What I'm trying to do is to pass a user to a php script via a href link, then have them passed back to exactly the same position that they were at before they clicked the link, like the page hasn't been refreshed. Does anyone know if or how this could be possible possible? Thank you.
Using HTML you can have the following
<p id='open_here'><a href='script.php'> Send to script </a> </p>
And then you can link back to that exact position with
Send Back to page
So essentially, instead of using a regular link as in the previuos code snippet, you could redirect back to the page using
//php redirect
<?php header('Location: mypage.html#open_here'); ?>
//Javascript redirect
<script type='text/javascript'>
window.location = "mypage.html#open_here";
</script>
If you don't mind adding some Javascript to make it work, here is a solution that will make it possible to redirect back to the exact same scrollbar position as when the user clicked the link.
index.php (the file where the link is)
<script>
window.addEventListener('load', function() {
// Do we have a #scroll in the URL hash?
if(window.location.hash && /#scroll/.test(window.location.hash)) {
// Scroll to the #scroll value
window.scrollTo(0, window.location.hash.replace('#scroll=', ''));
}
// Get all <a> elements with data-remember-position attribute
var links = document.querySelectorAll('a[data-remember-position]');
if(links.length) {
// Loop through the found links
for(var i = 0; i < links.length; i++) {
// Listen for clicks
links[i].addEventListener('click', function(e) {
// Prevent normal redirection
e.preventDefault();
// Redirect manually but put the current scroll value at the end
window.location = this.href + '?scroll=' + window.scrollY;
});
}
}
});
</script>
page.php (the PHP script that redirects back)
<?php
// Get the provided scroll position if it exists, otherwise put 0
$scrollPos = (array_key_exists('scroll', $_GET)) ? $_GET['scroll'] : 0;
// Redirect back to index.php and provide the scroll position as a hash value
header('Location: index.php#scroll='.$scrollPos);
Hope it helps! :)
I am just spilling ideas here, but I would use javascript to intercept user's click on the href, and .preventDefault first. Then figure out where the user is on the page. Maybe by splitting the page into sections, indentified by IDs. Your html markup would be something like
<div id="section-1"></div>
<div id="section-2"></div>
<div id="section-3"></div>
so when javascript prevents the link from executing, it would figure out in which section the user currently is. Let's say we know each section's height. Then we need to find out the scrollbar position. I haven't done that, but have a look here
http://api.jquery.com/scrollTop/
Once we know the height of each section and once we can detect where the scroll bar is, we can determine in which section the user is residing. Then, we fetch the url of the href link and add a query string to it like, http://something.com/script.php?section=2 and redirect user to it with whatever data you want . Then once the script has done it's job append the query string to the redirect-uri and redirect the user back with something like http://something.com#section-2 and the user will immediatly pop to section-2
I know this isn't a very specific answer, but hopefully I've given you some leads and ideas how to accomplish this. Let me know how it works!
I'd had to remember the scroll position for a <select>. Example below. Three
submit buttons to illustrate why there's three getElementById. To see
it work you must move the scroll bar first
<?php
$scrollusObscura=$_GET["imgbtn"];
$header = <<<EOD
<!DOCTYPE html>
<html>
<head>
<title>snk_db</title>
<meta http-equiv="Content-Type" content="text/html;charset=utf-8" >
<head>
<script>
function gety(){
var y=document.getElementById('myUlID').scrollTop;
document.getElementById('imgbtn1').value=y;
document.getElementById('imgbtn2').value=y;
document.getElementById('imgbtn3').value=y;
}
function itemRelevatur(scrollum){
document.getElementById('myUlID').scrollTo(0, scrollum);
}
</script>
</head>
<body onload="itemRelevatur({$scrollusObscura})" >
EOD;
$html= <<<EOD
<div >
<select size="6" id="myUlID" name="myUlName" onscroll="myTimer = setInterval(gety, 300)">
<option>'1'</option>
<option>'2'</option>
<option>'3'</option>
<option>'4'</option>
<option>'5'</option>
<option>'6'</option>
<option>'7'</option>
<option>'8'</option>
<option>'9'</option>
<option>'10'</option>
<option>'11'</option>
<option>'12'</option>
<option>'13'</option>
<option>'14'</option>
<option>'15'</option>
<option>'16'</option>
<option>'17'</option>
<option>'18'</option>
<option>'19'</option>
</select>
</div>
EOD;
$html1= <<<EOD
<div><form method='GET' action'myscript.php'>
<input type='hidden' name='imgbtn' id='imgbtn1' value=''></input>
<input type='submit' value='Submit' ></input>
</form>
EOD;
$html2= <<<EOD
<form method='GET' action'myscript.php'>
<input type='hidden' name='imgbtn' id='imgbtn2' value=''></input>
<input type='submit' value='Submit' ></input>
</form>
EOD;
$html3= <<<EOD
<form method='GET' action'myscript.php'>
<input type='hidden' name='imgbtn' id='imgbtn3' value=''></input>
<input type='submit' value='Submit' ></input>
</form></div>
EOD;
echo $header;
echo $html;
echo $html1;
echo $html2;
echo $html3."</body></html>";
I had major problems with cookie javascript libraries, most cookie libraries could not load fast enough before i needed to scroll in the onload event. so I went for the modern html5 browser way of handling this. it stores the last scroll position in the client web browser itself, and then on reload of the page reads the setting from the browser back to the last scroll position.
