I have a character string like (ascii codes):
32,13,7,11,11,
"string1,blah;like: this...", 10,10, 32,32,32,32, 138,138, 32,32,32,32, 13,7, 11,11,
"string2/lorem/example-text...", 10,10, 32,32,32,32,32, 143,143,143,143,143
So the sequence is:
any characters, followed by my search string, followed by any
characters
11,11
the string I want to replace
any non-printable characters
If the block contains string1 then I need to replace the next string with something else. The second string always starts directly after the 11,11.
I'm using PHP.
I thought something like this, but I am not getting the correct result:
$updated = preg_replace("/(.*string1.*?\\v+)([[:print:]]+)([[:ascii:]]*)/mi", "$1"."new string"."$3", $orig);
This puts "new string" between the 10,10 and the 138,138 (and replaces the 32's).
Also tried \xb instead of \v.
Normally I test with regex101, but not sure how to do that with non-printable characters. Any suggestions from regex guru's?
Edit: the expected output is the sequence:
32,13,7,11,11,
"string1,blah;like: this...", 10,10, 32,32,32,32, 138,138, 32,32,32,32, 13,7, 11,11,
"new string", 10,10, 32,32,32,32,32, 143,143,143,143,143
Edit: sorry for the confusion regarding the ascii codes.
Here's a complete example:
<?php
$s = chr(32).chr(32).chr(7).chr(11).chr(11);
$s .= "string1,blah;like: this...". chr(10).chr(10).chr(32).chr(32).chr(32).chr(32).chr(138).chr(138);
$s .= chr(32).chr(32).chr(32).chr(32).chr(13).chr(7).chr(11).chr(11);
$s .= "string2/lorem/example-text...". chr(10).chr(10).chr(32).chr(32).chr(32).chr(32).chr(32).chr(143).chr(143).chr(143);
$result = preg_replace('/(.*string1.*?\v+)([[:print:]]+)([[:ascii:]]*)/mi', "$1"."new string"."$3", $s);
echo "\n------------------------\n";
echo $result;
echo "\n------------------------\n";
The text string2/lorem/example-text... should be replaced by new string.
My php-cli halted every time preg_match has reached char(138) and I don't know why.
I will throw my hat on this RegEx (note: \v matches a new-line | no flags are set):
"[^"]*"[^\x0b]+\v{2}"\K[^"]*
PHP code:
$source = chr(32).chr(13).chr(7).chr(11).chr(11)."\"string1,blah;like: this...\"".chr(10).
chr(10).chr(32).chr(32).chr(32).chr(32).chr(138).chr(138).chr(32).chr(32).chr(32).chr(32).
chr(13).chr(7).chr(11).chr(11)."\"string2/lorem/example-text...\"".chr(10).chr(10).chr(32).
chr(32).chr(32).chr(32).chr(32).chr(143).chr(143).chr(143).chr(143).chr(143);
echo preg_replace('~"[^"]*"[^\x0b]+\v{2}"\K[^"]*~', "new string", $source);
Beautiful output:
"string1,blah;like: this..."
��
"new string"
�����
Live demo
Solved. It was a combination of things:
/mis was needed (instead of /mi)
\x0b was needed (instead of \v)
Complete working example:
<?php
$s = chr(32).chr(32).chr(7).chr(11).chr(11);
$s .= "string1,blah;like: this...". chr(10).chr(10).chr(32).chr(32).chr(32).chr(32).chr(138).chr(138);
$s .= chr(32).chr(32).chr(32).chr(32).chr(13).chr(7).chr(11).chr(11);
$s .= "string2/lorem/example-text...". chr(10).chr(10).chr(32).chr(32).chr(32).chr(32).chr(32).chr(143).chr(143).chr(143);
$result = preg_replace('/(.*string1.*?\x0b+)([[:print:]]+)/mis', "$1"."new string", $s);
echo "\n------------------------\n";
echo $result;
echo "\n------------------------\n";
Thanks for everyone's suggestions. It put me on the right track.
Related
I'm using this code inside PHP
case preg_match('/\/start( .*)?/', $text):
echo "got you";
break;
Using this regex all I need to do is catching following structure:
$text needs to be:
/start
or
/start xyz
Where "xyz" stands for random content. These are the two only formats which should be accepted by the regex. For some reason my regex seems to be not working as expected.
This should do the trick:
^\/start\s?[\S]*$
Here is an example in python DEMO:
import re
textlist = ["^/start xyz","/start","/start not to match"]
regex = "^/start\s?[\S]*$"
for text in textlist:
thematch = re.search(regex, text)
if thematch:
print ("match found")
else:
print ("no match sir!")
What it's doing: the line starts with /start and might have space, then there might be any amount of non space (including none) and then the line ends.
Hopefully that helps!
EDIT;
PHP version of this code.
$textlist = array("^/start xyz","/start","/start not to match");
$regex = "#^/start\s?[\S]*$#";
foreach($textlist as $text){
preg_match($regex, $text, $thematch);
if ($thematch){
print ("match found\n");
}else{
print ("no match sir!\n");
}
}
Demo here: https://3v4l.org/OFpnG
I have a string, that look like this "<html>". Now what I want to do, is get all text between the "<" and the ">", and this should apply to any text, so that if i did "<hello>", or "<p>" that would also work. Then I want to replace this string with a string that contains the string between the tags.
For example
In:
<[STRING]>
Out:
<this is [STRING]>
Where [STRING] is the string between the tags.
