These are two files
Calling.php
<html>
<body>
<form action="Called.php" method="get">
<input type="button" name="B1" value="B1">
<input type="button" name="B2" value="B2">
<input type="Submit" name="Submit1"/>
<!-- Google
yahoo
-->
</form>
</body>
</html>
And Called.php
<?php
if(isset($_GET("Submit1")))
{
echo("<script>location.href = 'http://stackoverflow.com';</script>");
}
if(isset($_GET["B1"]))
{
echo("<script>location.href = 'http://google.com/';</script>");
exit();
}
if(isset($_GET["B2"]))
- List item
{
echo "<meta http-equiv='refresh' content='0;url=http://www.yahoo.com'>";
exit();
}
?>
When i click the buttons "B1" and "B2", page will blink but now where redirect and third one "Submit" button will redirect to new page and there i am getting the out put as "Called.php".
Please spend few seconds for this php beginner.
You can't directly because the button click is a client side activity and PHP is server side. If you make all the inputs submit then the one the user clicked will be submitted as part of the $_GET array but that only works if the user clicks one of them and doesn't submit the form by, say, hitting Enter in a text input.
You could attach AJAX events to the button and have them trigger off a PHP script to run the function you want to run, but that has its own set of issues.
EDIT: I should note that your method of redirecting is rather inelegant to say the least. You can just use header() to do the redirection, it would be much cleaner than all this messing around with echoing out javascript.
You need to use Ajax to do this. If you are using jQuery ajax the code will look something like this
$(function(){
$('input[type="button"]').click(function(){
var name = $(this).attr('value');
$.ajax({
type :'GET',
url : 'Calling.php',
data :{name:name}
success : function(data) {
//do smthng
}
})
})
})
//Code is not tested. Need to verify.
Related
I want to create a confirm yes/no box in php
my code like this:
<?php
if(isset($_REQUEST['id']))
{
?>
<script>
var cf=confirm("do you want to delete Y/N");
if(cf)
{ i want to call code edit of php
}
</script>
<?php
}
?>
<html>
<head>
</head>
<body>
<form name="frm" method="post" action="edit.php">
Edit <br>
Edit <br>
Edit <br>
</form>
</body>
</html>
I Want to when press Yes i call code edit in PHP
But it do not work.
Can you help me ?
Thanks you
Just use inline onclick event.
This is a simple techique, you can use it in your PHP page.
Edit
In your code, you have mentioned PHP but, have used JavaScript.
If you want to do a confirm with PHP,
Create an intermediate page for confirmation.
Post form data there.
On confirmation page, add two submit buttons:
Yes: If pressed this, redirect/post to edit page.
No: If pressed this, redirect back to form
So, your confirmation page should be:
<html>
<head>
</head>
<body>
<?php
if (isset($_POST['confirm'])) {
if ($_POST['confirm'] == 'Yes') {
header("Location:edit.php?id=1");
}
else if ($_POST['confirm'] == 'No') {
header("goBack.php");
}
}
?>
<form method="post">
<?php
if(isset($_REQUEST['id']))
{
?>
<input type="submit" name="confirm" value="Yes"><br/>
<input type="submit" name="confirm" value="No"><br/>
<?php
}
?>
</form>
Put an id on your form:
Create an event listener for the form's onsubmit event
<script>
function onFormSubmission(e){
return confirm("do you want to delete Y/N");
}
var frm = document.getElementById('frm');
frm.addEventListener("submit", onFormSubmission);
</script>
When the user submits a form they will be prompted with your message. If they click Yes the function will return true and the form will be submitted. Otherwise the function will return false and the form submission will be cancelled
I think this is what you want to do:
<?php
//YOU MUST BE SURE THAT YOUR URL CONTAINS THE $_REQUEST['id'] PARAMETER, OTHERWISE IT WON'T WORK FROM YOUR CODE... IF YOU WANT IT TO WORK REGARDLESS OF THAT, JUST COMMENT OUT THE IF(ISSET(... BLOCK...