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>
<script type="text/javascript">
$(document).ready(function () {
if (localStorage.getItem("my_app_name_here-quote-scroll") != null) {
$(window).scrollTop(localStorage.getItem("my_app_name_here-quote-scroll"));
}
$(window).on("scroll", function() {
localStorage.setItem("my_app_name_here-quote-scroll", $(window).scrollTop());
});
});
</script>
Related
I'm learning AJAX and want to create a really simple web app to use my knowledge in the "real world".
I'm trying to calculte different percentages of a user input value, and make it appears on the webpage, without refreshing, thanks to AJAX.
Here is my HTML form:
<form id="warmupForm" class="form">
<label for="userWorkLoad">Work load (in kgs)</label><br>
<input type="text" name="userWorkLoad" id="userWorkLoad">
<button type="submit">Calculate</button>
</form>
<div id="#output">This is where I want the result to be shown with AJAX</div>
Here is some of my PHP code, for you to get the idea:
# Get the user input (work load in kgs)
if (isset($_POST['userWorkLoad'])) {
$workload = $_POST['userWorkLoad'];
# Avoid JS hacking
$workload = htmlspecialchars($workload);
}
# CALCULATION #
# Calculate 55% of the work load (1st warm up set)
$FirstWarmupSet = ($workload * 0.55);
# Calculate 70% of the work load (2nd warm up set)
$SecondWarmupSet = ($workload * 0.7);
# First Warmup set #
echo "<li>Do 8 reps with " . $FirstWarmupSet . " kgs, then take 1 minute rest.</li>";
echo "<br>";
# Second Warmup set #
echo "<li>Do 5 reps with " . $SecondWarmupSet . " kgs, then take 1 minute rest.</li>";
echo "<br>";
// etc etc...
I'd like the different variables values from PHP to be shown in my "#output" div when the user click on the submit button.
I've tried a lot of different things (AJAX without jQuery, AJAX with jQuery), but didn't manage to get what I want.
I'm sure I'm doing something wrong, but I don't know what. I'm sure my PHP script is working, since I used it without AJAX without any problem.
I would be very grateful if someone could help me on that.
As mentioned above, the easiest way to make an AJAX request for you is probably to try jQuery:
<!doctype html>
<html>
<head>
<meta charset="utf-8">
<!-- Add jQuery on your HTML page -->
<script src="https://code.jquery.com/jquery-3.5.1.min.js"></script>
<!-- Add some custom JavaScript file -->
<script type="text/javascript" src="script.js"></script>
</head>
<body>
<form id="warmupForm" class="form">
<label for="userWorkLoad">Work load (in kgs)</label><br>
<input type="text" name="userWorkLoad" id="userWorkLoad">
<button id="btn" type="submit">Calculate</button>
</form>
<div id="output">This is where I want the result to be shown with AJAX</div>
</body>
</html>
The script.js content:
$(function() {
// Process a button click
$("#btn").click(function() {
event.preventDefault();
// Get input field
var userWorkLoadInput = $("#userWorkLoad");
// Build some request parameters
var params = {
userWorkLoad: userWorkLoadInput.val()
};
// Let's name your PHP script file as "server.php"
// And send POST request with those parameters
$.post("server.php", params, function(response) {
// Response text we're going to put into the `output`
$("#output").html(response);
});
});
});
You can simply do it using Jquery instead of using Ajax (using PHP you should add method="POST" to the form).
