I have a choice widget in a form:
$years = range(14,130);
$this->widgetSchema['age'] = new sfWidgetFormSchema();
foreach (array('from', 'to') as $value)
{
$this->widgetSchema['age'][$value] = new sfWidgetFormChoice(array(
'label' => $value,
'choices' => array_merge(array('' => '-'),array_combine($years,$years))));
}
If i choose for example 14 and in the action that receives the form is written something like this:
var_dump($valores_widgets['age']['from']);
that shows 0. But I expected 14.
Any idea?
Regards
Javi
Check the documentation of array_merge:
If, however, the arrays contain
numeric keys, the later value will not
overwrite the original value, but will
be appended.
If all of the arrays contain only
numeric keys, the resulting array is
given incrementing keys starting from
zero.
A quick test:
maerlyn#biliskner:~$ php --run '$years=range(14,16);var_dump(array_merge(array("" => "-"), array_combine($years,$years)));'
array(4) {
[""]=>
string(1) "-"
[0]=>
int(14)
[1]=>
int(15)
[2]=>
int(16)
}
So your $years array gets reindexed during the merge. When using the + operator instead:
maerlyn#biliskner:~$ php --run '$years=range(14,16);var_dump(array("" => "-") + array_combine($years,$years));'
array(4) {
[""]=>
string(1) "-"
[14]=>
int(14)
[15]=>
int(15)
[16]=>
int(16)
}
Related
i want to edit a script i found online. is has an hardcoded array like this.
$servers = array(
'Google Web Search' => array(
'ip' => '',
'port' => 80,
'info' => 'Hosted by The Cloud',
'purpose' => 'Web Search'
),
'Example Down Host' => array(
'ip' => 'example.com',
'port' => 8091,
'info' => 'ShittyWebHost3',
'purpose' => 'No purpose'
)
);
Result:
array(2) {
["Google Web Search"]=>
array(4) {
["ip"]=>
string(0) ""
["port"]=>
int(80)
["info"]=>
string(19) "Hosted by The Cloud"
["purpose"]=>
string(10) "Web Search"
}
["Example Down Host"]=>
array(4) {
["ip"]=>
string(11) "example.com"
["port"]=>
int(8091)
["info"]=>
string(14) "ShittyWebHost3"
["purpose"]=>
string(10) "No purpose"
}
}
I put this data in a database and want to make the same array but i dont seem to get it working
This is the code i added to make an array:
$query ="SELECT name, ip, port, hosting FROM sites";
$select = $conn->prepare($query);
$select->execute(array());
$testing = array();
while($rs = $select->fetch(PDO::FETCH_ASSOC)) {
$testing[] = array($rs['name'] => array('ip'=> $rs['ip'], 'port'=> $rs['port'], 'hosting'=> $rs['hosting']));
}
The result from this is:
array(2) {
[0]=>
array(1) {
["Google Web Search"]=>
array(3) {
["ip"]=>
string(10) "google.com"
["port"]=>
string(2) "80"
["hosting"]=>
string(19) "Hosted by The Cloud"
}
}
[1]=>
array(1) {
["Example Down Host"]=>
array(3) {
["ip"]=>
string(11) "example.com"
["port"]=>
string(2) "09"
["hosting"]=>
string(14) "ShittyWebHost3"
}
}
}
is there a way to make the bottom array the same as the top array, i dont want to edit the whole script, this seems easier.
You are appending a new integer indexed element with [] and then adding 2 nested arrays. Instead, add the name as the key:
$testing[$rs['name']] = array('ip'=> $rs['ip'],
'port'=> $rs['port'],
'hosting'=> $rs['hosting']);
Since you specify the columns in the query and they are the same as the array keys, then just this:
$testing[$rs['name']] = $rs;
When you assign a value to an array you use the syntax $arr[key] = $value. If you omit the key during the assignment, $value will be assigned to the next available integer key of the array, starting from 0.
This is an example of how it works:
$arr = array();
$arr[] = 'one';//Empty, so insert at 0 [0=>'one']
$arr[] = 'two';//Last element at 0, so use 1 [0=>'one',1=>'two']
$arr[6]= 'three';//Key is used, so use key [0=>'one',1=>'two',6=>'three']
$arr[] = 'four';//Max used integer key is 6, so use 7
print_r($arr);//[0=>'one',1=>'two',6=>'three',7=>'four']
So, when in your code you are using
$testing[] = array(
$rs['name'] => array(
'ip'=> $rs['ip'],
'port'=> $rs['port'],
'hosting'=> $rs['hosting']
)
);
You are assigning the newly created array to the positions 0,1,2,..N.
To avoid this, just specify the key explicitly, using the value you really want, like
$testing['name'] => array(
'ip'=> $rs['ip'],
'port'=> $rs['port'],
'hosting'=> $rs['hosting']
);
You can read more about arrays in the documentation
Side note
If you don't mind having an extra column in the generated arrays, you can rewrite entirely your code this way:
$query ="SELECT name, ip, port, hosting FROM sites";
$results = $conn->query($query)->fetchAll(PDO::FETCH_ASSOC);
$testing = array_column($results,null,'name');
It's slightly slower, but very handy in my opinion, PDOStatement::fetchAll retrieves all the data at once and array_column using null as second parameter does reindex the array with the wanted column as key.
