I know there's "PHP keep checkbox checked after submitting form" on here, but that thread does not solve my problem, because I have multiple checkbox, what I need is when you check a checkbox, this stay checked after submit.
At the moment with this code nothing happens, I tried another way but when I check "id7" checkbox, all the checkbox get checked.
I have to know which checkbox was checked by the id that I give it, but I do not know how.
while ($fila = mysql_fetch_array($rs)) {
echo utf8_encode("
<tr>
<td>
".$fila['title']."
</td>
");?>
<td>
<input type="checkbox" name="checklist[]" value="<?php echo htmlspecialchars($fila['id']); ?>" <?php if(isset($_POST['checklist[]']) && is_array($_POST['checklist[]']) && in_array('$fila', $_POST['checklist[]'])) echo 'checked="checked"'; ?> />
</td>
<?php
}
}
?>
First, the value of checkbox is $fila['id'] so when you are checking, use $fila['id'] instead of $fila. Also, when PHP receive array input fields with [] in their names the [] will be removed so that the correct POST variable is $_POST['checklist'].
Try changing this line:
<input type="checkbox" name="checklist[]" value="<?php echo htmlspecialchars($fila['id']); ?>" <?php if(isset($_POST['checklist[]']) && is_array($_POST['checklist[]']) && in_array('$fila', $_POST['checklist[]'])) echo 'checked="checked"'; ?> />
to
<input type="checkbox" name="checklist[]" value="<?php echo htmlspecialchars($fila['id']); ?>" <?php if(isset($_POST['checklist']) && is_array($_POST['checklist']) && in_array($fila['id'], $_POST['checklist'])) echo 'checked="checked"'; ?> />
"name" is like a variable name - by using checklist[] you're defining an array as the variable.
Why not just name each checkbox properly? When the form is submitted, use the contents of $_POST to set each variable into the user's $_SESSION.
If the page is refreshed, use the values from $_SESSION to determine if the checkbox should be ticked. Something like (untested):
<input type="checkbox" name="vehicle" value="Bike"
<?php if (isset($_SESSION['bike_checked']) echo 'checked'; ?>> I have a bike<br>
<input type="checkbox" name="vehicle" value="Car"
<?php if (isset($_SESSION['car_checked']) echo 'checked'; ?>> I have a car<br>
<input type="submit" value="Submit">
Related
I have this html form with checkboxes that keep their status checked or unchecked after submitting the form and reloading the page:
<form method="post" action="">
<input type="checkbox" name="keyword1" value="keyword1" <?php if(isset($_POST['keyword1'])) echo "checked='checked'"; ?> />keyword1
<input type="checkbox" name="keyword2" value="keyword2" <?php if(isset($_POST['keyword2'])) echo "checked='checked'"; ?> />keyword2
<input type="checkbox" name="keyword2" value="keyword3" <?php if(isset($_POST['keyword2'])) echo "checked='checked'"; ?> />keyword3
<input type="submit" />
</form>
Problem is, that at first page load the checkboxes are unchecked. Is there any possibility to have all checkboxes with status checked at the beginning and then keep their new status after submit? So far I could not figure out how to do this. Any help would be much appreciated. Thanks,
you could use $_SESSION instead of $_POST :
<input type="checkbox" name="keyword1" value="keyword1" <?php if(isset($_SESSION['keyword1'])) echo "checked='checked'"; ?> />keyword1
And then put this on the top of your file :
session_start();
if (isset($_POST['my_form'])) {
if (isset($_POST['keyword1'])) {
$_SESSION['keyword1'] = 'checked';
}
}
I am trying to get a checkbox checked by default, but everything I have tried doesn't seem to work. I don't know if it has to do with the PHP that is in the code.
function show_subscription_checkbox ($id='0') {
global $sg_subscribe;
sg_subscribe_start();
if ( $sg_subscribe->checkbox_shown ) return $id;
if ( !$email = $sg_subscribe->current_viewer_subscription_status() ) :
$checked_status = ( !empty($_COOKIE['subscribe_checkbox_'.COOKIEHASH]) && 'checked' == $_COOKIE['subscribe_checkbox_'.COOKIEHASH] ) ? true : false;
?>
<p <?php if ($sg_subscribe->clear_both) echo 'style="clear: both;" '; ?>class="subscribe-to-comments">
<input type="checkbox" name="subscribe" id="subscribe" value="subscribe" style="width: auto;" <?php if ( $checked_status ) echo 'checked="checked" '; ?>/>
<label for="subscribe"><?php echo $sg_subscribe->not_subscribed_text; ?></label>
</p>
This is a wordpress plugin that allows you to subscribe to blog comments.
