There's gotta be something small I keep missing here, but I can't find it for the life of me.
$insert = mysql_query("INSERT INTO USERS
(`FBID`, `FIRST_NAME`, `LAST_NAME`, `GENDER`)
VALUES ('$fbid', '$firstName', '$lastName', '$gender')");
The error is:
Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1
Any ideas?
You are not having variables correctly escaped. Use mysql_real_escape_string and code like this:
$insert = mysql_query("INSERT INTO USERS (`FBID`, `FIRST_NAME`, `LAST_NAME`, `GENDER`)
VALUES (
'".mysql_real_escape_string($fbid)."',
'".mysql_real_escape_string($firstName)."',
'".mysql_real_escape_string($lastName)."',
'".mysql_real_escape_string($gender)."'
)");
If the variables contain any quotes, they create the problem if you don't properly escape them.
Do any of your names contain single quotes?
Try writing out the value of the query to log/console/debug to ensure that it's what you expect.
Try wrapping your variables in {}.
'{$fbid}', '{$firstName}', '{$lastName}', '{$gender}'
Otherwise you are going to have to use string concatenation.
'".$fbid."','".$firstName."','"...
I'm assuming your variables already contain proper escaped data.
Try doing it like this:
$sql = <<EOL
INSERT INTO USERS (`FBID`, `FIRST_NAME`, `LAST_NAME`, `GENDER`)
VALUES ('$fbid', '$firstName', '$lastName', '$gender')
EOL;
$stmt = mysql_query($sql) or die("MySQL error: " . mysql_error());
This will preserve the query for you in $sql so you can echo it out elsewhere and see what was actually produced.
Related
Been looking around all over forums and found similarish issues like MySQL INSERT INTO with PHP $variable . But it's not quite getting to my question.
I want to use variables for the columns but I get errors with my MySQL insert statement
$columns = 'id, test';
$sql_store = "INSERT into test ('$columns') VALUES (NULL, 1)";
$sql = mysqli_query($db, $sql_store) or die(mysql_error());
You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near ''id, Storlek') VALUES (NULL, 1)' at line 1
Thankful for help!
Problem : Your $columns variable is string which is not true.
Try like this,
PHP
$columns_array = array('id','test');
$columns = implode(",",$columns_array);
$sql_store = "INSERT into test (".$columns.") VALUES (NULL, 1)";
$sql = mysqli_query($db, $sql_store) or die(mysql_error());
It looks like your SQL command, after variable substitution, looks like
INSERT into test ('id, Storlek') VALUES (NULL, 1) /* wrong! */
It needs to say this ...
INSERT into test (id, Storlek) VALUES (NULL, 1)
or maybe this...
INSERT into test (`id`, `Storlek`) VALUES (NULL, 1)
So get rid of the quote marks surrounding your $columns variable.
$bzSendMail = mysqli_query($Connection, "INSERT INTO messages_inbox (from, towho, subject, text, rcvdat) VALUES ('$MyID', '$SenderID', '$subject', '$text' ,'$sentat')");
I'm trying to make this query works, but it keeps showing me the following error!
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'from, towho, subject, text, rcvdat) VALUES ('1', '2', 'd', 'd' ,'2014-09-07 17:0' at line 1
Anyone can help me?
you are using
FROM
as a column name in your table. You can use '' to specify the column name but it is always better not to use that kind of names as your column names.
$bzSendMail = mysqli_query($Connection, "INSERT INTO messages_inbox (`from`, `towho`, `subject`, `text`, `rcvdat`) VALUES ('$MyID', '$SenderID', '$subject', '$text' ,'$sentat')");
From is a key word in Mysql use backward quotes to skip this as follows
$bzSendMail = mysqli_query($Connection, "INSERT INTO messages_inbox (`from`, `towho`, `subject`, `text`, `rcvdat`) VALUES ('$MyID', '$SenderID', '$subject', '$text' ,'$sentat')");
from is a reserved word in sql. Make backticks around it.
$to = '555';
$from = '555';
$message = 'stuff';
mysql_query("INSERT INTO `convo` (to, from, content)
VALUES ( '$to', '$from', '$message' )") or die(mysql_error());
I can't figure out what is wrong with my above simple query. What obvious thing am I missing?
You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near 'to, from, content) VALUES ( '555', '555', 'stuff' )' at line 1
It looks like to is a MySQL reserved word.
Try
mysql_query("INSERT INTO `convo` (`to`, `from`, `content`) VALUES ( '$to', '$from', '$message' )") or die(mysql_error());
TO is a MySQL keyword. To fix this, wrap backticks around your to field.
