Count number of different strings? - php

I have an array that looks like
Array
(
[1] => Array
(
[0] => Date
[1] => Action
)
[2] => Array
(
[0] => 2011-01-22 11:23:19
[1] => SHARE_TWEET
)
[3] => Array
(
[0] => 2011-01-22 11:23:19
[1] => SHARE_FACEBOOK
)
and many other different values (about 10), what I want to do is I want to count the number of times a string is in the array. I was going to use array_count_values but it doesn't count multidimensional arrays.
Any other options?

This could be done by first flattening the array, and then using array_count_values() on it:
For flattening, here is the trick:
$array = call_user_func_array('array_merge', $arrays);
And then:
$counts = array_count_values($array);
Output:
array (
'Date' => 1,
'Action' => 1,
'2011-01-22 11:23:19' => 2,
'SHARE_TWEET' => 1,
'SHARE_FACEBOOK' => 1,
)
Full code:
$array = call_user_func_array('array_merge', $arrays);
var_export(array_count_values($array));

Any time you're dealing with arrays, especially with loops in PHP I can't string enough suggest you look at the array documentation, You'd be suprised how quickly you realise most of the loops in your code is unnecessary. PHP has a built in function to achieve what you're after called array_walk_recursive. And since you're using PHP5 you can use closures rather that create_function (which can be very troublesome, especially to debug, and can't be optimised by the PHP interpreter afik)
$strings = array();
array_walk_recursive($arr, function($value, $key) use (&$strings) {
$strings[$value] = isset($strings[$value]) ? $strings[$value]+1 : 1;
});
I know, unary statements aren't always clear, but this one is simple enough, but feel free to expand out the if statement.
The result of the above is:
print_r($strings);
Array
(
[Date] => 1,
[Action] => 1,
[2011-01-22 11:23:19] => 2,
[SHARE_TWEET] => 1,
[SHARE_FACEBOOK] => 1,
)

Pseudo Code
$inputArray = // your array as in the example above
foreach ($inputArray as $key => $value) {
$result[$value[1]] = $result[$value[1]] + 1;
}
var_dump($result);

Here is a way to do the job:
$arr = Array (
1 => Array (
0 => 'Date',
1 => 'Action'
),
2 => Array (
0 => '2011-01-22 11:23:19',
1 => 'SHARE_TWEET'
),
3 => Array (
0 => '2011-01-22 11:23:19',
1 => 'SHARE_FACEBOOK'
)
);
$result = array();
function count_array($arr) {
global $result;
foreach($arr as $k => $v) {
if (is_array($v)) {
count_array($v);
} else {
if (isset($result[$v])) {
$result[$v]++;
} else {
$result[$v] = 1;
}
}
}
}
count_array($arr);
print_r($result);
output:
Array
(
[Date] => 1
[Action] => 1
[2011-01-22 11:23:19] => 2
[SHARE_TWEET] => 1
[SHARE_FACEBOOK] => 1
)

Related

php merge arrays and change its grouping [duplicate]

