array(24) { ["user_id"]=> string(1) "9" ["facebook_id"]=> string(15) "381305418721463" ["first_name"]=> string(4) "John" ["last_name"]=> string(4) "Does" ["current_latitude"]=> string(10) "-37.825697" ["current_longitude"]=> string(10) "144.999965" ["current_address"]=> string(45) "229 Swan Street, Richmond VIC 3121, Australia" ["date_of_birth"]=> string(10) "01/01/1990" ["city"]=> string(30) "Melbourne, Victoria, Australia" ["country"]=> string(0) "" ["email_address"]=> string(22) "bzingatester#gmail.com" ["profile_pic"]=> string(0) "" ["first_login"]=> string(2) "no" ["blocked_users_id"]=> string(0) "" ["my_friend"]=> string(52) "10152805813948795,10155307822515151,1389504958030240" ["search_radius"]=> string(2) "50" ["device_type"]=> string(3) "ios" ["device_id"]=> string(1) "1" ["device_token"]=> string(64) "6ddaf9d59418e99b1c9cb28c21d94647bfed9f78a80b410164c1f2798beee84a" ["hideFromActivityFeed"]=> string(2) "no" ["hideFromFriendsofFriends"]=> string(2) "no" ["hideNotification"]=> string(2) "no" ["created_date"]=> string(19) "2015-01-07 01:00:11" ["modified_date"]=> string(19) "2015-02-27 05:36:12" }
In PHP I have an array called $userData as per above, I want to be able to echo values such as first name 'first_name', using code like this
echo $userInfo->first_name;
(this doesnt seem to work)
I DO NOT want to loop and fetch all keys in array using foreach, just get values 'first_name', 'last_name' ect. from the array
Please try like this,
$first_name = $userInfo['first_name'] // $userInfo is array name
You can change the array to object and then use -> like below
$userData= (object) $userData;
And then
$userData->firstName ..etc
Please use type casting.
$userinfo = (array)$userInfo;
Then you access your key first_name.
echo $userinfo['first_name'];
First of use a different method to dump data ..
echo "<pre>";
print_r($your_array);
exit;
It just simply bodes for a better presentation to see what is an object and what is an array.
You cannot access array members with the object notation. You can however cast your array as an object.
(object)$yourarray;
If you want to access array members, use :
$yourarray['first_name'];
If you cast as an object:
$obj = (object)$yourarray;
Now access:
$obj->firstname;
Hope that helps.
Actually we use arrays in programming to prevent loop or something like this to find a value, so instead of this structure,
$a = 'text1';
$b = 0;
$c = true;
$d = 'text2';
we use arrays:
$array = array('a' = > 'text1', 'b' => 0, 'c' => true, 'd' => 'text2' );
and to access the value of some key, we call the key name, inside brackets after array's name:
echo $array['a'];
//will echo text1
//or
echo $array['b'];
//will echo true
This is associative array...
if you just pass values to an array without keys, php will use numeric keys instead...
$array = array( 'text1', '0', true, 'text2' );
$array[0] = 'text1';
$array[1] = 0;
$array[2] = true;
$array[3] = 'text2';
Related
i want to edit a script i found online. is has an hardcoded array like this.
$servers = array(
'Google Web Search' => array(
'ip' => '',
'port' => 80,
'info' => 'Hosted by The Cloud',
'purpose' => 'Web Search'
),
'Example Down Host' => array(
'ip' => 'example.com',
'port' => 8091,
'info' => 'ShittyWebHost3',
'purpose' => 'No purpose'
)
);
Result:
array(2) {
["Google Web Search"]=>
array(4) {
["ip"]=>
string(0) ""
["port"]=>
int(80)
["info"]=>
string(19) "Hosted by The Cloud"
["purpose"]=>
string(10) "Web Search"
}
["Example Down Host"]=>
array(4) {
["ip"]=>
string(11) "example.com"
["port"]=>
int(8091)
["info"]=>
string(14) "ShittyWebHost3"
["purpose"]=>
string(10) "No purpose"
}
}
I put this data in a database and want to make the same array but i dont seem to get it working
This is the code i added to make an array:
$query ="SELECT name, ip, port, hosting FROM sites";
$select = $conn->prepare($query);
$select->execute(array());
$testing = array();
while($rs = $select->fetch(PDO::FETCH_ASSOC)) {
$testing[] = array($rs['name'] => array('ip'=> $rs['ip'], 'port'=> $rs['port'], 'hosting'=> $rs['hosting']));
}
The result from this is:
array(2) {
[0]=>
array(1) {
["Google Web Search"]=>
array(3) {
["ip"]=>
string(10) "google.com"
["port"]=>
string(2) "80"
["hosting"]=>
string(19) "Hosted by The Cloud"
}
}
[1]=>
array(1) {
["Example Down Host"]=>
array(3) {
["ip"]=>
string(11) "example.com"
["port"]=>
string(2) "09"
["hosting"]=>
string(14) "ShittyWebHost3"
}
}
}
is there a way to make the bottom array the same as the top array, i dont want to edit the whole script, this seems easier.