I have tried
echo 'checked=\"checked\" ';
echo 'checked="checked" ' ;
echo 'checked> ';
The plugin author states that you used to be able to default check the checkbox but not anymore.
Since this is showing up in google for "default checked checkbox", I figured I'd answer it. Alpay was right: The correct way to ensure that a checkbox is checked by default is like so (followed by an example of one that is not checked):
<input type="checkbox" name="vehicle" value="Car" checked> I have a car
<input type="checkbox" name="vehicle" value="Bike"> I have a bike
Answer was found on w3schools. The author of the original question was having trouble with his PHP code, which is not at all related to the question title.
In HTML, if you want a checkbox to be checked by default, see the following;
<input type="checkbox" name="name1" value="uc"> This checkbox is unchecked <br>
<input type="checkbox" name="name2" value="c" checked> This checkbox is checked<br>
So, you might consider changing
<?php if ( $checked_status ) echo 'checked="checked" '; ?>
to
<?php if ( $checked_status ) echo 'checked'; ?>
The problem is not in the HTML markup being generated; echo 'checked="checked" ', as in the question, works well, and so would the simpler echo 'checked'.
The problem is with the condition $checked_status. You are testing for a variable that is undefined, as far as the code posted is considered.
I had the same problem. I figured out that I was trying to put the checkbox into a table but left out the and.
didn't check:
if(!$stump){echo '<input type="checkbox" name="stump" value="stump" checked="checked"><b> Stump Job!</b>';}
checked:
if(!$stump){echo '<td><input type="checkbox" name="stump" value="stump" checked="checked"><b> Stump Job!</b></td>';}
In regular PHP you can use this to "save" the checked state after its been submitted.
<form name="checkbox" method="post" action="#" >
<input type="checkbox" name="checkbox1" value="Bike" <?php if ($_POST['checkbox1']=="Bike") echo "checked";?>>I have a bike
<input type="checkbox" name="checkbox2" value="Car" <?php if ($_POST['checkbox2']=="Car") echo "checked";?>>I have a car
<input type="submit" name="submit" value="Display this Data" />
if you want to use this data for something else after the submit, just add:
<?php
if(isset($_POST['checkbox1']) OR isset($_POST['checkbox2']) )
{
echo "for 1 : ".$_POST['checkbox1']."for 2: ".$_POST['checkbox2'];
}
?>
if you want to clear the form (basically clear all the post data) you can add:
<form method="post" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>">
<input type="submit" name="Clear all form data" value= "Clear this form">
</form>
I have an array of checkboxes name="box[]". Through PHP I make sure that they're checked after they're submitted by echoing "checked='checked'" if they were checked at submit event.
Now, if I check the third box, the value jumps down to the first checkbox after submit, since the array was empty up until the third checkbox. Same, if I check the 2nd and 3rd checkbox, they jump down to 1st and 2nd after submit. This is the code I'm using:
<form method="post">
<input type="checkbox" name="box[]" value="true" <?php if ($box[0] == true) echo "checked='checked'"; ?>><br>
<input type="checkbox" name="box[]" value="true" <?php if ($box[1] == true) echo "checked='checked'"; ?>><br>
<input type="checkbox" name="box[]" value="true" <?php if ($box[2] == true) echo "checked='checked'"; ?>><br>
<p>
<input type="submit" value="Submit">
</form>
Try it at:
http://experiencerapanui.com/selecttest.php
Can I make the checkboxes fill up the array with a value "false" or whatever, if the box is unchecked? Which way should I go?
****** EDIT ******
Thanks to phant0m, I managed to come up with a solution:
<form method="post">
<input type="checkbox" name="box[]" value="1" <?php if (in_array("1", $box)) echo "checked='checked'"; ?>><br>
<input type="checkbox" name="box[]" value="2" <?php if (in_array("2", $box)) echo "checked='checked'"; ?>><br>
<input type="checkbox" name="box[]" value="3" <?php if (in_array("3", $box)) echo "checked='checked'"; ?>><br>
<p>
<input type="submit" value="Submit">
</form>
Putting unique values for the checkboxes, then if I find the value in the array $box[], the box is marked as checked.
This does not work, because only those checkboxes, that are checked, are being put into the $box array.
Either use different names, or different values to distinguish between them.
