i am trying to use this bit of code to first retrieve a URL that is stored in a txt file on my server and save it as a variable, then run file_get_contents a second time using the URL i just retrieved and saved as a variable.
the code works for the first file_get_contents and echoes the URL that is stored, but fails to then use that URL in the second file_get_contents to echo the contents of the URL.
<?php
$files = file_get_contents('http://example.com/txtfile.txt');
echo $files;
$file = file_get_contents($files);
echo $file;
?>
Well the direct solution to your problem is:
<?php
$files = file_get_contents('http://example.com/txtfile.txt');
echo $files;
$files = trim($files);
$file = file_get_contents($files);
echo $file;
?>
But this is huge security risk. Running file_get_contents to open a variable file is risky.
Related
I have a task to do in which i have to list the directories with it's files which i did, but i don't understand how to delete file or edit specific file in the directories any help will be appreciated Thanks.
<?php
error_reporting(0);
if(isset($_GET['dir']))
{
// /$path = 'E:\xampp\\'.$_GET['dir'];
$path = $_GET['dir'];
}
else
{
$path = 'E:\xampp\\';
}
if(is_dir($path))
{
$arrDir = scandir($path);
echo "<ul>";
foreach ($arrDir as $key => $value)
{
echo "<a href='http://localhost/vishrut/FileUpload/filelist.php?
dir=".$path.'/'.$value."'>".$value.'</a><br>';
}
echo "</ul>";
}
else
{
echo "<textarea>";
echo file_get_contents($path);
echo "</textarea>"."<br>";
}
?>
There are lots of PHP's functions to handle files: https://www.php.net/manual/en/ref.filesystem.php
For your needs see these:
file_get_contents to read the entire file contents
file_put_contents to write the content in a file
unlink to delete a file
So, the steps to modify a file may be:
get the complete contents with file_get_contents:
$contents = file_get_contents($filePath);
apply your edits to the $contents content:
$newContents = ...
overwrite the file content:
file_put_contents($filePath, $newContents);
To delete a file is simple:
unlink($filePath);
It's important to note that your code is subjected to injection because you don't check the user data passed with $_GET.
If your script will be used only by you it's ok, instead you must check all user input: the first rule of Web programming is NEVER TRUST YOUR USERS! Also trusted users may write wrong characters in the url and that may have unexpected results (e.g. delete the wrong file!)
Read https://www.php.net/manual/en/mongodb.security.script_injection.php
I have a script with a mysql query which saves a file called invoice.xml every day automatically by running a cron job. In case no data is found a no_orders.txt is saved.
I would like this file not be saved to the same folder as the script.php file is in but to a subfolder called invoices.
The renaming of the old invoice.xml is done with the following code
// rename old file
$nowshort = date("Y-m-d");
if(file_exists('invoice.xml')) {
rename('invoice.xml','invoice_'.$nowshort.'.xml');
}
The saving is done with the following code:
if($xml1 !='') {
$File = "invoice.xml";
$Handle = fopen($File, 'w');
fwrite($Handle, $xml1);
print "Data Written - ".$nowMysql;
fclose($Handle);
#print $xml;
die();
} else {
print "No new orders - ".$nowMysql;
$File = "no_orders_".$nowshort.".txt";
$Handle = fopen($File, 'w');
fclose($Handle);
die();
}
Could I please get assistance how to save this file to a subfolder. Also the renaming of the existing file would need to be within the subfolder then. I have already tried with possibilities like ../invoice/invoice.xml but unfortunately without any success.
Thank you
Just give the path of file 'invoice.xml' to $File.
Otherwise create some $Dir object which will point to Folder named 'invoice', then use accordingly
Use __DIR__ magic constant to retrieve your script.php directory, then you can append /invoice/invoice.xml .
Example if path to your script php something like this:
/var/www/path/to/script.php
$currentDir = __DIR__; //this wil return /var/www/path/to
$invoicePath = $currentDir.'/invoice/invoice.xml';
Can someone explain me why when i POST RAW Data for example "test.txt" in the below script
<?php
echo file_get_contents("php://input");
?>
it only prints the text "test.txt" instead of the file contents of that file?
Thank you
Your code reads the contents of the raw POST data and echoes it back.
Whereas what you want is this:
// retrieve the requested filename
$fileName = file_get_contents("php://input");
// echo the contents of the requested file
echo file_get_contents($fileName);
Depending on what you're trying to, you may wish to sanitize the $fileName input (not shown: too broad) and restrict access to a specific local directory:
$path = $myLocalDirectory . DIRECTORY_SEPARATOR . $fileName;
if (file_exists($path) {
echo file_get_conents($path);
}
Try like this ..
$input = "abc.txt";
echo file_get_contents($input);
It gives the content of the text file abc.txt
I have a folder on my server called /assets/includes/updates/ with .php files inside featuring static html content.
I'd like to randomly grab a file from this folder and echo it into a div. Here is what I have:
<?php
function random_update($dir = $_SERVER['DOCUMENT_ROOT'].'/assets/includes/updates/')
{
$files = glob($dir . '/*.*');
$file = array_rand($files);
return $files[$file];
}
?>
<div class="my-div">
<?php echo random_update(); ?>
</div><!--end my-div-->
I am getting 500 errors? Also, my intention is to only echo 1 file at a time. Will the provided code accomplish that?
Php does not recognize the syntax you used. You have to bypass it like this:
<?php
function random_update($dir = NULL)
{
if ($dir === NULL) {
$dir = $_SERVER['DOCUMENT_ROOT'] . '/assets/includes/updates/';
}
$files = glob($dir . '/*.*');
$file = array_rand($files);
return $files[$file];
}
Also, you might want to enable error dumping in your development environment so you know what went wrong next time.
Aside from another answers spotted issues, for your code to do what you want, you have to replace your following code:
<?php echo random_update(); ?>
for this one:
<?php echo file_get_contents (random_update()); ?>
because your current code will print the filename inside the div, while I think you wanted the actual content of the file to be inserted in the div.
You can't use any expression as "default" function's argument value.
I'm trying to create an Intranet page that looks up all pdf documents in a UNC path and the returns them in a list as hyperlinks that opens in a new window. I'm nearly there however the following code displays the FULL UNC path - My question how can I display only the Filename (preferably without the .pdf extension too). I've experimented with the basename function but can't seem to get the right result.
//path to Network Share
$uncpath = "//myserver/adirectory/personnel/";
//get all files with a .pdf extension.
$files = glob($uncpath . "*.pdf");
//print each file name
foreach ($files as $file)
{
echo "<a target=_blank href='File:///$file'>$file</a><br>";
}
The links work fine it just the display text shows //myserver/adirectory/personnel/document.pdf rather than just document. Note the above code was taken from another example I found whilst researching. If there's a whole new better way then I'm open to suggestions.
echo basename($file);
http://php.net/basename
Modify your code like this:
<?
$uncpath = "//myserver/adirectory/personnel/";
//get all files with a .pdf extension.
$files = glob($uncpath . "*.pdf");
//print each file name
foreach ($files as $file)
{
echo "<a target=_blank href='File:///$file'>".basename($file)."</a><br>";
}
?>
You may try this, if basename() does not work for some reason:
$file_a = explode('/',$file);
if (trim(end($file_a)) == '')
$filename = $file_a[count($file_a)-2];
else
$filename = end($file_a);