PDOStatement::fetchAll
array_column
How to sort the following array?
I have an multidimensional array that gets filled with total hours for each brand
$totalHours = array(
'brand' => array(),
'project' => array(),
'hours' => array()
);
The output is something like this (project is not filled):
array(3) {
["brand"]=>
array(3) {
[0]=>
string(4) "Nike"
[1]=>
string(9) "Coke Cola"
[2]=>
string(8) "Converse"
}
["project"]=>
array(3) {
[0]=>
string(6) "Bonobo"
[1]=>
string(4) "LDRU"
[2]=>
string(2) "US"
}
["hours"]=>
array(3) {
[0]=>
int(28)
[1]=>
int(106)
[2]=>
string(1) "2"
}
}
Now I would like to sort the array based on the "hours" field.
I've tried the array_multisort but it seems like I simply don't get how this function works and how to apply it to this array.
I have been able to sort an single array with just one row of values. If I apply that to this problem im sorting only the hours field, leaving the others unsorted and therefore the array is corrupted.
The "project" does actually contains a string. It always does. In this example I didn't filled it.
array_multisort should work:
$totalHours = array(
'brand' => array('Nike', 'Coke Cola', 'Converse'),
'project' => array(),
'hours' => array(28, 106, '2')
);
array_multisort($totalHours['hours'], $totalHours['brand']);
var_dump($totalHours);
That data format is not very convenient because there is no direct association between brands and hours, they even sit in different arrays! Plus, the last hour is a string, not an integer.
We're going to have to create an intermediate array to associate them and sort them. We'll then re-inject everything in the original array.
// Make sure both arrays of brands and hours and the same size
if (count($totalHours['brand']) != count($totalHours['hours'])) {
throw new Exception('Invalid data!');
}
// Make sure every hour record is an integer, not a string
$totalHours['hours'] = array_map('intval', $totalHours['hours']);
// array_combine will sort all arrays based on the sorting of the first one
array_multisort($totalHours['hours'], $totalHours['brand'], $totalHours['project']);
EDIT: Using array_multisort was #delprks 's idea originally. Here I applied it to both brand and project arrays.
You cant do that with a single array_* function!
if (project is not filled) always and the indexes of brand and hours are equal, then you can do:
$forsort = array_combine($totalHours["brands"],$totalHours["hours"]);
asort($forsort,SORT_NUMERIC);
$totalHours["brands"]=array_keys($forsort);
$totalHours["hours"]=array_values($forsort);
But, this is just an answer for you question, not best practise at all.
array(24) { ["user_id"]=> string(1) "9" ["facebook_id"]=> string(15) "381305418721463" ["first_name"]=> string(4) "John" ["last_name"]=> string(4) "Does" ["current_latitude"]=> string(10) "-37.825697" ["current_longitude"]=> string(10) "144.999965" ["current_address"]=> string(45) "229 Swan Street, Richmond VIC 3121, Australia" ["date_of_birth"]=> string(10) "01/01/1990" ["city"]=> string(30) "Melbourne, Victoria, Australia" ["country"]=> string(0) "" ["email_address"]=> string(22) "bzingatester#gmail.com" ["profile_pic"]=> string(0) "" ["first_login"]=> string(2) "no" ["blocked_users_id"]=> string(0) "" ["my_friend"]=> string(52) "10152805813948795,10155307822515151,1389504958030240" ["search_radius"]=> string(2) "50" ["device_type"]=> string(3) "ios" ["device_id"]=> string(1) "1" ["device_token"]=> string(64) "6ddaf9d59418e99b1c9cb28c21d94647bfed9f78a80b410164c1f2798beee84a" ["hideFromActivityFeed"]=> string(2) "no" ["hideFromFriendsofFriends"]=> string(2) "no" ["hideNotification"]=> string(2) "no" ["created_date"]=> string(19) "2015-01-07 01:00:11" ["modified_date"]=> string(19) "2015-02-27 05:36:12" }
In PHP I have an array called $userData as per above, I want to be able to echo values such as first name 'first_name', using code like this
echo $userInfo->first_name;
(this doesnt seem to work)
I DO NOT want to loop and fetch all keys in array using foreach, just get values 'first_name', 'last_name' ect. from the array
Please try like this,
$first_name = $userInfo['first_name'] // $userInfo is array name
You can change the array to object and then use -> like below
$userData= (object) $userData;
And then
$userData->firstName ..etc
Please use type casting.
$userinfo = (array)$userInfo;
Then you access your key first_name.
echo $userinfo['first_name'];
First of use a different method to dump data ..
echo "<pre>";
print_r($your_array);
exit;
It just simply bodes for a better presentation to see what is an object and what is an array.