You are appending a new integer indexed element with [] and then adding 2 nested arrays. Instead, add the name as the key:
$testing[$rs['name']] = array('ip'=> $rs['ip'],
'port'=> $rs['port'],
'hosting'=> $rs['hosting']);
Since you specify the columns in the query and they are the same as the array keys, then just this:
$testing[$rs['name']] = $rs;
When you assign a value to an array you use the syntax $arr[key] = $value. If you omit the key during the assignment, $value will be assigned to the next available integer key of the array, starting from 0.
This is an example of how it works:
$arr = array();
$arr[] = 'one';//Empty, so insert at 0 [0=>'one']
$arr[] = 'two';//Last element at 0, so use 1 [0=>'one',1=>'two']
$arr[6]= 'three';//Key is used, so use key [0=>'one',1=>'two',6=>'three']
$arr[] = 'four';//Max used integer key is 6, so use 7
print_r($arr);//[0=>'one',1=>'two',6=>'three',7=>'four']
So, when in your code you are using
$testing[] = array(
$rs['name'] => array(
'ip'=> $rs['ip'],
'port'=> $rs['port'],
'hosting'=> $rs['hosting']
)
);
You are assigning the newly created array to the positions 0,1,2,..N.
To avoid this, just specify the key explicitly, using the value you really want, like
$testing['name'] => array(
'ip'=> $rs['ip'],
'port'=> $rs['port'],
'hosting'=> $rs['hosting']
);
You can read more about arrays in the documentation
Side note
If you don't mind having an extra column in the generated arrays, you can rewrite entirely your code this way:
$query ="SELECT name, ip, port, hosting FROM sites";
$results = $conn->query($query)->fetchAll(PDO::FETCH_ASSOC);
$testing = array_column($results,null,'name');
It's slightly slower, but very handy in my opinion, PDOStatement::fetchAll retrieves all the data at once and array_column using null as second parameter does reindex the array with the wanted column as key.
PDOStatement::fetchAll
array_column
So this below is the structure of JSON i have when I decode it in PHP, but for some reason I am having hard time to loop through this JSON object. I don't know how can I get each values of "incident","description","technique" from those array to save them In my DB.
array(1) {
["Access"]=>
array(2) {
[0]=>
array(3) {
["incident"]=>
string(19) "sssssssssssssssssss"
["description"]=>
string(10) "ssssssssss"
["technique"]=>
string(19) "Link "
}
[1]=>
array(3) {
["incident"]=>
string(18) "ssssssssssssssssss"
["description"]=>
string(0) ""
["technique"]=>
string(19) "Link "
}
}
}
So far I have this PHP code but it's returning me an error saying invalid argument in first foreach loop.
$objectFirst =($_POST['Access1']);
$data = json_decode($objectFirst,true);
foreach ($data->Access as $tech){
foreach($tech as $incident){
foreach($incident as $ss){
var_dump($ss->incident);
}
}
}
When you access the element with this notation, $data->Access, it means you try to access a property of the $data object. But in your case, $data is an array, therefore you have to use the array notation.
So it should be corrected as $data['Access']. One other issue in your code is the level of loops.
foreach ($data->Access as $tech){
foreach($tech as $incident){
foreach($incident as $ss){
var_dump($ss->incident);
}
}
}
The inner most loop is incorrect because $incident will contain a string, not an array. When you try to access $ss['incident'], it will fail. So just change it to:
foreach ($data['Access'] as $tech){
foreach($tech as $incident){
var_dump($incident);
}
}
Hope it helps!
<?php
$data = [
'access' =>
[
[
'foo' => 'I',
'bar' => 'got'
],
[
'foo' => 'a',
'bar' => 'big'
]
]
];
foreach($data['access'] as $array)
var_dump($array['foo'], $array['bar']);
Output:
string(1) "I"
string(3) "got"
string(1) "a"
string(3) "big"
I'm using a Gravity Forms to create a form but want to do something extra with the data after submission of the form.