$editURL = "edit.php"; //EDIT URL HERE
if(isset($_REQUEST['id'])) {
//ASSIGN THE ID TO A VARIABLE FOR BUILDING THE URL LATER IN JS...
//THE DEFAULT ID IS 1 BUT YOU CAN DECIDE WITH YOUR OWN LOGIC
$defaultID = ($dID = intval(trim($_REQUEST['id']))) ? $dID : 1;
?>
<script>
function confirmEdit(evt){
evt.preventDefault();
var cf=confirm("do you want to delete Y/N");
var id=<?php echo defaultID; ?>;
if(cf){
//i want to call code edit of php
//HERE'S THE CODE YOU MAY NEED TO RUN;
if(id){
//RETURN TRUE SO THAT THE SCRIPT WITH LINK TO THE APPROPRIATE URL
return true;
// OR REDIRECT WITH JAVASCRIPT TO EDIT PAGE WITH APPROPRIATE ID
//window.location = "" + <?php echo $editURL; ?> + "?id=" + id; //YOU ALREADY HAVE THE EDIT URL... JUST APPEND THE QUERY-STRING WITH ID TO USE IN THE EDIT PAGE
// You might also just (without redirecting) return true here so to that the page continues like you just clicked on the link itself...
}
}
}
</script>
<?php
}
?>
<html>
<head>
</head>
<body>
<!-- THE FORM TAG IS NOT NECESSARY IN THIS CASE SINCE YOUR ANCHOR TAGS HAVE THE EXACT URL YOU WANT ASSOCIATED WITH THEM... AND YOU DON'T EVEN NEED JAVASCRIPT IN THIS CASE... BECAUSE THE HREF OF THE LINKS ARE HARD-CODED... -->
<!-- <form name="frm" method="post" action="edit.php"> -->
<a class='class-4-css' onclick="confirmEdit();" id='dynamic-id-based-btn-1' href="edit.php?id=1">Edit Page 1 </a> <br>
<a class='class-4-css' onclick="confirmEdit();" id='dynamic-id-based-btn-2' href="edit.php?id=2">Edit Page 2</a> <br>
<a class='class-4-css' onclick="confirmEdit();" id='dynamic-id-based-btn-3' href="edit.php?id=3">Edit Page 3</a> <br>
<!-- </form> -->
</body>
</html>
So, now clicking on any of the Links will Ask me to confirm if I want to delete the Resource or not. If I choose yes, then the appropriate page is loaded for the Process...
not sure if the other answers really answered your question, this was my problem too, then I experimented and here's what I came up with:
.
confirmation in php :
$Confirmation = "<script> window.confirm('Your confirmation message here');
</script>";
echo $Confirmation;
if ($Confirmation == true) {
your code goes here
}
that's all, other people might look for this, you're welcome :)
I was looking to simply have a confirmation box in php before triggering POST isset without going through javascript:
echo "<input id='send_btn' type='submit' value='previous'
name='previous' OnClick=\"return confirm('Are you sure you want to go
to previous');\" >";
This appeared for me to be the easiest solution.
I have a tiny form on a page where I ask for the users name, the form sends the data to name.php and echos back the users name for example "Hello Steven" Steven being the name entered into the form.
Now that the name has been echoed to that form, I would like to echo that same data again elsewhere on the page. This is where I've run into a wall.
I would rather not send the names entered into the form to a server or database, but simply keep them for a session and then lose them.
The issue now is echoing the form data multiple times on one page.
