How can i stop a php while loop repeating over and over? - php

Question

I have a polymer(1.0) app i am trying to create (based on stretch-tutorials league table), i cant figure out the routing if use mvc, so i have opted for the one page site, referencing different php files.
I Have a table in MYSql that i trying to incorporate into the table, using a simple echo table script, but this repeats itself hundreds of times. How can i stop this loop ?
$result = mysql_query('select * from results',$connection) or die('cannot show tables');
while($tableName = mysql_fetch_row($result)) {
$sql = ('SELECT `home_team_name`,`away_team_name`,`home_goals_for`, `away_goals_for`, DATE_FORMAT(`fixture_date`, "%e %M %Y"), TIME_FORMAT(`fixture_time`, "%h:%i %p") FROM `results` ORDER BY fixture_date desc LIMIT 20 '.$table) or die('cannot show columns from '.$table);
echo '<h3>',$table,'</h3>';
$result2 = mysql_query($sql);
if(mysql_num_rows($result2)) {
echo '<table cellpadding="4" cellspacing="0" class="table table-striped table-hover table-bordered">';
echo '<tr class="info"><th>Home team</th><th>Away Team</th><th>Score</th><th>Score</th><th>Date<th>Time</th></tr>';
while($row2 = mysql_fetch_row($result2)) {
echo '<tr>';
foreach($row2 as $key=>$value) {
echo '<td>',$value,'</td>';
}
echo '</tr>';
}
echo '</table><br />';
}
}
I have added ' < 50 ' but this returns 50 table header rows only ?
the site is live at http://jay-o.uk/#!/results the css and other data are okay for now, just this pesky loop.

Answer 1

Well.. maybe you need this code:
// Create an array
$items = array();
while ($row = mysql_fetch_array($resulting, MYSQL_ASSOC)) {
/* print new insert */
var_dump('new item');
/* add a new item */
$items[] = array(
'home_team_name' => $row['home_team_name'],
'away_team_name' => $row['away_team_name'],
'home_goals_for' => $row['home_goals_for'],
'away_goals_for' => $row['away_goals_for']
);
}
$json_response = json_encode($items);
print $json_response;
If $json_response are a empty array maybe the problem is that the query don't return any row.

Answer 2

You need to set a "LIMIT" in the first query if you want to avoid a timeout operation, also i think that is posible to call a unique query that return all the info that you need but i don't know because your query is unintelligible.
Your code is wrong, the second query don't use the $table variable that is null value and what is de purpose to putting it after the limit parameter?
$results = mysql_query('SELECT * FROM table_name ORDER BY field_name LIMIT 50');
if(mysql_num_rows($results)) {
print '<table>';
while ($row = mysql_fetch_row($results)) {
print '<tr>';
foreach ($row as $field_name => $field_value) print '<td>'.$field_value.'</td>';
print '</tr>'
}
print '</table>';
}

Answer 3

Sorry, the code is a bit messy, ive been working on this for a while and ifs frustrating, im not sure where i am going wrong, if i remove the $tableName variable i get an empty array, no matter what i do this is the results.
I have tried in json to no avail...
$db = mysql_connect($host,$user,$pass);
if (!$db) {
die('Could not connect to db: ' . mysql_error());
}
//Select the Database
mysql_select_db($db_name,$db);
$resulting = mysql_query("select * from results", $db);
//Create an array
$json_response = array();
while ($row = mysql_fetch_array($resulting, MYSQL_ASSOC)) {
$row_array['home_team_name'] = $row['home_team_name'];
$row_array['away_team_name'] = $row['away_team_name'];
$row_array['home_goals_for'] = $row['home_goals_for'];
$row_array['away_goals_for'] = $row['away_goals_for'];
//push the values in the array
array_push($json_response,$row_array);
$json = json_encode($json_response);
//echo $json;
$json_result = print_r((array) json_decode($json,true));
echo $json_result;
}
which leaves this: jay-o.uk/config/config.php
Could this be because i am referring to a view in mySql rather than a table ?

Answer 4

How about a simpler solution, just limit the query from the database to 1:
$results = mysql_query('SELECT * FROM table_name ORDER BY field_name LIMIT 1');