I have a multidimensional array and am trying to group them according to the value in a specific column.
I'm trying to group them by level, but I won't actually know the level beforehand. So, it's not like I can put it in a for loop and say while $i < 7, because I won't know that 7 is the maximum value for the level key, and frankly, I'm not sure that's how I would need to do it even if I did.
[
['cust' => 'XT8900', 'type' => 'standard', 'level' => 1],
['cust' => 'XT8944', 'type' => 'standard', 'level' => 1],
['cust' => 'XT8922', 'type' => 'premier', 'level' => 3],
['cust' => 'XT8816', 'type' => 'permier', 'level' => 3],
['cust' => 'XT7434', 'type' => 'standard', 'level' => 7],
]
Desired result:
Array (
[1] => Array (
[0] => Array (
[cust] => XT8900
[type] => standard
)
[1] => Array (
[cust] => XT8944
[type] => standard
)
)
[3] => Array (
[2] => Array (
[cust] => XT8922
[type] => premier
)
[3] => Array (
[cust] => XT8816
[type] => permier
)
)
[7] => Array (
[4] => Array (
[cust] => XT7434
[type] => standard
)
)
)
Best way, if you have control over building the initial array, is just set things up like that at the start as you add entries.
If not then build a temporary array to sort:
foreach ($input_arr as $key => &$entry) {
$level_arr[$entry['level']][$key] = $entry;
}
Leaves you with the form you wanted and everything referenced together.
Build the array like that in the first place though if at all possible.
You need to group them by level first
Use foreach to loop into array check if the level is the same with the previous item then group it with that array
$templevel=0;
$newkey=0;
$grouparr[$templevel]="";
foreach ($items as $key => $val) {
if ($templevel==$val['level']){
$grouparr[$templevel][$newkey]=$val;
} else {
$grouparr[$val['level']][$newkey]=$val;
}
$newkey++;
}
print($grouparr);
The output of print($grouparr); will display like the format you hoped for
You can also try to
print($grouparr[7]);
Will display
[7] => Array (
[4] => Array (
[cust] => XT7434
[type] => standard
)
)
Or
print($grouparr[3]);
Will display
[3] => Array (
[2] => Array (
[cust] => XT8922
[type] => premier
)
[3] => Array (
[cust] => XT8816
[type] => permier
)
)
Here is the solution I landed on for an identical problem, wrapped as a function:
function arraySort($input,$sortkey){
foreach ($input as $key=>$val) $output[$val[$sortkey]][]=$val;
return $output;
}
To sort $myarray by the key named "level" just do this:
$myArray = arraySort($myArray,'level');
Or if you didn't want it as a function, just for a one time use, this would create $myNewArray from $myArray grouped by the key 'level'
foreach ($myArray as $key=>$val) $myNewArray[$val['level']][]=$val;
function group_assoc($array, $key) {
$return = array();
foreach($array as $v) {
$return[$v[$key]][] = $v;
}
return $return;
}
//Group the requests by their account_id
$account_requests = group_assoc($requests, 'account_id');
$result = array();
foreach ($yourArrayList as $data) {
$id = $data['level'];
if (isset($result[$id])) {
$result[$id][] = $data;
} else {
$result[$id] = array($data);
}
}
Best ans.
$levels = array_unique(array_column($records, 'level'));
$data = array();
foreach($records as $key => $value){
$data[$levels[array_search($value['level'],$levels )]][] = $value ;
}
print_r($data);
To generate the question's exact desured output from the sample input, pull/pop the last value from each row, use that value as the first level grouping key. Then use the original first level index as the second level key. Then push the two remaining elements into the group's subset.
Code: (Demo)
$result = [];
foreach ($array as $key => $row) {
$result[array_pop($row)][$key] = $row;
}
var_export($result);
For functional style syntax, use array_reduce(). (Demo)
var_export(
array_reduce(
array_keys($array),
function($result, $key) use ($array) {
$result[array_pop($array[$key])][$key] = $array[$key];
return $result;
}
)
);
function _group_by($array,$key,$keyName)
{
$return = array();
foreach($array as $val) {
$return[$keyName.$val[$key]][] = $val;
}
return $return;
} //end of function

