$bzSendMail = mysqli_query($Connection, "INSERT INTO messages_inbox (from, towho, subject, text, rcvdat) VALUES ('$MyID', '$SenderID', '$subject', '$text' ,'$sentat')");
I'm trying to make this query works, but it keeps showing me the following error!
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'from, towho, subject, text, rcvdat) VALUES ('1', '2', 'd', 'd' ,'2014-09-07 17:0' at line 1
Anyone can help me?
you are using
FROM
as a column name in your table. You can use '' to specify the column name but it is always better not to use that kind of names as your column names.
$bzSendMail = mysqli_query($Connection, "INSERT INTO messages_inbox (`from`, `towho`, `subject`, `text`, `rcvdat`) VALUES ('$MyID', '$SenderID', '$subject', '$text' ,'$sentat')");
From is a key word in Mysql use backward quotes to skip this as follows
$bzSendMail = mysqli_query($Connection, "INSERT INTO messages_inbox (`from`, `towho`, `subject`, `text`, `rcvdat`) VALUES ('$MyID', '$SenderID', '$subject', '$text' ,'$sentat')");
from is a reserved word in sql. Make backticks around it.
Related
This is my code to insert registration information
$query = "INSERT INTO $tbl_name
(idmembers,name,email,phone,
jn_dt,pan,pwd,
enroller_id,enrolled_id,tside)
VALUES ('$name', '$email', '$phone',
'$jn_dt', '$pan', '$pwd',
'$enroller_id', '$enrolled_id', '$tside')";
$data = mysql_query($query)or die(mysql_error());
if($data) {
header("location:registration.php?sucessful=true");
}
but I am getting the error "You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'hjkoputrd', '123654', 'F' at line 16"... Please help me.. thanks in advance..
You are inserting field idmembers, but you dont use it in values.
If your idmembers column is autoincrementing you do not have to specify it in query.
"INSERT INTO $tbl_name (name,email,phone,jn_dt,pan,pwd,enroller_id,enrolled_id,tside) VALUES ('$name', '$email', '$phone', '$jn_dt', '$pan', '$pwd', '$enroller_id', '$enrolled_id', '$tside')"
I think column idmembers is your PRIMARY KEY auto increament thats way you are not using it in VALUES.
If it is a PK than just remove that column from your query.
You aren't including anything into idmembers. If is autoincrement in idmembers set to true, idmembers will be included and set automatically, so you must remove it from your query.
This question already has answers here:
MySQL, safely using reserved word in query [duplicate]
(2 answers)
Closed 9 years ago.
I am building a small Twitter clone for personal use, and I have so trouble with it.
Fist, I want to show you my SQL structure of the table "poke_history":
http://puu.sh/3Sci0.png
This is the command I use to insert the values into a table (in PHP):
$insert = "INSERT INTO poke_history (id, from, time, reason) VALUES ('".$to_id."', '".$from_id."', '".$time."', '".$reason."')";
mysql_query($insert) or die(mysql_error());
This is the annoying error that I am getting:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'from, time, reason) VALUES ( '1'' at line 3.
Let me clarify some things.
$to_id is a number.
$from_id is a number.
$time is a number (coming from PHP's time()).
$reason is a text string.
I am using MySQL and PHP5.
Try to quote your column identifiers like
INSERT INTO poke_history (`id`, `from`, `time`, `reason`) ...
Everything inside `` is considered to be a "identifier" not a language keyword. From the SQL-syntax it should be clear that after INSERT INTO tablename cannot come a FROM, but the MySQL sometimes needs this kind of guidance (and other sql parsers, too).
credit to mario as well:
from is a reserved keyword. Use backticks to escape them.
for example
`from`
INSERT INTO table (`from`) ....
So your code would like this:
$insert = "INSERT INTO poke_history (`id`, `from`, `time`, `reason`) VALUES ('".$to_id."', '".$from_id."', '".$time."', '".$reason."')";
mysql_query($insert) or die(mysql_error());
$insert = "INSERT INTO poke_history (`id`, `from`, `time`, `reason`) VALUES (".$to_id.", ".$from_id.", ".$time.", '".$reason."')";
mysql_query($insert) or die(mysql_error());
Numbers don't need to be quoted. Only strings.
Also don't use mysql, it's deprecated. Better use PDO, with prepared statements, to avoid issues like this.
You should try to use prepared statements to prevent SQL injection.
