Related
I'm trying to update a simple string to the database with PHP and AJAX.
Here is the code:
HTML
<form id="phoneNumberForm" class="form-inline" method="post" enctype="multipart/form-data">
<div class="form-group mx-sm-3 mb-2 align-content-center">
<label for="phoneNumber" class="sr-only">Phone</label>
<input type="text" class="form-control" name="phoneNumber" id="phoneNumber" placeholder="Phone">
</div>
<button type="submit" name="phoneNumber_submit" id="phoneNumber_submit" class="btn btn-primary mb-2">Save</button>
<div id="phoneSuccess"></div>
</form>
PHP
if (isset($_POST['phoneNumber_submit'])) {
$phoneNumber = $_POST['phoneNumber'];
$profileEditAdmin = $db->query('UPDATE users SET user_phone = ? WHERE user_name = ?', $phoneNumber, $_SESSION['user_name']);
}
AJAX
$('#phoneNumberForm').submit(function(e) {
e.preventDefault();
let phoneNumber = $('#phoneNumber').val();
let $body = $("body");
$(document).on({
ajaxStart: function() { $body.addClass("loading"); },
ajaxStop: function() { $body.removeClass("loading"); }
});
$.ajax({
type: "POST",
data: {
phoneNumber:phoneNumber,
},
success: function() {
$('#phoneSuccess').html('<p>Saved.</p>');
setTimeout(function() {
$('#phoneSuccess').fadeOut();
}, 2000)
}
});
});
When I remove preventDefault() I get the entry in the database, but page is reloaded.
My goal is to have an entry in the database and to avoid page refreshing.
Here your PHP looks for a variable called phoneNumber_submit:
if (isset($_POST['phoneNumber_submit'])) {
But here your AJAX sends only a variable called phoneNumber:
data: {
phoneNumber:phoneNumber,
}
Clearly these two names do not match, so the if statement will never be true and the query will never run. It works when you submit the form without AJAX because you have name="phoneNumber_submit" on your submit button, so this value is sent to the server.
So you can either:
1) hard-code this value into your data parameter:
data: {
"phoneNumber": phoneNumber,
"phoneNumber_submit": true
}
OR
2) just let jQuery do the work for you and use the serialize function to get all the values and names you've already defined in your HTML and send them directly to the server, without you needing to specify each one again:
data: $(this).serialize()
Note: this in the above code will be your <form> element since you're handling the form's "submit" event.
I have a classifieds website, and on the page where ads are showed, I am creating a "Send a tip to a friend" form...
So anybody who wants can send a tip of the ad to some friends email-adress.
I am guessing the form must be submitted to a php page right?
<form name="tip" method="post" action="tip.php">
Tip somebody:
<input
name="tip_email"
type="text"
size="30"
onfocus="tip_div(1);"
onblur="tip_div(2);"
/>
<input type="submit" value="Skicka Tips" />
<input type="hidden" name="ad_id" />
</form>
When submitting the form, the page gets reloaded... I don't want that...
Is there any way to make it not reload and still send the mail?
Preferrably without ajax or jquery...
I've found what I think is an easier way.
If you put an Iframe in the page, you can redirect the exit of the action there and make it show up.
You can do nothing, of course. In that case, you can set the iframe display to none.
<iframe name="votar" style="display:none;"></iframe>
<form action="tip.php" method="post" target="votar">
<input type="submit" value="Skicka Tips">
<input type="hidden" name="ad_id" value="2">
</form>
You'll need to submit an ajax request to send the email without reloading the page. Take a look at http://api.jquery.com/jQuery.ajax/
Your code should be something along the lines of:
$('#submit').click(function() {
$.ajax({
url: 'send_email.php',
type: 'POST',
data: {
email: 'email#example.com',
message: 'hello world!'
},
success: function(msg) {
alert('Email Sent');
}
});
});
The form will submit in the background to the send_email.php page which will need to handle the request and send the email.
You either use AJAX or you
create and append an iframe to the document
set the iframes name to 'foo'
set the forms target to 'foo'
submit
have the forms action render javascript with 'parent.notify(...)' to give feedback
optionally you can remove the iframe
Fastest and easiest way is to use an iframe.
