How to get all pid and styles attribute from following json data with minimum loop in php
{"general":{"note":{"display":false}},"elements":{"the-1":{"index":1,"src":"shirt1.png","pid":"pid-3563130","angle":0,"styles":"background:transparent;top:51.80000305175781px;left:122px;width:80px;height:80px;","background":"transparent","pos":{"top":51.80000305175781,"left":122},"size":{"width":80,"height":80},"details":{"other":""}},"the-2":{"index":2,"src":"shirt2.png","pid":"pid-132002","angle":0,"styles":"background:transparent;top:44.80000305175781px;left:155px;width:80px;height:80px;","background":"transparent","pos":{"top":44.80000305175781,"left":155},"size":{"width":80,"height":80},"details":{"other":""}}}}
Thanks
$str = '{"general":{"note":{"display":false}},"elements":{"the-1":{"index":1,"src":"shirt1.png","pid":"pid-3563130","angle":0,"styles":"background:transparent;top:51.80000305175781px;left:122px;width:80px;height:80px;","background":"transparent","pos":{"top":51.80000305175781,"left":122},"size":{"width":80,"height":80},"details":{"other":""}},"the-2":{"index":2,"src":"shirt2.png","pid":"pid-132002","angle":0,"styles":"background:transparent;top:44.80000305175781px;left:155px;width:80px;height:80px;","background":"transparent","pos":{"top":44.80000305175781,"left":155},"size":{"width":80,"height":80},"details":{"other":""}}}}';
$arr = json_decode($str, true);
foreach ($arr['elements'] as $element) {
echo 'pid: ' . $element['pid'] . '<br />';
echo 'styles: ' . $element['styles'] . '<br />';
}
use json_decode function in PHP to get assosiative array.
<?php
$myJson = '{"general":{"note":{"display":false}},"elements":{"the-1":{"index":1,"src":"shirt1.png","pid":"pid-3563130","angle":0,"styles":"background:transparent;top:51.80000305175781px;left:122px;width:80px;height:80px;","background":"transparent","pos":{"top":51.80000305175781,"left":122},"size":{"width":80,"height":80},"details":{"other":""}},"the-2":{"index":2,"src":"shirt2.png","pid":"pid-132002","angle":0,"styles":"background:transparent;top:44.80000305175781px;left:155px;width:80px;height:80px;","background":"transparent","pos":{"top":44.80000305175781,"left":155},"size":{"width":80,"height":80},"details":{"other":""}}}}';
$myArray = json_decode($myJson,true);
$myInnerArray = $myArray['elements'];
$styles = array();
foreach($myInnerArray as $element)
$styles[] = $element['styles'];
print_r($styles);
?>
PHP has great abilities to handle json.
Let's assume the JSON string you've posted above is stored in a PHP variable $myJSON.
So we can easily store an associative array of these values into $myJSONArray like so:
$myJSONArray = json_decode( $myJSON, true );
So, now we just loop through:
foreach( $myJSONArray['elements'] as $arr => $key )
echo( "A PID: " . $key['pid'] . "\n" );
See it in action on Codepad.
$json = json_decode('{"general":{"note":{"display":false}},"elements":{"the-1":{"index":1,"src":"shirt1.png","pid":"pid-3563130","angle":0,"styles":"background:transparent;top:51.80000305175781px;left:122px;width:80px;height:80px;","background":"transparent","pos":{"top":51.80000305175781,"left":122},"size":{"width":80,"height":80},"details":{"other":""}},"the-2":{"index":2,"src":"shirt2.png","pid":"pid-132002","angle":0,"styles":"background:transparent;top:44.80000305175781px;left:155px;width:80px;height:80px;","background":"transparent","pos":{"top":44.80000305175781,"left":155},"size":{"width":80,"height":80},"details":{"other":""}}}}', true);
$elements = $json['elements'];
foreach($elements as $element){
$pid = $element['pid'];
$styles = $element['styles'];
echo $pid.': '.$styles.'<br />';
}
Example here
Related
in this my php code
echo $_POST[result];
in this my php result
{
"result_code":0,
"err_cd":"",
"result_msg":"",
"store_id":"M20C2685",
"status":"APPROVED",
"order_no":"600a2a044c9be",
"tr_no":725,
"tr_price":1000,
"pay_price":1000,
"approved_day":"20210122",
"approved_time":"102744",
"param1":"",
"param2":""
}
I want to print out each value one by one. What should I do?
json_decode Parsing JSON
<?php
$str = '{"result_code":0,
"err_cd":"",
"result_msg":"",
"store_id":"M20C2685",
"status":"APPROVED",
"order_no":"600a2a044c9be",
"tr_no":725,
"tr_price":1000,
"pay_price":1000,
"approved_day":"20210122",
"approved_time":"102744",
"param1":"",
"param2":""
}';
$arr = json_decode($str, true);
echo $arr['err_cd'] . PHP_EOL;
echo $arr['result_msg'] . PHP_EOL;
echo $arr['store_id'] . PHP_EOL;
echo $arr['status'] . PHP_EOL;
// ......
