Unformat money when parsing in PHP - php

Question

Is there a way to get the float value of a string like this: 75,25 €, other than parsefloat(str_replace(',', '.', $var))?
I want this to be dependent on the current site language, and sometimes the comma could be replaced by dot.

Answer 1

This is a bit more complex/ slow solution, but works with all locales. #rlenom's solution work only with dots as decimal separator, and some locales, like Spanish, use the comma as decimal separator.
<?php
public function getAmount($money)
{
$cleanString = preg_replace('/([^0-9\.,])/i', '', $money);
$onlyNumbersString = preg_replace('/([^0-9])/i', '', $money);
$separatorsCountToBeErased = strlen($cleanString) - strlen($onlyNumbersString) - 1;
$stringWithCommaOrDot = preg_replace('/([,\.])/', '', $cleanString, $separatorsCountToBeErased);
$removedThousandSeparator = preg_replace('/(\.|,)(?=[0-9]{3,}$)/', '', $stringWithCommaOrDot);
return (float) str_replace(',', '.', $removedThousandSeparator);
}
Tests:
['1,10 USD', 1.10],
['1 000 000.00', 1000000.0],
['$1 000 000.21', 1000000.21],
['£1.10', 1.10],
['$123 456 789', 123456789.0],
['$123,456,789.12', 123456789.12],
['$123 456 789,12', 123456789.12],
['1.10', 1.1],
[',,,,.10', .1],
['1.000', 1000.0],
['1,000', 1000.0]
Caveats:
Fails if the decimal part have more than two digits.
This is an implementation from this library:
https://github.com/mcuadros/currency-detector

Answer 2

use ereg_replace
$string = "$100,000";
$int = ereg_replace("[^0-9]", "", $string);
echo $int;
outputs
1000000
function toInt($str)
{
return (int)preg_replace("/\..+$/i", "", preg_replace("/[^0-9\.]/i", "", $str));
}
Update
<?php
$string = array("$1,000,000.00","$1 000 000.00","1,000 000.00","$123","$123 456 789","0.15¢");
foreach($string as $s) {
echo $s . " = " . toInt($s) . "\n";
}
function toInt($str)
{
return preg_replace("/([^0-9\\.])/i", "", $str);
}
?>
Outputs
$1,000,000.00 = 1000000.00
$1 000 000.00 = 1000000.00
1,000 000.00 = 1000000.00
$123 = 123
$123 456 789 = 123456789
0.15¢ = 0.15
and if you cast it as an integer
<?php
$string = array("$1,000,000.00","$1 000 000.00","1,000 000.00","$123","$123 456 789","0.15¢");
foreach($string as $s) {
echo $s . " = " . _toInt($s) . "\n";
}
function _toInt($str)
{
return (int)preg_replace("/([^0-9\\.])/i", "", $str);
}
?>
outputs
$1,000,000.00 = 1000000
$1 000 000.00 = 1000000
1,000 000.00 = 1000000
$123 = 123
$123 456 789 = 123456789
0.15¢ = 0
So there you have it. single line, one replace. you're good to go.

Answer 3

You can use
NumberFormatter::parseCurrency - Parse a currency number
Example from Manual:
$formatter = new NumberFormatter('de_DE', NumberFormatter::CURRENCY);
var_dump($formatter->parseCurrency("75,25 €", $curr));
gives: float(75.25)
Note that the intl extension is not enabled by default. Please refer to the Installation Instructions.

Answer 4

You're gonna need to remove the currency symbol from the string. PHP's intval stops at the 1st non-numeric character it finds.
$int = intval(preg_replace('/[^\d\.]/', '', '$100')); // 100
Though if you have a value like $100.25, you might wanna use floatval instead.
$float = floatval(preg_replace('/[^\d\.]/', '', '$100.25')); // 100.25

Answer 5

PHP has intval (here are the docs), which is (as far as I can tell) exactly the same as JavaScript's parseInt.
However, for what's worth, I don't think either function will help you with what you're trying to do. Because the first character is non-numeric, both freak out (PHP will give you 0, JS will give you NaN). So in either language, you're going to have to do some string/regex parsing.

Answer 6

I'm an newbie, so there's probably an obvious (to others, not me) downside to the approach below, but thought I would share it anyway. I'd be interested to know whether it's faster or slower than using preg_replace, but didn't do any speed testing.
$badChars = array("$", ",", "(", ")");
$dirtyString = "($3,895.23)";
$cleanString = str_ireplace($badChars, "", $dirtyString);
echo "$dirtyString becomes $cleanString<p>";
$dirtyString can be an array, so:
$badChars = array("$", ",", "(", ")");
$dirtyStrings = array("($3,895.23)", "1,067.04", "$5683.22", "$9834.48");
$cleanStrings = str_ireplace($badChars, "", $dirtyStrings);
echo var_dump($cleanStrings);

Answer 7

Casting is your friend:
$int = (int) $string;
Update based on op:
Try something like this:
<?php
function extract_numbers($string)
{
return preg_replace("/[^0-9]/", '', $string);
}
echo extract_numbers('$100');
?>
Demo: http://codepad.org/QyrfS7WE

Answer 8

I had a similar problem where I didn't receive the currency symbol, just the strings (ie: 1,234,567.89 or 1.234.567,89).
This helped me normalize both cases into floats:
$val = str_replace(",", ".", $formatted);
$val = preg_replace("/[\,\.](\d{3})/", "$1", $val);
But Gordon's answer is much cleaner.