I make this code that, after 9 seconds, it call an ajax function, and print the result elaborated from the server to the client.
This is the JS code :
function changeSponsor() {
$.ajax({
type: 'POST',
cache: false,
url: './auth/ajax.php',
data: 'id=changespon',
success: function(msg) {
$('.menusponsor').hide().fadeIn(1000).html(msg);
}
});
}
$(document).ready(function() {
x=window.setInterval("changeSponsor()", 9000);
});
the result is printed on a div at the top of the page. when the result is printed to the client (after, as said, 9 seconds), and I am at the bottom of the page, the page go automatically at the top. I don't want this.
You can see an exemple at this link : open this page, go to the bottom (is not so long this page) and after few seconds (9). You will se the page scroll at the top.
How can resolve this problem? Cheers
It doesn't look like anything that you mention would move the page up, it must be something else?
I found that the page moves up normally when you do something to the url, like adding a hash (#)? are you adding a hash or altering the url in any way?
solution:
oh the problem is with your html, you need to hide the child of menusponsor and not the container itself.
try this
function changeSponsor() {
$.ajax({
type: 'POST',
cache: false,
url: './auth/ajax.php',
data: 'id=changespon',
success: function(msg) {
$('.menusponsor').find('div').hide().fadeIn(1000).html(msg);
}
});
}
Can you tell us a little more about what happens when the page jumps to the top? Are you calling this function somewhere other than this setInterval?
What does your html look like? If you're replacing a huge portion of the page, it's possible that, for a split second, the page is very short, putting you at the top of the page.
Related
Something weird - I have the script inside the bootstrap modal.
sometimes the script is loaded and works and sometimes it doesn't.
here is a URL for example:
https://ns6.clubweb.co.il/~israelig/sites/followmyroutes/test_sec.php
Click on the button and see the modal, then close the modal and open it again. After the couple of times, the scripts inside the modal stops working (scripts like form validation [when you submit it], image browser)
How can I fix it so all the script will work every time?
The way you populate the html is right or not suggested to be advised by coders. Check again from where you got the documentation.
your existing code from backend call
$(document).on('ready', function() {
$("#input-8").fileinput({
});
});
Try changing like
$(document).on('ready', function() {
setImageUploader();
});
function setImageUploader(){
$(document).find("#input-8").fileinput({
});
}
And also
$.ajax({
cache: false,
type: 'GET',
url: 'itinPage-secManage.view.php',
data: info,
success: function(data) {
$modal.find('.modal-body').html(data);
setTimeout(function(){ //added this line.
setImageUploader()
})
}
});
i think the problem in the syncronisation of the request, you can use Ajax reque
It looks like your common libraries like jquery bootstrap-datepicker, fileinput theme etc are being get every time the modal is launched.
This may cause a sort of namespace corruption or some weird side effect of the kind you seem to see.
You could put all the common libraries outside of the modal to prevent this from happening.
the problem in the ajax request, I means you maste waite while the request it's done.
var request = $.ajax({
cache: false,
type: 'GET',
url: 'itinPage-secManage.view.php',
data: info
});
request.done(function(data) {
$modal.find('.modal-body').html(data);
});
I know there are a few topics on this subject, but after I spent 2 or 3 hours trying to get something good out of them, I just decided to ask this question on a specific point.
So here is my problem : I have got a table and I am using a jQuery function to select a row of this table. Now what i actually want to do is getting the text content of the div contained in the first td of the row.
I already used a getter on it and I am checking the getted value with an alert as you can see in th following code :
$("#myRow").click(function() {
$(".selectedRow").removeClass("selectedRow").addClass("unselected");
$(this).addClass("selectedRow").removeClass("unselected");
var myValue = $(".selectedRow .firstTd div").text();
alert('myValue');
});
So now, what I am trying to do is to send the myValue variable through an ajax request by replacing my alert by this piece of code :
$.ajax({
type: 'get',
url: 'index.php',
data: {"myValue" : myValue},
success: function(rs)
{
alert(myValue);
}
});
Then, back to my php code, I am tring to observe the obtained variable by using an echo, just like this :
<?php echo $_GET['myValue']; ?>
But there is just no way for me to know if my page got it beacause the echo just prints nothing... So i was wondering if someone could do something for me. Thanks.
PS : Oh, by the way ; I don't really know if this can matter, but my page index.php already receives data by a post.
You can't, but read this, php is on the server, while js usually runs on the client, but your ajax trick can work. Just do some processing in the recieving php.
I usually put my ajax recieving end in a different file, and process the rest by the variables posted.
Just try to put the $_GET['myValue']; into an if, or a switch.
Do a var dump of the request var to see if anything is coming through:
<?php
var_dump($_REQUEST);
If not, do a console.log() on 'myValue' to make sure it exists before sending the ajax request - the issue may lie in your js rather than you php.
If you are POSTing data then adjust accordingly - e.g.
$.ajax({
type: 'post',
url: 'index.php',
data: {"myValue" : myValue},
success: function(data)
{
console.log('successfuly posted:');
console.log(data);
}
});
then:
<?php echo $_POST['myValue']; ?>
If you were using GET your data would be in the url, e.g:
index.php?myValue=something
I'm not sure if you are aware of that, but you should wrap you function in document ready statement as below.
