How I cut the extra 0 string from those sample.
current string: 0102000306
required string: 12036
Here a 0 value have in front of each number. So, i need to cut the extra all zero[0] value from the string and get my expected string. It’s cannot possible using str_replace. Because then all the zero will be replaced. So, how do I do it?
Using a regex:
$result = preg_replace('#0(.)#', '\\1', '0102000306');
Result:
"12036"
Using array_reduce:
$string = array_reduce(str_split('0102000306', 2), function($v, $w) { return $v.$w[1]; });
Or array_map+implode:
implode('',array_map('intval',str_split('0102000306',2)));
$currentString = '0102000306';
$length = strlen($currentString);
$newString = '';
for ($i = 0; $i < $length; $i++) {
if (($i % 2) == 1) {
$newString .= $currentString{$i};
}
}
or
$currentString = '0102000306';
$tempArray = str_split($currentString,2);
$newString = '';
foreach($tempArray as $val) {
$newString .= substr($val,-1);
}
It's not particularly elegant but this should do what you want:
$old = '0102000306';
$new = '';
for ($i = 0; $i < strlen($old); $i += 2) {
$new .= $old[$i+1];
}
echo $new;
Related
I am using codes like "gjhyYhK", "HJjhkeuJ" etc. But want user to show these codes like:
gj_y__K
HJj__e_J
means code will be edited with "_" at random positions in code.
This will do what you want:
$str = "gjhyYhK";
$len = strlen($str);
$num_to_remove = ceil($len * .4); // 40% removal
for($i = 0; $i < $num_to_remove; $i++)
{
$k = 0;
do
{
$k = rand(1, $len);
} while($str[$k-1] == "_");
$str[$k-1] = "_";
}
print $str . "\n";
If you want more underscores, change the value of $underscores. This will guarantee you get how many underscores you want, so long as you want fewer than the length of the string
Try this:
$string=array(
'gjhyYhK',
'HJjhkeuJ'
);
$arr=array();
foreach ($string as $key=>$value) {
$arr[$key]='';
for ($i=1; $i <=strlen($value); $i++) {
if(rand(0,1)){
$arr[$key].=substr($string[$key],$i,1);
}else{
$arr[$key].='_';
}
}
}
var_dump($arr);
you can try below code to get the functionality what you are looking for
<?php
$string = "gjhyYhK";
$percentage = 40;
$total_length = strlen($string);
$number_of_underscore = floor(($percentage / 100) * $total_length); // I have use floor value, you can use ceil() as well
for ($i = 1; $i <= $number_of_underscore; $i++)
{
$random_position = rand(0, strlen($string) - 1); // get the random position of character to be replaced
if (substr($string, $random_position, 1) !== '_') // check if its already replaced underscore (_)
{
$string = preg_replace("/" . (substr($string, $random_position, 1)) . "/", '_', $string, 1); // here preg_replaced use to replace the character only once, (i.e str_replace() will replace all matching characters)
}
else
{
$i--; // else decrement $i for the loop to run one more time
}
}
echo $string;
?>
let me know if any other help needed
$str = "ADFJ";
$strlen = strlen($str);
$newStr = '';
for ($i = 0; $i < $strlen; $i++) {
if ($i == rand(0, $strlen)) {
$newStr .= '_';
} else {
$newStr .= $str[$i];
}
}
echo $newStr;
Assume I have a string variable:
$str = "abcdefghijklmn";
What is the best way in PHP to write a function to start at the end of the string, and return every other character? The output from the example should be:
nljhfdb
Here is what I have so far:
$str = "abcdefghijklmn";
$pieces = str_split(strrev($str), 1);
$return = null;
for($i = 0; $i < sizeof($pieces); $i++) {
if($i % 2 === 0) {
$return .= $pieces[$i];
}
}
echo $return;
Just try with:
$input = 'abcdefghijklmn';
$output = '';
for ($i = strlen($input) - 1; $i >= 0; $i -= 2) {
$output .= $input[$i];
}
Output:
string 'nljhfdb' (length=7)
You need to split the string using str_split to store it in an array. Now loop through the array and compare the keys to do a modulo operation.
