echo the before year and month using a function in php? - php

Question

i am a newbie of php, supposed my blog created on 2011 year 1 month.and the article stored time as this 1305357473. now i want to use a function, which can output the before year and moth as this.
2011 year 1 month
2011 year 2 month
2011 year 3 month
2011 year 4 month
2011 year 5 month
......
i want to make the function can output the current and the past year and month.
this is my function and output the result. but i don't know how to finish.
function outYearMonth($year,$month){
$year=date(Y);
$past_month=strtotime(date(1)) ;
$month=strtotime(date(m));
$jg_month=round($month - $past_month);
$month=array();
for($i==0;$i<=$jg_month;$i++){
$month[]= date(1)+1;
}
}

Answer 1

This code:
$months = 10; //count of months
$date = date_create( 'now' );
echo date_format( $date, 'Y M' );
for ( $i = 0; $i < $months; $i++ ) {
date_sub( $date , date_interval_create_from_date_string( '1 months' ) );
echo date_format( $date, 'Y M' );
}
Will output:
2011 May
2011 Apr
2011 Mar
2011 Feb
2011 Jan
2010 Dec
2010 Nov
2010 Oct
2010 Sep
2010 Aug
2010 Jul

Answer 2

echo date('Y m');
will give you this year and month
echo date('Y m',strtotime('last month',time()))
will give you last month
for looping through all the month just get the current month and make a loop
$currentMonth = (int) date('m',time());
$currentYear = date('Y',time());
for($i=0; $i <= $currentMonth; $i++) {
echo "$currentYear $i";
}
will echo all months
2011 1
2011 2
2011 3
2011 4
2011 5