PHP Mysql & Jquery dynamically populating multiple records - php

Question

I want to above Master and child system by using PHP,MYSQL & JQuery.
I am attaching sample image link below See screenshot
Product Quantity and UOM is field which belong to MAster Table and
Code, Component, category, quantity (Also) & UOM (duplicate) is belong to Child table.
I want to add Code, Component, category, quantity etc multiple time whenever user click on add.
Just need to know how can i save all these multiple records when someone completed their works and click on Final Save Button?
I am really and very aggressively searching for this but didn't get any anwer.
If anyone who can find the way or any help or anything that will help me towards this system.
Thanks a lots pls pls Help

Answer 1

you'll want to use
jQuery ajax to save data
.clone() to add a record in the UI you'll have to reset the values will your at it
that should get you started

Answer 2

Each time your user clicks 'add' you want to take the values of your form inputs, build a new table row and show their selected values. This is easy enough, but you also need to add hidden inputs which represent what they chose in the select boxes above, so when the user clicks save, the whole form is posted and you can process the input. A simple example would be:
<script>
var count = 0;
$('#add').click(function(event)
{
var code = $('#code').val(),
component = $('#component').val()
category = $('#category').val(),
uom = $('#uom').val();
$('#table').append(
'<tr>'
+ '<td>' + code + '<input type="hidden" name="record[' + count + '][code]"></td>'
+ '<td>' + component + '<input type="hidden" name="record[' + count + '][component]"></td>'
+ '<td>' + category + '<input type="hidden" name="record[' + count + '][category]"></td>'
+ '<td>' + uom + '<input type="hidden" name="record[' + count + '][uom]"></td>'
+ '</tr>'
);
/*
EDIT: I changed this to a DECREMENTOR so our keys don't overlap and override
anything that is CURRENTLY in the database
*/
count --;
})
</script>
This would attach a click handler to the add button. Each time it is clicked, we get the values of the inputs, store them in a variable, and build + append a new table row to your "preview table" below, which shows the values they selected and creates hidden inputs which can be processed later after the user clicks Save.
Some notes about this:
- it only gets the value of the selected inputs (so for the select boxes, the value of the option not the text. you'll have to do some extra work to replace that into your table row.
- your entire table will have to be encapsulated in a <form> tag, which your save button must also be inside.
Once you get the posted data to the server, do a print_r($_POST) to see what it looks like, you should be able to figure out how to process it fairly easily.
edit
Okay, so you asked a lot of questions here, i'll try to address them as best I can, without writing a novel.
What if someone mistakenly clicks on add and wants to cancel the addition (or changes their mind, whatever).
This actually isn't that hard. If this happens, just remove the appended table row from your table using $.remove. Since all the hidden input elements are contained within the table row, they will also be removed from the form so when the user posts, the fields will not be present.
How should you sanitize the data?
Sanitize the data when the user clicks add, as you populate the form, instead of afterwards, just before you post the form. It will be easier to deal with the input errors when the user clicks add than it will be to deal with them when they click save.
How can you use this method if you want to modify existing records in the database?
There's a few different ways you can handle this. The easiest way is to pre-populate your form with table rows for each existing row in your database, and add an id (assuming you have an auto-increment primary key for each row) input value for that record on the table row. This way when you're processing the form, you'll be able to see if it's an existing record by checking for the existence of the id in the posted data and verifying that it exists in your database. If it doesn't have an id key you know that it is a new record and you need to do an INSERT, and if it does, you can do an UPDATE or leave the record be. For DELETED rows, you'll want to loop through your POSTed data before doing any INSERTs and gather the id values that have been posted and run a query something like DELETE FROM table WHERE ID IN (<list of posted ids>). This will delete any rows that the user removed, then you can loop through the POSTed data again and insert the new rows.
An example of pre-populating this table would look something like this:
<?php
$query = "SELECT * FROM bill_items WHERE bill_id = 123";
$result = mysql_query($query);
$materials = array();
while ($row = mysql_fetch_assoc($query))
{
$materials []= $row;
}
?>
<? foreach ($materials as $material): ?>
<tr>
<td>
<?= $material['code']; ?>
<input type="hidden" name="record[<?= $material['id']; ?>][code]"
value="<?= $material['uom']; ?>">
</td>
<td>
<?= $material['component']; ?>
<input type="hidden" name="record[<?= $material['id']; ?>][component]"
value="<?= $material['uom']; ?>">
</td>
<td>
<?= $material['category'];
<input type="hidden" name="record[<?= $material['id']; ?>][category]"
value="<?= $material['uom']; ?>">
</td>
<td>
<?= $material['quantity']; ?>
<input type="hidden" name="record[<?= $material['id']; ?>][quantity]"
value="<?= $material['uom']; ?>">
</td>
<td>
<?= $material['uom']; ?>
<input type="hidden" name="record[<?= $material['id']; ?>][uom]"
value="<?= $material['uom']; ?>">
<input type="hidden" name="record[<?= material['id']; ?>][id]"
value="<?= $material['id']; ?>">
</td>
</tr>
<? endforeach; ?>
Also, a note. I changed the javascript example code above. I changed count++ to count-- because when you pre-populate the form with data that is currently in the database you are going to use the id of the material in the input key. When a user adds new data, there is a possibility that the key generated with javascript (with count++) will collide with the existing table data. To rectify this, we change it to count--. This key (in javascript) really isn't important, it's just keeping our data grouped together, so a negative value here does not affect anything.