I have a character string like (ascii codes):
32,13,7,11,11,
"string1,blah;like: this...", 10,10, 32,32,32,32, 138,138, 32,32,32,32, 13,7, 11,11,
"string2/lorem/example-text...", 10,10, 32,32,32,32,32, 143,143,143,143,143
So the sequence is:
any characters, followed by my search string, followed by any
characters
11,11
the string I want to replace
any non-printable characters
If the block contains string1 then I need to replace the next string with something else. The second string always starts directly after the 11,11.
I'm using PHP.
I thought something like this, but I am not getting the correct result:
$updated = preg_replace("/(.*string1.*?\\v+)([[:print:]]+)([[:ascii:]]*)/mi", "$1"."new string"."$3", $orig);
This puts "new string" between the 10,10 and the 138,138 (and replaces the 32's).
Also tried \xb instead of \v.
Normally I test with regex101, but not sure how to do that with non-printable characters. Any suggestions from regex guru's?
Edit: the expected output is the sequence:
32,13,7,11,11,
"string1,blah;like: this...", 10,10, 32,32,32,32, 138,138, 32,32,32,32, 13,7, 11,11,
"new string", 10,10, 32,32,32,32,32, 143,143,143,143,143
Edit: sorry for the confusion regarding the ascii codes.
Here's a complete example:
<?php
$s = chr(32).chr(32).chr(7).chr(11).chr(11);
$s .= "string1,blah;like: this...". chr(10).chr(10).chr(32).chr(32).chr(32).chr(32).chr(138).chr(138);
$s .= chr(32).chr(32).chr(32).chr(32).chr(13).chr(7).chr(11).chr(11);
$s .= "string2/lorem/example-text...". chr(10).chr(10).chr(32).chr(32).chr(32).chr(32).chr(32).chr(143).chr(143).chr(143);
$result = preg_replace('/(.*string1.*?\v+)([[:print:]]+)([[:ascii:]]*)/mi', "$1"."new string"."$3", $s);
echo "\n------------------------\n";
echo $result;
echo "\n------------------------\n";
The text string2/lorem/example-text... should be replaced by new string.
My php-cli halted every time preg_match has reached char(138) and I don't know why.
I will throw my hat on this RegEx (note: \v matches a new-line | no flags are set):
"[^"]*"[^\x0b]+\v{2}"\K[^"]*
PHP code:
$source = chr(32).chr(13).chr(7).chr(11).chr(11)."\"string1,blah;like: this...\"".chr(10).
chr(10).chr(32).chr(32).chr(32).chr(32).chr(138).chr(138).chr(32).chr(32).chr(32).chr(32).
chr(13).chr(7).chr(11).chr(11)."\"string2/lorem/example-text...\"".chr(10).chr(10).chr(32).
chr(32).chr(32).chr(32).chr(32).chr(143).chr(143).chr(143).chr(143).chr(143);
echo preg_replace('~"[^"]*"[^\x0b]+\v{2}"\K[^"]*~', "new string", $source);
Beautiful output:
"string1,blah;like: this..."
��
"new string"
�����
Live demo
Solved. It was a combination of things:
/mis was needed (instead of /mi)
\x0b was needed (instead of \v)
Complete working example:
<?php
$s = chr(32).chr(32).chr(7).chr(11).chr(11);
$s .= "string1,blah;like: this...". chr(10).chr(10).chr(32).chr(32).chr(32).chr(32).chr(138).chr(138);
$s .= chr(32).chr(32).chr(32).chr(32).chr(13).chr(7).chr(11).chr(11);
$s .= "string2/lorem/example-text...". chr(10).chr(10).chr(32).chr(32).chr(32).chr(32).chr(32).chr(143).chr(143).chr(143);
$result = preg_replace('/(.*string1.*?\x0b+)([[:print:]]+)/mis', "$1"."new string", $s);
echo "\n------------------------\n";
echo $result;
echo "\n------------------------\n";
Thanks for everyone's suggestions. It put me on the right track.
i use (str_replace) function to replace ##ID## in youtube url with this regular expression : (?P<id>[a-z-A-Z_0-9]+)
so i use this code to do this :
<?php
$urlbase = 'https://www.youtube.com/watch?v=##ID##';
$lastchange = str_replace('##ID##', '(<id>[a-z-A-Z_0-9]+)', $urlbase);
echo $lastchange;
?>
i get the output in the browser like this : https://www.youtube.com/watch?v=(?P[a-z-A-Z_0-9]+), its looks like <id> not show up !
i try this simple code :
<?php
echo "This is my <id>";
?>
but i just get this is my in the browser !