Here's an example:
$(document).ready(function(){
$("#send").click(function(){
// your calculates
$("#output").html(...);
});
});
...
<button type="submit" id="send">Calculate</button>
I want to create a confirm yes/no box in php
my code like this:
<?php
if(isset($_REQUEST['id']))
{
?>
<script>
var cf=confirm("do you want to delete Y/N");
if(cf)
{ i want to call code edit of php
}
</script>
<?php
}
?>
<html>
<head>
</head>
<body>
<form name="frm" method="post" action="edit.php">
Edit <br>
Edit <br>
Edit <br>
</form>
</body>
</html>
I Want to when press Yes i call code edit in PHP
But it do not work.
Can you help me ?
Thanks you
Just use inline onclick event.
This is a simple techique, you can use it in your PHP page.
Edit
In your code, you have mentioned PHP but, have used JavaScript.
If you want to do a confirm with PHP,
Create an intermediate page for confirmation.
Post form data there.
On confirmation page, add two submit buttons:
Yes: If pressed this, redirect/post to edit page.
No: If pressed this, redirect back to form
So, your confirmation page should be:
<html>
<head>
</head>
<body>
<?php
if (isset($_POST['confirm'])) {
if ($_POST['confirm'] == 'Yes') {
header("Location:edit.php?id=1");
}
else if ($_POST['confirm'] == 'No') {
header("goBack.php");
}
}
?>
<form method="post">
<?php
if(isset($_REQUEST['id']))
{
?>
<input type="submit" name="confirm" value="Yes"><br/>
<input type="submit" name="confirm" value="No"><br/>
<?php
}
?>
</form>
Put an id on your form:
Create an event listener for the form's onsubmit event
<script>
function onFormSubmission(e){
return confirm("do you want to delete Y/N");
}
var frm = document.getElementById('frm');
frm.addEventListener("submit", onFormSubmission);
</script>
When the user submits a form they will be prompted with your message. If they click Yes the function will return true and the form will be submitted. Otherwise the function will return false and the form submission will be cancelled
I think this is what you want to do:
<?php
//YOU MUST BE SURE THAT YOUR URL CONTAINS THE $_REQUEST['id'] PARAMETER, OTHERWISE IT WON'T WORK FROM YOUR CODE... IF YOU WANT IT TO WORK REGARDLESS OF THAT, JUST COMMENT OUT THE IF(ISSET(... BLOCK...
$editURL = "edit.php"; //EDIT URL HERE
if(isset($_REQUEST['id'])) {
//ASSIGN THE ID TO A VARIABLE FOR BUILDING THE URL LATER IN JS...
//THE DEFAULT ID IS 1 BUT YOU CAN DECIDE WITH YOUR OWN LOGIC
$defaultID = ($dID = intval(trim($_REQUEST['id']))) ? $dID : 1;
?>
<script>
function confirmEdit(evt){
evt.preventDefault();
var cf=confirm("do you want to delete Y/N");
var id=<?php echo defaultID; ?>;
if(cf){
//i want to call code edit of php
//HERE'S THE CODE YOU MAY NEED TO RUN;
if(id){
//RETURN TRUE SO THAT THE SCRIPT WITH LINK TO THE APPROPRIATE URL
return true;
// OR REDIRECT WITH JAVASCRIPT TO EDIT PAGE WITH APPROPRIATE ID
//window.location = "" + <?php echo $editURL; ?> + "?id=" + id; //YOU ALREADY HAVE THE EDIT URL... JUST APPEND THE QUERY-STRING WITH ID TO USE IN THE EDIT PAGE
// You might also just (without redirecting) return true here so to that the page continues like you just clicked on the link itself...
