I want to use PHP to insert date into mysql datetime field.
$time = date('Y-m-d');
mysql_query(INSERT INTO A (date) VALUE ('$time'));
Table A date column is datetime field. I want it shows 2011-01-24. But it always shows 2011-01-24 00:00:00. So my problem is how to remove the suffix "00:00:00".
Since the field is a DATETIME field, it stores the DATE and the TIME. If you want to exclusively store the date, make it a DATE field.
Change the column type to DATE instead of datetime!
A bit unclear, I see 2 possible solutions:
If you're referring to removing the suffix 00:00:00 from the MySQL, you need to change the field type from datetime into a date.
If you're referring to the removal of the suffix from the php script, well you can always use
mysql_query(SELECT DATE_FORMAT(date, '%d-%m-%Y') FROM a);
read up mysql date and time functions
Change the field to a DATE field in your table. Your PHP code is fine as it is.
Related
I have issue with this date m/d/y for example 01/09/15 but when i insert that in my table of field name date and declared date i adde to me 2001/09/15 how can i save this format 01/09/15 in field database of my table
You can't change the format of mysql dates. You could save your date as a varchar but you can't use any manipulation.
You can save it as a mysql date or a time int, and then cast it to the format that you want, using date function.
You can read more about this in this post:
Change date format (in DB or output) to dd/mm/yyyy - PHP MySQL
I hope this will be useful.
I have what is most likely a very simple question.. I am designing a simple blogging system and I am trying to put the current date into the table where the blog post is stored whilst waiting for administrator approval. but the method I have used puts 0000-00-00 into the date column! What I am using is as follows:
$query = "INSERT INTO blogentry VALUES ('".$mnam."','".date('d-m-Y h:m:s') ."\n"."','".$mcom."','".$approve."')";
I am relatively new to php so stumble accross errors like this all the time... but I cant seem to google this one!
Thanks guys!
So the easiest way to do this is just let MySQL handle it with the NOW() function:
INSERT INTO blogentry VALUES( ..., NOW(), ... )
Another option is to use TIMESTAMPs by changing your table - set the column to type TIMESTAMP with DEFAULT CURRENT_TIMESTAMP, and you can just ignore that column when inserting - it will automatically be filled with the current time. You will need to specify the columns you're inserting to in order to skip a column:
INSERT INTO blogentry( column1, column2 ) VALUES( column1value, column2value )
Finally, you NEED to sanitize your inputs. Preferably using prepared statements and PDO (http://php.net/manual/en/pdo.prepared-statements.php), or at least using mysql_real_escape_string.
From the MySQL manual on DATE, DATETIME
The DATE type is used for values with a date part but no time part.
MySQL retrieves and displays DATE values in 'YYYY-MM-DD' format. The
supported range is '1000-01-01' to '9999-12-31'.
This means you have to insert the dates in YYYY-MM-DD format. You are using date('d-m-Y h:m:s') format. Change that to date('Y-m-d') and it should insert correctly.
If you want the time as well, then you need to change the column datatype to DATETIME and then insert using the format date('Y-m-d H:i:s').
As other mention, you can use an INT column type instead and store a Unix timestamp which is stored in UTC so it is more portable. You can then easily manipulate the timestamp to output the date any way you would like.
Try just storing a strtotime() result. It creates a unique timestamp, which can then be parsed however you need it in the future.
You might need to give the timestamp to the date function:
date('d-m-Y h:m:s', strtotime('now'))
Also, to do a standard datetime format:
date('Y-m-d H:i:s', strtotime('now'))
I am working with dates, in both PHP as well as MySQL. EVerytime I use to convert date in unix format. But this time I have taken field in DB as date. But issue is it is taking yyyy-mm-dd format. I want to store it in dd-mm-yyyy format. Is this possible if I set default setting of DB. or each time I have to explode the dd-mm-yyyy format in PHP and convert it in YYYY-MM-DD format. Its my first query.
Second query is I wish to fetch the records from today's date. I mean dates after today's date. Like today then tomorrow then so on.... Is it possible to use order by on date field.
Just use:
$date = date('d-m-Y', strtotime($dateFromDB));
That will convert from MySQL DateTime to the format you have specified.
It is possible to order by date fields, e.g.:
SELECT *
FROM table
WHERE date > [yourDate]
ORDER BY date [DESC | ASC]
Your second requirement contradicts with the first one.
If you store your date in dd-mm-yyyy format, you'll be unable to sort your dates.
So - yes, you have to "explode" the dd-mm-yyyy date in PHP or format it any other way. That's not a big deal though. Everyone does it.
If you have a field of type 'datetime' you can use the MySQL-Command: FROM_UNIXTIME(%d) for conversion. 'order by' should be no problem.
Store the date in default format that is yyyy-mm-dd
when you want to display in front end
use the following query to
select otherFields, date_format(dateField,'%d-%m-%Y') from tableName;
For ordering by date
SELECT * FROM tbl
ORDER BY date DESC
I am aware of the MySQL Date_Format function but am looking to achieve the following:
I have on column with a day date in 2 digit format (01-30). I am trying to update another date formatted field with the current year, the next month (m+1) and the day field mentioned previously.
In PHP i would do this using mktime function but this must be done using mysql calls only.
Is it possible to transform in this way?
update table set field1 = concat(date_format(curdate(),"%Y-%m"),'-',field2) + interval 1 month
There is a function called STR_TO_DATE in mysql which you should be able to use to create a brand new date with using the seperate parts you described in your problem. The final input into the function should be STR_TO_DATE('01,5,2013','%d,%m,%Y') where argument one is the actual date string and argument two represents the format of the new date. You should be able to create the first argument by concatenating your parts together and then specifying whatever date format you need.
I have a moodle installation in which there is a column in mdl_user table called firstaccess whose type is bigint(10) and contains date in following format 1266839570.
I am writing a query for accessing users according to date filters. For e.g. i want to check which users firstaccess is greater than '2010-04-12'. How can i convert the date? These two date formats are different. I think firstaccess is unix timestamp. Should i change the '2010-04-12' into unix timestamp or there is a way to convert firstaccess i.e 1266839570 to yyyy-mm-dd format.
Please help me on this.
Thanks
You can create a unix timestamp in php with the mktime() function, then simply put it in your query.
MySQL has a date_format() function, that can format dates however you like, but I'm not sure if it works with bigints. You'd better go with the mktime.
date() and mktime() are functions to concert from unix timestamp and back.
You can convert your dates in either way
I believe you can write your query using a timestamp. Eg.
SELECT * FROM mytable WHERE firstaccess >= TIMESTAMP('2010-04-12')
http://dev.mysql.com/doc/refman/5.0/en/timestamp.html
I don't know what form the date in your form is, but you can easily convert it to a timestamp (if it already isn't one) using mktime. For example:
$mytimestamp=mktime(0,0,0, $month, $day, $year);
Then just add it to your query:
$myQuery= "SELECT whatever FROM sometable WHERE " . $mytimestamp . ">=firstaccess";
Like Paul Peelen, my answer is a MySQL query. I'm going the other way, though, and converting first access into a date.
Using the date information in your problem:
SELECT * FROM mytable WHERE DATE_FORMAT(FROM_UNIXTIME(firstaccess), '%Y-%m-%d') > '2010-04-12';