The code I am using right now for the tiny form is as follows:
<form role="form" id="inviteform3" class="form-inline" action="name.php" method="POST">
<div class="form-group">
<input type="text" class="form-control input-sm" name="name" placeholder="Your Name"
id="hello" autocomplete="off" style="margin-top:10px">
</div>
<center>
<span id="result"></span>
<button class="btn btn-brand btn-sm next-screen animated bounceInUp"
id="go" style="margin-top:5px; display:none" href="#services" data-animation-delay=".5s">
Let's Go!</button></center>
<button class="btn btn-block btn-brand btn-xs invitebtn3" id="casi" type="submit"
style="margin-top:5px"><i class="fa fa-thumbs-o-up"></i> Submit</button>
</form>
My php form (name.php) is as follows:
<html>
<body>
Let's get started, <?php echo $_POST["name"]; ?>
</body>
</html>
and my js code is:
<script>
$(document).on("ready", function(){
//Form action
$("#inviteform3").on("submit", function(event){
// Stop submit event
event.preventDefault();
$.ajax({
type:'POST',
url: 'name.php',
data:$('#inviteform3').serialize(),
success: function(response)
{
$('#inviteform3').find('#result').html(response);
}});
});
});
</script>
We need to get a few things straight:
I would rather not send the names entered into the form to a server or database, but simply keep them for a session and then lose them.
You ARE sending that data to the server, you have used jQuery and AJAX to POST your form to name.php (php works on the server) from which you receive the response and add it your page with the line:
$('#inviteform3').find('#result').html(response);
If you want to KEEP that data stored (for example in a session), you can use the PHP suggested by Antony D'Andrea in name.php. When the browser is closed, the session is destroyed. Untill then you can use the session variable where ever you want.
Now that the name has been echoed to that form, I would like to echo
that same data again elsewhere on the page. This is where I've run
into a wall.
You are echoing the name in name.php, your AJAX call then retrieves the whole page (including the html and body tags) and adds it to #result. If you want to show the name mulitple times, just append it multiple times with the line above.
$("#inviteform3").on("submit", function(event) {
var name = $("form input['name']").val();
// Here is the interesting part
sessionStorage.setItem("name", name);
}
// Get that name
var access_name = sessionStorage.getItem("name");
$("#some_id").html(access_name); // Inserts the name where you want it.
sessionStorage is wiped every time the tab/window is closed.
You could use PHP instead of Javascript.
session_start();
$_SESSION['name'] = $_POST['name'];
The $_SESSION variable is cleared when the browser is closed and is global so can be accessed anywhere. session_start has to be the very first thing you do though on line 1 of the first page that is run.
More info about sessions in PHP can be found here and the about $_SESSION here.
For example:
You are posting to name.php. So on line 1 of name.php do
<?php session_start(); ?>
Then do
<?php
if (isset($_POST['name'])) {
$_SESSION['name'] = $_POST['name'];
}
?>
Then wherever you want to use it, just do echo $_SESSION['name'];
If you want to echo in other files. Then in line 1 of the other file do
<?php session_start(); ?>
Then:
<?php
if (isset($_SESSION['name'])) {
echo $_SESSION['name'];
}
?>
The if statement is just there for checking, but you don't need it if you are confident it is set.
What I'm trying to do is to pass a user to a php script via a href link, then have them passed back to exactly the same position that they were at before they clicked the link, like the page hasn't been refreshed. Does anyone know if or how this could be possible possible? Thank you.
Using HTML you can have the following
<p id='open_here'><a href='script.php'> Send to script </a> </p>
And then you can link back to that exact position with
Send Back to page
So essentially, instead of using a regular link as in the previuos code snippet, you could redirect back to the page using
//php redirect
<?php header('Location: mypage.html#open_here'); ?>
//Javascript redirect
<script type='text/javascript'>
window.location = "mypage.html#open_here";
</script>
If you don't mind adding some Javascript to make it work, here is a solution that will make it possible to redirect back to the exact same scrollbar position as when the user clicked the link.
index.php (the file where the link is)
<script>
window.addEventListener('load', function() {
// Do we have a #scroll in the URL hash?
