jQuery AJAX refresh page content after success - php

Question

I'm updating my database with jQuery .click() and then calling my AJAX; my question is once the SQL has ran what is the best way to refresh the content on the page so I'll be able to do the previous action again, currently I'm using window.location.reload(true); but I don't like that method because I don't want to have the page reloading all I want is for the content on the element I used to update it with to be to match the database field after the AJAX was successful
Here's my jQuery:
$(document).ready(function(){
$("span[class*='star']").click(function(){
var data = $(this).data('object');
$.ajax({
type: "POST",
data: {art_id:data.art_id,art_featured:data.art_featured},
url: "ajax-feature.php",
success: function(data){
if(data == false) {
window.location.reload(true);
} else {
window.location.reload(true);
}
}
});
console.log(data.art_featured);
});
});
PHP:
<section class="row">
<?php
$sql_categories = "SELECT art_id, art_featured FROM app_articles"
if($result = query($sql_categories)){
$list = array();
while($data = mysqli_fetch_assoc($result)){
array_push($list, $data);
}
foreach($list as $i => $row){
?>
<div class="row">
<div class="column one">
<?php if($row['art_featured']==0){
?>
<span data-object='{"art_id":"<?php echo $row['art_id'];?>", "art_featured":"<?php echo $row['art_featured'];?>"}' class="icon-small star"></span>
<?php
} else if($row['art_featured']==1) {
?>
<span data-object='{"art_id":"<?php echo $row['art_id'];?>", "art_featured":"<?php echo $row['art_featured'];?>"}' class="icon-small star-color"></span>
<?php
}
?>
</div>
</div>
<?php
}
} else {
echo "FAIL";
}
?>
</section>
EDIT:
I need to update the class .star or .star-color with art_featured depending on what the value of a art_featured is at the time, basically where ever I'm echoing out art_featured I need that to reload once the Ajax is successful.
EDIT:
$("span[class*='star']").click(function(){
var data = $(this).data('object');
var $this = $(this); //add this line right after the above
$.ajax({
type: "POST",
data: {art_id:data.art_id,art_featured:data.art_featured},
url: "ajax-feature.php",
success:function(art_featured){
//remember $this = $(this) from earlier? we leverage it here
$this.data('object', $.extend($this.data('object')),{
art_featured: art_featured
});
}
});
console.log(data.art_featured);
});

Answer 1

If you can just return art_featured after the MySQL database success, it'll send it back to the ajax success function. here, we can manipulate data, however, first we should store reference to the element that was clicked on.
var data = $(this).data('object');
var $this = $(this); //add this line right after the above
Now in our success function, instead of using data just use art_featured because that's all we are returning. Now we can update the existing data object on the target.
success:function(art_featured){
//remmeber $this = $(this) from earlier? we leverage it here
$this.data('object', $.extend($this.data('object'),{
art_featured: art_featured
}));
}
The above will extend the existing data object, allowing key:value pairs to be redefined based on the object we are extending.
You should find this working as intended.

Answer 2

I don't fully understand your question so let's assume the content you want to change is a div with class div, and you want to replace the content with the content just sent i.e. the data. Then you would need to return the data (probably using JSON would be easiest), then your call would be
$.ajax({
type: "POST",
data: {art_id:data.art_id,art_featured:data.art_featured},
url: "ajax-feature.php",
dataType:'json',
success: function(data){
for(n in data){
$('.div').append('<p>'+data[n]+'</p>');
}
}
});
Note addition of dataType return as being json, then iterating over the json data by for n in data, then using n to call the data from the array. So if the third item was name then you could do something like
$('.div').append('<p>Name is '+data[3]+'</p>');
You will have to return the data from the PHP form by json encoding it which can be done with the json_encode php function. If it's cross domain you'll have to use jsonp
EDIT:
If you already know the data you want to replace before you send the form (i.e. don't need a response) then you can just put those variables into the success call back. This will wait for the ajax to return successfully, then update your div.
So you could have this
var updateText = yourDataFromForm
$.ajax({
type: "POST",
data: {art_id:data.art_id,art_featured:data.art_featured},
url: "ajax-feature.php",
dataType:'json',
success: function(data){
$('.div').append('<p>'+updateText+'</p>');
}
});