$query = "
INSERT INTO
poke_history (`id`, `from`, `time`, `reason`)
VALUES
(:id, :from, :time, :reason)";
$db = new PDO("mssql:host=sqlserver;dbname=database", "username", "password");
$statement = $db->prepare($query);
$parameters = array(
":id" => $name,
":from" => $from,
":time" => $time,
":reason" => $reason
);
$statement->execute($parameters);
I think that you forgot to add * in between INSERT and INTO, here is the fixed script:
$insert = "INSERT * INTO poke_history (id, from, time, reason) VALUES ('".$to_id."', '".$from_id."', '".$time."', '".$reason."')";
mysql_query($insert) or die(mysql_error());
The reason why you are getting the error is because you are trying to use a built in function name for one of your columns. Say you have the following CREATE TABLE...
CREATE TABLE customers
(
name varchar(80),
streetAddr varchar(160),
"from" varchar(60),
);
Notice that to create the table I had to put the column from in quotes. Now if you wanted to insert a row into this table, your insert statement should look like the following:
INSERT INTO ShoppingFun.dbo.customers
(
name,
streetAddr,
"from"
)
VALUES
(
'MRBubbleGum',
'1061 SW BubbleGumVillage St',
'yourmom'
)
I'm a newbie and I've been trying for over an hour to solve this simple query:
mysql_query("INSERT INTO `tracks` (artistID, albumID, format, trackID, niceTitle, title, trackNumber, description, pictureURL, playCount) VALUES('$artistID', '$albumID[$i]', 'hq','$ID[0]', '$trackName', '$title', '$j', '$description', '$pictureURL', '$playCount'") or die(mysql_error());
I just get this error every time:
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '' at line 1
I've done mysql_escape_string() on all variables too. Any ideas?
You are missing the final closing ):
mysql_query("INSERT INTO `tracks` (artistID, albumID, format, trackID, niceTitle, title, trackNumber, description, pictureURL, playCount) VALUES('$artistID', '$albumID[$i]', 'hq','$ID[0]', '$trackName', '$title', '$j', '$description', '$pictureURL', '$playCount')") or die(mysql_error());
You have no ending parenthesis ")" in your query
$to = '555';
$from = '555';
$message = 'stuff';
mysql_query("INSERT INTO `convo` (to, from, content)
VALUES ( '$to', '$from', '$message' )") or die(mysql_error());
I can't figure out what is wrong with my above simple query. What obvious thing am I missing?
You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use
near 'to, from, content) VALUES ( '555', '555', 'stuff' )' at line 1
It looks like to is a MySQL reserved word.
Try
mysql_query("INSERT INTO `convo` (`to`, `from`, `content`) VALUES ( '$to', '$from', '$message' )") or die(mysql_error());
TO is a MySQL keyword. To fix this, wrap backticks around your to field.
There's gotta be something small I keep missing here, but I can't find it for the life of me.
$insert = mysql_query("INSERT INTO USERS
(`FBID`, `FIRST_NAME`, `LAST_NAME`, `GENDER`)
VALUES ('$fbid', '$firstName', '$lastName', '$gender')");
The error is:
Error: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '1' at line 1
Any ideas?
You are not having variables correctly escaped. Use mysql_real_escape_string and code like this:
$insert = mysql_query("INSERT INTO USERS (`FBID`, `FIRST_NAME`, `LAST_NAME`, `GENDER`)
VALUES (
'".mysql_real_escape_string($fbid)."',
'".mysql_real_escape_string($firstName)."',
'".mysql_real_escape_string($lastName)."',
'".mysql_real_escape_string($gender)."'
)");
If the variables contain any quotes, they create the problem if you don't properly escape them.
Do any of your names contain single quotes?
Try writing out the value of the query to log/console/debug to ensure that it's what you expect.
Try wrapping your variables in {}.
'{$fbid}', '{$firstName}', '{$lastName}', '{$gender}'
Otherwise you are going to have to use string concatenation.
'".$fbid."','".$firstName."','"...
I'm assuming your variables already contain proper escaped data.
Try doing it like this:
$sql = <<EOL
INSERT INTO USERS (`FBID`, `FIRST_NAME`, `LAST_NAME`, `GENDER`)
VALUES ('$fbid', '$firstName', '$lastName', '$gender')
EOL;
$stmt = mysql_query($sql) or die("MySQL error: " . mysql_error());
This will preserve the query for you in $sql so you can echo it out elsewhere and see what was actually produced.