I'm repeatedly getting a syntax error when inserting in to mysql, normally this works fine but I can't seem to get it to work. I can echo out the variables no problem but for some reason I can't insert them.
variables (the session vars are brought over from another page)
session_start();
$name=$_SESSION['bName'];
$email=$_SESSION['email'];
$ship_address = $_SESSION['sAddress'];
$voucher=$_SESSION['voucher'];
$sku=$_SESSION['sku'];
$credit_card=$_POST['credit_card'];
$security_code=$_POST['security_code'];
$payment_type=$_POST['payment_type'];
$cc_number=substr($credit_card, 0, 4) . str_repeat('x', (strlen($credit_card) - 4)) . substr($credit_card, -4, 4);
$phone=$_SESSION['billPhone'];
$status="Redeemed";
$date = date('Y/m/d');
$tracking ="";
insert query
//Insert Queries
$sqlInsert = "INSERT INTO `customers`(`name`, `email`, `address`, `phone`, `sku`, `creditcard`, `securitycode`, `paymenttype`, `voucher`, `purchase_id`, `tracking`, `status`, `date_recieved`)
VALUES( $name, $email, $ship_address, $phone, $sku, $credit_card, $security_code, $payment_type, $voucher, $purchase_id, $tracking, $status, $date)";
mysql_query($sqlInsert) or die ('Error Inserting into database' . mysql_error());
I've also tried
VALUES( '$name', '$email', '$ship_address', '$phone', '$sku', '$credit_card', '$security_code', '$payment_type', '$voucher', '$purchase_id', '$tracking', '$status', '$date')
but it doesn't work. The error I get is
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'lastname, fahad#semail.com, 22 toronto ont l6a0l4, 416-123-4567, 1001234, 1234567' at line 1
Any ideas?
Thanks
all string values must be quoted.
VALUES("'.$name.'", "'.$email.'" ...
Do it like this, so the fields are delimited:
VALUES( '$name', '$email', ...
check your error message to see what kind of garbage you are currently generating.
You could use PDO to create prepared statements instead. Then you won't have to worry about escaping your values like drdwilcox's example 'Jerry''s'. It also helps as a counter measure against SQL Injection attacks.
I would almost guarantee that you have a single-quote in your name field. If you want to place a single quote into a string field in SQL, you must double it: 'Jerry''s'
And you need the '$name' version.
I have this query running in my PHP script:
$insertQuery = "INSERT INTO blog_articles
VALUES '$title', $tags', '$category', '$blog', '$author', '$date'";
I then run this script:
if ($result = $connector->query($insertQuery)){
// It worked, give confirmation
echo '<center><b>Article added to the database</b></center><br>';
}else{
// It hasn't worked so stop. Better error handling code would be good here!
die (mysql_error());
}
}
I get this error:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Title Number 1, General, Blogging, Kayaking, General, Tgis is blog number spelli' at line 2
But I cannot tell what the error is.
You have a single quote missing before $tags.
Your query should be more like this
INSERT INTO blog_articles (`title`, `tags`, `category`, `blog`, `author`, `date`)
VALUES ('$title', '$tags', '$category', '$blog', '$author', '$date')
You should also look into sanitizing your query. Perhaps this way (but i don't know your exact setup, so results might vary)
$sql = sprintf("INSERT INTO blog_articles (`title`, `tags`, `category`,
`blog`, `author`, `date`) VALUES ('%s', '%s', '%s', '%s', '%s', '%s')",
mysql_real_escape_string($title), mysql_real_escape_string($tags),
mysql_real_escape_string($category), mysql_real_escape_string($blog),
mysql_real_escape_string($author), mysql_real_escape_string($date));
This uses the sprintf() function, the php documentation has some great examples.
You need to add the names of the fields you are inserting to
INSERT INTO blog_articles ('title', 'tags', 'category', 'blog', 'author', 'date') VALUES ('$title', '$tags', '$category', '$blog', '$author', '$date')
Also you should add some code to escape double or single quote in your text that could break the SQL query.
use the PHP function mysql_real_escape_string()
mysql_real_escape_string() calls MySQL's library function mysql_real_escape_string, which prepends backslashes to the following characters: \x00, \n, \r, \, ', " and \x1a.
For more details:
http://uk.php.net/mysql_real_escape_string
As aknock says, you are missing a ' before $tags.
However, you really need to be using mysql_escape_string to protect against SQL injection attacks. Using mysql_escape_string for your SQL query parameters is a good habit to get into.
Using a DB wrapper like PEAR can make escaping parameters much less painful. Your code above could be written like:
$insertQuery = "INSERT INTO blog_articles \
(`title`, `tags`, `category`, `blog`, `author`, `date`) \
VALUES (?, ?, ?, ?, ?, ?)";
$data = array($title, $tags, $category, $blog, $author, $date);
if ($result = $connector->query($insertQuery, $data)) {
// It worked, give confirmation
echo '<center><b>Article added to the database</b></center><br>';
}else{
// It hasn't worked so stop. Better error handling code would be good here!
die (mysql_error());
}
(assuming $connector is a PEAR DB object)
Explicitly giving the names and order of the columns that you're inserting makes your code much more maintainable and readable. If you change the database schema later, you will be protected from inserting values into the wrong column, or into columns that don't exist any more.