keeping radio button value after post - php

HI
i'm using a php page and i need to keep the value of and check box and radio button (checked or not checked) after post page.
how could i make it?
thanks

First get the radio button value.
$radiobuttonvalue = $_POST['radiobuttoname']
Then for each radio button with the same name, do this
<input type="radio" name="radiobuttonname" value="value" id="radiobuttonname" <?php if($radiobuttonvalue == "value") { echo 'checked="checked"';} ?>

You need something like:-
<?php
$postCheckboxName = '';
if (isset($_POST['checkbox_name']) || 'any_value' == $_POST['checkbox_name']) {
$postCheckboxName = ' checked="checked"';
}
?>
<input type="checkbox" name="checkbox_name" value="any_value"<?php echo $postCheckboxName;?> />
<?php
$postRadioName = '';
if (isset($_POST['radio_name']) || 'any_other_value' == $_POST['radio_name']) {
$postRadioName = ' checked="checked"';
}
?>
<input type="checkbox" name="radio_name" value="any_other_value"<?php echo $postRadioName;?> />
This code should get you going. I'm basically checking whether the POST value of either the checkbox / radio element is set or not & whether the corresponding element's value matches with my respective element's value or not.
Hope it helps.

Something like this:
<?php if (isset($_POST['checkbox_name']))?>
<input type="checkbox" checked="checked" value="<?php echo $_POST['checkbox_name'];?>" />
<?php} ?>
<?php if (isset($_POST['radio_name']))?>
<input type="radio" checked="checked" value="<?php echo $_POST['radio_name'];?>" />
<?php} ?>
What happens is that you check if the input variables are in the $_POST and if so you add checked="checked" to the input fields to make them checked.

This worked for me, and is self explanatory
sample code usage:
<div class="form-group">
<label class="radio-inline">
<input type="radio" name="time" value="lunch" <?php if (isset($_POST[ 'time']) && $_POST[ 'time']=='lunch' ){echo ' checked="checked"';}?>>Lunch</label>
<label class="radio-inline">
<input type="radio" name="time" value="dinner" <?php if (isset($_POST[ 'time']) && $_POST[ 'time']=='dinner' ){echo ' checked="checked"';}?>>Dinner</label>
</div>

Related

maintain checkbox which were checked after submit

I know there's "PHP keep checkbox checked after submitting form" on here, but that thread does not solve my problem, because I have multiple checkbox, what I need is when you check a checkbox, this stay checked after submit.
At the moment with this code nothing happens, I tried another way but when I check "id7" checkbox, all the checkbox get checked.
I have to know which checkbox was checked by the id that I give it, but I do not know how.
while ($fila = mysql_fetch_array($rs)) {
echo utf8_encode("
<tr>
<td>
".$fila['title']."
</td>
");?>
<td>
<input type="checkbox" name="checklist[]" value="<?php echo htmlspecialchars($fila['id']); ?>" <?php if(isset($_POST['checklist[]']) && is_array($_POST['checklist[]']) && in_array('$fila', $_POST['checklist[]'])) echo 'checked="checked"'; ?> />
</td>
<?php
}
}
?>
First, the value of checkbox is $fila['id'] so when you are checking, use $fila['id'] instead of $fila. Also, when PHP receive array input fields with [] in their names the [] will be removed so that the correct POST variable is $_POST['checklist'].
Try changing this line:
<input type="checkbox" name="checklist[]" value="<?php echo htmlspecialchars($fila['id']); ?>" <?php if(isset($_POST['checklist[]']) && is_array($_POST['checklist[]']) && in_array('$fila', $_POST['checklist[]'])) echo 'checked="checked"'; ?> />
to
<input type="checkbox" name="checklist[]" value="<?php echo htmlspecialchars($fila['id']); ?>" <?php if(isset($_POST['checklist']) && is_array($_POST['checklist']) && in_array($fila['id'], $_POST['checklist'])) echo 'checked="checked"'; ?> />
"name" is like a variable name - by using checklist[] you're defining an array as the variable.
Why not just name each checkbox properly? When the form is submitted, use the contents of $_POST to set each variable into the user's $_SESSION.
If the page is refreshed, use the values from $_SESSION to determine if the checkbox should be ticked. Something like (untested):
<input type="checkbox" name="vehicle" value="Bike"
<?php if (isset($_SESSION['bike_checked']) echo 'checked'; ?>> I have a bike<br>
<input type="checkbox" name="vehicle" value="Car"
<?php if (isset($_SESSION['car_checked']) echo 'checked'; ?>> I have a car<br>
<input type="submit" value="Submit">