Group and merge subarray data based on one column value

I have an array in PHP code below, and I want to convert this array to be grouped by data value. It's always hard to simplify arrays.
Original array:
Array
(
[0] => Array
(
[date] => 2017-08-22
[AAA] => 1231
)
[1] => Array
(
[date] => 2017-08-21
[AAA] => 1172
)
[2] => Array
(
[date] => 2017-08-20
[AAA] => 1125
)
[3] => Array
(
[date] => 2017-08-21
[BBB] => 251
)
[4] => Array
(
[date] => 2017-08-20
[BBB] => 21773
)
[5] => Array
(
[date] => 2017-08-22
[CCC] => 3750
)
[6] => Array
(
[date] => 2017-08-20
[CCC] => 321750
)
)
Below is my desired array:
Array
(
[2017-08-22] => Array
(
[AAA] => 1231
[CCC] => 3750
)
[2017-08-21] => Array
(
[AAA] => 1172
[BBB] => 251
)
[2017-08-20] => Array
(
[AAA] => 1125
[BBB] => 21773
[CCC] => 321750
)
)
It is also ok to have empty null value if the data doesn't exist. [BBB] => NULL for 2017-08-22.
Can anybody help? Thanks in advance...
A simple loop should do this..
$group = [];
foreach ($data as $item) {
if (!isset($group[$item['date']])) {
$group[$item['date']] = [];
}
foreach ($item as $key => $value) {
if ($key == 'date') continue;
$group[$item['date']][$key] = $value;
}
}
Here : this should do the work.
$dst_array = array();
foreach ($array as $outerval) {
foreach ($outerval as $key => $innerval) {
if ($key != 'date') {
$dst_array[$outerval['date']][$key] = $innerval;
}
}
}
It iterates through the array and then through the entries in each subarray. Any any that is not a date is assigned in the destination array in the subarray corresponding to its date and with its own current key.
I definitely wouldn't recommend any techniques that involve more than one loop -- this process can certainly be performed in a single loop.
If you like language construct iteration, use a foreach() loop: (Demo)
$result = [];
foreach ($array as $row) {
$date = $row['date'];
unset($row['date']);
$result[$date] = array_merge($result[$date] ?? [], $row);
}
var_export($result);
If you like to use functional programming and fewer global variables, use array_reduce(): (Demo)
var_export(
array_reduce(
$array,
function($accumulator, $row) {
$date = $row['date'];
unset($row['date']);
$accumulator[$date] = array_merge($accumulator[$date] ?? [], $row);
return $accumulator;
},
[]
)
);
These techniques unconditionally push data into the subarray with the key based on the date column value.
The above technique will work consistently even if the order of your subarray elements changes.
The ?? (null coalescing operator) is to ensure that array_merge() always has an array in the first parameter -- if processing the first occurrence of a given date, you simply merge the current iteration's data (what's left of it after unset() removes the date element) with an empty array.
I believe this solution will work for you:
<?php
$array = Array
(
0 => Array
(
'date' => '2017-08-22',
'AAA' => '1231',
),
1 => Array
(
'date' => '2017-08-21',
'AAA' => '1172',
),
2 => Array
(
'date' => '2017-08-20',
'AAA' => '1125'
),
3 => Array
(
'date' => '2017-08-21',
'BBB' => '251'
),
4 => Array
(
'date' => '2017-08-20',
'BBB' => '21773',
),
5 => Array
(
'date' => '2017-08-22',
'CCC' => '3750'
),
6 => Array
(
'date' => '2017-08-20',
'CCC' => '321750'
)
);
echo '<pre>';
$array1 = array('AAA' => null, 'BBB' => null, 'CCC' => null);
$array2 = array();
array_walk($array, function ($v) use (&$array2, $array1) {
$a = $v['date'];
if (!isset($array2[$a])) {
$array2[$a] = $array1;
}
unset($v['date']);
$array2[$a] = array_merge($array2[$a], $v);
});
print_r($array2);
Output
Array
(
[2017-08-22] => Array
(
[AAA] => 1231
[BBB] =>
[CCC] => 3750
)
[2017-08-21] => Array
(
[AAA] => 1172
[BBB] => 251
[CCC] =>
)
[2017-08-20] => Array
(
[AAA] => 1125
[BBB] => 21773
[CCC] => 321750
)
)
check output at: https://3v4l.org/NvLB8
Another approach (quick & dirty) making use of an arrays internal pointer:
$newArray = [];
foreach ($array as $childArray) {
$date = current($childArray);
$value = next($childArray); // this advances the internal pointer..
$key = key($childArray); // ..so that you get the correct key here
$newArray[$date][$key] = $value;
}
This of course only works with the given array structure.
Another perfect usage example for the PHP function array_reduce():
// The input array
$input = array(
0 => array(
'date' => '2017-08-22',
'AAA' => '1231',
),
// The rest of your array here...
);
$output = array_reduce(
$input,
function (array $carry, array $item) {
// Extract the date into a local variable for readability and speed
// It is used several times below
$date = $item['date'];
// Initialize the group for this date if it doesn't exist
if (! array_key_exists($date, $carry)) {
$carry[$date] = array();
}
// Remove the date from the item...
// ...and merge the rest into the group of this date
unset($item['date']);
$carry[$date] = array_merge($carry[$date], $item);
// Return the partial result
return $carry;
},
array()
);
The question is not clear. What is the expected result if one key (AAA f.e) is present on two or more dates? This answer keeps only the last value associated with it.

