PHP - Comparing double to a string is weird? - php

I'm seeing some weird behavior in php when comparing a double to a string and was hoping someone could explain to me what is going on.
If I declare $num = 0.333;
and then test
$num == '0.333',
this comes out as true. If I then add 1 to $num and then subtract 1, then $num == '0.333' comes out as false. If I then cast $num as a string, the comparison goes back to being true. Why is it doing this?
Here's a sample:
<?php
$num = 0.333;
//returns 0.333 double Yes
echo $num, ' ', gettype($num), ' ', $num == '0.333' ? 'Yes' : 'No', '<br />';
$num += 1;
$num = $num - 1;
//returns 0.333 double No
echo $num, ' ', gettype($num), ' ', $num == '0.333' ? 'Yes' : 'No', '<br />';
$str = (string)$num;
//returns 0.333 string Yes
echo $str, ' ', gettype($str), ' ', $str == '0.333' ? 'Yes' : 'No', '<br />';
?>
Thanks.

You are comparing a floating point.
http://php.net/manual/en/language.types.float.php says:
never compare floating point numbers for equality.
The == compares for value, but 'across' types: one of the types must be converted before it can actually be compared. And this will result in comparison of floating point variables. That's why after doing a seemingly balanced action (+1 and -1) you're getting different results.

For comparing value AND type in PHP, you need to use 3 "=". like :
$num = 333
$num === 333 => true
$num === '333' => false
See here for more details http://php.net/manual/en/language.operators.comparison.php
A possible way to compare Float, is to use the method indicated in the comments of php.net regarding floats :
<?php
$number1=number_format($float1,2,'.','');
$number2=number_format($float2,2,'.''');
if($number1!=$number2){
echo 'do correction here!';
}
?>
But apparently, there isn't a definitive, best way to do it (or I didn't found it). Some convert the float to String, other does the code I just wrote.
As you like ;)

Take away point: use === instead of == to avoid type coercion.
The reason is that in the first instance $num is a double, but it is also equal to the string '0.333'.
Using === shows that the double 0.333 isn't the same as the string '0.333'.
The second one has done some addition, now the double isn't exactly 0.333 anymore, so it isn't the same as a string to to floating point inaccuracies.
The third one has cast 0.333 to a string, which is of course the same as the string.

To compare two float or double use http://php.net/manual/en/function.bccomp.php

You are comparing a float for which trailing digits are a problem.
One think you can do is convert the float to a string and take the first x characters (ie if you have a string '.333' that you're comparing it to, convert the float to a string and take the first four characters), or you can floor the float to the proper decimals before comparing it.

