Basically what I'm trying to achieve is go through an array and do a query based on that data - e.g. array of names bob, bill, ben and query a database table based on all of the items in the array - so SELECT * FROM table WHERE name="$name".
The code I have is:
<?php
session_start();
$array = $_SESSION['basket'];
foreach ($array = $_SESSION['basket'] as $value);
$query = "SELECT * FROM catalogue WHERE plantname='$value'";
$result = mysql_query($query) or die("Query failed : " . mysql_error());
echo "<table>\n";
while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) {
echo "\t<tr>\n";
foreach ($line as $col_value) {
echo "\t\t<td>$col_value</td>\n";
}
echo "\t</tr>\n";
}
echo "</table>\n";
?>
but this is only displaying the last item it should be picking out of the query, any help is much appreciated.
The problem is with this line
foreach ($array = $_SESSION['basket'] as $value);
$query = "SELECT * FROM catalogue WHERE plantname='$value'";
First is the semicolon - it shouldn't be there. Also notice that you have no { } around your foreach statement, so you build a query for each item in your session variable, but execute it only for the last one.
To get everything for all the possible $values, which is what I think you're trying to do, you want something like this:
SELECT * FROM catalogue WHERE plantname IN ('value1', 'value2')
Which can be accomplished with something like:
$query = "SELECT * FROM catalogue WHERE plantname IN ('" . implode($array, "', '") . "')";
...without hitting the database multiple times.
UPDATED: Moved query outside of loop.
<?php
session_start();
$array = $_SESSION['basket'];
$query = "SELECT * FROM catalogue WHERE plantname IN ('" . implode("', '", $array) . "')";
$result = mysql_query($query) or die("Query failed : " . mysql_error());
echo "<table>\n";
while ($line = mysql_fetch_array($result, MYSQL_ASSOC)) {
echo "\t<tr>\n";
foreach ($line as $col_value) {
echo "\t\t<td>$col_value</td>\n";
}
echo "\t</tr>\n";
}
echo "</table>\n";
?>
There are a number of issues in your code.
Firstly you have already assigned to $array so you only need to do:
foreach($array as $value)
Secondly you shouldn't be running queries inside a loop, as the basket gets bigger the more queries are executed on every page request.
Why not push the row into $_SESSION['basket'] then you can just loop $_SESSION['basket'] to show it rather than running loads of queries, it will make your code execute faster and you'll right less code.
Also be careful with the other answers as they haven't considered security as database input should be escaped.
Related
I have a polymer(1.0) app i am trying to create (based on stretch-tutorials league table), i cant figure out the routing if use mvc, so i have opted for the one page site, referencing different php files.
I Have a table in MYSql that i trying to incorporate into the table, using a simple echo table script, but this repeats itself hundreds of times. How can i stop this loop ?
$result = mysql_query('select * from results',$connection) or die('cannot show tables');
while($tableName = mysql_fetch_row($result)) {
$sql = ('SELECT `home_team_name`,`away_team_name`,`home_goals_for`, `away_goals_for`, DATE_FORMAT(`fixture_date`, "%e %M %Y"), TIME_FORMAT(`fixture_time`, "%h:%i %p") FROM `results` ORDER BY fixture_date desc LIMIT 20 '.$table) or die('cannot show columns from '.$table);
echo '<h3>',$table,'</h3>';
$result2 = mysql_query($sql);
if(mysql_num_rows($result2)) {
echo '<table cellpadding="4" cellspacing="0" class="table table-striped table-hover table-bordered">';
echo '<tr class="info"><th>Home team</th><th>Away Team</th><th>Score</th><th>Score</th><th>Date<th>Time</th></tr>';
while($row2 = mysql_fetch_row($result2)) {
echo '<tr>';
foreach($row2 as $key=>$value) {
echo '<td>',$value,'</td>';
}
echo '</tr>';
}
echo '</table><br />';
}
}
I have added ' < 50 ' but this returns 50 table header rows only ?
the site is live at http://jay-o.uk/#!/results the css and other data are okay for now, just this pesky loop.
Well.. maybe you need this code:
// Create an array
$items = array();
while ($row = mysql_fetch_array($resulting, MYSQL_ASSOC)) {
/* print new insert */
var_dump('new item');
/* add a new item */
$items[] = array(
'home_team_name' => $row['home_team_name'],
'away_team_name' => $row['away_team_name'],
'home_goals_for' => $row['home_goals_for'],
'away_goals_for' => $row['away_goals_for']
);
}
$json_response = json_encode($items);
print $json_response;
If $json_response are a empty array maybe the problem is that the query don't return any row.
You need to set a "LIMIT" in the first query if you want to avoid a timeout operation, also i think that is posible to call a unique query that return all the info that you need but i don't know because your query is unintelligible.