if(window.location.hash && /#scroll/.test(window.location.hash)) {
// Scroll to the #scroll value
window.scrollTo(0, window.location.hash.replace('#scroll=', ''));
}
// Get all <a> elements with data-remember-position attribute
var links = document.querySelectorAll('a[data-remember-position]');
if(links.length) {
// Loop through the found links
for(var i = 0; i < links.length; i++) {
// Listen for clicks
links[i].addEventListener('click', function(e) {
// Prevent normal redirection
e.preventDefault();
// Redirect manually but put the current scroll value at the end
window.location = this.href + '?scroll=' + window.scrollY;
});
}
}
});
</script>
page.php (the PHP script that redirects back)
<?php
// Get the provided scroll position if it exists, otherwise put 0
$scrollPos = (array_key_exists('scroll', $_GET)) ? $_GET['scroll'] : 0;
// Redirect back to index.php and provide the scroll position as a hash value
header('Location: index.php#scroll='.$scrollPos);
Hope it helps! :)
I am just spilling ideas here, but I would use javascript to intercept user's click on the href, and .preventDefault first. Then figure out where the user is on the page. Maybe by splitting the page into sections, indentified by IDs. Your html markup would be something like
<div id="section-1"></div>
<div id="section-2"></div>
<div id="section-3"></div>
so when javascript prevents the link from executing, it would figure out in which section the user currently is. Let's say we know each section's height. Then we need to find out the scrollbar position. I haven't done that, but have a look here
http://api.jquery.com/scrollTop/
Once we know the height of each section and once we can detect where the scroll bar is, we can determine in which section the user is residing. Then, we fetch the url of the href link and add a query string to it like, http://something.com/script.php?section=2 and redirect user to it with whatever data you want . Then once the script has done it's job append the query string to the redirect-uri and redirect the user back with something like http://something.com#section-2 and the user will immediatly pop to section-2
I know this isn't a very specific answer, but hopefully I've given you some leads and ideas how to accomplish this. Let me know how it works!
I'd had to remember the scroll position for a <select>. Example below. Three
submit buttons to illustrate why there's three getElementById. To see
it work you must move the scroll bar first
<?php
$scrollusObscura=$_GET["imgbtn"];
$header = <<<EOD
<!DOCTYPE html>
<html>
<head>
<title>snk_db</title>
<meta http-equiv="Content-Type" content="text/html;charset=utf-8" >
<head>
<script>
function gety(){
var y=document.getElementById('myUlID').scrollTop;
document.getElementById('imgbtn1').value=y;
document.getElementById('imgbtn2').value=y;
document.getElementById('imgbtn3').value=y;
}
function itemRelevatur(scrollum){
document.getElementById('myUlID').scrollTo(0, scrollum);
}
</script>
</head>
<body onload="itemRelevatur({$scrollusObscura})" >
EOD;
$html= <<<EOD
<div >
<select size="6" id="myUlID" name="myUlName" onscroll="myTimer = setInterval(gety, 300)">
<option>'1'</option>
<option>'2'</option>
<option>'3'</option>
<option>'4'</option>
<option>'5'</option>
<option>'6'</option>
<option>'7'</option>
<option>'8'</option>
<option>'9'</option>
<option>'10'</option>
<option>'11'</option>
<option>'12'</option>
<option>'13'</option>
<option>'14'</option>
<option>'15'</option>
<option>'16'</option>
<option>'17'</option>
<option>'18'</option>
<option>'19'</option>
</select>
</div>
EOD;
$html1= <<<EOD
<div><form method='GET' action'myscript.php'>
<input type='hidden' name='imgbtn' id='imgbtn1' value=''></input>
<input type='submit' value='Submit' ></input>
</form>
EOD;
$html2= <<<EOD
<form method='GET' action'myscript.php'>
<input type='hidden' name='imgbtn' id='imgbtn2' value=''></input>
<input type='submit' value='Submit' ></input>
</form>
EOD;
$html3= <<<EOD
<form method='GET' action'myscript.php'>
<input type='hidden' name='imgbtn' id='imgbtn3' value=''></input>
<input type='submit' value='Submit' ></input>
</form></div>
EOD;
echo $header;
echo $html;
echo $html1;
echo $html2;
echo $html3."</body></html>";
I had major problems with cookie javascript libraries, most cookie libraries could not load fast enough before i needed to scroll in the onload event. so I went for the modern html5 browser way of handling this. it stores the last scroll position in the client web browser itself, and then on reload of the page reads the setting from the browser back to the last scroll position.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function () {
if (localStorage.getItem("my_app_name_here-quote-scroll") != null) {
$(window).scrollTop(localStorage.getItem("my_app_name_here-quote-scroll"));
}
$(window).on("scroll", function() {
localStorage.setItem("my_app_name_here-quote-scroll", $(window).scrollTop());
});
});
</script>
I'm trying to execute a PHP function in the same page after the user enters a text and presses a submit button.
