(my first post was not clear and confusing so I've edited the question)
I was studying string manipulation.
You can use strlen() or substr() but cannot rely on other functions that are predefined in libraries.
Given string $string = "This is a pen", remove "is" so that
return value is "Th a pen" (including 3 whitespaces).
Remove 'is' means if a string is "Tsih", we don't remove it. Only "is" is removed.
I've tried (shown below) but returned value is not correct. I've run test test and
I'm still capturing the delimiter.
Thanks in advance!
function remove_delimiter_from_string(&$string, $del) {
for($i=0; $i<strlen($string); $i++) {
for($j=0; $j<strlen($del); $j++) {
if($string[$i] == $del[$j]) {
$string[$i] = $string[$i+$j]; //this grabs delimiter :(
}
}
}
echo $string . "\n";
}
Clarifying, the original quiestion is not Implement a str_replace, It's remove 'is' from 'this is a pen' without any functions and no extra white spaces between words. The easiest way would be $string[2] = $string[3] = $string[5] = $string[6] = '' but that would leave an extra white space between Th and a (Th[ ][ ]a).
There you go, no functions at all
$string = 'This is a pen';
$word = 'is';
$i = $z = 0;
while($string[$i] != null) $i++;
while($word[$z] != null) $z++;
for($x = 0; $x < $i; $x++)
for($y = 0; $y < $z; $y++)
if($string[$x] === $word[$y])
$string[$x] = '';
If you were allowed to use substr() it'd be so much easier. Then you could just loop it and check for the matched value, why can't you use substr() but you can strlen() ?
But without, this works at least:
echo remove_delimiter_from_string("This is a pen","is");
function remove_delimiter_from_string($input, $del) {
$result = "";
for($i=0; $i<strlen($input); $i++) {
$temp = "";
if($i < (strlen($input)-strlen($del))) {
for($j=0; $j<strlen($del); $j++) {
$temp .= $input[$i+$j];
}
}
if($temp == $del) {
$i += strlen($del) - 1;
} else {
$result .= $input[$i];
}
}
return $result;
}
The following code can also used to replace the sub string:
$restring = replace_delimiter_from_string("This is a pen","is", "");
var_dump($restring);
$restring = replace_delimiter_from_string($restring," ", " ");
var_dump($restring);
function replace_delimiter_from_string($input, $old, $new) {
$input_len = strlen($input);
$old_len = strlen($old);
$check_len = $input_len-$old_len;
$result = "";
for($i=0; $i<=$check_len;) {
$sub_str = substr($input, $i, $old_len);
if($sub_str === $old) {
$i += $old_len;
$result .= $new;
}
else {
$result .= $input[$i];
if($i==$check_len) {
$result = $result . substr($input, $i+1);
}
$i++;
}
}
return $result;
}
Related
I am trying to get the length of a string and replace its first and last 3 characters with a star sign (*) and get the string length WITHOUT using any PHP build in functions.
strlen - substr - preg_replace
Example: $string = "123456789"; $new_string = "***456***";
Is it possible?
I have checked many tutorials and couldn't figure it out. Please help. Thanks!
Universal solution:
$string = "123456789";
$i = 0;
$limit = 3;
while (isset($string[$i])) {
if ($i < $limit) {
$string[$i] = '*';
}
$i++;
}
// you can rewrite this as loop
$string[$i - 1] = '*';
$string[$i - 2] = '*';
$string[$i - 3] = '*';
Starting with php7.1 where negative string indexes are allowed:
$string = "123456789";
// you can rewrite it to a loop too
$string[0] = $string[1] = $string[2] = $string[-1] = $string[-2] = $string[-3] = '*';
echo $string;
Solution without any function, but it emits PHP Notice, you can supress it with #:
$string = "123456789";
$i = 0;
$limit = 3;
while (true) {
if ($string[$i] == '') {
break;
}
if ($i < $limit) {
$string[$i] = '*';
}
$i++;
}
/* Simplified version:
while ($string[$i] != '') {
if ($i < $limit) {
$string[$i] = '*';
}
$i++;
}
*/
$string[$i - 1] = '*';
$string[$i - 2] = '*';
$string[$i - 3] = '*';
echo $string;
I don't know why you don't want to use any PHP functions. However, it is still possible.