Put a frame at the bottom of your page.
<iframe name="frame"></iframe>
And in your form do this.
<form target="frame">
</form>
and to make the frame invisible in your css.
iframe{
display: none;
}
SUBMITTING THE FORM WITHOUT RELOADING THE PAGE AND GET THE RESULT OF SUBMITTED DATA ON THE SAME PAGE.
Here's some of the code I found on the internet that solves this problem :
1.) IFRAME
When the form is submitted, The action will be executed and target the specific iframe to reload.
index.php
<iframe name="content" style="">
</iframe>
<form action="iframe_content.php" method="post" target="content">
<input type="text" name="Name" value="">
<input type="submit" name="Submit" value="Submit">
</form>
iframe_content.php
<?php
$Submit = isset($_POST['Submit']) ? $_POST['Submit'] : false;
$Name = isset($_POST['Name']) ? $_POST['Name'] : '';
if($Submit){
echo $Name;
}
?>
2.) AJAX
Index.php:
<form >
<input type="" name="name" id="name">
<input type="" name="descr" id="descr">
<input type="submit" name="" value="submit" onclick="return clickButton();">
</form>
<p id="msg"></p>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>
<script type="text/javascript">
function clickButton(){
var name=document.getElementById('name').value;
var descr=document.getElementById('descr').value;
$.ajax({
type:"post",
url:"server_action.php",
data:
{
'name' :name,
'descr' :descr
},
cache:false,
success: function (html)
{
alert('Data Send');
$('#msg').html(html);
}
});
return false;
}
</script>
server_action.php
<?php
$name = isset($_POST['name']) ? $_POST['name'] : '';
$descr = isset($_POST['descr']) ? $_POST['descr'] : '';
echo $name;
echo $descr;
?>
Tags: phpajaxjqueryserversidehtml
A further possibility is to make a direct javascript link to your function:
<form action="javascript:your_function();" method="post">
...
It's a must to take help of jquery-ajax in this case. Without ajax, there is currently no solution.
First, call a JavaScript function when the form is submitted. Just set onsubmit="func()". Even if the function is called, the default action of the submission would be performed. If it is performed there would be no way of stoping the page from refreshing or redirecting. So, next task is to prevent the default action. Insert the following line at the start of func().
event.preventDefault()
Now, there will be no redirecting or refreshing. So, you simply make an ajax call from func() and do whatever you want to do when call ends.
Example:
Form:
<form id="form-id" onsubmit="func()">
<input id="input-id" type="text">
</form>
Javascript:
function func(){
event.preventDefault();
var newValue = $('#input-field-id').val();
$.ajax({
type: 'POST',
url: '...',
data: {...},
datatype: 'JSON',
success: function(data){...},
error: function(){...},
});
}
this is exactly how it CAN work without jQuery and AJAX and it's working very well using a simple iFrame. I LOVE IT, works in Opera10, FF3 and IE6. Thanks to some of the above posters pointing me the right direction, that's the only reason I am posting here:
<select name="aAddToPage[65654]"
onchange="
if (bCanAddMore) {
addToPage(65654,this);
}
else {
alert('Could not add another, wait until previous is added.');
this.options[0].selected = true;
};
" />
<option value="">Add to page..</option>
[more options with values here]</select>
<script type="text/javascript">
function addToPage(iProduct, oSelect){
iPage = oSelect.options[oSelect.selectedIndex].value;
if (iPage != "") {
bCanAddMore = false;
window.hiddenFrame.document.formFrame.iProduct.value = iProduct;
window.hiddenFrame.document.formFrame.iAddToPage.value = iPage;
window.hiddenFrame.document.formFrame.submit();
}
}
var bCanAddMore = true;</script>
<iframe name="hiddenFrame" style="display:none;" src="frame.php?p=addProductToPage" onload="bCanAddMore = true;"></iframe>
the php code generating the page that is being called above:
if( $_GET['p'] == 'addProductToPage' ){ // hidden form processing
if(!empty($_POST['iAddToPage'])) {
//.. do something with it..
