http://www.instamapper.com/api?action=getPositions&key=584014439054448247&num=10&format=json
is the url, which contains json data. I want to use that data and send SMS to a particular phone no if value of latitude and longitude(Extracted from JSON).
Check constraints, we can use through php. But the main problem is How to extract data from JSON file?
I don't want to give you the solution, so the below should be enough to get you started.
Read in the JSON data using file_get_contents
Parse the JSON string into a PHP object using json_decode
Your code should look something like this:
$url = "http://www.instamapper.com/api?action=getPositions&key=584014439054448247&num=10&format=json";
$contents = file_get_contents($url);
$jsonObj = json_decode($contents);
You mean something like this?
<?php
$jsonurl = "http://search.twitter.com/trends.json";
$json = file_get_contents($jsonurl,0,null,null);
$json_output = json_decode($json);
foreach ( $json_output->trends as $trend )
{
echo "{$trend->name}\n";
}
Related
I am using currencylayer JSON API to get realtime currency conversion value - does anybody know how I could grab both the "result" value and the "quote" value from the API response below using PHP?
I am new to PHP, and I am wondering if it's possible to store it in a variable.
This is the JSON:
{
"success":true,
"terms":"https:\/\/currencylayer.com\/terms",
"privacy":"https:\/\/currencylayer.com\/privacy",
"query":{
"from":"CAD",
"to":"GBP",
"amount":234
},
"info":{
"timestamp":1432829168,
"quote":0.524191
},
"result":122.660694
}
I have played around with file_get_contents("URL") but I didnt understand how to get a single value out.
Request URL looks like this:
https://apilayer.net/api/convert?access_key=...&from=CAD&to=GBP&amount=234
Thanks for the help!
Ok, lets say that json response is in a variable named $response, you must use json_decode and then do as follows:
$decoded = json_decode($response);
$result = $decoded->result;
$quote = $decoded->info->quote;
var_dump($result, $quote);
Try this
$jsonArray = file_get_contents($yourUrl);
$jsonObject = json_decode($jsonArray);
echo $jsonObject->result;
echo $jsonObject->info->quote;
I'm trying to create a very simple php script that can pull data from a JSON file (array?) and echo it to the page. Sadly, I'm a complete newbie when it comes to PHP.
My goal is to dump all IP addresses and the corresponding client version into an output like this...
"127.0.0.1" "/Satoshi:0.9.1/"
"127.0.0.2" "/Satoshi:0.9.0/"
"127.0.0.3" "/Satoshi:0.9.0/"
"127.0.0.4" "/Satoshi:0.9.1/"
I can get the code to dump all data, but I'm not sure how to pull the ip and version without the ip and client version being named.. If that even makes sense?
Here is the code. What do I need to make it dump the correct data?
<?php
$url = 'https://getaddr.bitnodes.io/nodes/1407675714.json';
$JSON = file_get_contents($url);
echo $JSON;
$data = json_decode($JSON);
var_dump($data);
?>
Thanks for your help!
Something like
<?php
$url = 'https://getaddr.bitnodes.io/nodes/1407675714.json';
$JSON = file_get_contents($url);
$data = json_decode($JSON);
$data = (array)$data; // cast from stdClass to array, as results have int keys
foreach($data['nodes'] as $results){
echo $results[0]. " ". $results[3]."<br />";
}
?>
It doesn't makes much sense to convert an array of hashes into the one of some non-named entities. I guess that all you need is to dump it in the following way:
foreach($data as $t)
{
echo("ip=".$t->ip." ua=".$t->ua);
}
I don't think there is any reason to cast to an array. Just process the returned object. This one has the double quotes as requested as well.
<?php
$url = 'https://getaddr.bitnodes.io/nodes/1407675714.json';
$json = file_get_contents($url);
$data = json_decode($json);
foreach($data->nodes as $results){
echo "\"".$results[0]."\" \"".$results[3]."\"<br />";
}
?>
I am retrieving some data from Wikipedia using Wikipedia API as JSON. I am getting html tags along with the data as response. When displaying on browser the html tags are displayed as plain text not as the regular output(I hope I am clear with this sentence). I want to show those as how it should look instead of plain text.following is my PHP code.