Use a capture group to match everything after < that isn't >, and substitute that into the replacement string.
preg_replace('/<([^>]*)>/, '<this is $1>/, $string);
here is a solution to test on the pattern exists and then capture it to finally modify it ...
<?php
$str = '<[STRING]>';
$pattern = '#<(\[.*\])>#';
if(preg_match($pattern, $str, $matches)):
var_dump($matches);
$str = preg_replace($pattern, '<this is '.$matches[1].'>', $str);
endif;
echo $str;
?>
echo $str;
You can test here: http://ideone.com/uVqV0u
I don't know if this can be usefull to you.
You can use a regular expression that is the best way. But you can also consider a little function that remove first < and last > char from your string.
This is my solution:
<?php
/*Vars to test*/
$var1="<HTML>";
$var2="<P>";
$var3="<ALL YOU WANT>";
/*function*/
function replace($string_tag) {
$newString="";
for ($i=1; $i<(strlen($string_tag)-1); $i++){
$newString.=$string_tag[$i];
}
return $newString;
}
/*Output*/
echo (replace($var1));
echo "\r\n";
echo (replace($var2));
echo "\r\n";
echo (replace($var3));
?>
Output give me:
HTML
P
ALL YOU WANT
Tested on https://ideone.com/2RnbnY
How can I find and replace the same characters in a string with two different characters? I.E. The first occurrence with one character, and the second one with another character, for the entire string in one go?
This is what I'm trying to do (so users need not type html in the body): I've used preg_replace here, but I'll willing to use anything else.
$str = $str = '>>Hello, this is code>> Here is some text >>This is more code>>';
$str = preg_replace('#[>>]+#','[code]',$str);
echo $str;
//output from the above
//[code]Hello, this is code[code] Here is some text [code]This is more code[code]
//expected output
//[code]Hello, this is code[/code] Here is some text [code]This is more code[/code]
But problem here is, both >> get replaced with [code]. Is it possible to somehow replace the first >> with [code] and the second >> with a [/code] for the entire output?
Does php have something to do this in one go? How can this be done?
$str = '>>Hello, this is code>> Here is some text >>This is more code>>';
echo preg_replace( "#>>([^>]+)>>#", "[code]$1[/code]", $str );
The above will fail if something like the following is your input:
>>Here is code >to break >stuff>>
To deal with this, use negative lookahead:
#>>((?!>[^>]).+?)>>#
will be your pattern.
echo preg_replace( "#>>((?!>[^>]).+?)>>#", "[code]$1[/code]", $str );
I am running a RST to php conversion and am using preg_match.
this is the rst i am trying to identify:
An example of the **Horizon Mapping** dialog box is shown below. A
summary of the main features is given below.
.. figure:: horizon_mapping_dialog_horizons_tab.png
**Horizon Mapping** dialog box, *Horizons* tab
Some of the input values to the **Horizon Mapping** job can be changed
during a Workflow using the internal programming language, IPL. For
details, refer to the *IPL User Guide*.
and I am using this regex:
$match = preg_match("/.. figure:: (.*?)(\n{2}[ ]{3}.*\n)/s", $text, &$result);
however it is returning as false.
here is a link of the expression working on regex
http://regex101.com/r/oB3fW7.
Are you sure that the line break is \n, is doubt, use \R:
$match = preg_match("/.. figure:: (.*?)(\R{2}[ ]{3}.*\R)/s", $text, &$result);
\R stands for either \n, \r and \r\n
My instinct would be to do some troubleshooting around the s flag as well as the $result variable passed by reference. To achieve the same without any interference from dots and the return variable, can you please try this regex:
..[ ]figure::[ ]([^\r\n]*)(?:\n|\r\n){2}[ ]{3}[^\r\n]*\R
In code, please try exactly like this:
$regex = "~..[ ]figure::[ ]([^\r\n]*)(?:\n|\r\n){2}[ ]{3}[^\r\n]*\R~";
if(preg_match($regex,$text,$m)) echo "Success! </br>";
Finally:
If this does not working, you might have a weird Unicode line break that php is not catching. To debug, for each character of your string, iterate through all the string's characters
Iterate: foreach(str_split($text) as $c) {
Print the character: echo $c . " value = "
Print the value from this function: . _uniord($c) . "<br />"; }
My users sometimes use chinese characters for the title of their input.
My slugs are in the format of /stories/:id-:name where an example could be /stories/1-i-love-php.
How do I allow chinese characters?
I have googled and found the japanese version of this answer over here.
Don't quite understand Japanese, so I am asking about the chinese version.
Thank you.
i have tested in Bengali characters
it may work. try this:
at first the coded page (write code where in the page) have to convert into encoding type in UTF-8, then write code.
code here:
function to_slug($string, $separator = '-') {
$re = "/(\\s|\\".$separator.")+/mu";
$str = #trim($string);
$subst = $separator;
$result = preg_replace($re, $subst, $str);
return $result;
}
$id=34;
$string_text="আড়াইহাজারে দেড় বছরের --- শিশুর -গলায় ছুরি";
$base_url="http://example.com/";
echo $target_url=$base_url.$id."-". #to_slug($string_text);
var_dump($target_url);
output:
http://example.com/34-আড়াইহাজারে-দেড়-বছরের-শিশুর-গলায়-ছুরি
string 'http://example.com/34-আড়াইহাজারে-দেড়-বছরের-শিশুর-গলায়-ছুরি' (length=136)