<?php
function privacy($string)
{
//get the string length
$i = 0;
/*
while (isset($string[$i])) {
$i++;
}
*/
while ($string[$i] !== "") {
$i++;
}
//replace the first and last 3 characters of the $string with a star
//if the length is bigger than or equals to 6
if ($i >= 6) {
for ($x = 0; $x < 3; $x++) {
$string[$x] = "*";
$string[$i - $x] = "*";
}
}
return $i . "<br>" . $string;
}
echo privacy("123456789");
?>
Will echo out this
9
***456***
I think it is the easiest way to get the string length and replace the first and last 3 characters without confusion. So far!
Good luck!
You can simply achieve it usong loop.(No built-in function)
$string = "123456789";
$i = 0;
$new_str = "";
while(true)
{
$val = #$string[$i];
if($val == "")
break;
if($i<3)
$new_str .= "*";
else
$new_str .= $val;
$i++;
}
for($j=0;$j<$i;$j++)
{
if($j >= ($i-3))
$new_str[$j]="*";
}
echo $new_str;
DEMO
you can access a string like you would access an array.
$var = "leroy jenkins";
$var[2] = 'd';
var_dump($var); // "ledoy jenkins"
but I'm currently not sure how to get the last 3 without using a build in function
<?php
echo my_string_replace("world","jonathan","hello world helloworld");
function my_string_replace($find, $replace, $string)
{
//Block of codes here...
}
?>
I can only use loops, if else statements, and other commands such as break and continue. I want to create my own algorithm. Please help me. This should output : hello jonathan hellojonathan"
error_reporting(0); used for hide "Uninitialized string offset" notice.
<?php
function str_v2($num){
error_reporting(0);
for($i=0; $num[$i] != "";$i++);
echo $i; }//end of function
$name = "Hope this will work.";
echo str_v2($name);
?>
That was a fun brain teaser. Here you go:
echo my_string_replace("world", "jonathan", "hello world helloworld");
function my_string_replace($find, $replace, $string)
{
$characterCount = strlen($string);
$findCount = strlen($find);
$replaceCount = strlen($replace);
for ($i = 0; $i < $characterCount - $findCount +1; $i++) {
if ($string[$i] == $find[0]) {
$j = 1;
$found = true;
while ($j < $findCount) {
if ($string[$i + $j] != $find[$j]) {
$found = false;
break;
}
$j++;
}
if ($found) {
// copy string until current position
$replaced = '';
for ($x = 0; $x < $i; $x++) {
$replaced .= $string[$x];
}
// append replacement
$replaced .= $replace;
// copy after match till end
for ($x = $i + $findCount; $x < $characterCount; $x++) {
$replaced .= $string[$x];
}
// continue with replaced string, after replacement
$string = $replaced;
$characterCount = strlen($string);
$i = $i + $replaceCount;
}
}
}
return $string;
}
I am using codes like "gjhyYhK", "HJjhkeuJ" etc. But want user to show these codes like:
gj_y__K
HJj__e_J
means code will be edited with "_" at random positions in code.