$url = 'http://en.wikipedia.org/w/api.php?action=query&prop=extracts&titles=Sachin_Tendulkar&format=json&redirects&inprop=url&indexpageids';
$json = file_get_contents($url);
echo $json ;
Following is the angularJS controller which is used to display the data
var demoApp = angular.module('demoApp',[]);
demoApp.controller('SimpleController',function ($scope,$http){
$http.post('server/view1.php').success(function(data){
$scope.info = data;
});
});
In this case:
$url = 'http://en.wikipedia.org/w/api.php?action=query&prop=extracts&titles=Sachin_Tendulkar&format=json&redirects&inprop=url&indexpageids';
$jsonString = file_get_contents( $url );
$jsonDecoded = json_decode($jsonString, true );
$pageData = $jsonDecoded['query']['pages'][57570]['extract'];
echo $pageData;
You need to use the function json_decode if you want to interpret JSON data.
You must use json_decode($json) to parse response to valid php code.
i have this public JSON https://raw.github.com/currencybot/open-exchange-rates/master/latest.json and i need to extract data from it, right now i tried something like this:
$input = file_get_contents("https://raw.github.com/currencybot/open-exchange-rates/master/latest.json");
$json = json_decode($input);
echo $json[rates]->EUR;
but i obtain a blank page, any suggestion? Thanks !! Ste
json_decode either returns an object, or an array (when you use the second param). You are trying to use both.
Try:
$json = json_decode($input);
echo $json->rates->EUR;
OR
$json = json_decode($input, true);
echo $json['rates']['EUR'];
As to the blank page, please add the following to the top of your script:
error_reporting(E_ALL);
init_set('display_errors', true);
A 500 Error indicates you are unable to resolve that url using file_get_contents.
Check here for more information.
Read the help for json_decode ... without the second parameter it returns and object not an array ...
Either :
$json = json_decode($input);
echo $json->rates->EUR;
or
$json = json_decode($input,true);
echo $json['rates']['EUR'];
Try:
$arr = json_decode($input, true);
var_dump($arr);
echo $arr['rates']['EUR'];
Further Reading:
http://de.php.net/manual/de/function.json-encode.php
For anexample with cURL and SSL read this:
http://unitstep.net/blog/2009/05/05/using-curl-in-php-to-access-https-ssltls-protected-sites/
The link looks like starting with https, while file_get_contents can't deal with SSL. My suggestion is using curl.
How to transfer json data to html with php?
$url="http://api.nytimes.com/svc/search/v1/article?format=json&query=usa&rank=newest&api-key=mykey"
when I type the url in browser, it return
{"offset" : "0" , "results" : [{"body" : "A guide to cultural and recreational goings-on in and around the Hudson Valley. ...}]}
how to put the json body data into html? I mean like this echo '<div class="body"></div>';
You first need to get the file. You should use curl for this. In the example below I used the file_get_contents() function, you might want to replace it. Use json_decode() to parse the JSON for you.
$json = file_get_contents($url);
$data = json_decode($json);
echo $data->results[0]->body;
This will echo A guide to cultural....
Use json_decode() on the content of the file, which you can retrieve with file_get_contents($url), then you have an array you can use to build the HTML.
$url="http://api.nytimes.com/svc/search/v1/article?format=json&query=usa&rank=newest&api-key=mykey";
$dataRaw = file_get_contents($url);
if ($dataRaw) {
$data = json_decode($dataRaw, true);
foreach ($data['results'] as $cEntry) {
?>
<div class="body">
<?php echo $cEntry['body']; ?>
</div>
<?php
}
}
I'm not sure why you would, but assuming fopen() URL opening is enabled, you could do...
echo file_get_contents($url);
like this ?
<?php
$url="http://api.nytimes.com/svc/search/v1/article?format=json&query=usa&rank=newest&api-key=mykey";
$json = file_get_contents($url);
echo $json;
Once you've loaded a JSON string into PHP, you can then convert it into a PHP array by using the function json_decode(). You can then print the appropriate array element into your HTML output as with any other PHP variable.
Try this:
$jsonDecoded = json_decode($yourJsonEncodedData);
echo $jsonDecoded->results->body;