I'm using var_dump($_POST); to see what the resulting information that is sent is and I get this:
array(12) { ["input_1"]=> string(8) "John Doe" ["input_2"]=> string(11) "Some School" ["input_3"]=> string(8) "Any City" ["input_4"]=> string(7) "Alabama" ["input_5"]=> string(3) "456" ["is_submit_18"]=> string(1) "1" ["gform_submit"]=> string(2) "18" ["gform_unique_id"]=> string(0) "" ["state_18"]=> string(60) "WyJhOjA6e30iLCI5ZTU3ZGE4Mjk1MjFkYjg3MzRlNGQ5MzZjN2E5OWU1MiJd" ["gform_target_page_number_18"]=> string(1) "0" ["gform_source_page_number_18"]=> string(1) "1" ["gform_field_values"]=> string(0) "" }
I'm not familiar with this, yet (I learn so much from all of your help) how would I use, for example, the result from ["input_5"]?
Thank you in advance.
Do you mean this? echo $_POST['input_5'];
$_POST is an associate array, meaning that it is a container for multiple values (array) with named keys (associative). A numeric array doesn't have key names, and looks up values by index instead.
Associate Array - use this to store data that intuitively should be named and order does not matter
$myArr = [
'Name' => 'John Doe',
'Address' => '000 Some St.',
'Phone' => '000-0000'
];
$myArr['Address'];
//or
$key = 'Address';
$myArr[$key]; //use a variable as a key
Numeric Array - use this to store the same type of data where order matters
$myArr = [a,b,c,d,e,f,g];
$toDo = [
'Go to the store',
'Buy Eggs',
'Make Breakfast',
'Be Happy'
];
$myArr[0] //"a"
$toDo[1] //"Buy Eggs"
I have an array with multiple values and need to push a value into this array.
The orignial array looks like:
[0]=> array(2) { ["name"]=> string(17) "Name" ["id"]=> string(8) "134567" }
[1]=> array(2) { ["name"]=> string(13) "Name" ["id"]=> string(9) "123456" }
And I need to put these values into the above array:
$personal['id']
$personal['name']
How can this be done?
Use square bracket notation to append to the original array:
$original[] = $person;
Or if $person is more complex and you only want those two keys:
$original[] = array(
'name' => $personal['name'],
'id' => $personal['id']);
Assuming that the $personal array only contains id and name you could use array_push.
array_push($array, $personal);
Seems that the guy who gave me the answer deleted his answer,
But this I used to add values to
$originalArray[]['id'] = $personal['id'];
$originalArray[]['name'] = $personal['name'];
Anyway ++1 for you, thanks! :)
See if this works for you:
$yourarray[]=$personal;
I'm trying to print an ID from MySQL, the field loads into an array and is visible via print_r but I can't echo it or transfer it to another variable ... what am I missing?
if ( $_POST['section'] == "freelance" ) {
$field_name = "promoter";
} else {
$field_name = "connector";
}
echo $row[$field_name.'_login_ID']
As requested the results of var_dump($row)
array(13) {
["connector_login_id"] => string(2) "14"
["connector_type"] => string(10) "non-profit"
["unique_code"] => string(9) "test-t001"
["update_code"] => string(1) "N"
["md5ID"] => string(0) ""
["username"] => string(6) "bugger"
["connectorEmail"] => string(17) "gzigner#gmail.com"
["password"] => string(32) "098f6bcd4621d373cade4e832627b4f6"
["connectorPass"] => string(4) "test"
["active"] => string(1) "Y"
["modified"] => string(19) "2009-08-21 15:37:22"
["lastlogin"] => string(19) "0000-00-00 00:00:00"
["md5email" ]=> string(32) "051cba58da33fac6b2d18af5182079f4"
}
$row[$field_name.'_login_ID'] <-- "ID"
array(13) {
["connector_login_id"] <-- "id"
Seems like a simple typo to me.
Alternatively, are you sure $field_name gets set to 'connector', since 'promoter_login_id' doesn't exist in this array.
This is purely speculation without your code, but it's probable that the field you are trying to echo contains a hyphen, e.g. "mytable-id", considering that it does indeed show when you use print_r() to print out the entire array. If this is the case you would need to use {'mytable-id'} to get/echo it's value:
echo($dataArray->MyTable->{'mytable-id'});
*Edit: I don't know if your code is copy and pasted, but the value you are trying to print is:
echo $row[$field_name.'_login_ID'];
instead of:
echo $row[$field_name.'_login_id'];
PHP is case-sensitive. You could also try this:
$field_name = $field_name.'_login_id';
echo $row[$field_name];
or
$field_name = $field_name.'_login_id';
echo $row['$field_name'];