is there a way i can convert text into Image & then Rotate it & then display it all using script\code to display in the webpage
Yes, you can, take a look at GD's imagettfext or Imagick's annotateImage.
You can write a script, which you embed in your html-page like an usual image:
<img src="rotatedtext.php?text=blablubb" />
Don't forget to set the content-type of the http-header in that script to image/png (I recommend png for that purpose) before outputing the png-data:
//create the image here and then:
header("Content-Type: image/png");
imagepng($image);
Related
I have a PHP function that does on-the-fly image resizing for thumbnail creation.
I am having trouble as it's just displaying raw image stream instead of the actual image.
My code is using a function called thumbnail:
$thumbnail = thumbnail($item['filename'], 209, 137);
imagejpeg($thumbnail);
I've tried putting in:
header("Content-type: image/jpeg");
However, this just expects the full page to be an image. I have absolutely no idea where to go from here, been working at it for a while. I'd rather not save the image to disk although it's looking like this might be necessary.
You either
Do it the normal way
This mean you point at one url, and serve the contents of one image:
<img src="myimage.php">
and myimage.php is a script that looks like:
header('Content-type: image/jpeg');
imagejpeg($thumbnail);
die;
This technique has the advantage of being.. the normal way of doing things.
OR
Output the image inline
Using data uris outputting the contents as a base64 encoded string
<img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAUA
AAAFCAYAAACNbyblAAAAHElEQVQI12P4//8/w38GIAXDIBKE0DHxgljNBAAO
9TXL0Y4OHwAAAABJRU5ErkJggg==" alt="Red dot">
This technique is most appropriate with small images.
It has the advantage of meaning all the images are in the main http request - at the (possibly sizable) disadvantage of making the page harder to edit/build and possibly negating the benefits of browser caching (unless the html page is itself cached).
Being normal is easier
Regarding this statement in the question:
However, this just expects the full page to be an image
That's right - if you do it the normal way you want to point at your php script with the src attribute of an image tag, and server only an image - i.e. the exact same response as if you were pointing at an image file with a browser.
Unless you have a good reason to do things a different way - the "normal" way is a good place to start.
You can point an html img tag to an php file.
<img src='thumbnail.php?file=<?php echo $item['filename']; ?>' />
Then on your php file you display the image and change the headers since all it is doing is displaying an image.
$thumbnail = thumbnail($_GET['filename'], 209, 137);
imagejpeg($thumbnail);
header("Content-type: image/jpeg");
You need to insert the image like you would a normal image in HTML and create the image in a separate PHP file:
image.php
<?php
$img = imagecreate(100,100); //Create an image 100px x 100px
imagecolorallocate($img, 255,0,0); //Fill the image red
header('Content-type: image/jpeg'); //Set the content type to image/jpg
imagejpeg($img); //Output the iamge
imagedestroy($img); //Destroy the image
?>
myWebpage.html
<img src="image.php" />
I like the photo that I keep stored in my view using the following code but the problem is I can not play because I need the header('Content-Type: image/jpeg'); implementation would then display., But I have orders sure before header('Content-Type: image/jpeg'); What should I do to display images with no header.
If you're only outputting the image, then it doesn't matter if you have other PHP instructions before it since the only output should be the image.
If you are trying to output an image directly into an HTML document, consider using a data URI:
<img src="data:image/jpeg;base64,<?php echo base64_encode($imagedata); ?>" />
I have a PHP function that does on-the-fly image resizing for thumbnail creation.
I am having trouble as it's just displaying raw image stream instead of the actual image.
My code is using a function called thumbnail:
$thumbnail = thumbnail($item['filename'], 209, 137);
imagejpeg($thumbnail);
I've tried putting in:
header("Content-type: image/jpeg");
However, this just expects the full page to be an image. I have absolutely no idea where to go from here, been working at it for a while. I'd rather not save the image to disk although it's looking like this might be necessary.
You either
Do it the normal way
This mean you point at one url, and serve the contents of one image:
<img src="myimage.php">
and myimage.php is a script that looks like:
header('Content-type: image/jpeg');
imagejpeg($thumbnail);
die;
This technique has the advantage of being.. the normal way of doing things.