The first I think of is using forms. When the user submits a form, a PHP function will be executed in the same page. The user will not be directed to another page. The processing will be done and displayed in the same page (without reloading).
Here is what I reach to:
In the test.php file:
<form action="test.php" method="post">
<input type="text" name="user" placeholder="enter a text" />
<input type="submit" value="submit" onclick="test()" />
</form>
The PHP code [ test() function ] is in the same file also:
<?php
function test() {
echo $_POST["user"]; // Just an example of processing
}
?>
However, I still getting a problem! Does anyone have an idea?
This cannot be done in the fashion you are talking about. PHP is server-side while the form exists on the client-side. You will need to look into using JavaScript and/or Ajax if you don't want to refresh the page.
test.php
<form action="javascript:void(0);" method="post">
<input type="text" name="user" placeholder="enter a text" />
<input type="submit" value="submit" />
</form>
<script type="text/javascript">
$("form").submit(function(){
var str = $(this).serialize();
$.ajax('getResult.php', str, function(result){
alert(result); // The result variable will contain any text echoed by getResult.php
}
return(false);
});
</script>
It will call getResult.php and pass the serialized form to it so the PHP can read those values. Anything getResult.php echos will be returned to the JavaScript function in the result variable back on test.php and (in this case) shown in an alert box.
getResult.php
<?php
echo "The name you typed is: " . $_REQUEST['user'];
?>
NOTE
This example uses jQuery, a third-party JavaScript wrapper. I suggest you first develop a better understanding of how these web technologies work together before complicating things for yourself further.
You have a big misunderstanding of how the web works.
Basically, things happen this way:
User (well, the browser) requests test.php from your server
On the server, test.php runs, everything inside is executed, and a resulting HTML page (which includes your form) will be sent back to browser
The browser displays the form, the user can interact with it.
The user submits the form (to the URL defined in action, which is the same file in this case), so everything starts from the beginning (except the data in the form will also be sent). New request to the server, PHP runs, etc. That means the page will be refreshed.
You were trying to invoke test() from your onclick attribute. This technique is used to run a client-side script, which is in most cases Javascript (code will run on the user's browser). That has nothing to do with PHP, which is server-side, resides on your server and will only run if a request comes in. Please read Client-side Versus Server-side Coding for example.
If you want to do something without causing a page refresh, you have to use Javascript to send a request in the background to the server, let PHP do what it needs to do, and receive an answer from it. This technique is basically called AJAX, and you can find lots of great resources on it using Google (like Mozilla's amazing tutorial).
Here is a full php script to do what you're describing, though pointless. You need to read up on server-side vs. client-side. PHP can't run on the client-side, you have to use javascript to interact with the server, or put up with a page refresh. If you can't understand that, there is no way you'll be able to use my code (or anyone else's) to your benefit.
The following code performs AJAX call without jQuery, and calls the same script to stream XML to the AJAX. It then inserts your username and a <br/> in a div below the user box.
Please go back to learning the basics before trying to pursue something as advanced as AJAX. You'll only be confusing yourself in the end and potentially wasting other people's money.