What's the probleme ? and how i can fix it , thanks
is being interpreted as HTML so your browser is parsing it and since it is not a renderable element, it shows nothing. Try:
<?php
echo "This is my <id>
?>
As for the str_replace, it's doing exactly what the function is supposed to be doing. If you're looking to use regular expressions in string replacements, use preg_replace
The tag <id> is being removed by your browser. It is really there if you watch the source code. Maybe you should try:
$urlbase = 'https://www.youtube.com/watch?v=##ID##';
$lastchange = str_replace('##ID##', '(<id>[a-z-A-Z_0-9]+)', $urlbase);
echo urlencode( $lastchange );
Problem is with the line:
$lastchange = str_replace('##ID##', '(<id>[a-z-A-Z_0-9]+)', $urlbase);
str_replace does not use regex.
You will need preg_replace
$pattern = '(<id>[a-z-A-Z_0-9]+)'
$replacement = '##ID##'
$string = $urlbase
$lastchange = preg_replace($pattern, $replacement, $string);
Also < and > are html entities which means they are reserved chars for HTML they have some special meanings if you want to show them then you must use there entity name eg < and > in your case respectively.
<?php
echo " echo "This is my <id>";
?>
How can I find and replace the same characters in a string with two different characters? I.E. The first occurrence with one character, and the second one with another character, for the entire string in one go?
This is what I'm trying to do (so users need not type html in the body): I've used preg_replace here, but I'll willing to use anything else.
$str = $str = '>>Hello, this is code>> Here is some text >>This is more code>>';
$str = preg_replace('#[>>]+#','[code]',$str);
echo $str;
//output from the above
//[code]Hello, this is code[code] Here is some text [code]This is more code[code]
//expected output
//[code]Hello, this is code[/code] Here is some text [code]This is more code[/code]
But problem here is, both >> get replaced with [code]. Is it possible to somehow replace the first >> with [code] and the second >> with a [/code] for the entire output?
Does php have something to do this in one go? How can this be done?
$str = '>>Hello, this is code>> Here is some text >>This is more code>>';
echo preg_replace( "#>>([^>]+)>>#", "[code]$1[/code]", $str );
The above will fail if something like the following is your input:
>>Here is code >to break >stuff>>
To deal with this, use negative lookahead:
#>>((?!>[^>]).+?)>>#
will be your pattern.
echo preg_replace( "#>>((?!>[^>]).+?)>>#", "[code]$1[/code]", $str );
I have a string
$string = "test<String>";
but when i make
echo $string;
it shows:
testString
and when I send the $string to mobile as SMS it shows
<testString>
How can I show "test<String>" with < and > symbol ?
thanks in advance.
You basically do it in reverse.
<String>
this will tell html to output the less than and greater than characters.
This should help you out
http://www.w3schools.com/html/html_entities.asp
You can try:
$string = "test<string>";
$string = htmlspecialchars($string);
echo $string;
Don't know what SMS-api you are using, maybe you have to urlencode the string before you send it to the api.
Didn't find any solution for mobile sms tag, so for mobile i've used ( and ) instead of < and > for serving purpose temporarily.
I want to change every C style unicode char into html entity. I've written this function to do that:
function ununicode($text) {
$text = preg_replace('/\\\\u([0-9a-f]{4})/i', '&#x$1;', $text);
return $text;
}
it works good, but ignores second character in sth like that \u00f6\u00df. ie it will produce: ö\u00df
whats wrong with my regex?
Try adding the g flag (which allows more than one replacement per line), so that it's this:
$text = preg_replace('/\\\\u([0-9a-f]{4})/ig', '&#x$1;', $text);
Edit:
Your code as written seems to work for me:
php > $text = "\u00f6\u00df";
php > print $text;
\u00f6\u00df
php > $text2 = preg_replace('/\\\\u([0-9a-f]{4})/i', '&#x$1;', $text);
php > print $text2;
öß