PHP- get the last 6 months from the current date - php

I am trying to get the last six months from the current date in PHP. It's a simple problem, but my code is not giving the right result.
for ($j = 0; $j <= 5; $j++) {
echo date("F Y", strtotime(" -$j month"));
echo "<br>";
}
And the output is
March 2018
March 2018
January 2018
December 2017
December 2017
October 2017
I dont understand why March is coming twice.

Because strototime('-1 month') doesn't handle correctly the end of month.
You could use the first day of the current month:
$dt = strtotime(date('Y-m-01'));
for ($j = 0; $j <= 5; $j++) {
echo date("F Y", strtotime(" -$j month", $dt));
echo "<br>";
}
Outputs:
March 2018
February 2018
January 2018
December 2017
November 2017
October 2017

Related

Removing months in a year [duplicate]

This question already has answers here:
Get the last 12 months in PHP
(5 answers)
Closed 3 years ago.
I'm trying to use a loop to show the last 12 months, but March appears twice.
for ($i=0; $i < 12; $i++) {
$month = date("d/m/Y", strtotime("now -$i month"));
echo "$month<br>";
}
Output:
30/01/2020
30/12/2019
30/11/2019
30/10/2019
30/09/2019
30/08/2019
30/07/2019
30/06/2019
30/05/2019
30/04/2019
30/03/2019
02/03/2019
How can I solve this?
Use the first day of the month as the basis in your script.
"first day of this month -$i month"
Use DateTime and keep track of month/year combinations that you already had:
$dt = new DateTime();
$previous = [];
for ($i=0; $i < 12; $i++) {
$month = $dt->format("d/m/Y");
echo "$month<br>".PHP_EOL;
$previous[$dt->format('Y-m')] = true;
$dt->modify('-1 month');
while (array_key_exists($dt->format('Y-m'), $previous)) {
$dt->modify('-1 day');
}
}
If this encounters a previously encountered month-year combination, it starts substracting days until it reaches the previous month.
Will produce this output:
30/01/2020
30/12/2019
30/11/2019
30/10/2019
30/09/2019
30/08/2019
30/07/2019
30/06/2019
30/05/2019
30/04/2019
30/03/2019
28/02/2019
You probably want to use DatePeriod for this task and not date. It's much simpler and more sane.
$start = new DateTime;
$start->setDate($start->format('Y'), $start->format('n'), 1); // Normalize the day to 1
$start->sub(new DateInterval('P12M'));
$interval = new DateInterval('P1M');
$recurrences = 12;
foreach (new DatePeriod($start, $interval, $recurrences, true) as $date) {
echo $date->format('F, Y'), "\n"; // attempting to make it more clear to read here
}
Output:
February, 2019
March, 2019
April, 2019
May, 2019
June, 2019
July, 2019
August, 2019
September, 2019
October, 2019
November, 2019
December, 2019
January, 2020

PHP Date function skipping February. Does anybody know of a work around for this date bug?

I am displaying month titles 3 month into the future as well as getting the 1st and last day of each of those months.
for($i = 1; $i < 4; $i++) { // For each month for 3 months
$monthTitle = date('F Y', strtotime('+'.$i.' month'));
$begin_date = date('Y-m-01', strtotime('+'.$i.' month')); // First day of calendar month in future.
$end_date = date('Y-m-t', strtotime('+'.$i.' month')); // Last day of calendar months in future.
};
Nov. 29, 2015 output is:
December 2015
2015-12-01
2015-12-31
January 2016
2016-01-01
2016-01-31
February 2016
2016-02-01
2016-02-29
This was working great right up until yesterday, Nov. 29, 2015 but today Nov. 30, 2015 it skips February.
Nov. 30, 2015 output is:
December 2015
2015-12-01
2015-12-31
January 2016
2016-01-01
2016-01-31
March 2016
2016-03-01
2016-03-31
I'm guessing a bug but does anybody know of a work around?
Thanks to #devlin carnate for pointing me in the right direction.
for($i = 1; $i < 4; $i++) { # for each month
$tmp = date('Y-m-15'); // Get the middle of the month to avoid PHP date bug.
$begin_date = date('Y-m-01', strtotime($tmp . '+'.$i.' month')); // First day of calendar month in future.
$end_date = date('Y-m-t', strtotime($begin_date)); // Last day of calendar months in future.
$monthTitle = date('F Y', strtotime($begin_date));
};
This seems to work very well.
You can use DateInterval to add one month to the current date, so you can get the first and the last day of month.
<?php
$date = new DateTime('2015-12-01');
$i = 0;
while($i < 3){
printf("%s | first day: %s, | last day: %s <br>", $date->format('F Y'), $date->format('d'), $date->format('t'));
$date->add(new DateInterval('P1M'));
$i++;
}
Output:
December 2015 - first day: 01, | last day: 31
January 2016 - first day: 01, | last day: 31
February 2016 - first day: 01, | last day: 29
if last day of next month is needed then you can use this
$d = new DateTime( '2010-01-31' );
$d->modify( 'last day of next month' );
echo $d->format( 'Y-m-d' ), "\n";