Retrieve mysql value from php for radio buttons

As trivial as it can seems, I'm having problems retrieving values for radio buttons from MySql database through PHP. It's my first learning project so I'm trying my best
Question has already been asked but I found no useful answer.
The php code does a simple "Select *" so I retrieve all the fields.
This is the php code
<label>Owner: <?php echo $row['Owner']; ?></label></br>
<input type="radio" name="Owner" checked=<?php if($row['Owner'] = "A") { echo "true"; }?> value="A">A
<input type="radio" name="Owner" checked=<?php if($row['Owner'] = "B") { echo "true"; }?> value="B">B</br></br>
and I retrieve the values with mysqli_fetch_array().
This is the result:
As you can see the label retrieves the correct value, the radio buttons not.
I've already tried putting == instead of = and putting ' instead of " but I don't know why the checkbox "B" is checked, since Owner value is A.
Also, if there are any best practices which are better than this, you're welcome.
The HTML attribute checked should not get a value, its mere presence indicates that the radio button is checked. So do this:
<label>Owner: <?php echo $row['Owner']; ?></label></br>
<input type="radio" name="Owner" <?php if($row['Owner']=="A") {echo "checked"}?> value="A">A
<input type="radio" name="Owner" <?php if($row['Owner']=="B") {echo "checked"}?> value="B">B
Or using the more compact short echo tag <?= .. ?> and ternary operator:
<label>Owner: <?=$row['Owner']?></label></br>
<input type="radio" name="Owner" <?=$row['Owner']=="A" ? "checked" : ""?> value="A">A
<input type="radio" name="Owner" <?=$row['Owner']=="B" ? "checked" : ""?> value="B">B
Note that you need double equals signs for comparisons.
try this code not = but use ==
<input type="radio" name="Owner" <?php if($row['Owner'] == "A") { echo "checked"; }?> value="A">
$gender=$row['gender'];
<input type="radio" name="gender" <?php if($gender=="Male"){?> checked="true" <?php } ?> />Male
<input type="radio" name="gender" <?php if($gender=="Female"){?> checked="true" <?php } ?>/>Female
$owner=$row['owner'];
$owners= ['A'=>'', 'B'=> ''];
$owners[$owner] = 'checked';
<input type="radio" name="Owner" <?php echo $owners['A']?> value="A">A
<input type="radio" name="Owner" <?php echo $owners['B']?> value="B">B
i think it's easy and simple and so useful if you have many values in DB.
i tried the answer given by #trincot but it give me errors so i have make little changes to improve the answer
<input type="radio" name="Owner" <?php if($row['Owner']=="A") {?> <?php echo "checked";?> <?php }?> value="A">A
<input type="radio" name="Owner" <?php if($row['Owner']=="B") {?> <?php echo "checked";?> <?php }?> value="B">B

How do I get checkbox as checked if value is stored in database?