}
print('
<html>
<body>
<form name="formFrame" id="formFrameId" style="display:none;" method="POST" action="frame.php?p=addProductToPage" >
<input type="hidden" name="iProduct" value="" />
<input type="hidden" name="iAddToPage" value="" />
</form>
</body>
</html>
');
}
This should solve your problem.In this code after submit button click we call jquery ajax and we pass url to posttype POST/GET
data: data information you can select input fields or any other.
sucess: callback if everything is ok from server
function parameter text, html or json, response from server
in sucess you can write write warnings if data you got is in some kind of state and so on. or execute your code what to do next.
<form id='tip'>
Tip somebody: <input name="tip_email" id="tip_email" type="text" size="30" onfocus="tip_div(1);" onblur="tip_div(2);"/>
<input type="submit" id="submit" value="Skicka Tips"/>
<input type="hidden" id="ad_id" name="ad_id" />
</form>
<script>
$( "#tip" ).submit(function( e ) {
e.preventDefault();
$.ajax({
url: tip.php,
type:'POST',
data:
{
tip_email: $('#tip_email').val(),
ad_id: $('#ad_id').val()
},
success: function(msg)
{
alert('Email Sent');
}
});
});
</script>
You can try setting the target attribute of your form to a hidden iframe, so the page containing the form won't get reloaded.
I tried it with file uploads (which we know can't be done via AJAX), and it worked beautifully.
Have you tried using an iFrame? No ajax, and the original page will not load.
You can display the submit form as a separate page inside the iframe, and when it gets submitted the outer/container page will not reload. This solution will not make use of any kind of ajax.
function Foo(){
event.preventDefault();
$.ajax( {
url:"<?php echo base_url();?>Controllername/ctlr_function",
type:"POST",
data:'email='+$("#email").val(),
success:function(msg) {
alert('You are subscribed');
}
} );
}
I tried many times for a good solution and answer by #taufique helped me to arrive at this answer.
NB : Don't forget to put event.preventDefault(); at the beginning of the body of the function .
I did something similar to the jquery above, but I needed to reset my form data and graphic attachment canvases.
So here is what I came up with:
<script>
$(document).ready(function(){
$("#text_only_radio_button_id").click(function(){
$("#single_pic_div").hide();
$("#multi_pic_div").hide();
});
$("#pic_radio_button_id").click(function(){
$("#single_pic_div").show();
$("#multi_pic_div").hide();
});
$("#gallery_radio_button_id").click(function(){
$("#single_pic_div").hide();
$("#multi_pic_div").show();
});
$("#my_Submit_button_ID").click(function() {
$("#single_pic_div").hide();
$("#multi_pic_div").hide();
var url = "script_the_form_gets_posted_to.php";
$.ajax({
type: "POST",
url: url,
data: $("#html_form_id").serialize(),
success: function(){
document.getElementById("html_form_id").reset();
var canvas=document.getElementById("canvas");
var canvasA=document.getElementById("canvasA");
var canvasB=document.getElementById("canvasB");
var canvasC=document.getElementById("canvasC");
var canvasD=document.getElementById("canvasD");
var ctx=canvas.getContext("2d");
var ctxA=canvasA.getContext("2d");
var ctxB=canvasB.getContext("2d");
var ctxC=canvasC.getContext("2d");
var ctxD=canvasD.getContext("2d");
ctx.clearRect(0, 0,480,480);
ctxA.clearRect(0, 0,480,480);
ctxB.clearRect(0, 0,480,480);
ctxC.clearRect(0, 0,480,480);
ctxD.clearRect(0, 0,480,480);
} });
return false;
}); });
</script>
That works well for me, for your application of just an html form, we can simplify this jquery code like this:
<script>
$(document).ready(function(){
$("#my_Submit_button_ID").click(function() {
var url = "script_the_form_gets_posted_to.php";
$.ajax({
type: "POST",
url: url,
data: $("#html_form_id").serialize(),
success: function(){
document.getElementById("html_form_id").reset();
} });
return false;
}); });
</script>
I don't know JavaScript and I just started to learn PHP, so what helped for me from all those responses was:
Create inedx.php and insert:
<iframe name="email" style=""></iframe>
<form action="email.php" method="post" target="email">
<input type="email" name="email" >
<input type="submit" name="Submit" value="Submit">
</form>
Create email.php and insert this code to check if you are getting the data (you should see it on index.php in the iframe):
<?php
if (isset($_POST['Submit'])){
$email = $_POST['email'];
echo $email;
}
?>
If everything is ok, change the code on email.php to:
<?php
if (isset($_POST['Submit'])){
$to = $_POST['email'];
$subject = "Test email";
$message = "Test message";
$headers = "From: test#test.com \r\n";
$headers .= "Reply-To: test#test.com \r\n";
$headers .= "MIME-Version: 1.0\r\n";
$headers .= "Content-Type: text/html; charset=ISO-8859-1\r\n";
mail($to, $subject, $message, $headers);
}
?>
Hope this helps for all other rookies like me :)
Modern Answer without XHR or jQuery
It's 2022, we don't need to use old tools like XHR or jQuery when we have the Fetch API and the FormData API!
