Please see this link
http://thedesigningworld.com/bea
Here's a Small form contains 8-9 fields + a group of checkboxes
I want to save all details in DB + want to display in a table in proper manner, but it not works properly
Here's the code which i used
for($i=0;$i<count($_POST[wert1]);$i++)
{
if($_POST[wert1][$i]!= "")
{
$check1[] =$_POST['wert1'][$i]; } }
$new1=implode(',', $check1);
$result = "INSERT into table1(check1) values($new1)";
$result = mysqli_query($con, $result);
So i've one doubt that for each checkbox row, should i need to define same array name or different like here i used array name as wert1[] for first row
Checkbox values are not transmitted if the box is not checked.
If you have influence, you could put a hidden input field of the same name before the checkbox and the value "0", like:
<input type="hidden" name="checkbox_name" value="0" />
<input type="checkbox" name="checkbox_name" value="1">Some Text</input>
In you example site, you're using array notation, which is basically a good thing. However, you have not given an index so you might not recognize missing elements.
Related
Here I just grabbed the ID or a data in the check box. But I want to capture more data with the ID. How to do it?
I don't know any language better than PHP.
How to take multiple data in checkbox value PHP.<input type="checkbox" name="check_data[]" value="<?php echo $row['id']; ?>">
I dont know what data you want to insert. For example if you want to insert id, username and birthday in value:
<input type="checkbox" name="check_data" value="id, username, birthday"/>
after you submit your form, you can catch the values from that checkbox like below:
$checkboxValues = explode(" ", $_POST['check_data']);
I have a form with dynamically added checkboxes - each checkbox together with a hidden field. I need only the checked values displayed in pairs with the hidden field when submitted.
This is what I have:
<input type="checkbox" name="valg[]" value="<?=$hent_data[id]?>" />
<input type="hidden" name="process_id[]" value="<?=$hent_data[process_id]?>" />
<?php
if($_POST[submit] != ""){
$arrlength=count($_POST[valg]);
for($x=0;$x<$arrlength;$x++) {
$dimen1 = $_POST[valg][$x];
$dimen2 = $_POST[process_id][$x];
echo $hest = "INSERT INTO chosen (kat_ref, prod_ref, process_id) VALUES ($dimen1, '', $dimen2)"."<br/>";
}
}
?>
When submitted I get the correct number of rows as I have checked, with the correct checkbox value, BUT, the problem is in the hidden text input. On submit it lists all hidden values.
Let's say in a form with 10 checkboxes (and hidden text input) I have ticked 3 checkboxes I would want the exact 3 hidden text input boxes to be listet together with the ticked checkboxes, but it returns them all, which means that no matter how many checkboxes I check, it'll still parse all the hidden value fields.
Any ideas?
I hope you understand - or else let me know ;-)
From the discussion, to me it seems better to send the checkbox in key=>value
<input type="checkbox" name="valg[<?=$hent_data[id]?>]" value="<?=$hent_data[process_id]?>" />
This will give you a result in the php side similar to
Array
(
[valg] => Array
(
[uniqueKey3] => processID3
[uniqueKey7] => processID7
[uniqueKey8] => processID8
)
)
Therefore in the php you can do this:
foreach($_POST['valg'] as $ID => $processID){
echo $hest = "INSERT INTO chosen (kat_ref, prod_ref, process_id) VALUES ($ID, '', $processID)"."<br/>";
}
This is more of a technique question rather than maybe code. I am having a php form with many fields (items to select). Naturally some of the items might be selected and some not. How do I know which ones are selected when i post the data from page 1 to page 2? I thought of testing each one if empty or not, but there are just too many fields and it doesn't feel at all efficient to use or code.
Thanks,
UPDATE EDIT:
I've tried the following and maybe it will get me somewhere before I carry on testing the repliers solutions...