This will do what you want:
$str = "gjhyYhK";
$len = strlen($str);
$num_to_remove = ceil($len * .4); // 40% removal
for($i = 0; $i < $num_to_remove; $i++)
{
$k = 0;
do
{
$k = rand(1, $len);
} while($str[$k-1] == "_");
$str[$k-1] = "_";
}
print $str . "\n";
If you want more underscores, change the value of $underscores. This will guarantee you get how many underscores you want, so long as you want fewer than the length of the string
Try this:
$string=array(
'gjhyYhK',
'HJjhkeuJ'
);
$arr=array();
foreach ($string as $key=>$value) {
$arr[$key]='';
for ($i=1; $i <=strlen($value); $i++) {
if(rand(0,1)){
$arr[$key].=substr($string[$key],$i,1);
}else{
$arr[$key].='_';
}
}
}
var_dump($arr);
you can try below code to get the functionality what you are looking for
<?php
$string = "gjhyYhK";
$percentage = 40;
$total_length = strlen($string);
$number_of_underscore = floor(($percentage / 100) * $total_length); // I have use floor value, you can use ceil() as well
for ($i = 1; $i <= $number_of_underscore; $i++)
{
$random_position = rand(0, strlen($string) - 1); // get the random position of character to be replaced
if (substr($string, $random_position, 1) !== '_') // check if its already replaced underscore (_)
{
$string = preg_replace("/" . (substr($string, $random_position, 1)) . "/", '_', $string, 1); // here preg_replaced use to replace the character only once, (i.e str_replace() will replace all matching characters)
}
else
{
$i--; // else decrement $i for the loop to run one more time
}
}
echo $string;
?>
let me know if any other help needed
$str = "ADFJ";
$strlen = strlen($str);
$newStr = '';
for ($i = 0; $i < $strlen; $i++) {
if ($i == rand(0, $strlen)) {
$newStr .= '_';
} else {
$newStr .= $str[$i];
}
}
echo $newStr;
How to get the count of string 2 occurrence in string 1 without php built-in functions.
Example:
$strone = "Arun sukumar";
$strtwo = "a";
//Expected Output: 2
$strone = "Arun sukumar";
$strtwo = "uk";
//Expected Output: 1
I need to get the count without using any php built-in functions.
This is the question asked in a interview, is there any logic in that?
You need to take your needle, get the first char.. then iterate over each char of the haystack until you get match. Then take the next char of needle and check the next char of the haystack for a match... continue until you have the complete match for needle or until you fial to match a char.
hint: you can access the individual chars of a string by index with $string{0} where 0 is the zero based index of the char in the string.
$strone = 'arun sukumar';
$strtwo = 'a';
echo parsestr($strone, $strtwo);
function parsestr($strone, $strtwo)
{
$len = 0;
while ($strtwo{$len} != '') {
$len++;
}
$nr = 0;
while ($strone{$nr} != '')
{
if($strone{$nr} != ' ')
{
$data[$nr] = $strone{$nr};
}
$nr++;
}
$newdata = $data;
if($len > 1)
{
$newdata = array();
$j = 0;
foreach($data as $val)
{
$str .= $val;
if($j == ($len -1))
{
$newdata[] = $str;
$str = '';
$j = 0;
}
else
$j++;
}
}
$i = 0;
foreach($newdata as $val)
{
if($val == $strtwo)
{
$i++;
}
}
return $i;
}
Try this
$string = 'Arun sukumar';
$sub_string = 'a';
$count = 0;
for($i=0;$i < strlen($string); $i++){
$flag = 0;
$j=0;
if(strtolower($string[$i]) == $sub_string[$j])
{
//echo "match";
$flag = 1;
$k = $i;
for(;$j< strlen($sub_string); $j++){//echo "[".$j . $k."] $count $flag";
if(strtolower($string[$k]) != $sub_string[$j]){
$flag = 0;
break;
}
$k++;
}//echo "<br> $flag";
}
if($flag == 1){
$count++;
$flag = 0;
}
}
echo $count;
?>
Not sure why you would not want to use the built-in PHP functions since they would be faster, but something like this would work:
<?php
$haystack = 'Arun sukumar';
$needle = 'a';
// you seem to want a case insensitive search, so do a strtolower first
$haystack = strtolower($haystack);
$hitCount = 0;
for ($i = 0; $i < strlen($haystack); ++$i) {
if ($needle === substr($haystack, $i, strlen($needle))) {
$hitCount++;
}
}
echo 'Output: ' . $hitCount;
?>
This question already has answers here:
Reverse the letters in each word of a string
(6 answers)
Closed 1 year ago.
This task has already been asked/answered, but I recently had a job interview that imposed some additional challenges to demonstrate my ability to manipulate strings.
Problem: How to reverse words in a string? You can use strpos(), strlen() and substr(), but not other very useful functions such as explode(), strrev(), etc.
Example:
$string = "I am a boy"
Answer:
I ma a yob
Below is my working coding attempt that took me 2 days [sigh], but there must be a more elegant and concise solution.