2 arrays: keep only elements with different value

I have 2 arrays:
Array
(
[0] => Array
(
[id] => 1
[fieldname] => banana
[value] => yellow
)
)
Array
(
[0] => Array
(
[id] => 1
[fieldname] => rome
[value] => city
)
[1] => Array
(
[id] => 2
[fieldname] => bla
[value] => yes
)
)
I want to create a new array that contains only elements where "id" is different. In other words I want to get this output:
Array
(
[0] => Array
(
[id] => 2
[fieldname] => bla
[value] => yes
)
)
[id] => 2 was the only different [id] so I keep it.
Said that I've already managed to achieve my goal with an inefficient pile of foreach, if statements and temp variables. I really don't want to use a wall of code for this very small thing so I started to look for a native PHP function with no success. What's the easiest way to get the result? Is it possible that I strictly need to use a foreach with so many if?
You can use array_udiff with a function.
Computes the difference of arrays by using a callback function for
data comparison.
Returns an array containing all the values of the first array that are not
present in any of the other arguments.
The code:
// Setup two arrays as per your question
$array1 = array (
'0' => array (
'id' => '1',
'fieldname' => 'banana',
'value' => 'yellow',
)
);
$array2 = array (
'0' => array (
'id' => '1',
'fieldname' => 'rome',
'value' => 'city',
),
'1' => array (
'id' => '2',
'fieldname' => 'bla',
'value' => 'yes',
)
);
// Setup the callback comparison function
function arrayCompare($array2, $array1) {
return $array2['id'] - $array1['id'];
}
// Use array_udiff() with the two arrays and the callback function
$arrayDiff = array_udiff($array2, $array1, 'arrayCompare');
print_r($arrayDiff);
The above code returns the following:
Array (
[1] => Array (
[id] => 2
[fieldname] => bla
[value] => yes
)
)
This should do it. Not super short and it does use a temporary variable, so perhaps not what you were looking for. I've named the two arrays one and two.
$ids = array();
$result = array();
foreach ($one as $x) {
$ids[$x['id']] = 1; //This way, isset($x['id']) vill return true
}
foreach ($two as $x) {
if (!isset($ids[$x['id']])) {
$result[] = $x;
}
}
I would be surprised if there wasn't an even more compact way to do it.
EDIT: This is an alternative variant with nested for each. Not particularly short either.
$result = array();
foreach ($one as $x) {
foreach ($two as $y) {
if ($x['id'] == $y['id']) {
//A match, lets try the next $x
continue 2;
}
}
//No matching id in $two
$result[] = $x;
}

Group 2d array data using column value to create a 3d array

I have a multidimensional array and am trying to group them according to the value in a specific column.
I'm trying to group them by level, but I won't actually know the level beforehand. So, it's not like I can put it in a for loop and say while $i < 7, because I won't know that 7 is the maximum value for the level key, and frankly, I'm not sure that's how I would need to do it even if I did.
[
['cust' => 'XT8900', 'type' => 'standard', 'level' => 1],
['cust' => 'XT8944', 'type' => 'standard', 'level' => 1],
['cust' => 'XT8922', 'type' => 'premier', 'level' => 3],
['cust' => 'XT8816', 'type' => 'permier', 'level' => 3],
['cust' => 'XT7434', 'type' => 'standard', 'level' => 7],
]
Desired result:
Array (
[1] => Array (
[0] => Array (
[cust] => XT8900
[type] => standard
)
[1] => Array (
[cust] => XT8944
[type] => standard
)
)
[3] => Array (
[2] => Array (
[cust] => XT8922
[type] => premier
)
[3] => Array (
[cust] => XT8816
[type] => permier
)
)
[7] => Array (
[4] => Array (
[cust] => XT7434
[type] => standard
)
)
)
Best way, if you have control over building the initial array, is just set things up like that at the start as you add entries.
If not then build a temporary array to sort:
foreach ($input_arr as $key => &$entry) {
$level_arr[$entry['level']][$key] = $entry;
}
Leaves you with the form you wanted and everything referenced together.
Build the array like that in the first place though if at all possible.
You need to group them by level first
Use foreach to loop into array check if the level is the same with the previous item then group it with that array
$templevel=0;
$newkey=0;
$grouparr[$templevel]="";
foreach ($items as $key => $val) {
if ($templevel==$val['level']){
$grouparr[$templevel][$newkey]=$val;
} else {
$grouparr[$val['level']][$newkey]=$val;
}
$newkey++;
}
print($grouparr);
The output of print($grouparr); will display like the format you hoped for
You can also try to
print($grouparr[7]);
Will display
[7] => Array (
[4] => Array (
[cust] => XT7434
[type] => standard
)
)
Or
print($grouparr[3]);
Will display
[3] => Array (
[2] => Array (
[cust] => XT8922
[type] => premier
)
[3] => Array (
[cust] => XT8816
[type] => permier
)
)
Here is the solution I landed on for an identical problem, wrapped as a function:
function arraySort($input,$sortkey){
foreach ($input as $key=>$val) $output[$val[$sortkey]][]=$val;
return $output;
}
To sort $myarray by the key named "level" just do this:
$myArray = arraySort($myArray,'level');
Or if you didn't want it as a function, just for a one time use, this would create $myNewArray from $myArray grouped by the key 'level'
foreach ($myArray as $key=>$val) $myNewArray[$val['level']][]=$val;
function group_assoc($array, $key) {
$return = array();
foreach($array as $v) {
$return[$v[$key]][] = $v;
}
return $return;
}
//Group the requests by their account_id
$account_requests = group_assoc($requests, 'account_id');
$result = array();
foreach ($yourArrayList as $data) {
$id = $data['level'];
if (isset($result[$id])) {
$result[$id][] = $data;
} else {
$result[$id] = array($data);
}
}
Best ans.
$levels = array_unique(array_column($records, 'level'));
$data = array();
foreach($records as $key => $value){
$data[$levels[array_search($value['level'],$levels )]][] = $value ;
}
print_r($data);
To generate the question's exact desured output from the sample input, pull/pop the last value from each row, use that value as the first level grouping key. Then use the original first level index as the second level key. Then push the two remaining elements into the group's subset.
Code: (Demo)
$result = [];
foreach ($array as $key => $row) {
$result[array_pop($row)][$key] = $row;
}
var_export($result);
For functional style syntax, use array_reduce(). (Demo)
var_export(
array_reduce(
array_keys($array),
function($result, $key) use ($array) {
$result[array_pop($array[$key])][$key] = $array[$key];
return $result;
}
)
);
function _group_by($array,$key,$keyName)
{
$return = array();
foreach($array as $val) {
$return[$keyName.$val[$key]][] = $val;
}
return $return;
} //end of function