<html>
<body>
<form name="test" id="name" action="testprocess.php" method="POST">
<input type="text" name="choices[shirt]">
<input type="text" name="choices[pants]">
<input type="text" name="choices[tie]">
<input type="text" name="choices[socks]">
<input type="submit" value="submit data" />
</form>
</body>
</html>
and then second page:
<?php
$names = $_POST['choices'];
echo "Names are: <br>";
print_r($names);
?>
This gives out the following:
Names are: Array ( [shirt] => sdjalskdjlk [pants] => lkjlkjlk [tie]
=> jlk [socks] => lkjlkjl )
Now what I am going to try to do is iterate over the array, and since the values in my case are numbers, I will just check which of the fields are > 0 given the default is 0. I hope this works...if not then I will let you know :)
I think what you're looking for is this:
<form action="submit.php" method="POST">
<input type="checkbox" name="checkboxes[]" value="this" /> This
<input type="checkbox" name="checkboxes[]" value="might" /> might
<input type="checkbox" name="checkboxes[]" value="work" /> work
<input type="submit" />
</form>
And then in submit.php, you simply write:
<?php
foreach($_POST['checkboxes'] as $value) {
echo "{$value} was checked!";
}
?>
The square brackets in the name of the checkbox elements tell PHP to put all elements with this name into the same array, in this case $_POST['checkboxes'], though you could call the checkboxes anything you like, of course.
You should post your code so we would better understand what you want to do.
But from what I understood you are making a form with check boxes. If you want to see if the check boxes are selected, you can go like this:
if(!$_POST['checkbox1'] && !$_POST['checkbox2'] && !$_POST['checkbox3'])
This looks if all the three check boxes are empty.
Just an idea:
Create a hidden input field within your form with no value. Whenever any of the forms fields is filled/selected, you add the name attribute of that field in this hidden field (Field names are saved with a comma separator).
On doing a POST, you can read this variable and only those fields present in this have been selected/filled in the form.
Hope this helps.
Try this.....
<?php
function checkvalue($val) {
if($val != "") return true;
else return false;
}
if(isset($_POST['submit'])) {
$values = array_filter(($_POST), "checkvalue");
$set_values = array_keys($values);
}
?>
In this manner you can get all the values that has been set in an array..
I'm not exactly sure to understand your intention. I assume that you have multiple form fields you'd like to part into different Web pages (e.g. a typical survey form).
If this is the case use sessions to store the different data of your forms until the "final submit button" (e.g. on the last page) has been pressed.
How do I know which ones are selected when i post the data from page 1 to page 2?
is a different question from how to avoid a large POST to PHP.
Assuming this is a table of data...
Just update everything regardless (if you've got the primary / unique keys set correctly)
Use Ajax to update individual rows as they are changed at the front end
Use Javascript to set a flag within each row when the data in that row is modified
Or store a representation of the existing data for each row as a hidden field for the row, on submission e.g.
print "<form....><table>\n";
foreach ($row as $id=>$r) {
print "<tr><td><input type='hidden' name='prev[$id]' value='"
. md5(serialize($r)) . "'>...
}
...at the receiving end...
foreach ($_POST['prev'] as $id=>$prev) {
$sent_back=array( /* the field values in the row */ );
if (md5(serialize($sent_back)) != $prev) {
// data has changed
update_record($id, $sent_back);
}
}
I've just started using jQuery. One thing I've been using it for is adding rows to a table that is part of a form.
When I add a new row, I give all the form elements names like 'name_' + rowNumber. I increment rowNumber each time I add a row.
I also usually have a Remove Row Button. Even when a row is removed, the rowNumber count stays the same to keep from repeating element names.
When the form is submitted, I set a hidden element to equal the rowNumber value from jQuery. Then in PHP, I count from 1 to the rowNumber value. Then for each value, I perform an isset($_REQUEST['name'_ . index]). This is how I extract the form elements that remained after deleting rows in jQuery.
Does anyone here have a better technique for accounting for deleted rows?
For some of our simpler tables, we use a field name such as 'name[]', though for JavaScript they would need a usable id.
It does add some complexity in that 'name[0]' has to assume 'detail[0]' is the correct element.