}
}
}
</script>
<?php
}
?>
<html>
<head>
</head>
<body>
<!-- THE FORM TAG IS NOT NECESSARY IN THIS CASE SINCE YOUR ANCHOR TAGS HAVE THE EXACT URL YOU WANT ASSOCIATED WITH THEM... AND YOU DON'T EVEN NEED JAVASCRIPT IN THIS CASE... BECAUSE THE HREF OF THE LINKS ARE HARD-CODED... -->
<!-- <form name="frm" method="post" action="edit.php"> -->
<a class='class-4-css' onclick="confirmEdit();" id='dynamic-id-based-btn-1' href="edit.php?id=1">Edit Page 1 </a> <br>
<a class='class-4-css' onclick="confirmEdit();" id='dynamic-id-based-btn-2' href="edit.php?id=2">Edit Page 2</a> <br>
<a class='class-4-css' onclick="confirmEdit();" id='dynamic-id-based-btn-3' href="edit.php?id=3">Edit Page 3</a> <br>
<!-- </form> -->
</body>
</html>
So, now clicking on any of the Links will Ask me to confirm if I want to delete the Resource or not. If I choose yes, then the appropriate page is loaded for the Process...
not sure if the other answers really answered your question, this was my problem too, then I experimented and here's what I came up with:
.
confirmation in php :
$Confirmation = "<script> window.confirm('Your confirmation message here');
</script>";
echo $Confirmation;
if ($Confirmation == true) {
your code goes here
}
that's all, other people might look for this, you're welcome :)
I was looking to simply have a confirmation box in php before triggering POST isset without going through javascript:
echo "<input id='send_btn' type='submit' value='previous'
name='previous' OnClick=\"return confirm('Are you sure you want to go
to previous');\" >";
This appeared for me to be the easiest solution.
I don't know if something like this has already been asked and answered, but since no matter what search query I make, nothing seems to be close to what I am looking to do. I am working on a project where the user will upload a file. Once the file has been uploaded it will show the user a success message as well as some file info. I am trying to keep this all within one page, if possible, but can't seem to get it to work. File gets uploaded, but the info does not show.
Here is something like what I am working with:
<?php
if(isset($_POST['uploadFile']) && isset($_FILES['file'])) {
move_uploaded_file($_FILES['file']['tmp_name'], "files/" . $_FILES['file']['name']);
$message = "\"" . $_FILES['file']['name'] . "\" uploaded successfully...";
}
?>
<html>
<head>
<title>Upload File</title>
<script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js"></script>
<script>
$(document).ready(function() {
$(".uploaded-file-info").hide();
$(".uploadForm").submit(function() {
$(".upload-form").hide();
$(".uploaded-file-info").show();
});
});
</script>
</head>
<body>
<div class="upload-form">
<form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>" enctype="multipart/form-data" class="uploadForm" >
<input type="file" name="file" /><br />
<input type="submit" name="uploadFile" value="Upload File" />
</form>
</div>
<div class="uploaded-file-info">
<p><?php echo $message; ?></p>
</div>
</body>
</html>
Like I said, the file gets uploaded, but the form doesn't hide and the file info ($message) doesn't show. Any suggestions?
The problem is the JQuery part :
$(".uploadForm").submit(function() {
$(".upload-form").show();
$(".uploaded-file-info").show();
});
coupled with this line :
<form method="post"
The JQuery part is saying : As soon as the form on the page is submitted, Show the information DIV.
The "Form" part just say : Submit the form.
So, when you click the button, the form is submitted and at the same time, the JQuery is executed. But then the form that you just posted needs to "refresh" the page to get the response back from the server. Basically, the JQuery you wrote display your div while you submit it. Meaning that it will work for a fraction of a second but will display an empty div because the response of the server is not there yet.
What you probably want to do is something like :
When the page loads
And there is content in the uploaded-file-info
Show the info and hide the form.
Add a Style tag with the following :
<style>
.uploaded-file-info {
display: none;
}
</style>
It will always hide the uploaded-file-info when the page loads.
Then, change your JavaScript code with :
<script>
$(document).ready(function() {
if ($('.uploaded-file-info > p').html() != "") {
$(".uploaded-file-info").show();
}
});
</script>
It says that when the page loads, if something is present inside the children of the element "uploaded-file-info", then show it. Otherwise, do nothing.
An easier solution would be to display the block, with php (so on the server side), only if a file was uploaded. No need for JQuery (client side) code.
Remove all the JQuery code and code within "<style>" tags and replace surround your "div class="uploaded-file-info" with an IF like this :
<?php if ($message != '') { ?>
<div class="uploaded-file-info">
<p><?php echo $message; ?></p>
</div>
<?php } ?>
Here's what will happen then:
you post (from your browser) the form
the server receives your post
if there is a file uploaded, it will initiate your "message" variable
and if the message variable exists, the server will put the "div uploaded-file-info" into the response. If not, everything surrounded by the "if" won't be put into the response.
your browser will receive the response and display it on screen.
