from the above code, so I tried this:
function homethumb(){ $this->count; $i = 0;
while($row = mysqli_fetch_object($this->result))
{
if($row->category = "web"){
$this->count++; $i++;
if($i == 1){echo '<div class="gal1">';}
echo ' <div class="gal"><img src="img/' . $row->thumb2 . '.jpg"></div>';
if($i == 2){
echo '</div> <!-- gal1 -->';
$i=0;
}
}
}
}
now the nested if statements do not generate the divs I need, how can I get this working
thanks for your help
I can't see your SQL based on your question, but you could just modify your SELECT query to include WHERE category="web"
This way, you're only selecting the rows you need, instead of looping over every row in that table.
Additionally, it appears that you're using assignment = instead of comparison == for your if statement.
Do you just need to have == instead of =?
if($row->category == "web"){
But it would be best to restrict the query to the results you need at the database level, unless you need the other rows for some reason.
1)You missed an equal sign:
if($row->category = "web") => if($row->category == "web")
Or better yet
if($row->category === "web")
2)If you want to only get fields with a specific category field, you can simply change your query:
[rest of your query] WHERE category="web"
OK, it should go like this, assuming the fields are sorted as follows
ID, category, website, thumb2, demo, graphics
function homethumb(){ $this->count; $i = 0;
while($row = mysqli_fetch_object($this->result))
{
if($row[1] == "web"){
$this->count++; $i++;
if($i == 1){echo '<div class="gal1">';}
echo ' <div class="gal"><img src="img/' . $row[3] . '.jpg"></div>';
if($i == 2){
echo '</div> <!-- gal1 -->';
$i=0;
}
}
}
}
and there is no need for the nested if, you can just use it in one line as follows:
if($row[1] = "web")
{
echo '<div class="gal1">';
echo ' <div class="gal"><img src="img/' . $row[3] . '.jpg"></div>';
echo '</div> <!-- gal1 -->';
}
1) Change your query to contain a WHERE category="web" clause
2) You have an assignment operator in your if clause (=), when you need an equality operator (==)
Sorry for the huge ignorance on the topic, but I really have no idea where to look other than this website when I come into trouble with my PHP.
What I'm trying to do here is use pre-designated IDs to call particular movies from a database. But all I get is an 'Invalid argument supplied for foreach()' message on the second and third foreach's below.
Here's my code in the head:
//Custom lists of movies to bring in
//New Releases list
$films_new_releases = array(40805, 46705, 41630, 44564, 39451, 20352, 43933, 49009, 49797, 42194);
//Most Popular list
$films_most_popular = array(27205, 16290, 10138, 41733, 37799, 18785, 19995, 17654, 10140, 12162);
//Get information from address bar
$list = $_GET['l'];
if ($list == 'new releases') {
$list_chosen = $films_new_releases;
}
elseif ($list == 'most popular') {
$list_chosen = $films_most_popular;
}
else {
$list_chosen = $films_new_releases;
}
And in amongst the body:
// Loop through each film returned
foreach ($list_chosen as $list_chosen_film) {
$films_result = $tmdb->getMovie($list_chosen_film);
$film = json_decode($films_result);
// Set default poster image to use if film doesn't have one
$backdrop_url = 'images/placeholder-film.gif';
// Loop through each poster for current film
foreach($film->backdrops as $backdrop) {
if ($backdrop->image->size == 'poster') {
$backdrop_url = $backdrop->image->url;
}
}
echo '<div class="view-films-film">
<img src="' . $backdrop_url . '" alt="' . $film->name . '" />
<div class="view-films-film-snippet">
<h2>' . $film->name . '</h2>';
if ($film->certification != null) {
echo '<img src="images/bbfc-' . strtolower($film->certification) . '.png" alt="" />';
}
echo ' <h3>Starring</h3>
<p>';
$num_actors = 0;
foreach ($film->cast as $cast) {
if ($cast->job == 'Actor') {
echo '' . $cast->name . ' ';
$num_actors++;
if ($num_actors == 5)
break;
}
echo ' </p>
<h3>Director</h3>
<p>';
foreach ($film->cast as $cast) {
if ($cast->job == 'Director') {
echo '' . $cast->name . ' ';
}
}
echo ' </p>
</div>
</div>';
}
// End films
}
The little testing I've done is checking what $list_chosen, $list_chosen_film, $films_result and $film actually contain by printing them at the bottom of the page.
$list_chosen shows - Array, $list_chosen_film shows - 42194, $films_result shows the entire JSON string, $film shows - Array.
Try adding:
print_r($film->backdrop);
before the second foreach() loop. Before the error message it won't be an array or it will contain zero elements (not allowed). If you also add:
echo $films_result;
you will be able to debug it and fully understand what is wrong. If not, post the whole output in your question.
This happens, because - as error displayed by PHP informed you - you have provided wrong parameter to foreach loop, probably null or some other value. Make sure you are providing array to foreach.
