how can I get these if statements working - php

Question

i am trying to get my data from the database and wrap it with html tags. here is the working code so far:
function homethumb(){ $this->count; $i = 0;
while($row = mysqli_fetch_object($this->result))
{
$this->count++; $i++;
if($i == 1){echo '<div class="gal1">';}
echo ' <div class="gal"><img src="img/' . $row->thumb2 . '.jpg"></div>';
if($i == 2){
echo '</div> <!-- gal1 -->';
$i=0;
}
}
}
Here I am getting everything from the database (Select * from portfolio), but in the portfolio I have, websites, demos and graphics; so I wanted to get only the data where category = "web" from the above code, so I tried this:
function homethumb(){ $this->count; $i = 0;
while($row = mysqli_fetch_object($this->result))
{
if($row->category = "web"){
$this->count++; $i++;
if($i == 1){echo '<div class="gal1">';}
echo ' <div class="gal"><img src="img/' . $row->thumb2 . '.jpg"></div>';
if($i == 2){
echo '</div> <!-- gal1 -->';
$i=0;
}
}
}
}
now the nested if statements do not generate the divs I need, how can I get this working
thanks for your help

Answer 1

I can't see your SQL based on your question, but you could just modify your SELECT query to include WHERE category="web"
This way, you're only selecting the rows you need, instead of looping over every row in that table.
Additionally, it appears that you're using assignment = instead of comparison == for your if statement.

Answer 2

Do you just need to have == instead of =?
if($row->category == "web"){
But it would be best to restrict the query to the results you need at the database level, unless you need the other rows for some reason.

Answer 3

1)You missed an equal sign:
if($row->category = "web") => if($row->category == "web")
Or better yet
if($row->category === "web")
2)If you want to only get fields with a specific category field, you can simply change your query:
[rest of your query] WHERE category="web"

Answer 4

OK, it should go like this, assuming the fields are sorted as follows
ID, category, website, thumb2, demo, graphics
function homethumb(){ $this->count; $i = 0;
while($row = mysqli_fetch_object($this->result))
{
if($row[1] == "web"){
$this->count++; $i++;
if($i == 1){echo '<div class="gal1">';}
echo ' <div class="gal"><img src="img/' . $row[3] . '.jpg"></div>';
if($i == 2){
echo '</div> <!-- gal1 -->';
$i=0;
}
}
}
}
and there is no need for the nested if, you can just use it in one line as follows:
if($row[1] = "web")
{
echo '<div class="gal1">';
echo ' <div class="gal"><img src="img/' . $row[3] . '.jpg"></div>';
echo '</div> <!-- gal1 -->';
}

Answer 5

1) Change your query to contain a WHERE category="web" clause
2) You have an assignment operator in your if clause (=), when you need an equality operator (==)