Intersecting multidimensional array of varying size

I have a multidimensional array that looks like this:
Array
(
[0] => Array
(
[0] => Array
(
[id] => 3
)
[1] => Array
(
[id] => 1
)
[2] => Array
(
[id] => 2
)
[3] => Array
(
[id] => 5
)
[4] => Array
(
[id] => 4
)
)
[1] => Array
(
[0] => Array
(
[id] => 1
)
[1] => Array
(
[id] => 3
)
[2] => Array
(
[id] => 4
)
[3] => Array
(
[id] => 5
)
)
[2] => Array
(
[0] => Array
(
[id] => 3
)
)
)
I need to find a way to return the intersecting value(s). In this case that would be
[id] => 3
The length of the array could be different, so I can't just use array_intersect().
This would be simple if your arrays contained only integers, but as they contain an another array, it gets a bit more complicated. But this should do it:
function custom_intersect($arrays) {
$comp = array_shift($arrays);
$values = array();
// The other arrays are compared to the first array:
// Get all the values from the first array for comparison
foreach($comp as $k => $v) {
// Set amount of matches for value to 1.
$values[$v['id']] = 1;
}
// Loop through the other arrays
foreach($arrays as $array) {
// Loop through every value in array
foreach($array as $k => $v) {
// If the current ID exists in the compare array
if(isset($values[$v['id']])) {
// Increase the amount of matches
$values[$v['id']]++;
}
}
}
$result = array();
// The amount of matches for certain value must be
// equal to the number of arrays passed, that's how
// we know the value is present in all arrays.
$n = count($arrays) + 1;
foreach($values as $k => $v) {
if($v == $n) {
// The value was found in all arrays,
// thus it's in the intersection
$result[] = $v;
}
}
return $result;
}
Usage:
$arrays = array(
array(array('id' => 3), array('id' => 1), array('id' => 2), array('id' => 5), array('id' => 4)),
array(array('id' => 1), array('id' => 3), array('id' => 4), array('id' => 5)),
array(array('id' => 3))
);
print_r(custom_intersect($arrays));
Result:
Array
(
[0] => 3
)
This function isn't perfect: if you have duplicate ID's in one array, it will not work. That would require a bit more code to first make the array values unique, but this will probably work in your case.
You can use array_uintersect() to get the intersection of arrays using a custom comparison function. You have to call it with call_user_func_array() though, as it expects each array as a separate argument:
//build list of parameters for array_uintersect()
$params = array_merge($input, array('compare_func'));
$result = call_user_func_array('array_uintersect', $params);
function compare_func($a, $b) {
return $a['id'] - $b['id'];
}
You can't simply call array_intersect() with call_user_func_array(), because it seems to compare arrays by comparing their string representation (which will always be 'Array').
$a = array(4,3);
$b = array(4,3,2,1);
$c = array(1,2,3,4,5);
$d = array(5,4,3);
$array = array($a,$b,$c,$d);
for ($i=0; $i<count($array); $i++){
if ($i==0){
$array2 = $array[$i];
} else {
$array2 = array_intersect($array2, $array[$i]);
}
}
print_r($array2);`
Result:
3,4
As mentioned in one of the comments of the php.net website (array_intersect function).
$a = array(1,2,3,4,5,2,6,1); /* repeated elements --> $a is not a set */
$b = array(0,2,4,6,8,5,7,9,2,1); /* repeated elements --> $b is not a set */
$ua = array_merge(array_unique($a)); /* now, $a is a set */
$ub = array_merge(array_unique($b)); /* now, $b is a set */
$intersect = array_merge(array_intersect($ua,$ub));
This will return this array:
Array
(
[0] => 1
[1] => 2
[2] => 4
[3] => 5
[4] => 6
)

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