// Circulates each value in the array
foreach ($arr as $item) {
echo $item . PHP_EOL;
}
I don't know who to export API
So the URL is:
https://en.wikipedia.org/w/api.php?action=query&prop=pageimages&format=json&pithumbsize=200&titles=Jean-Claude%20Van%20Damme
And I get
{"batchcomplete":"","query":{"pages":{"89265": {"pageid":89265,"ns":0,"title":"Jean-Claude Van Damme","thumbnail":{"source":"https://upload.wikimedia.org/wikipedia/commons/thumb/2/27/Jean-Claude_Van_Damme_2012.jpg/141px-Jean-Claude_Van_Damme_2012.jpg","width":141,"height":200},"pageimage":"Jean-Claude_Van_Damme_2012.jpg"}}}}
Who can I only export the source?
Now I have this code:
$json=file_get_contents("https://en.wikipedia.org/w/api.php?action=query&prop=pageimages&format=json&pithumbsize=200&titles=$title");
$details=json_decode($json);
echo $details['thumbnail']['source'];
So who I do?
You could use json_decode and pass true as the second parameter.
From the documentation:
When TRUE, returned objects will be converted into associative arrays.
Then I think what you are looking for is this:
$json=file_get_contents("https://en.wikipedia.org/w/api.php?action=query&prop=pageimages&format=json&pithumbsize=200&titles=Jean-Claude%20Van%20Damme");
$details=json_decode($json, true);
$source = $details['query']['pages']['89265']['thumbnail']['source'];
echo $source;
Will result in:
https://upload.wikimedia.org/wikipedia/commons/thumb/2/27/Jean-Claude_Van_Damme_2012.jpg/141px-Jean-Claude_Van_Damme_2012.jpg
Try this.
$json = file_get_contents("https://en.wikipedia.org/w/api.php?action=query&prop=pageimages&format=json&pithumbsize=200&titles=Jean-Claude%20Van%20Damme");
$details = json_decode($json);
$pages = $details->query->pages;
$output = '';
foreach ($pages as $pageid => $content){
$image_url = $content->thumbnail->source;
$title = $content->title;
$output .= '<img src="'.$image_url.'"/>'.$title;
}
echo $output;
I have a JSON file called from an URL. I've checked and I'm getting the the data from the URL.
I've tried a lot, but I can't get the loop foreach to work - what is wrong?
<?php
$url = 'http://banen.klintmx.dk/json/ba-simple-proxy.php?url=api.autoit.dk/car/GetCarsExtended/59efc61e-ceb2-463b-af39-80348d771999';
$json= file_get_contents($url);
$data = json_decode($json);
$rows = $data->{'contents'};
foreach($rows as $row) {
echo '<p>';
$FabrikatNavn = $row->{'contents'}->{'FabrikatNavn'};
$ModelNavn = $row->{'contents'}->{'ModelNavn'};
$PrisDetailDkk = $row->{'contents'}->{'PrisDetailDkk'};
echo $FabrikatNavn . $ModelNavn . ' Pris ' . $PrisDetailDkk;
echo '</p>';
}
?>
The actual problem is you trying to access content object again. Just change your foreach snippet with,
foreach ($rows as $row) {
echo '<p>';
$FabrikatNavn = $row->FabrikatNavn;
$ModelNavn = $row->ModelNavn;
$PrisDetailDkk = $row->PrisDetailDkk;
echo $FabrikatNavn . $ModelNavn . ' Pris ' . $PrisDetailDkk;
echo '</p>';
}
DEMO.
Use json_decode($data, true) so that it parses the JSON content into a PHP array. So it will be something like
$rows = $data['contents'];
foreach($rows as $row) {
echo '<p>';
$FabrikatNavn = $row['contents']['FabrikatNavn'];
$ModelNavn = $row['contents']['ModelNavn'];
$PrisDetailDkk = $row['contents']['PrisDetailDkk'];
echo $FabrikatNavn . $ModelNavn . ' Pris ' . $PrisDetailDkk;
echo '</p>';
}
Take a look at using json_decode($json, true) as this will convert the data to an associative array which seems to be the way you are approaching the solution.
Check the output by printing with var_dump() or print_r()
Try like this
$data = json_decode($json,true); //decode json result as array and thenloop it
print '<pre>';
print_r($data);
foreach($data as $row){
//do something here
}
If I wanted to echo the link of a general thread on 4chan.