<?php
$str = "abcdefghijklmn";
$nstr="";
foreach(str_split(strrev($str)) as $k=>$v)
{
if($k%2==0){
$nstr.= $v;
}
}
echo $nstr; //"prints" nljhfdb
I'd go for the same as Shankar did, though this is another approach for the loop.
<?php
$str = "abcdefghijklmn";
for($i=0;$i<strlen($str);$i++){
$res .= (($i-1) % 2 == 0 ? $str[$i] : "");
}
print(strrev($res)); // Result: nljhfdb
?>
reverse the string then do something like
foreach($array as $key => $value)
{
if($key%2 != 0) //The key is uneven, skip
continue;
//do your stuff
}
loop forward, append backward
<?php
$res = '';
$str = "abcdefghijklmn";
for ($i = 0; $i < strlen($str); $i++) {
if(($i - 1) % 2 == 0)
$res = $str[$i] . $res;
}
echo $res;
?>
preg_replace('/(.)./', '$1', strrev($str));
Where preg_replace replaces every two characters of the reversed string with the first of the two.
How about something like this:
$str = str_split("abcdefghijklmn");
echo join("",
array_reverse(
array_filter($str, function($var) {
global $str;
return(array_search($var,$str) & 1);
}
)
)
);
Any reason why this code sometimes only generates 4 character strings?
function genID()
{
$id = '';
$values = '0123456789abcdefghijklmnopqrstuvwxyz';
for($i=0; $i < 5; $i++) :
$str = substr($values, rand(0, strlen($values)), 1);
if(!is_nan(acos($str)))
(mt_rand(0, 1)) ? $str = strtoupper($str) : '';
$id .= $str;
endfor;
return $id; // e.g: ifR8j
}
acos($str) accepts numbers not string.... if u remove the aphabets from the string
ie.
$values = '0123456789abcdefghijklmnopqrstuvwxyz';
to
$values = '0123456789';
you will get the length as 5... Hope this helps..
Try, something simple:
function genID() {
$id = '';
$i = $length = 4;
$possible = "0123456789bcdfghjkmnpqrstvwxyz";
$possibleChar = strlen($possible) - 1;
while ($i) {
$char = $possible[mt_rand(0, $possibleChar)];
while (!strstr($id, $char)) {
$id .= $char;
$i--;
}
}
return $id;
}
(mt_rand(0, 1)) ? $str = strtoupper($str) : '';
This condition is met so sometimes you get an empty char.
Fix the condition or do the loop in some other manner.
For example
while(strlen($id)<5) {
//do the loop
}
The loop iterates 5 times.
rand will also return strlen, so $str will sometimes be ""
$str = substr($values, rand(0, strlen($values))-1, 1);
This will generate 5 characters always.
(my first post was not clear and confusing so I've edited the question)
I was studying string manipulation.
You can use strlen() or substr() but cannot rely on other functions that are predefined in libraries.
Given string $string = "This is a pen", remove "is" so that
return value is "Th a pen" (including 3 whitespaces).
Remove 'is' means if a string is "Tsih", we don't remove it. Only "is" is removed.
I've tried (shown below) but returned value is not correct. I've run test test and
I'm still capturing the delimiter.
Thanks in advance!
function remove_delimiter_from_string(&$string, $del) {
for($i=0; $i<strlen($string); $i++) {
for($j=0; $j<strlen($del); $j++) {
if($string[$i] == $del[$j]) {
$string[$i] = $string[$i+$j]; //this grabs delimiter :(
}
}
}
echo $string . "\n";
}
Clarifying, the original quiestion is not Implement a str_replace, It's remove 'is' from 'this is a pen' without any functions and no extra white spaces between words. The easiest way would be $string[2] = $string[3] = $string[5] = $string[6] = '' but that would leave an extra white space between Th and a (Th[ ][ ]a).