Related

Number format with a variable decimal place

Is there a built-in/neat way to format a number (just like number_format does), but without any rounding ups/downs?
For instance, number 1234.234 should be formatted as 1,234.234 and another number 1234 should be formatted as 1,234 (i.e. without any trailing .000)
You can define simple custom function for that:
<?php
function custom_number_format($number, $decimal = '.')
{
$broken_number = explode($decimal, $number);
if (isset($broken_number[1]))
return number_format($broken_number[0]) . $decimal . $broken_number[1];
else
return number_format($broken_number[0]);
}
$n1 = '1234.234';
$n2 = '1234';
echo custom_number_format($n1);
echo '<br>';
echo custom_number_format($n2);
?>
Output is:
1,234.234
1,234
Based on the arhey's answer
TLDR ;)
You can use number_format to format the number to a fixed-width format, then use rtrim twice to remove trailing zeroes, and dot.
rtrim(rtrim(number_format($number, 3, '.', ','), '0'), '.')
Starting from the last character, rtrim removes it while it is one of those given. In our case, we remove trailing dots, then we remove an eventual trailing zero.
rtrim(rtrim(number_format(1234.123, 3, '.', ','), '0'), '.')
// returns 1,234.123
rtrim(rtrim(number_format(1234.12, 3, '.', ','), '0'), '.')
// returns 1,234.12 (1,234.120, trimmed to 1234.12)
rtrim(rtrim(number_format(1234, 3, '.', ','), '0'), '.')
// returns 1,234 (1,234.000, trimmed to 1234)
rtrim(rtrim(number_format(1200, 3, '.', ','), '0'),'.')
// returns 1,200 (1,200.000, trimmed to 1200., trimmed to 1200)
Formal form, and discussion about the parameters (notably the decimals count)
rtrim(rtrim(number_format($number, <N>, '<D>', ''), '0'), '<D>')
Where :
D is the decimal separator. To avoid locale-formatting problems, explicitly specify it
N is the maximum digits you number can have.
If you know all your numbers will have less than 3 digits, go and take N=3.
What if you don't know how many decimals are at most ? Well, things are getting more complex.
It may worth recalling (as stated in the PHP documentation) that floats are stored :
with a precision (a number of digits, without distinction whether they are before or after the decimal separator), not a number of decimals
and in their binary form, not their decimal one, and that can lead to rounding errors when reaching precision limit.
For example, floor((0.1+0.7)*10) will usually return 7 instead of the
expected 8, since the internal representation will be something like
7.9999999999999991118....
So there is no universal good value, you'll have to choose it depending on the usual scale of your data.
And that explains why there is no built-in function for that : PHP can't choose for you.
You can use function:
<?php
function getNumberFormat($number) {
$numberAr = explode('.', (string)$number);
$count = 0;
if (2 === count($numberAr)) {
$count = strlen($numberAr[1]);
}
return number_format($number, $count, ',', '.');
}
$test1 = 1234.234;
$test2 = 1234;
echo getNumberFormat($test1); //1,234.234
echo getNumberFormat($test2); //1,234
I really liked arhey's answer, but later realized it has a major flaw. A number like 2100 will get converted to 2,1 instead of 2,100.
Below is how I ended up modifying it.
public function formatDecimal($number)
{
$stringVal = strval($number); //convert number to string
$decPosition = strpos($stringVal, ".");
if ($decPosition !== false) //there is a decimal
{
$decPart = substr($stringVal, $decPosition); //grab only the decimal portion
$result = number_format($stringVal) . rtrim($decPart, ".0");
}
else //no decimal to worry about
{
$result = number_format($stringVal);
}
return $result;
}
It's not as succinct a solution as I was hoping, but in my case I put it into a view helper (I'm using ZF2) and so it's just one simple function call in my view.
Hope this is helpful for someone!
rtrim(number_format(1234.234, 3),'.0');
rtrim(number_format(1234, 3),'.0');
Let's begin with that there's no decimal type in PHP. There's float only.
And if you know how float works, then you know that it's usually not possible to store exact decimal value that you think you have, but it's an approximation. That's because you can't express most of decimal numbers in binary system.
Therefore if you say:
$number = 1234.234;
Then you have a float that is close to this value. The real value is:
1234.23399999999992360244505107402801513671875
Therefore PHP can't just guess how do you want to round it. It needs to be specified explicitly.