Here's what I was thinking of, however I have no idea on what to do
$jsonurl = "http://a.4cdn.org/vg/catalog.json";
$json = file_get_contents($jsonurl);
$json_output = json_decode($json);
foreach( $json_output as $no )
{
if(strpos(sub, 'DOTA')) { //Not sure how I would do this
//echo the "no" of it in the json
}
}
Had to look at the JSON data to see what you were looking for. Give this a try
$jsonurl = "http://a.4cdn.org/g/catalog.json";
$json = file_get_contents($jsonurl);
$json_output = json_decode($json);
foreach ($json_output as $page) {
foreach($page->threads as $thread) {
if (isset($thread->sub)) {
$sub = $thread->sub;
$no = $thread->no;
echo $sub . ', Thread Number: ' . $no . '<br />';
/*
if (strpos($sub, 'DOTA') !== false) {
echo 'Found DOTA!!! Thread Number is: ' . $thread->no;
}
*/
}
}
}
You should study the JSON data that you receive in order to know how to extract the data. This is one way of doing it:
foreach( $json_output as $page ) {
foreach ($page->threads as $t) {
echo 'http://boards.4chan.org/vg/res/' . $t->no . ', ';
}
}
I need to convert a CSV file to JSON on the server using PHP. I am using this script which works:
function csvToJSON($csv) {
$rows = explode("\n", $csv);
$i = 0;
$len = count($rows);
$json = "{\n" . ' "data" : [';
foreach ($rows as $row) {
$cols = explode(',', $row);
$json .= "\n {\n";
$json .= ' "var0" : "' . $cols[0] . "\",\n";
$json .= ' "var1" : "' . $cols[1] . "\",\n";
$json .= ' "var2" : "' . $cols[2] . "\",\n";
$json .= ' "var3" : "' . $cols[3] . "\",\n";
$json .= ' "var4" : "' . $cols[4] . "\",\n";
$json .= ' "var5" : "' . $cols[5] . "\",\n";
$json .= ' "var6" : "' . $cols[6] . "\",\n";
$json .= ' "var7" : "' . $cols[7] . "\",\n";
$json .= ' "var8" : "' . $cols[8] . "\",\n";
$json .= ' "var9" : "' . $cols[9] . "\",\n";
$json .= ' "var10" : "' . $cols[10] . '"';
$json .= "\n }";
if ($i !== $len - 1) {
$json .= ',';
}
$i++;
}
$json .= "\n ]\n}";
return $json;
}
$json = csvToJSON($csv);
$json = preg_replace('/[ \n]/', '', $json);
header('Content-Type: text/plain');
header('Cache-Control: no-cache');
echo $json;
The $csv variable is a string resulting from a cURL request which returns the CSV content.
I am sure this is not the most efficient PHP code to do it because I am a beginner developer and my knowledge of PHP is low. Is there a better, more efficient way to convert CSV to JSON using PHP?
Thanks in advance.
Note. I am aware that I am adding whitespace and then removing it, I do this so I can have the option to return "readable" JSON by removing the line $json = preg_replace('/[ \n]/', '', $json); for testing purposes.
Edit. Thanks for your replies, based on them the new code is like this:
function csvToJson($csv) {
$rows = explode("\n", trim($csv));
$csvarr = array_map(function ($row) {
$keys = array('var0','var1','var2','var3','var4','var5','var6','var7','var8','var9','var10');
return array_combine($keys, str_getcsv($row));
}, $rows);
$json = json_encode($csvarr);
return $json;
}
$json = csvToJson($csv);
header('Content-Type: application/json');
header('Cache-Control: no-cache');
echo $json;
Well there is the json_encode() function, which you should use rather than building up the JSON output yourself. And there is also a function str_getcsv() for parsing CSV:
$array = array_map("str_getcsv", explode("\n", $csv));
print json_encode($array);
You must however adapt the $array if you want the JSON output to hold named fields.
I modified the answer in the question to use the first line of the CSV for the array keys. This has the advantage of not having to hard-code the keys in the function allowing it to work for any CSV with column headers and any number of columns.
Here is my modified version:
function csvToJson($csv) {
$rows = explode("\n", trim($csv));
$data = array_slice($rows, 1);
$keys = array_fill(0, count($data), $rows[0]);
$json = array_map(function ($row, $key) {
return array_combine(str_getcsv($key), str_getcsv($row));
}, $data, $keys);
return json_encode($json);
}
None of these answers work with multiline cells, because they all assume a row ends with '\n'. The builtin fgetcsv function understands that multiline cells are enclosed in " so it doesn't run into the same problem. The code below instead of relying on '\n' to find each row of a csv lets fgetcsv go row by row and prep our output.
function csv_to_json($file){
$columns = fgetcsv($file); // first lets get the keys.
$output = array(); // we will build out an array of arrays here.
while(!feof($file)){ // until we get to the end of file, we'll pull in a new line
$line = fgetcsv($file); // gets the next line
$lineObject = array(); // we build out each line with our $columns keys
foreach($columns as $key => $value){
$lineObject[$value] = $line[$key];
}
array_push($output, $lineObject);
}
return json_encode($output); // encode it as json before sending it back
}
Some tips...
If you have URL opening enabled for fopen() and wrappers, you can use fgetscsv().
You can build an array of the CSV, and then convert it with PHP's native json_encode().
The correct mime type for JSON is application/json.
You could probably reduce the overhead by removing all the spaces and \n's. But that's in your note.
You could increase the performance by skipping the preg_replace and passing a boolean that would turn it on and off.
Other than that, the variable unrolling of your var[1-10] actually is good, as long as there are always ten varaibles.
The explode and the foreach approach are just fine.
I recommend using Coseva (a csv parsing library) and using the built in toJSON() method.
<?php
// load
require('../src/CSV.php');
// read
$csv = new Coseva\CSV('path/to/my_csv.csv');
// parse
$csv->parse();
// disco
echo $csv->toJSON();