Also, every time you use foreach, do it like that:
if (count($some_list) > 0) {
foreach ($some_list as $list_item) {
// code for each item on the list
}
} else {
// code when there is nothing on the list
}
This will ensure you will not see errors just because there is nothing on the list.
EDIT:
On the documentation page you can find some tip how to avoid such errors if the collection you are trying to iterate through is empty. Just cast the collection to array type:
foreach ((array) $some_list as $list_item) {
// code for each item on the list
}
Can you provide a dump of $film? The error is telling you that you are pointing to an object that cannot be iterated through (most likely null).
I need to create a menu with PHP from a MySQL database.
Table called categories has id, name, parent_id, shortdesc, etc.
The output need to have parent list and children list under the partent list as follows.
If you can show me codes or website, I will appreciate it.
<ul id="catmenu">
<li class="menulist">Cars
<ul>
<li>Ford</li>
<li>Honda</li>
<li>Toyota</li>
</ul>
</li>
<li class="menulist">Food
<ul>
<li>Pasta</li>
<li>Pizza</li>
...
</ul>
</li>
...
...
</ul>
This is specifically for two levels deep. Recommended approach should it be more is to use an optimized table structure for traversal, like http://articles.sitepoint.com/article/hierarchical-data-database/2 (pointed out elsewhere) or to pull the data you need and push it into a dictionary (associative array) and query it that way.
<?php
$query = <<<EOT
SELECT
parent.name as parent_name,
child.name as child_name,
FROM
items child
INNER JOIN
items parent
ON
child.parent_id = parent.id
ORDER BY
parent.name
EOT;
$result = mysql_query($query) or die('Failure!');
echo "<ul id=\"catmenu\">";
$last_parent = '';
while($row = mysql_fetch_array($result)){
// If this is a new category, start a new one
if($last_parent != $row['parent_name']){
// Unless this is the first item, close the last category
if($last_parent != ''){
echo "</ul></li>";
}
$last_parent = $row['parent_name'];
echo "<li class=\"menulist\">{$row['parent_name']}<ul>";
}
echo "<li>{$row['child_name']}</li>";
}
// If we actually had items, close the "category"
if($last_parent != ''){
echo "</ul></li>";
}
echo "</ul>";
?>
If you have only two levels then, you could just display them :
echo '<ul id="catmenu">';
foreach($menu as $element) {
echo '<li><ul class="menulist">';
foreach($element['submenu'] as $submenu) {
echo '<li>' . $submenu['name'] . '</li>';
}
echo '</ul></li>';
}
echo '</ul>
If you have an undefined number of submenus however you should use a Recursive Function.
function menu($item) {
$ret = '<li>' . $item['name'];
if (!empty($item['submenu'])) {
foreach($item['submenu'] as $submenu) {
$ret .= menu($submenu);
}
}
return $ret;
}
echo menu($menu);
So every of your subcategories, whatever their number is will be displayed.
You make database like this.
ID NAME PARENT
0 Cars -1
1 Foods -1
2 Ford 0
3 Honda 0
4 Toyota 0
5 Pasta 1
6 Pizza 1
...
You query them all up and put it in an array.
$Menus = array();
// In a read MySQL loop
$Menus[$i]['ID']
$Menus[$i]['NAME']
$Menus[$i]['PARENT']
// Sorry, lazy to write. I think you know what I mean.
Then you loop all menu looking for PARENT == -1. Generate all UL and IL then sub it with another nested menu.
You can simply create a function like this.
var $MenuLevelClass = array("menulist");
function CreateMenu($Menus, $Tab = 0, $Parent = -1, $Level = 0) {
global $MenuLevelClass;
$CatClass = ($Level != 0) ? '' : ' class="catmenu"';
$MenuClass = $MenuLevelClass[$Level];
if ($MenuClass != '')
$MenuClass = ' class="'.$MenuClass.'"';
$TabCount = $Level + $Tab;
$TabUL = "";
for ($t = 0; $t < $TabCount; $t++)
$TabUL = $TabUL."\t";
$TabLI = $TabUL."\t";
?>
<?=$TabUL?><ul<?=$CatClass?>>
<?php
$MenuCount = count($Menus);
for ($m = 0; $m < $MenuCount; $m++) {
$Menu = $Menu[$m];
$ID = $Menu['ID'];
if ($ID != $Parent)
continue;
?>
<?=$TabLI?><li<?=$MenuClass?>><?=$Menu['Name']?><?=CreateMenu($Menus, $Tab + 1, $ID, $Level + 1)?></li>
<?php
?>
<?=$TabUL?></ul>
<?php
}
}
And to use it just run 'CreateMenu($Menus);' or 'CreateMenu($Menus, $PrefixTabCount);'.
CreateMenu will recursively create the nested menu for you.
I have not test it so you may have to adjust it.
Hope this helps.