php Determine a float variable has two decimal places

MySQL data imoprt mongo database.
price float(15,2) in mysql, mongo is not float(15,2).
I want to Determine a var $price have two decimal places.
eg. 100.00 is right, 100 or 100.0 is wrong.
eg.1
$price = 100.00;
$price have two decimal, it's right.
eg.2
$price = 100.0;
$price have not two decimal, it's wrong.
I like to use Regular Expressions to do these things
function validateTwoDecimals($number)
{
if(preg_match('/^[0-9]+\.[0-9]{2}$/', $number))
return true;
else
return false;
}
(Thanks to Fred-ii- for the corrections)
Everybody is dancing around the fact that floating point numbers don't have a number of decimal places in their internal representation. i.e. in float 100 == 100.0 == 100.00 == 100.000 and are all represented by the same number, effectively 100 and is stored that way.
The number of decimal places in this example only has a context when the number is represented as a string. In which case any string function that counts the number of digits trailing the decimal point could be used to check.
number_format($price, $numberOfDecimalDigits) === $price;
or
strrpos($price, '.') === strlen($price) - 1 - $numberOfDecimalDigits;
Trivia: $price should not be called a "float variable". This is a string that happens to represent a float value. 100.00 as a float has zero decimal digits, and 100.00 === 100 as float :
$price = 100.00;
echo $price; // output: 100
$price2 = (float)100;
echo $price === $price2; // ouput: 1
In order for this to work, the number will need to be wrapped in quotes.
With the many scripts I've tested, using $price = 100.00; without quotes did not work, while $price = 100.10; did, so this is as best as it gets.
<?php
$number = '100.00';
echo $number.'<br>';
$count = explode('.',$number);
echo 'The number of digits after the decimal point is: ' . strlen($count[1]);
if(strlen($count[1]) == 2){
echo "<br>";
echo "There is 2 decimal points.";
}
else{
echo "<br>";
echo "There is not 2 decimal points.";
}
After you format the value, you can check with simply splitting the value as string into 2 parts, for example with explode ...
$ex=explode('.',$in,2); if (strlen($ex[1])==2)
{
// true
}
else
{
// false
}
But again, as i've commented already, if you really have floating input, this is just not a reliable way, as floating numbers are without set decimal places, even if they appears so because of the rounding at the float=>string conversion
What you can do, if you really have floating numbers and wish to have xxx.yy format numbers:
1) convert float to string using round($x,2), so it will round to 2 decimal places.
2) explode the number as i've described, and do the following:
while (strlen($ex[1]<2)) {$ex[1].='0';}
$number=implode('.',$ex);
I would use the following function for that:
function isFloatWith2Decimals($number) {
return (bool) preg_match('/^(?:[1-9]{1}\d*|0)\.\d{2}$/', $number);
}
This will also check if you have only one leading 0 so number like 010.23 won't be considered as valid whereas number like 0.23 will.
And if you don't care about leading 0 you could use simpler method:
function isFloatWith2Decimals($number) {
return (bool) preg_match('/^\d+\.\d{2}$/', $number);
}
Of course numbers need to be passed as string - if you pass 100.00 won't be considered as true, whereas '100.00' will

How do I truncate a decimal in PHP?

I know of the PHP function floor() but that doesn't work how I want it to in negative numbers.
This is how floor works
floor( 1234.567); // 1234
floor(-1234.567); // -1235
This is what I WANT
truncate( 1234.567); // 1234
truncate(-1234.567); // -1234
Is there a PHP function that will return -1234?
I know I could do this but I'm hoping for a single built-in function
$num = -1234.567;
echo $num >= 0 ? floor($num) : ceil($num);
Yes intval
intval(1234.567);
intval(-1234.567);
Truncate floats with specific precision:
echo bcdiv(2.56789, 1, 1); // 2.5
echo bcdiv(2.56789, 1, 3); // 2.567
echo bcdiv(-2.56789, 1, 1); // -2.5
echo bcdiv(-2.56789, 1, 3); // -2.567
This method solve the problem with round() function.
Also you can use typecasting (no need to use functions),
(int) 1234.567; // 1234
(int) -1234.567; // -1234
http://php.net/manual/en/language.types.type-juggling.php
You can see the difference between intval and (int) typecasting from here.
another hack is using prefix ~~ :
echo ~~1234.567; // 1234
echo ~~-1234.567; // 1234
it's simpler and faster
Tilde ~ is bitwise NOT operator in PHP and Javascript
Double tilde(~) is a quick way to cast variable as integer, where it is called 'two tildes' to indicate a form of double negation.
It removes everything after the decimal point because the bitwise operators implicitly convert their operands to signed 32-bit integers. This works whether the operands are (floating-point) numbers or strings, and the result is a number
reference:
https://en.wikipedia.org/wiki/Double_tilde
What does ~~ ("double tilde") do in Javascript?
you can use intval(number); but if your number bigger than 2147483648 (and your machine/os is x64) all bigs will be truncated to 2147483648. So you can use
if($number < 0 )
$res = round($number);
else
$res = floor($number);
echo $res;
You can shift the decimal to the desired place, intval, and shift back:
function truncate($number, $precision = 0) {
// warning: precision is limited by the size of the int type
$shift = pow(10, $precision);
return intval($number * $shift)/$shift;
}
Note the warning about size of int -- this is because $number is potentially being multiplied by a large number ($shift) which could make the resulting number too large to be stored as an integer type. Possibly converting to floating point might be better.
You could get fancy with a $base parameter, and sending that to intval(...).
Could (should) also get fancy with error/bounds checking.
An alternative approach would be to treat number as a string, find the decimal point and do a substring at the appropriate place after the decimal based on the desired precision. Relatively speaking, that won't be fast.