I am having a problem in retrieving checkboxes from the database.
Actually I am making edit form by using the input form which insert the values in database.
I am facing problem with checkboxes and other inputs works fine.
My code looks like
<input type="checkbox" name="proizvodi[]" value="0" <?if ($row['PROIZVODI'] == '0') $checked = 'checked="checked"'; ?> checked="checked"><b>product1<b/> <input type="checkbox" name="proizvodi[]" value="1" <?if ($row['PROIZVODI'] == '1') $checked = 'checked="checked"'; ?> checked="checked"><b>product2<b/> <br/>
<input type="checkbox" name="proizvodi[]" value="2" <?if ($row['PROIZVODI'] == '2') $checked = 'checked="checked"'; ?> checked="checked"><b>product3</b> <br/>
To make it more clear, I want only checkboes that are stored in db to be checked. for ex if value 1 is stored in db, product1 checkbox will be checked, if value 1 is no stored then check box will be not checked.
I appreciate any help or advice.
Thanks in advance!
How about this? You need to echo the 'checked="checked"' and do not assign it to a variable
<input type="checkbox" name="proizvodi[]" value="0" <?php if (strpos($row['PROIZVODI'],'0') !== false) echo 'checked="checked"'; ?>><b>product1<b/>
<input type="checkbox" name="proizvodi[]" value="1" <?php if (strpos($row['PROIZVODI'],'1') !== false) echo 'checked="checked"'; ?>><b>product2<b/> <br/>
<input type="checkbox" name="proizvodi[]" value="2" <?php if (strpos($row['PROIZVODI'],'2') !== false) echo 'checked="checked"'; ?>><b>product3</b> <br/>
Write your rows like this don't make it any harder than it is:
<input type="checkbox" name="proizvodi[]" value="0" <?php if ($row['PROIZVODI'] == '0') { ?> checked="checked" <?php } ?> /><b>product1<b/>

Remember "Radio" value when submitting form to self on php page?

On a text input, this is how you would "remember" the value the user entered if the form gets submitted to itself, for say a picture upload tool which requires that, so the user wont have to type everything into the form again after uploading a picture.
<input type="text" id="text" name="text" value="<?php echo #$_POST['text'];?>">
but how is this done when it comes to radios?
I would prefer not to create the actual radio with php, I would prefer another solution. But in the end I would go with the easiest! Javascript is also okay to use here!
Thanks
<input type="radio" id="radio_button_1" name="radio_button" value="1"<?php if($_POST['radio_button'] == 1) { print ' checked="checked"'; } ?> />
<input type="radio" id="radio_button_2" name="radio_button" value="2"<?php if($_POST['radio_button'] == 2) { print ' checked="checked"'; } ?> />
To short further, you can write this statement as:
<input type="radio" id="radio_button_2" name="radio_button" value="2" <?=isset($_POST['radio_button']) ? "checked":"" ?> />
I arrived here via Google and the acccepted answer is missing the if(isset($_POST['radio_button'])) check first, which could be handy in some cases.
<input type="radio" id="radio_button_1" name="radio_button" value="1"<?php if(isset($_POST['radio_button']) && $_POST['radio_button'] == 1) { echo ' checked="checked"'; } ?> />
<input type="radio" id="radio_button_2" name="radio_button" value="2"<?php if(isset($_POST['radio_button']) && $_POST['radio_button'] == 2) { echo ' checked="checked"'; } ?> />

uncheck a checkbox when checking another

<?php
session_start();
if (count($_POST) > 0) {
$_SESSION['link'] = $_POST['link'];
}
?>
<form method="post">
Gmail: <input type="checkbox" name="link" value="gmail" id="gmail" <?php if ($_SESSION['link'] == 'gmail') echo "checked"; ?>>
Hotmail: <input type="checkbox" name="link" value="hotmail" id="hotmail" <?php if ($_SESSION['link'] == 'hotmail') echo "checked"; ?>>
<input type="submit" value="Spara">
</form>
Problem is if a box is checked you have to uncheck that then check another to change.
Is there a way so it unchecks the checked one when i check another? that sounds weird...
Thanks
You could just use Radio buttons instead, e.g:
<input type="radio" name="rdGroup1" value="John"> John
<input type="radio" name="rdGroup1" value="Jane"> Jane
There is a reason God created radio buttons. :)

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