<?php
function test() {
header("Content-Type: text/xml");
echo "<?xml version=\"1.0\" standalone=\"yes\"?><user>".$_GET["user"]."</user>"; //output an xml document.
}
if(isset($_GET["user"])){
test();
} else {
?><html>
<head>
<title>Test</title>
<script type="text/javascript">
function do_ajax() {
if(window.XMLHttpRequest){
xmlhttp=new XMLHttpRequest();
} else {
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function(){
if (xmlhttp.readyState==4 && xmlhttp.status==200)
{
var xmlDoc = xmlhttp.responseXML;
data=xmlDoc.getElementsByTagName("user")[0].childNodes[0].nodeValue;
mydiv = document.getElementById("Test");
mydiv.appendChild(document.createTextNode(data));
mydiv.appendChild(document.createElement("br"));
}
}
xmlhttp.open("GET","<?php echo $_SERVER["PHP_SELF"]; ?>?user="+document.getElementById('username').value,true);
xmlhttp.send();
}
</script>
</head>
<body>
<form action="test.php" method="post">
<input type="text" name="user" placeholder="enter a text" id="username"/>
<input type="button" value="submit" onclick="do_ajax()" />
</form>
<div id="Test"></div>
</body>
</html><?php } ?>
Without reloading, using HTML and PHP only it is not possible, but this can be very similar to what you want, but you have to reload:
<?php
function test() {
echo $_POST["user"];
}
if (isset($_POST[])) { // If it is the first time, it does nothing
test();
}
?>
<form action="test.php" method="post">
<input type="text" name="user" placeholder="enter a text" />
<input type="submit" value="submit" onclick="test()" />
</form>
Use SAJAX or switch to JavaScript
Sajax is an open source tool to make
programming websites using the Ajax
framework — also known as
XMLHTTPRequest or remote scripting —
as easy as possible. Sajax makes it
easy to call PHP, Perl or Python
functions from your webpages via
JavaScript without performing a
browser refresh.
That's now how PHP works. test() will execute when the page is loaded, not when the submit button is clicked.
To do this sort of thing, you have to have the onclick attribute do an AJAX call to a PHP file.
in case you don't want to use Ajax , and want your page to reload .
<?php
if(isset($_POST['user']) {
echo $_POST["user"]; //just an example of processing
}
?>
Take a look at this example:
<!DOCTYPE HTML>
<html>
<head>
</head>
<body>
<?php
// define variables and set to empty values
$name = $email = $gender = $comment = $website = "";
if ($_SERVER["REQUEST_METHOD"] == "POST") {
$name = test_input($_POST["name"]);
$email = test_input($_POST["email"]);
$website = test_input($_POST["website"]);
$comment = test_input($_POST["comment"]);
$gender = test_input($_POST["gender"]);
}
function test_input($data) {
$data = trim($data);
$data = stripslashes($data);
$data = htmlspecialchars($data);
return $data;
}
?>
<h2>PHP Form Validation Example</h2>
<form method="post" action="<?php echo htmlspecialchars($_SERVER["PHP_SELF"]);?>">
Name: <input type="text" name="name">
<br><br>
E-mail: <input type="text" name="email">
<br><br>
Website: <input type="text" name="website">
<br><br>
Comment: <textarea name="comment" rows="5" cols="40"></textarea>
<br><br>
Gender:
<input type="radio" name="gender" value="female">Female
<input type="radio" name="gender" value="male">Male
<br><br>
<input type="submit" name="submit" value="Submit">
</form>
<?php
echo "<h2>Your Input:</h2>";
echo $name;
echo "<br>";
echo $email;
echo "<br>";
echo $website;
echo "<br>";
echo $comment;
echo "<br>";
echo $gender;
?>
</body>
</html>
You can submit the form without refreshing the page, but to my knowledge it is impossible without using a JavaScript/Ajax call to a PHP script on your server. The following example uses the jQuery JavaScript library.
