Getting data from JSON with PHP [duplicate] - php

Question

This question already has an answer here:
How to extract and access data from JSON with PHP?
(1 answer)
Closed 11 months ago.
Here's the json
[{"location":"USA","email":"test#test.com","sex":"male","age":"Unkown","other":null,"profile":{"net":["55","56"],"networks":[{"site_url":"http://site.com","network":"test","username":"mike"},{"site_url":"http://site.com/2","network":"test2","username":"mike2"}]},"name":"Mike Jones","id":111}]
I wanted to know how I could echo out all networks so it echos out the site_url,network, and user for each of the 2.
How would I get "name" at the end out of there as well?
Tanks!

Answer 1

Use json_decode()
http://php.net/manual/en/function.json-decode.php
$data = json_decode(...your sstring ...);
echo $data[0]->name;

Answer 2

Use json_decode to decode the JSON data. Then you can iterate the array with foreach and access the site_url‍s of each array item with another foreach like:
$arr = json_decode($json);
foreach ($arr as $obj) {
foreach ($obj->profile->networks as $network) {
echo $network->site_url;
}
}

Answer 3

http://lt2.php.net/json_decode

Answer 4

Here's a straight-forward example doing the two things that you ask for (see inline comments).
$json = '[{"location":"USA","email":"test#test.com","sex":"male","age":"Unkown","other":null,"profile":{"net":["55","56"],"networks":[{"site_url":"http://site.com","network":"test","username":"mike"},{"site_url":"http://site.com/2","network":"test2","username":"mike2"}]},"name":"Mike Jones","id":111}]';
// "Decode" JSON into (dumb) native PHP object
$data = json_decode($json);
// Get the first item in the array (there is only one)
$item = $data[0];
// Loop over the profile.networks array
foreach ($item->profile->networks as $network) {
// echos out the site_url,network, and user
echo "site_url = " . $network->site_url . PHP_EOL;
echo "network = " . $network->network . PHP_EOL;
echo "user = " . $network->username . PHP_EOL;
}
// Get "name" at the end
echo "name = " . $item->name . PHP_EOL;
It should output (if you're viewing as HTML, it will be munged onto one line… don't output as HTML).
site_url = http://site.com
network = test
user = mike
site_url = http://site.com/2
network = test2
user = mike2
name = Mike Jones

Answer 5

Building on aviv's answer...
$data = json_decode(...your sstring ...);
echo $data[0]->location; // USA
...
echo $data[0]->profile->net[0]; // 55
echo $data[0]->profile->net[1]; // 56
echo $data[0]->profile->networks[0]->site_url; // http://site.com
echo $data[0]->profile->networks[0]->network; // test
echo $data[0]->profile->networks[0]->username; // mike
echo $data[0]->profile->networks[1]->site_url; // http://site.com/2
echo $data[0]->profile->networks[1]->network; // test2
echo $data[0]->profile->networks[1]->username; // mike2
echo $data[0]->name; // Mike Jones