You cannot access array members with the object notation. You can however cast your array as an object.
(object)$yourarray;
If you want to access array members, use :
$yourarray['first_name'];
If you cast as an object:
$obj = (object)$yourarray;
Now access:
$obj->firstname;
Hope that helps.
Actually we use arrays in programming to prevent loop or something like this to find a value, so instead of this structure,
$a = 'text1';
$b = 0;
$c = true;
$d = 'text2';
we use arrays:
$array = array('a' = > 'text1', 'b' => 0, 'c' => true, 'd' => 'text2' );
and to access the value of some key, we call the key name, inside brackets after array's name:
echo $array['a'];
//will echo text1
//or
echo $array['b'];
//will echo true
This is associative array...
if you just pass values to an array without keys, php will use numeric keys instead...
$array = array( 'text1', '0', true, 'text2' );
$array[0] = 'text1';
$array[1] = 0;
$array[2] = true;
$array[3] = 'text2';
I have an array with multiple values and need to push a value into this array.
The orignial array looks like:
[0]=> array(2) { ["name"]=> string(17) "Name" ["id"]=> string(8) "134567" }
[1]=> array(2) { ["name"]=> string(13) "Name" ["id"]=> string(9) "123456" }
And I need to put these values into the above array:
$personal['id']
$personal['name']
How can this be done?
Use square bracket notation to append to the original array:
$original[] = $person;
Or if $person is more complex and you only want those two keys:
$original[] = array(
'name' => $personal['name'],
'id' => $personal['id']);
Assuming that the $personal array only contains id and name you could use array_push.
array_push($array, $personal);
Seems that the guy who gave me the answer deleted his answer,
But this I used to add values to
$originalArray[]['id'] = $personal['id'];
$originalArray[]['name'] = $personal['name'];
Anyway ++1 for you, thanks! :)
See if this works for you:
$yourarray[]=$personal;
I'm trying to accomplish something very similar to what this user was doing Here.
I followed the answer, but I could not get it working. Inside the Active directory, my memberOf field looks like this:
CN=$VPN Users,CN=Users,DC=iai,DC=pri,CN=$ITAR,CN=Users,DC=iai,DC=pri,CN=allsubscribers,CN=Users,DC=iai,DC=pri
My Filter that works is:
(&(objectCategory=person)(sAMAccountName=$p_username))
I'm trying to get the following to work:
(&(objectCategory=person)(sAMAccountName=$p_username)(memberOf=CN=$ITAR))
I have tried adding the full DN which is
CN=Users,DC=iai,DC=pri
to my filter as well, but I get:
array(1) { ["count"]=> int(0) }
as my response.
I'm using ldap 3
This is the partial Working authentication code written in php:
$login = ldap_bind( $url, "username#somedomain", $password );
$attributes = array("displayname", "mailnickname");
$filter = "(&(objectCategory=person)(sAMAccountName=$username))";
$result = ldap_search($url, "CN=Users,DC=iai,DC=pri", $filter, $attributes);
$entries = ldap_get_entries($url, $result);
What am I doing wrong?
Code Result From #DaveRandom
First Var dump:
string(49) "(&(objectCategory=person)(sAMAccountName=rmoser))"
array(2) {
["count"] => int(1)
[0] => array(8) {
["displayname"] => array(2) {
["count"] => int(1)
[0] => string(10) "Ryan Moser"
}
[0] => string(11) "displayname"
["memberof"] => array(4) {
["count"] => int(3)
[0] => string(36) "CN=$VPN Users,CN=Users,DC=iai,DC=pri"
[1] => string(31) "CN=$ITAR,CN=Users,DC=iai,DC=pri"
[2] => string(40) "CN=allsubscribers,CN=Users,DC=iai,DC=pri"
}
[1]=> string(8) "memberof"
["mailnickname"] => array(2) {
["count"] => int(1)
[0] => string(6) "rmoser"
}
[2] => string(12) "mailnickname"
["count"] => int(3)
["dn"] => string(36) "CN=Ryan Moser,CN=Users,DC=iai,DC=pri"
}
}
bool(false)
Second var_dump:
string(70) "(&(objectCategory=person)(sAMAccountName=rmoser)(memberof=*CN=$ITAR*))"
array(1) {
["count"] => int(0)
}
LDAP filters look for an exact match.
In order to match CN=$ITAR anywhere in a value, you will need to surround it with the filter wildcard character *.
Try this filter:
(&(objectCategory=person)(sAMAccountName=$p_username)(memberOf=*CN=$ITAR*))
Also don't forget that $ITAR is a valid variable name in PHP, so if you place that filter string in double quotes (which you would need to in order for $p_username to be interpolated) PHP will attempt to interpolate $ITAR as a variable as well, find that it (probably) doesn't exist and the end result will be that it gets stripped from the string.
$filter = "(&(objectCategory=person)(sAMAccountName=$p_username)(memberOf=*CN=\$ITAR*))";
A useful link for any question concerning a dynamic filter built with PHP is this.