PHP: Problem submitting form in AJAX/JSON? - php

Question

currently I have following code:
home.php
<form name='myformname' id='myformid'>
<input type='text' name='mytext1' value='abc'>
<input type='text' name='mytext2' value='123'>
<input type='submit' value='Submit'>
</form>
<div id='textone'></div><div id='texttwo'></div>
_home.php
$arr = array( 'textone' => $_POST['mytext1'], 'texttwo' => $_POST['mytext2'] );
echo json_encode( $arr );
ajax.js
jQuery('#myformid').live('submit',function(event) {
$.ajax({
url: '_home.php',
type: 'POST',
data: $('#myformid').serialize(),
success: function( data ) {
// TODO: write code here to get json data and load DIVs instead of alert
alert(data);
}
});
return false;
});
Output on submit:
{"textone":"abc","texttwo":"123"}
Question
I want to load mytext1 value in textone DIV and mytext2 value in texttwo DIV using json data in _home.php
Hint: I am using this answer to do the same task on link click event. But how to do this on form submission ?
Thanks

Answer 1

You just wanna parse that JSON and set the divs to the values it contains right?
var divs = JSON.parse(data);
for (var div in divs) {
document.getElementById(div).innerHTML = divs[div];
}
(Previous poster's syntax is probably more like what you're after, and maybe is more cross-browser compatible, but doesn't include the JSON parsing.)
Since JSON is just a subset of JavaScript, you can just eval() it. JSON.parse() basically does that, but gives you assurances that if 'data' contains some nasty code instead of a simple object, it won't be evaluated.

Answer 2

In the success function
for (prop in data){
$('#' + prop).html(data[prop]);
}

Answer 3

Here is my complete JS solution:
jQuery('#myformid').live('submit',function(event) {
$.ajax({
url: '_home.php',
type: 'POST',
dataType: 'json',
data: $('#myformid').serialize(),
success: function( data ) {
for(var id in data) {
//jQuery('#' + id).html(data[id]); // This will also work
document.getElementById(id).innerHTML = data[id];
}
}
});
return false;
});