Unzip the file using php (collapses the ZIP file into one Folder) - php

Question

$file_name = 'New Folder.zip'
$zip = new ZipArchive;
$result = $zip->open($target_path.$file_name);
if ($result === TRUE) {
for($i = 0; $i < $zip->numFiles; $i++) {
$filename = $zip->getNameIndex($i);
$fileinfo = pathinfo($filename);
copy("zip://".$file_name."#".$filename, $target_path.$fileinfo['basename']);
}
}
When i run this code i get this error Warning: copy(zip://New Folder.zip#New Folder/icon_android.png) [function.copy]: failed to open stream: operation failed in...
How can I solve this...

Answer 1

From PHP's doc
$zip = new ZipArchive;
if ($zip->open('test.zip') === TRUE) {
$zip->extractTo($your_desired_dir);
$zip->close();
foreach (glob($your_desired_dir . DIRECTORY_SEPARATOR . 'New Folder') as $file) {
$finfo = pathinfo($file);
rename($file, $your_desired_dir . DIRECTORY_SEPARATOR . $finfo['basename']);
}
unlink($your_desired_dir . DIRECTORY_SEPARATOR . 'New Folder');
echo 'ok';
} else {
echo 'failed';
}
Dunno why are you using stream.

Answer 2

copy("zip://".$file_name."#".$filename, $target_path.$fileinfo['basename']);}
correct to
copy("zip://".dirname(__FILE__).'/'.$file_name."#".$filename, $target_path.$fileinfo['basename']);}
Full path need to use zip:// stream

Answer 3

see manual http://php.net/manual/en/book.zip.php
unzip.php (sample code)
// the first argument is the zip file
$in_file = $_SERVER['argv'][1];
// any other arguments are specific files in the archive to unzip
if ($_SERVER['argc'] > 2) {
$all_files = 0;
for ($i = 2; $i < $_SERVER['argc']; $i++) {
$out_files[$_SERVER['argv'][$i]] = true;
}
} else {
// if no other files are specified, unzip all files
$all_files = true;
}
$z = zip_open($in_file) or die("can't open $in_file: $php_errormsg");
while ($entry = zip_read($z)) {
$entry_name = zip_entry_name($entry);
// check if all files should be unzipped, or the name of
// this file is on the list of specific files to unzip
if ($all_files || $out_files[$entry_name]) {
// only proceed if the file is not 0 bytes long
if (zip_entry_filesize($entry)) {
$dir = dirname($entry_name);
// make all necessary directories in the file's path
if (! is_dir($dir)) { pc_mkdir_parents($dir); }
$file = basename($entry_name);
if (zip_entry_open($z,$entry)) {
if ($fh = fopen($dir.'/'.$file,'w')) {
// write the entire file
fwrite($fh,
zip_entry_read($entry,zip_entry_filesize($entry)))
or error_log("can't write: $php_errormsg");
fclose($fh) or error_log("can't close: $php_errormsg");
} else {
error_log("can't open $dir/$file: $php_errormsg");
}
zip_entry_close($entry);
} else {
error_log("can't open entry $entry_name: $php_errormsg");
}
}
}
}
from http://www.java-samples.com/showtutorial.php?tutorialid=985

Answer 4

First thing I would do is this:
echo "FROM - zip://".$file_name."#".$filename;
echo "<BR>TO - " . $target_path.$fileinfo['basename'];
and see what you get

Answer 5

I have used very simple method to do this
system('unzip assets_04_02_2015.zip');