Consider this: You check the second and the third checkbox. In PHP, you will receive:
$_POST['box'] = array(0 => "true", 1 => "true");
You cannot know, which checkboxes have been checked, unless all of them are.
The POST value should start with isset, then !empty($array) determines if the POST value is an array and prevents a null array error when no options are selected.
&& is_array($_POST['box']) could be used in addition to !empty($_POST['box']) as well to check the validity of the array.
A variable is used in the following examples for the value field, as it makes it easier to define and populate inputs when using a foreach loop and may be sanitized if needed as a preventive measure.
It would probably be a good idea to sanitize the $_POST array also, and enclosing it in a function with the validation would allow it all to be called from the checkbox input and keep the input area tidy.
<input type="checkbox" name="box[]" value="<?php echo $unique_id; ?>" <?php if(isset($_POST['box']) && !empty($_POST['box']) && in_array($unique_id, $_POST['box'])) echo "checked='checked'"; ?>>
OR
<input type="checkbox" name="box[]" value="<?php echo $unique_id; ?>" <?php my_function(); ?>>
Excellent question and solutions! There seem to be relatively few examples that use an array method to preserve Post selections, and the one provided here is relevant and very helpful even years later.
HI
i'm using a php page and i need to keep the value of and check box and radio button (checked or not checked) after post page.
how could i make it?
thanks
First get the radio button value.
$radiobuttonvalue = $_POST['radiobuttoname']
Then for each radio button with the same name, do this
<input type="radio" name="radiobuttonname" value="value" id="radiobuttonname" <?php if($radiobuttonvalue == "value") { echo 'checked="checked"';} ?>
You need something like:-
<?php
$postCheckboxName = '';
if (isset($_POST['checkbox_name']) || 'any_value' == $_POST['checkbox_name']) {
$postCheckboxName = ' checked="checked"';
}
?>
<input type="checkbox" name="checkbox_name" value="any_value"<?php echo $postCheckboxName;?> />
<?php
$postRadioName = '';
if (isset($_POST['radio_name']) || 'any_other_value' == $_POST['radio_name']) {
$postRadioName = ' checked="checked"';
}
?>
<input type="checkbox" name="radio_name" value="any_other_value"<?php echo $postRadioName;?> />
This code should get you going. I'm basically checking whether the POST value of either the checkbox / radio element is set or not & whether the corresponding element's value matches with my respective element's value or not.
Hope it helps.
Something like this:
<?php if (isset($_POST['checkbox_name']))?>
<input type="checkbox" checked="checked" value="<?php echo $_POST['checkbox_name'];?>" />
<?php} ?>
<?php if (isset($_POST['radio_name']))?>
<input type="radio" checked="checked" value="<?php echo $_POST['radio_name'];?>" />
<?php} ?>
What happens is that you check if the input variables are in the $_POST and if so you add checked="checked" to the input fields to make them checked.
This worked for me, and is self explanatory
sample code usage:
<div class="form-group">
<label class="radio-inline">
<input type="radio" name="time" value="lunch" <?php if (isset($_POST[ 'time']) && $_POST[ 'time']=='lunch' ){echo ' checked="checked"';}?>>Lunch</label>
<label class="radio-inline">
<input type="radio" name="time" value="dinner" <?php if (isset($_POST[ 'time']) && $_POST[ 'time']=='dinner' ){echo ' checked="checked"';}?>>Dinner</label>
</div>
How do I check a checkbox?
I've tried 1, On, and Yes. That doesn't work. Putting the worked "checked" alone works, but then how do I check with PHP after a form post of the checkbox is checked?
<input type="checkbox" class="inputcheckbox" id="newmsg" name=chk[newmsg2] value="1" />
A checkbox will only be a successful control if it is checked.
Controls that are not successful are not submitted as data.
Therefore, you can tell if a checkbox is checked by seeing if its value has been submitted.
E.g.
if ($_POST['chk']['newmsg2'] == 1) {
<input type="checkbox" class="inputcheckbox" id="newmsg" name=chk[newmsg2] value="1" <?php if ($_POST['chk']['newmsg2']): ?>checked="checked"<?php endif; ?> />
Here is the code;
<form action="test.php" method="POST">
<input type="checkbox" class="inputcheckbox" id="newmsg" name=chk[newmsg2] value="1" />
<input type="submit">
</form>
<?php
$check = $_POST['chk']['newmsg2'];
echo "***$check****"
?>
If it is checked $check will show 1.