How to transfer json data to html with php? - php

Question

How to transfer json data to html with php?
$url="http://api.nytimes.com/svc/search/v1/article?format=json&query=usa&rank=newest&api-key=mykey"
when I type the url in browser, it return
{"offset" : "0" , "results" : [{"body" : "A guide to cultural and recreational goings-on in and around the Hudson Valley. ...}]}
how to put the json body data into html? I mean like this echo '<div class="body"></div>';

Answer 1

You first need to get the file. You should use curl for this. In the example below I used the file_get_contents() function, you might want to replace it. Use json_decode() to parse the JSON for you.
$json = file_get_contents($url);
$data = json_decode($json);
echo $data->results[0]->body;
This will echo A guide to cultural....

Answer 2

Use json_decode() on the content of the file, which you can retrieve with file_get_contents($url), then you have an array you can use to build the HTML.
$url="http://api.nytimes.com/svc/search/v1/article?format=json&query=usa&rank=newest&api-key=mykey";
$dataRaw = file_get_contents($url);
if ($dataRaw) {
$data = json_decode($dataRaw, true);
foreach ($data['results'] as $cEntry) {
?>
<div class="body">
<?php echo $cEntry['body']; ?>
</div>
<?php
}
}

Answer 3

I'm not sure why you would, but assuming fopen() URL opening is enabled, you could do...
echo file_get_contents($url);

Answer 4

like this ?
<?php
$url="http://api.nytimes.com/svc/search/v1/article?format=json&query=usa&rank=newest&api-key=mykey";
$json = file_get_contents($url);
echo $json;

Answer 5

Once you've loaded a JSON string into PHP, you can then convert it into a PHP array by using the function json_decode(). You can then print the appropriate array element into your HTML output as with any other PHP variable.

Answer 6

Try this:
$jsonDecoded = json_decode($yourJsonEncodedData);
echo $jsonDecoded->results->body;