Generate gradient color from PHP - php

Question

I want to know how to build a function that give the code of an color and
display a gradient of this color. For example:
function generate_color(int colorindex)
{ .......
.......
Generate 10 pale colors of this color.
}
Please help me

Answer 1

The code Michael references is rather scary. But the solution is straightforward. It may be clearer if you consider simply a grey scale image:
function create_pallette($start, $end, $entries=10)
{
$inc=($start - $end)/($entries-1);
$out=array(0=>$start);
for ($x=1; $x<$entries;$x++) {
$out[$x]=$start+$inc * $x;
}
return $out;
}
Only using a 3D vector (RGB) instead of a 1D vector.
C.

Answer 2

In the answer to this question lies your solution, only in Javascript...
Generate lighter/darker color in css using javascript
I'm not going to write it out, but a simple Google search for 'lighten hex colour php' yields:
function colourBrightness($hex, $percent) {
// Work out if hash given
$hash = '';
if (stristr($hex,'#')) {
$hex = str_replace('#','',$hex);
$hash = '#';
}
/// HEX TO RGB
$rgb = array(hexdec(substr($hex,0,2)), hexdec(substr($hex,2,2)), hexdec(substr($hex,4,2)));
//// CALCULATE
for ($i=0; $i<3; $i++) {
// See if brighter or darker
if ($percent > 0) {
// Lighter
$rgb[$i] = round($rgb[$i] * $percent) + round(255 * (1-$percent));
} else {
// Darker
$positivePercent = $percent - ($percent*2);
$rgb[$i] = round($rgb[$i] * $positivePercent) + round(0 * (1-$positivePercent));
}
// In case rounding up causes us to go to 256
if ($rgb[$i] > 255) {
$rgb[$i] = 255;
}
}
//// RBG to Hex
$hex = '';
for($i=0; $i < 3; $i++) {
// Convert the decimal digit to hex
$hexDigit = dechex($rgb[$i]);
// Add a leading zero if necessary
if(strlen($hexDigit) == 1) {
$hexDigit = "0" . $hexDigit;
}
// Append to the hex string
$hex .= $hexDigit;
}
return $hash.$hex;
}
http://lab.pxwebdesign.com.au/?p=14
Your Google is just as good as mine!