HTML
<form method = 'post' action = '' id = 'theForm'>
...
</form>
JavaScript
$(function() {
$("#theForm").submit(function() {
var data = "a=5&b=6&c=7";
$.ajax({
url: "path/to/php/file.php",
data: data,
success: function(html) {
.. anything you want to do upon success here ..
alert(html); // alert the output from the PHP Script
}
});
return false;
});
});
Upon submission, the anonymous Javascript function will be called, which simply sends a request to your PHP file (which will need to be in a separate file, btw). The data above needs to be a URL-encoded query string that you want to send to the PHP file (basically all of the current values of the form fields). These will appear to your server-side PHP script in the $_GET super global. An example is below.
var data = "a=5&b=6&c=7";
If that is your data string, then the PHP script will see this as:
echo($_GET['a']); // 5
echo($_GET['b']); // 6
echo($_GET['c']); // 7
You, however, will need to construct the data from the form fields as they exist for your form, such as:
var data = "user=" + $("#user").val();
(You will need to tag each form field with an 'id', the above id is 'user'.)
After the PHP script runs, the success function is called, and any and all output produced by the PHP script will be stored in the variable html.
...
success: function(html) {
alert(html);
}
...
This is the better way that I use to create submit without loading in a form.
You can use some CSS to stylise the iframe the way you want.
A php result will be loaded into the iframe.
<form method="post" action="test.php" target="view">
<input type="text" name="anyname" palceholder="Enter your name"/>
<input type="submit" name="submit" value="submit"/>
</form>
<iframe name="view" frameborder="0" style="width:100%">
</iframe>
Hiya:
i know some people would be so tired of my questions, but I'm working on a uni project and need to get it done as soon as possible. This question is about using JS on a button(button) and sending a php_my_sql update on the same button. The problem is JS uses button, right? but PHP uses button(submit). How can I get these two to work on one of these buttons, cuz there has to be only one button.
this is my code for JS
<script type="text/javascript">
function formAction(){
var x=document.getElementById("collect")
x.remove(x.selectedIndex)
}
</script>
HTML
<form method="post">
<select id="collect" name="Select1" style="width: 193px">
<option>guns</option>
<option>knife</option>
</select> <input type="**submit/button**" onclick="formAction()" name="Collect" value="Collect" /></form>
PHP
<?
if (isset($_POST['Collect'])) {
mysql_query("UPDATE Player SET score = score+10
WHERE name = 'Rob Jackson' AND rank = 'Lieutenant'");
}
?>
This can be a way
Submit the form through JS after removing parameter
<script type="text/javascript">
function formAction(){
var x=document.getElementById("collect")
x.remove(x.selectedIndex);
document.forms[0].submit();
}
</script>
Input type button
<input type="button" onclick="formAction()" name="Collect" value="Collect" />
Embed jQuery and use $.post() to send an AJAX request.
JavaScript can interact with the button whilst the user is navigating the page and entering data into the form. The instant the user pushes the submit button and the request for the form submission is sent JS no longer has control. The request is sent to the form's action (most likely a PHP file) which processes the request and gives an answer back.
If you really need to combine the two, look into AJAX.
<?php print_r($_POST); ?>
<script type="text/javascript">
function formAction(){
var x=document.getElementById("collect");
x.remove(x.selectedIndex);
submit_form();
}
function submit_form() {
document.form1.submit();
}
</script>
<form method="post" name='form1'>
<input type='hidden' name='Collect'/>
<select id="collect" name="Select1" style="width: 193px">
<option>guns</option>
<option>knife</option>
</select> <input type="button" onclick="formAction()" name="Collect" value="Collect" /></form>
<?
if (isset($_POST['Collect'])) {
//do whatever update you want
}
?>
Simple Solution
Make this modification in the form tag
<form method="post" onsubmit="return formAction()">
In JavaScript function add a line "return true;" at the end of the function.
Voila ..!!! you are done..!!
Enjoy..!!