Your code is wrong, the second query don't use the $table variable that is null value and what is de purpose to putting it after the limit parameter?
$results = mysql_query('SELECT * FROM table_name ORDER BY field_name LIMIT 50');
if(mysql_num_rows($results)) {
print '<table>';
while ($row = mysql_fetch_row($results)) {
print '<tr>';
foreach ($row as $field_name => $field_value) print '<td>'.$field_value.'</td>';
print '</tr>'
}
print '</table>';
}
Sorry, the code is a bit messy, ive been working on this for a while and ifs frustrating, im not sure where i am going wrong, if i remove the $tableName variable i get an empty array, no matter what i do this is the results.
I have tried in json to no avail...
$db = mysql_connect($host,$user,$pass);
if (!$db) {
die('Could not connect to db: ' . mysql_error());
}
//Select the Database
mysql_select_db($db_name,$db);
$resulting = mysql_query("select * from results", $db);
//Create an array
$json_response = array();
while ($row = mysql_fetch_array($resulting, MYSQL_ASSOC)) {
$row_array['home_team_name'] = $row['home_team_name'];
$row_array['away_team_name'] = $row['away_team_name'];
$row_array['home_goals_for'] = $row['home_goals_for'];
$row_array['away_goals_for'] = $row['away_goals_for'];
//push the values in the array
array_push($json_response,$row_array);
$json = json_encode($json_response);
//echo $json;
$json_result = print_r((array) json_decode($json,true));
echo $json_result;
}
which leaves this: jay-o.uk/config/config.php
Could this be because i am referring to a view in mySql rather than a table ?
How about a simpler solution, just limit the query from the database to 1:
$results = mysql_query('SELECT * FROM table_name ORDER BY field_name LIMIT 1');
this is the values in the $result
id name
1 a
2 b
2 c
2 d
3 e
..
I'm creating a loop function using mysql_fetch_array()
while($row = mysql_fetch_array($result)) {
$temp_id = $row['id'];
while($temp_id == $row['id']) {
if($temp_id == $row['id']) {
mysql_fetch_array($result);
}
$temp_id = $row['id'];
echo $row['name'].",";
}
echo "<br/>";
}
this works but the problem is, the mysql_fetch_array jumps on one of the values during the transition of the id's..
I want the values of this to be like these
a
b,c,d
e
my question is, is there a simple rewind function that will step only once in the rows?
I have searched about the mysql_data_seek() but I think this would require additional control variables like $i to locate the address..
thanks.. any suggestions and function samples will be very great!
Use one loop with mysql_fetch_array first to create an array of the rows. Then, iterate over the rows themselves.
Based on the update to your question it seems like you would want to use GROUP_CONCAT in the query, but you can still do it in PHP:
$rows = array();
while($row = mysql_fetch_assoc($result)) {
if (!isset($rows[$row['id']]) {
$rows[$row['id'] = array();
}
$rows[$row['id']][] = $row['name'];
}
foreach ($rows as $row) {
echo implode(',', $row) . "<br>";
}
Try this code
while($row = mysql_fetch_array($result)) {
$temp[$row['id']][] = $row['name'];
}
foreach($temp as $row) {
echo implode(',', $row) . '<br/>';
}
I'm trying to fetch all records from my table on my site, I have the following
$sth = $conn->prepare("SELECT * FROM directory WHERE user_active != ''");
$sth->execute();
/* Exercise PDOStatement::fetch styles */
$result = $sth->fetch(PDO::FETCH_ASSOC);
foreach ($sth->fetchAll(PDO::FETCH_ASSOC) as $result) {
echo $result[First_Name];
}
Only its not returning all records, only my first, Can anybody see where I'm going wrong?
You need to use a loop:
while ($result = $sth->fetch(PDO::FETCH_ASSOC)) {
echo $result[First_Name];
echo ' ' . $result[Surname];
}
Or you could use fetchAll method:
foreach ($sth->fetchAll(PDO::FETCH_ASSOC) as $result) {
echo $result[First_Name];
echo ' ' . $result[Surname];
}
And Note: If First_Name and Surname are not constants, then you should use the string as the key name.
$result['First_Name'] and $result['Surname']
Well, you only call $sth->fetch once. You need to loop over the results.
while ($row = $sth->fetch(PDO::FETCH_ASSOC)) {
echo $row['First_Name'] . ' ' . $row['Surname'] . "\n";
}
Also don't call array string indexes without braces. This way PHP checks if the key is a CONSTANT, then casts it to string. This is just bad practice and might lead to unexpected bahavior.
If this returns only one row, you probably have only one row in the database (or the result set). Show us more code!