These are two files
Calling.php
<html>
<body>
<form action="Called.php" method="get">
<input type="button" name="B1" value="B1">
<input type="button" name="B2" value="B2">
<input type="Submit" name="Submit1"/>
<!-- Google
yahoo
-->
</form>
</body>
</html>
And Called.php
<?php
if(isset($_GET("Submit1")))
{
echo("<script>location.href = 'http://stackoverflow.com';</script>");
}
if(isset($_GET["B1"]))
{
echo("<script>location.href = 'http://google.com/';</script>");
exit();
}
if(isset($_GET["B2"]))
- List item
{
echo "<meta http-equiv='refresh' content='0;url=http://www.yahoo.com'>";
exit();
}
?>
When i click the buttons "B1" and "B2", page will blink but now where redirect and third one "Submit" button will redirect to new page and there i am getting the out put as "Called.php".
Please spend few seconds for this php beginner.
You can't directly because the button click is a client side activity and PHP is server side. If you make all the inputs submit then the one the user clicked will be submitted as part of the $_GET array but that only works if the user clicks one of them and doesn't submit the form by, say, hitting Enter in a text input.
You could attach AJAX events to the button and have them trigger off a PHP script to run the function you want to run, but that has its own set of issues.
EDIT: I should note that your method of redirecting is rather inelegant to say the least. You can just use header() to do the redirection, it would be much cleaner than all this messing around with echoing out javascript.
You need to use Ajax to do this. If you are using jQuery ajax the code will look something like this
$(function(){
$('input[type="button"]').click(function(){
var name = $(this).attr('value');
$.ajax({
type :'GET',
url : 'Calling.php',
data :{name:name}
success : function(data) {
//do smthng
}
})
})
})
//Code is not tested. Need to verify.
I need a reference on how to make 2 pages become one.
Originally i have 2 php pages. View.php and comment.php
The view.php will have a link to call comment.php. When click the 'comment' link, it will open comment.php like pop up. After fill in the comment, and click send, it will closed and return the view.php.
The problem is, Instead of popup i want it hide until i click it. I dont know what is the exact term to call this process. I know it got something to do with javascript, using id, onclick function and similar to frame function. Because i dont know what it call, it hard for me to research. So anyone please tell me what it called or gimme any references or example solution on how to do it.
thank you very much
UPDATED:
dear all..
found this code in internet. Like RageZ said..it uses css and javascript to show and hide img. how to use for others?
do i need to convert my comment.php into a function and put in view.php n use the id for that function. is it possible?
<html>
<head>
<script>
function changeme(id, action) {
if (action=="hide") {
document.getElementById(id).style.display = "none";
} else {
document.getElementById(id).style.display = "block";
}
}
</script>
</head>
<body>
<img id="myIMG" style="display: none;" src="question.php.html"width="100" height="100" />
<span onclick="changeme('myIMG', 'show');" style="color: blue; text-decoration: underline; cursor: pointer;">Show the image</span>
<span onclick="changeme('myIMG', 'hide');" style="color: blue; text-decoration: underline; cursor: pointer;">Hide the image</span>
</body>
</html>
I think what your looking for is something like Greybox?
It opens a new pag ontop of the page, instead of opening a popup, you best check out the examples, they will be way more clear than anything I can say here.
You can do the described process for example with the following:
view.php
<script language="JavaScript">
function openComment(id) // Open comment.php in a new window and send the id of the thing you want to comment
{
window.open('comment.php?id='+id, '_blank');
}
</script>
Comment
comment.php
<?php
if ( isset($_POST['msg']) && intval($_POST['id']) > 0 ) // If a comment is sent and the id is a number > 0
{
/* Write your message to db */
?>
<!-- Reload the underlying window and close the popup -->
<script language="JavaScript">
window.parent.reload();
window.close();
</script>
<?php
}
else // Show the Form to post a comment
{
?>
<form name="comment" action="comment.php" method="POST">
<input type="hidden" name="id" value="<?php echo $_GET['id'] ?>" />
<input type="text" name="msg" value="Input your comment here" />
<input type="submit" value="Submit" />
</form>
<?php } ?>
you can use Ajax/DHTML to make the popup and post the data to the server in the same page.
I think you would need a framework to do that quick there is a lot of javascript framework around:
jquery
dojo
ExtJS
prototype
All I have forgotten