PHP SimpleXML: Feed modification - php

Question

I want to modify an RSS feed. I want to remove X items from feed and then return the new feed as XML.
<?php
class RSS {
private $simpleXML;
public function __construct($address) {
$xml = file_get_contents($address);
$this->simpleXML = simplexml_load_string($xml);
}
private function getRssInformation() {
// Here I want to get the Rss Head information ...
}
// Here I get X items ...
private function getItems($itemsNumber, $UTF8) {
$xml = null;
$items = $this->simpleXML->xpath('/rss/channel/item');
if(count($items) > $itemsNumber) {
$items = array_slice($items, 0, $itemsNumber, true);
}
foreach($items as $item) {
$xml .= $item->asXML() . "\n";
}
return $xml;
}
public function getFeed($itemsNumber = 5, $UTF8 = true) {
// Here i will join rss information with X items ...
echo $this->getItems($itemsNumber, $UTF8);
}
}
?>
Is it possible with XPath?
Thank you.

Answer 1

Another way to do it (but could be cleaner) :
private function getItems($itemsNumber, $UTF8) {
$xml = '<?xml version="1.0" ?>
<rss version="2.0">
<channel>';
$i = 0;
if (count($this->simpleXML->rss->channel->item)>0){
foreach ($this->simpleXML->rss->channel->item as $item) {
$xml .= str_replace('<?xml version="1.0" ?>', '', $item->asXML());
$i++;
if($i==$itemsNumber) break;
}
}
$xml .=' </channel></rss> ';
return $xml;
}
But I think asXML(); add the XML declaration :
<?xml version="1.0" ?>
I edited my code. It's dirty but it should work. Any better idea?