I've got a database table with at least three rows in it. From php, I have successfully connected to my db and extracted all table information with 'SELECT * from mytable' .
Now I want to loop through first each row, and then each cell, printing out the contents of each cell.
I know this might be a simple task for a more experienced programmer, but I can't figure it out, and I can't find any examples online and it's driving me stark raving bonkers.
How can I do this ?
You could use a for each loop...
//Do the query
$query = "SELECT * FROM table";
$result = mysql_query($query);
//iterate over all the rows
while($row = mysql_fetch_assoc($result)){
//iterate over all the fields
foreach($row as $key => $val){
//generate output
echo $key . ": " . $val . "<BR />";
}
}
Haven't tested it, so there may be a syntax error in it, but this is the main idea
There are a couple of examples in the manual that could help you with that ; for instance, on the manual page of mysql_query (quoting, and adapting a bit) :
You first have to execute the query :
$result = mysql_query('SELECT * from mytable');
if (!$result) {
die('Invalid query: ' . mysql_error());
}
Note that dying in case of an error, and echoing the error-message, is OK while developping -- but you shouldn't do that in a production environment !
And, then, you have to loop over the lines of results, fetching them one at a time :
while ($row = mysql_fetch_assoc($result)) {
// Use the data in $row
}
And, inside this loop, as $row is an array, you can iterate over its content with a foreach loop :
foreach ($row as $name => $value) {
echo "column $name contains $value<br />";
}
Note : at this point, you should really invest some time going through a couple of sections of the PHP manual : it will take some time, yes ; but it will definitely help you, and will not be wasted time :-)
Ok I have a table with a few fields. One of the fields is username. There are many times where the username is the same, for example:
username: bob
password: bob
report: 1
username: bob
password: bob
report: 2
I did a SQL statement to select * where username='bob'; but when I do the following PHP function, it will only return the last result:
$thisrow = mysql_fetch_row($result);
I need to get every field from every row. How should I go about doing this?
$mainsection="auth"; //The name of the table
$query1="select * from auth where username='$user'";
$result = mysql_db_query($dbname, $query1) or die("Failed Query of " . $query1); //do the query
$thisrow=mysql_fetch_row($result);
echo "Study: " . $thisrow[1] . " - " . $thisrow[5];
Sorry for such a dumb question. I can't seem to get the while loops of more than one field working for the life of me.
mysql_fetch_row fetches each row one at a time. In order to retrieve multiple rows, you would use a while loop like this:
while ($row = mysql_fetch_row($result))
{
// code
}
Use a loop, and use mysql_fetch_array() instead of row:
while($row = mysql_fetch_array($result)) {
echo "Study: " . $row[1] . " - " . $row[5];
// but now with mysql_fetch_array() you can do this instead of the above
// line (substitute userID and username with actual database column names)...
echo "Study: " . $row["userID"] . " - " . $row["username"];
}
I suggest you to read this:
http://www.w3schools.com/php/php_mysql_select.asp
It will give you an overview idea of how to properly connect to mysql, gather data etc
For your question, you should use a loop:
while ($row = mysql_fetch_row($result)){//code}
As said by htw
You can also obtain a count of all rows in a table like this:
$count = mysql_fetch_array(mysql_query("SELECT COUNT(*) AS count FROM table"));
$count = $count["count"];
You can also append a normal WHERE clause to the select above and only count rows which match a certain condition (if needed). Then you can use your count for loops:
$data = mysql_query("SELECT * WHERE username='bob'");
for ($i = 0; $i
Also, mysql_fetch_array() is usually a lot easier to use as it stores data in an associative array, so you can access data with the name of the row, rather than it's numeric index.
Edit:
There's some kind of bug or something going on where my second code block isn't showing everything once it's posted. It shows fine on the preview.
I like to separate the DB logic from the display. I generally put my results into an array that I can call within the HTML code. Purely personal preference; but here's how'd I'd approach the problem: (I'd take the $sql out of the error message in production)
<?php
$sql="
SELECT *
FROM auth
WHERE username='$user';
";
$result = mysql_query($sql)
or die("Failed Query : ".mysql_error() . $sql); //do the query
while ($ROW = mysql_fetch_array($result,MYSQL_ASSOC)) {
$USERS[] = $ROW;
}
?>
HTML CODE
<? foreach ($USERS as $USER) { ?>
Study: <?=$USER['dbFieldName'];?> - <?=$USER['dbFieldName2'];?>
<? } //foreach $USER ?>
$qry=mysql_query(select * where username='bob');
if(mysql_num_rows($qry))
{
while($row=mysql_fetch_array($qry,MSQL_NUM))
{
echo $row[0]." ".$row[1]." ".$row[2]."<br>";
}
}