Get last node in XML using DOMDocument PhP - php

Question

I've made a class that reads value and node name of value and combines it into array to use it as a simple and quick access to config in XML. But this solution works only if ill give bottom node, XML looks like this.
<?xml version="1.0" encoding="ISO-8859-2"?>
<settings>
<const>
<inscript>true</inscript>
<title>Template</title>
</const>
<meta>
</meta>
<db>
<user>user</user>
<pass>pass</pass>
<host>host</host>
<name>name</name>
</db>
<path>
<style>
<css>/Template/view/www/style/</css>
<img>/Template/view/www/style/img</img>
</style>
</path>
</settings>
Now I want to get for example whole db node and return it as an array where node name wold be the key and node value, value. but im stuck at this. Heres what i made so far.
class config {
private static $xml = "lib/config/settings.xml";
private static $xmlRoot = "settings";
public static function loadConfig($value) {
$domDocument = new DOMDocument();
$domDocument->load(self::$xml);
$settings = $domDocument->getElementsByTagName(self::$xmlRoot);
try {
foreach ($settings as $setting) {
$configValue = $setting->getElementsByTagName($value)->item(0)->nodeValue;
$configNode = $setting->getElementsByTagName($value)->item(0)->nodeName;
$test = $setting->getElementsByTagName("path")->item(0)->childNodes->item(2)->nodeName;
var_dump($test);
}
$configValue = explode(' ', trim(preg_replace( '/\s+/', ' ', $configValue)));
$configNode = explode(' ', trim(preg_replace( '/\s+/', ' ', $configNode)));
$configArray = array_combine($configNode, $configValue);
return $configArray;
}
catch(Exception $e) {
echo '<h1>Błąd - '.$e->getMessage().'</h1>';
}
}
}

Answer 1

You could use XPath like this:
$xp = new DOMXPath($domDocument);
$config = array();
foreach ($xp->query('./db/*') as $node) {
$config[$node->nodeName] = $node->textContent;
}
return $config;