Printing big numbers in PHP

The number is 13911392101301011 and regardless of using sprintf or number_format i get the same strange result.
sprintf('%017.0f', "13911392101301011"); // Result is 13911392101301012
number_format(13911392101301011, 0, '', ''); // Result is 13911392101301012
sprintf('%017.0f', "13911392101301013"); // Result is 13911392101301012
number_format(13911392101301013, 0, '', ''); // Result is 13911392101301012
As you actually have the number as a string, use the %s modifier:
sprintf('%s', "13911392101301011"); // 13911392101301011
Note that PHP is using a signed integer internally. The size depends on your system.
32bit system:
2^(32-1) = 2147483648
64bit system:
2^(64-1) = 9223372036854775808
-1 because 1 bit is reserved for the signage flag.
Since you are dealing with large numbers here, you may want to keep them as strings and perform numerical operation on the string values using BCMath functions.
$val = "13911392101301011";
echo $val; // 13911392101301011
echo bcadd($val, '4'); // 13911392101301015
echo bcmul($val, '2'); // 27822784202602022
You can do easily this way :-
ini_set("precision",25); // change 25 to whatever number you want or need
$num = 13911392101301011;
print $num;
Documentation states that $number in number_format is float so there is explicit typecast. Equivalent would look like this:
sprintf('%017.0f', (float) "13911392101301011");
Float is precise to around 14 digits and your number has 17 digits.
Your number_format call is setting the . and , to blank
string number_format ( float $number , int $decimals = 0 , string $dec_point = '.' , string $thousands_sep = ',' )
try this:
number_format(13911392101301011, 0, '.', ',');

Thousands separator with money_format?

$numval = 12345.50;
Desired output:
12 345,50
The comma instead of a dot is not a problem but how can I get the thousands separator to be a white-space?
I noticed PHP money format with spaces but this is not a duplicate post. Using number_format is out of question as it rounds the input value. I can't allow the values passed through it to be rounded at all.
Is there a built-in way to do exactly what number_format() does, but without rounding the value or do I have to write my own function to do this?
If rounding is out of the question, so is float values. You must go back to integers if you don't want rounding since floating-point arithmetic is not exact. In that case you'll have to implement the formatting function yourself.
This is especially true if you are handling money. See for example Why not use Double or Float to represent currency?
This looks like the version of the function you want to use:
string number_format ( float $number , int $decimals = 0 , string $dec_point = '.' , string $thousands_sep = ',' )
So for example:
$newNumber = number_format($oldNumber, 2, ",", " ");
For more information check out http://php.net/manual/en/function.number-format.php
From this comment of the number_format() page (I modified the function to match the number_format defaults though).
To prevent rounding:
function fnumber_format($number, $decimals=0, $dec_point='.', $thousands_sep=',') {
if (($number * pow(10 , $decimals + 1) % 10 ) == 5) //if next not significant digit is 5
$number -= pow(10 , -($decimals+1));
return number_format($number, $decimals, $dec_point, $thousands_sep);
}

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