There you go, no functions at all
$string = 'This is a pen';
$word = 'is';
$i = $z = 0;
while($string[$i] != null) $i++;
while($word[$z] != null) $z++;
for($x = 0; $x < $i; $x++)
for($y = 0; $y < $z; $y++)
if($string[$x] === $word[$y])
$string[$x] = '';
If you were allowed to use substr() it'd be so much easier. Then you could just loop it and check for the matched value, why can't you use substr() but you can strlen() ?
But without, this works at least:
echo remove_delimiter_from_string("This is a pen","is");
function remove_delimiter_from_string($input, $del) {
$result = "";
for($i=0; $i<strlen($input); $i++) {
$temp = "";
if($i < (strlen($input)-strlen($del))) {
for($j=0; $j<strlen($del); $j++) {
$temp .= $input[$i+$j];
}
}
if($temp == $del) {
$i += strlen($del) - 1;
} else {
$result .= $input[$i];
}
}
return $result;
}
The following code can also used to replace the sub string:
$restring = replace_delimiter_from_string("This is a pen","is", "");
var_dump($restring);
$restring = replace_delimiter_from_string($restring," ", " ");
var_dump($restring);
function replace_delimiter_from_string($input, $old, $new) {
$input_len = strlen($input);
$old_len = strlen($old);
$check_len = $input_len-$old_len;
$result = "";
for($i=0; $i<=$check_len;) {
$sub_str = substr($input, $i, $old_len);
if($sub_str === $old) {
$i += $old_len;
$result .= $new;
}
else {
$result .= $input[$i];
if($i==$check_len) {
$result = $result . substr($input, $i+1);
}
$i++;
}
}
return $result;
}
How can I iteratively create a variant of "Murrays" that has an apostrophe after each letter? The end-result should be:
"m'rrays,mu'rrays,mur'rays,murr'ays,murra'ys,murray's"
My suggestion:
<?php
function generate($str, $add, $separator = ',')
{
$split = str_split($str);
$total = count($split) - 1;
$new = '';
for ($i = 0; $i < $total; $i++)
{
$aux = $split;
$aux[$i+1] = "'" . $aux[$i+1];
$new .= implode('', $aux).$separator;
}
return $new;
}
echo generate('murrays', "'");
?>
You want to iterate through the name, and re-print it with apostrophe's? Try the following:
<?php
$string = "murrays";
$array = str_split($string);
$length = count($array);
$output = "";
for ($i = 0; $i < $length; $i++) {
for($j = 0; $j < $length; $j++) {
$output .= $array[$j];
if ($j == $i)
$output.= "'";
}
if ($i < ($length - 1))
$output .= ",";
}
print $output;
?>
Here’s another solution:
$str = 'murrays';
$variants = array();
$head = '';
$tail = $str;
for ($i=1, $n=strlen($str); $i<$n; $i++) {
$head .= $tail[0];
$tail = substr($tail, 1);
$variants[] = $head . "'" . $tail;
}
var_dump(implode(',', $variants));
well that's why functionnal programming is here
this code works on OCAML and F#, you can easily make it running on C#
let generate str =
let rec gen_aux s index =
match index with
| String.length s -> [s]
| _ -> let part1 = String.substr s 0 index in
let part2 = String.substr s index (String.length s) in
(part1 ^ "'" ^ part2)::gen_aux s (index + 1)
in gen_aux str 1;;
generate "murrays";;
this code returns the original word as the end of the list, you can workaround that :)
Here you go:
$array = array_fill(0, strlen($string) - 1, $string);
implode(',', array_map(create_function('$string, $pos', 'return substr_replace($string, "\'", $pos + 1, 0);'), $array, array_keys($array)));