Next, call the AJAX request on some action, in this case we can use a click on the row in table.
$(document).ready(function () {
$("#myRow").click(function() {
$(".selectedRow").removeClass("selectedRow").addClass("unselected");
$(this).addClass("selectedRow").removeClass("unselected");
var myValue = $(".selectedRow .firstTd div").text();
alert('myValue');
$.ajax({
type: 'get',
url: 'index.php',
data: {"myValue" : myValue},
success: function(data)
{
console.log('you have posted:' + data.myValue);
}
});
});
});
Okay so it seems that i totally misunderstanded on the way that the $.ajax function works.
I now do use the $.post function (which is actually the same), this way :
$.post('pageElement.php', { myValue : $(".selectedRow .firstTd div").text() },
function(data) { $("#test").html(data); }
);
The url "pageElement.php" refers to a page containing this code :
<div><?php echo $_POST['myValue']; ?></div>
The function called at the end of the process just puts this code into a div of my original page, so i can use it as a php variable now and then send it to another page through a form.
I have this JavaScript code:
$(document).ready(function(){
$('#sel').change(function(){
$.ajax({
type: "POST",
url: "modules.php?name=TransProject_Management&file=index",
data: "&op=index_stat&stat="+$(this).val(),
cache: false,
success: function(data) {
//alert(data);
$("#ajax_results").html(data);
}
});
});
});
On status change i need to refresh a div without page reload. But it returns blank page. If i try alert the result on success, i get the response, also i checked with inspect element, its ok. The problem is that it returns blank page.
The file i'm working on, is the same( modules.php?name=TransProject_Management&file=index ) i called in ajax.
the html:
<body>
//...
<div id="ajax_results">
//.....
//somewhere here is the select option <select id="sel">......</select>
//.....
</div>
</body>
Any help, would be very appreciated.
use the following code to return your response html:
echo json_encode(array($your_response));
Then in your javascript, you will need to reference the data as:
success: function(data) {
$("#ajax_results").html(data[0]);
}
since it is now an array.
this in your ajax function refers to the jQuery XHR object, NOT the $('#sel') object. Just assign it to a variable before the ajax function like var sel = $(this) then use it later inside the function. Try this:
$('#sel').change(function(){
var sel = $(this);
$.ajax({
type: "POST",
url: "modules.php?name=TransProject_Management&file=index",
data: "&op=index_stat&stat="+sel.val(),
cache: false,
success: function(data) {
//alert(data);
$("#ajax_results").html(data);
}
});
});
});
Hmm, first glance the code looks good. Have you tried using Chrome debug tools? Hit F12 and check the Network tab, this will show you what is being returned. You can also debug without using an alert so you can step through to see what exactly the properties are.
Just thought, you might need to add 'd' to the data returned. Anyway, if you do what I suggested above, put a pause break on the line and run the code you will see what you need.
Based on your comments below the question, it seems that you are using the same script to display your page and to call in the javascript. This script seems to return a complete html page, starting with the <html> tag.
A page can only have one <html> tag and when you try to dump a complete html page inside an element in another page, that will lead to invalid html and unpredictable results.
The solution is to have your ajax script only return the necessary elements / html that needs to be inserted in #ajax_results, nothing more.
I'm trying to implement a single-star rating (i.e. a like button).
I want to change (toggle) the star image. The only problem it seems to have is that while using $.ajax, on "success:" part, the src attr (or anything else really, like .css) applies for one (the first) time ONLY! In fact, the client has to refresh the page to see the latest star image/status (which loads from the db).
Here's the code:
<script language="javascript">
// Ajax: Star
$("#p<?php echo $pID;?>").find('.star').click(function (e) {
e.preventDefault();
$.ajax({
type: "POST",
url: "./ajax.php",
data: "pID=<?php echo $pID;?>",
cache: false,
success: function(html)
{
$("#s<?php echo $pID;?>").attr("src",html);
}
});
});
// END OF: Ajax: Star
</script>
the php file echos back a filename which is meant to be replaced with the src attribute (e.g. star-on.png OR star-off.png)
So I think the question is: Why the "success: function" triggers only once?
I finally realized what the problem is. It is due to the server side file (php) as it always evaluates the static data given from the client side file. All I need to do is refreshing the toggle's trigger on my php file.
In my code I have an iFrame which loads dynamic content it's like a webpage(B.html) inside a page(A.php). in "A.php" user can edit inline the "B.html" once the process of editing has completed. In my submission I am sending iframes information to another page (script.php). I tried everything but content is not comming up in "script.php".
In nutshell, I want to tranfer my big html text with all stuff to a PHP via AJAX. I have no idea how to do it... my code would be something like below :-
Code for "A.php" inscript :
"myframe" is the iframe which contains the big chunk of HTML.
sendString = $("#myframe").contents();//Tried everything here[JSON as well]
$.ajax({
url: "script.php",
type: "POST",
data: sendingString,
cache: false,
success: function (html) {
return html;
}
});
Any help would be appreciated.
Regards,
Amjad
$("#myframe").contents() will get you it's nodes as a jQuery object. Try $("#myframe").html() instead to get the contents as a string.
EDIT: Oh, and it also helps if you fix your variable names. Change data: sendingString to data: sendString.