OR
Output the image inline
Using data uris outputting the contents as a base64 encoded string
<img src="data:image/png;base64,iVBORw0KGgoAAAANSUhEUgAAAAUA
AAAFCAYAAACNbyblAAAAHElEQVQI12P4//8/w38GIAXDIBKE0DHxgljNBAAO
9TXL0Y4OHwAAAABJRU5ErkJggg==" alt="Red dot">
This technique is most appropriate with small images.
It has the advantage of meaning all the images are in the main http request - at the (possibly sizable) disadvantage of making the page harder to edit/build and possibly negating the benefits of browser caching (unless the html page is itself cached).
Being normal is easier
Regarding this statement in the question:
However, this just expects the full page to be an image
That's right - if you do it the normal way you want to point at your php script with the src attribute of an image tag, and server only an image - i.e. the exact same response as if you were pointing at an image file with a browser.
Unless you have a good reason to do things a different way - the "normal" way is a good place to start.
You can point an html img tag to an php file.
<img src='thumbnail.php?file=<?php echo $item['filename']; ?>' />
Then on your php file you display the image and change the headers since all it is doing is displaying an image.
$thumbnail = thumbnail($_GET['filename'], 209, 137);
imagejpeg($thumbnail);
header("Content-type: image/jpeg");
You need to insert the image like you would a normal image in HTML and create the image in a separate PHP file:
image.php
<?php
$img = imagecreate(100,100); //Create an image 100px x 100px
imagecolorallocate($img, 255,0,0); //Fill the image red
header('Content-type: image/jpeg'); //Set the content type to image/jpg
imagejpeg($img); //Output the iamge
imagedestroy($img); //Destroy the image
?>
myWebpage.html
<img src="image.php" />
All,
I am executing a PHP script through CURL which returns a PNG file as an output. How can I show the png file in a php web page?
echo '<img src="urltotheimage.php" alt="Alt text" />';
First of all, why do you need to fetch a PNG through CURL? There's better ways to get a image from server, for example using the <img /> tag..
Anyways, I assume you are getting the binary data in a variable, you can output the image by setting appropriate headers and echoing the data:
header('Content-type: image/png');
echo $image;
as you are receiving the string representing the png and if that is base64 encoded then you can embed directly on the image tag as follows:
<img src="data:image/png;base64,aAbBcCdDeEfFgGhH..." />
where aAbBcCdDeEfFgGhH... would be the image string.
see more on data uri's here: http://en.wikipedia.org/wiki/Data_URI_scheme#Inclusion_in_HTML_or_CSS_using_PHP
I have a web page that displays images that I don't know their size in advance. I was trying to use the GD functions to make the script resize and crop the images from me " Just before they are displayed.. I don't need caches" but I failed.
I need a script that I can call like this
<img src="display.php?src=blablabla&height=100&width=200" ?>
or even by calculating the width and height of css to preserve the proportions and make the image touch the box from inside like
<img src="blabla.jpg" style="height:<?php echo $height; ?>; width:<?php echo width; ?>" />
I don't need any sort of caching. How can I do that ?
WideImage rlz! :)
The resize's like that:
header('Content-type: image/jpeg');
echo WideImage::load('image.jpg')->resize(200, 100)->asString('jpg', 80);
// image.jpg resized at 200x100 with 80% of quality
You'll need to use the first style. Because this would be happening server-side, you can't check the CSS to get the desired size.
You just need to use the GD functions to open the appropriate file, use imagecopyresampled() to resize it, and then output to the buffer using imagejpeg. Don't forget to set the right headers:
header('Content-type: image/jpeg');
OR phpthumb http://phpthumb.sourceforge.net/
Demo is available at: http://phpthumb.sourceforge.net/demo/demo/phpThumb.demo.demo.php
You are looking for TimThumb (Demo | Source Code):
Simply copy the source code into a new
document called ‘timthumb.php’, place
it in a folder on your site (ex:
/scripts/) and call the image like
this:
<img src="/scripts/timthumb.php?src=/images/whatever.jpg&h=150&w=150&zc=1" alt="">