Intention:
1. get number of words
2. based on word count, grab each word and store into array
3. loop through array and output each word in reverse order
Code:
$str = "I am a boy";
echo reverse_word($str) . "\n";
function reverse_word($input) {
//first find how many words in the string based on whitespace
$num_ws = 0;
$p = 0;
while(strpos($input, " ", $p) !== false) {
$num_ws ++;
$p = strpos($input, ' ', $p) + 1;
}
echo "num ws is $num_ws\n";
//now start grabbing word and store into array
$p = 0;
for($i=0; $i<$num_ws + 1; $i++) {
$ws_index = strpos($input, " ", $p);
//if no more ws, grab the rest
if($ws_index === false) {
$word = substr($input, $p);
}
else {
$length = $ws_index - $p;
$word = substr($input, $p, $length);
}
$result[] = $word;
$p = $ws_index + 1; //move onto first char of next word
}
print_r($result);
//append reversed words
$str = '';
for($i=0; $i<count($result); $i++) {
$str .= reverse($result[$i]) . " ";
}
return $str;
}
function reverse($str) {
$a = 0;
$b = strlen($str)-1;
while($a < $b) {
swap($str, $a, $b);
$a ++;
$b --;
}
return $str;
}
function swap(&$str, $i1, $i2) {
$tmp = $str[$i1];
$str[$i1] = $str[$i2];
$str[$i2] = $tmp;
}
$string = "I am a boy";
$reversed = "";
$tmp = "";
for($i = 0; $i < strlen($string); $i++) {
if($string[$i] == " ") {
$reversed .= $tmp . " ";
$tmp = "";
continue;
}
$tmp = $string[$i] . $tmp;
}
$reversed .= $tmp;
print $reversed . PHP_EOL;
>> I ma a yob
Whoops! Mis-read the question. Here you go (Note that this will split on all non-letter boundaries, not just space. If you want a character not to be split upon, just add it to $wordChars):
function revWords($string) {
//We need to find word boundries
$wordChars = 'abcdefghijklmnopqrstuvwxyz';
$buffer = '';
$return = '';
$len = strlen($string);
$i = 0;
while ($i < $len) {
$chr = $string[$i];
if (($chr & 0xC0) == 0xC0) {
//UTF8 Characer!
if (($chr & 0xF0) == 0xF0) {
//4 Byte Sequence
$chr .= substr($string, $i + 1, 3);
$i += 3;
} elseif (($chr & 0xE0) == 0xE0) {
//3 Byte Sequence
$chr .= substr($string, $i + 1, 2);
$i += 2;
} else {
//2 Byte Sequence
$i++;
$chr .= $string[$i];
}
}
if (stripos($wordChars, $chr) !== false) {
$buffer = $chr . $buffer;
} else {
$return .= $buffer . $chr;
$buffer = '';
}
$i++;
}
return $return . $buffer;
}
Edit: Now it's a single function, and stores the buffer naively in reversed notation.
Edit2: Now handles UTF8 characters (just add "word" characters to the $wordChars string)...
My answer is to count the string length, split the letters into an array and then, loop it backwards. This is also a good way to check if a word is a palindrome. This can only be used for regular string and numbers.
preg_split can be changed to explode() as well.
/**
* Code snippet to reverse a string (LM)
*/
$words = array('one', 'only', 'apple', 'jobs');
foreach ($words as $d) {
$strlen = strlen($d);
$splits = preg_split('//', $d, -1, PREG_SPLIT_NO_EMPTY);
for ($i = $strlen; $i >= 0; $i=$i-1) {
#$reverse .= $splits[$i];
}
echo "Regular: {$d}".PHP_EOL;
echo "Reverse: {$reverse}".PHP_EOL;
echo "-----".PHP_EOL;
unset($reverse);
}
Without using any function.
$string = 'I am a boy';
$newString = '';
$temp = '';
$i = 0;
while(#$string[$i] != '')
{
if($string[$i] == ' ') {
$newString .= $temp . ' ';
$temp = '';
}
else {
$temp = $string[$i] . $temp;
}
$i++;
}
$newString .= $temp . ' ';
echo $newString;
Output: I ma a yob