How to unzip file in server(linux) with php code - php

Question

I tried a lot of code, But not work.
<?php
$file = $_GET['file'];
if (isset($file))
{
echo "Unzipping " . $file . "<br>";
if(system('unzip '. $file.' -d dirtounzipto ' ))
{echo 'GGWP';}else{echo 'WTF';}
exit;
}?>
How can i unzip in server. with "system" or "shell_exec" code.

Answer 1

$zip_filename = "test.zip";
$zip_extract_path = "/";
try{
$zip_obj = new ZipArchive;
if (file_exists($zip_filename)) {
$zip_stat = $zip_obj->open($zip_filename);
if ($zip_stat === TRUE) {
$res = $zip_obj->extractTo($zip_extract_path);
if ($res === false) {
throw new Exception("Error in extracting file on server.");
}
$zip_obj->close();
} else {
throw new Exception("Error in open file");
}
} else {
throw new Exception("zip file not found for extraction");
}
}catch (Exception $e) {
echo $e->getMessage();
}

Answer 2

Please make good use of PHP's ZipArchive library:
<?php
$zip = new ZipArchive;
if ($zip->open('test.zip') === TRUE) {
$zip->extractTo('/my/destination/dir/');
$zip->close();
echo 'ok';
} else {
echo 'failed';
}
?>
Version requirement: PHP >= 5.2.0, PECL zip >= 1.1.0
UPDATE To create the destination path automatically, you can use:
mkdir($path, 0755, true);
which create the folders required automatically.

Answer 3

PHP has built-in extensions for dealing with compressed files. There should be no need to use system calls for this. ZipArchivedocs is one option.
// assuming file.zip is in the same directory as the executing script.
$file = 'file.zip';
// get the absolute path to $file
$path = pathinfo(realpath($file), PATHINFO_DIRNAME);
//folder name as per zip file name
$foldername = basename($file, ".zip");
mkdir($foldername, 0755, true);
$path = $path . "/" . $foldername;
$zip = new ZipArchive;
$res = $zip->open($file);
if ($res === TRUE) {
// extract it to the path we determined above
$zip->extractTo($path);
$zip->close();
echo "WOOT! $file extracted to $path";
} else {
echo "Doh! I couldn't open $file";
}