PHP will create an array and append elements if the field name ends with [] similar to
<input name="field[]" value="first value" />
<input name="field[]" value="second value" />
// is roughly the same as
$_POST['field'][] = 'first value';
$_POST['field'][] = 'second value';
Use arrays to hold you values in your submission. So bin the row count at the client side, and name your new elements like name[]. This means that $_POST['name'] will be an array.
That way at the server side you can easily get the row count (if you need it) with:
$rowcount = count($_POST['name']);
...and you can loop through the rows at the server side like this:
for ($i = 0; isset($_POST['name'][$i]; $i++) {}
You could extract all the rows by doing a foreach($_POST as $key => $value).
When adding a dynamic form element use the array naming method. for example
<input type="text" name="textfield[]" />
When the form is posted the textfield[] will be a PHP array, you can use it easily then.
When you remove an element make sure its removed from the HTML DOM.
Like blejzz suggests, I think if you use $_GET, then you can just cycle through all of the inputs that were sent, ignoring the deleted rows.
foreach ($_GET as $k=>$v) {
echo "KEY: ".$k."; VALUE: ".$v."<BR>";
}
I notice that you mention "accounting for deleted rows"; you could include a hidden input, and add a unique value to it each time someone deletes a row. For example, the input could hold comma-separated values of the row numbers:
<input type="hidden" value="3,5,8" id="deletions" />
and include in your jQuery script:
$('.delete').click(function(){
var num = //whatever your method for getting the row number
var v = $('#deletions').val();
v = v.split(',');
v.push(num);
v = v.join(',');
$('#deletions').val(v);
});
Then you should be able to know which rows were deleted (if that is what you were looking for).
you can use POST or GET
After submit you can use all of your form element with this automaticly. You dont need to reorganise your form element names. Even you dont need to know form elements names.
<form method="POST" id="fr" name="fr">.....</form>
<?php
if(isset($_POST['fr'])){
foreach($_POST as $data){
echo $data;
}
}
?>
Also you should look this
grafanimasyon.blogspot.com.tr/2015/02/veritabanndan-php-form-olusturucu.html
This is a automated form creator calcutating your database tables. You can see how to give name to form elements and use them.
I have fieldset with multiple checkboxes for a MySQL insert from a form.
<fieldset id="my_checkboxes">
<legend>My Checkboxes (Select at least 2)</legend>
<label for="checkbox1">
<input type="checkbox" id="checkbox1" value="yes" name="the_checkbox" />
CheckBox #1
</label>
<label for="checkbox2">
<input type="checkbox" id="checkbox2" value="yes" name="the_checkbox2" />
CheckBox #2
</label>
</fieldset>
I need to be able to have each checkbox have a unique NAME attribute because each checkbox inserts data into it's own column in the database. (Otherwise, i would just use the the_checkbox[] as the name for each).
My problem is I need to have the user select at least 2 checkboxes in order to submit the form. Since I have seperate names for each, I cannot use the following code anymore as it counts by name:
$checkboxcount = count($_POST['the_checkbox']);
if($checkboxcount < 1)
{
$errors[] = $checkboxcount;
}
MY SQL statement looks like this:
$sql = "INSERT INTO $db_table(the_checkbox,the_checkbox2) values
(
'".mysql_real_escape_string(stripslashes($_REQUEST['the_checkbox']))."',
'".mysql_real_escape_string(stripslashes($_REQUEST['the_checkbox2']))."'
)";
What would you suggest for me to either A. Count checkboxes even with seperate Names, or B. keep the same name but somehow insert data into MySQL as seperate column names?
If you prefer to keep different names, then do something like this:
$chkbox_count = 0;
if (isset($_POST['the_checkbox']) && $_POST['the_checkbox'] == "yes") $chkbox_count++;
if (isset($_POST['the_checkbox2']) && $_POST['the_checkbox'] == "yes") $chkbox_count++;
// etc...
I would usually prefer to use use the same name for a related group of checkboxes though, with different values, but the way you are handing them directly into a SQL string makes your method of different names a little easier to handle.