How to loop through months that have been already passed

I have the following to loop through each month of the year. However, it seems to skip February.
$start = new DateTime('2015-01-01');
$start->modify('last day of this month');
$current = new DateTime('now');
$end = new DateTime('2018-01-01');
$interval = DateInterval::createFromDateString('1 month');
$period = new DatePeriod($start, $interval, $end);
$timestamps = array();
foreach ($period as $dt) {
$dt->modify('last day of this month');
echo 'C:' . $current->format('d F Y') . '<br>';
echo 'S:' . $start->format('d F Y') . '<br>';
echo 'D:' . $dt->format('d F Y') . '<br>';
echo '<br><br>';
}
However, the above outputs:
C:17 March 2015
S:31 January 2015
D:31 January 2015
C: 17 March 2015
S:31 January 2015
D:31 March 2015
C: 17 March 2015
S:31 January 2015
D:30 April 2015
Can anyone spot my mistake? I expected the second D to have a value of the 28 February 2015.
I just want a list of months that have already been passed.
Update
The problem highlighted by MLeFevre in the comments is that working with date intervals can be tricky. See Example #3 Beware when adding months http://php.net/manual/en/datetime.add.php.
Rather than use a DatePeriod, why not just use the modify method slightly differently like this:
$current = new DateTime('now');
$end = new DateTime('2018-01-01');
while($current < $end) {
$current->modify('last day of next month');
echo 'C:' . $current->format('d F Y') . '<br>';
}
In your question, you're firstly adding a month, then going to the end of that month. This doesn't work, as the length of each month varies.
Sample output:
C:30 April 2015
C:31 May 2015
C:30 June 2015
C:31 July 2015
C:31 August 2015
C:30 September 2015
C:31 October 2015
C:30 November 2015
C:31 December 2015
C:31 January 2016
C:29 February 2016
C:31 March 2016
// etc.
To loop from $start to $current, you could change the logic slightly like this:
$start = new DateTime('2015-01-31'); // start from end of month
$current = new DateTime('now');
do {
echo 'C:' . $start->format('d F Y') . '<br>';
} while($start->modify('last day of next month') < $current);
Output:
C:31 January 2015
C:28 February 2015
It happen because February has 28 days and your interval is 1 month (30 days). So it skips 30 days from 30 January to 2 March. Then it move to last day of March.
Change
$start->modify('last day of this month');
to
$start->modify('first day of this month');
Your first date is 31-Jan-2015. Since February has no 31st, it's going to March 3rd. Then you are telling it to go to the end of that month which is why you are getting the end of March after January and not February.

How to list the last N months with PHP DateTime

I want to populate a select input with the last 5 months (including the current month). So on 09/04/2014 the options should look something like this:
April 2014
March 2014
February 2014
January 2014
December 2013
My first solution with PHP DateTime seemed to work:
for ($i = 0; $i < 5; $i++) {
$date = new DateTime($i.' months ago');
echo $date->format('F Y'); //populate select input
}
But in fact it doesn't handle edge cases. For example, on 31/03/2014 it produces:
March 2014
March 2014
January 2014
December 2013
December 2013
What is the correct way to list the last 10 months with PHP DateTime?
$date = new DateTime("2014/03/31");
for ($i = 0; $i <= 9; $i++) {
$date->modify("-1 month");
echo $date->format('F Y'); //populate select input
}
You are getting same 2 months, because when you are subtracting 1 month from date, that has more days than previous month. Example: when you subtract 1 month from 31.3. you will get 3.3. (same month), and not 28.2. as you might expect...
My suggestion is to get first day of current month, and then do your logic:
$dt = new DateTime('first day of this month');
for ($i = 1; $i <= 10; $i++) {
echo $dt->format('F Y'), "\n";
$dt->modify('-1 month');
}
demo

echo the before year and month using a function in php?

i am a newbie of php, supposed my blog created on 2011 year 1 month.and the article stored time as this 1305357473. now i want to use a function, which can output the before year and moth as this.
2011 year 1 month
2011 year 2 month
2011 year 3 month
2011 year 4 month
2011 year 5 month
......
i want to make the function can output the current and the past year and month.
this is my function and output the result. but i don't know how to finish.
function outYearMonth($year,$month){
$year=date(Y);
$past_month=strtotime(date(1)) ;
$month=strtotime(date(m));
$jg_month=round($month - $past_month);
$month=array();
for($i==0;$i<=$jg_month;$i++){
$month[]= date(1)+1;
}
}
This code:
$months = 10; //count of months
$date = date_create( 'now' );
echo date_format( $date, 'Y M' );
for ( $i = 0; $i < $months; $i++ ) {
date_sub( $date , date_interval_create_from_date_string( '1 months' ) );
echo date_format( $date, 'Y M' );
}
Will output:
2011 May
2011 Apr
2011 Mar
2011 Feb
2011 Jan
2010 Dec
2010 Nov
2010 Oct
2010 Sep
2010 Aug
2010 Jul
echo date('Y m');
will give you this year and month
echo date('Y m',strtotime('last month',time()))
will give you last month
for looping through all the month just get the current month and make a loop
$currentMonth = (int) date('m',time());
$currentYear = date('Y',time());
for($i=0; $i <= $currentMonth; $i++) {
echo "$currentYear $i";
}
will echo all months
2011 1
2011 2
2011 3
2011 4
2011 5

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