The first thing we need to do is prevent the default form submission behavior from occurring with event.preventDefault():
form.addEventListener("submit", function(event){
event.preventDefault();
// ...
});
Now we need to replace the submission behavior with our own AJAX request. The Fetch API makes it pretty simple to post form data - just create a new FormData object, populating it with the form's values, and use it as the body of a fetch request:
fetch(form.action, {
method: "post",
body: new URLSearchParams(new FormData(form))
});
Note that this submits an HTTP request using the multipart/form-data format. If you need to post the data using application/x-www-form-urlencoded, create a new URLSearchParams object from the FormData object and use that as the fetch's body.
fetch(form.action, {
method: "post",
body: new URLSearchParams(new FormData(form))
});
Here's a full code example:
let form = document.querySelector("form");
form.addEventListener("submit", function(event){
event.preventDefault();
fetch(form.action, {
method: "post",
body: //new FormData(form) // for multipart/form-data
new URLSearchParams(new FormData(form)) //for application/x-www-form-urlencoded
});
});
<form method="POST">
<input name="name" placeholder="Name" />
<input name="phone" type="tel" placeholder="Phone" />
<input name="email" type="email" placeholder="Email" />
<input name="submit" type="submit" />
</form>
The page will get reloaded if you don't want to use javascript
You will need to use JavaScript without resulting to an iframe (ugly approach).
You can do it in JavaScript; using jQuery will make it painless.
I suggest you check out AJAX and Posting.
if you're submitting to the same page where the form is you could write the form tags with out an action and it will submit, like this
<form method='post'> <!-- you can see there is no action here-->
Here is some jQuery for posting to a php page and getting html back:
$('form').submit(function() {
$.post('tip.php', function(html) {
// do what you need in your success callback
}
return false;
});
I have a classifieds website, and on the page where ads are showed, I am creating a "Send a tip to a friend" form...
So anybody who wants can send a tip of the ad to some friends email-adress.
I am guessing the form must be submitted to a php page right?
<form name="tip" method="post" action="tip.php">
Tip somebody:
<input
name="tip_email"
type="text"
size="30"
onfocus="tip_div(1);"
onblur="tip_div(2);"
/>
<input type="submit" value="Skicka Tips" />
<input type="hidden" name="ad_id" />
</form>
When submitting the form, the page gets reloaded... I don't want that...
Is there any way to make it not reload and still send the mail?
Preferrably without ajax or jquery...
I've found what I think is an easier way.
If you put an Iframe in the page, you can redirect the exit of the action there and make it show up.
You can do nothing, of course. In that case, you can set the iframe display to none.
<iframe name="votar" style="display:none;"></iframe>
<form action="tip.php" method="post" target="votar">
<input type="submit" value="Skicka Tips">
<input type="hidden" name="ad_id" value="2">
</form>
You'll need to submit an ajax request to send the email without reloading the page. Take a look at http://api.jquery.com/jQuery.ajax/
Your code should be something along the lines of:
$('#submit').click(function() {
$.ajax({
url: 'send_email.php',
type: 'POST',
data: {
email: 'email#example.com',
message: 'hello world!'
},
success: function(msg) {
alert('Email Sent');
}
});
});
The form will submit in the background to the send_email.php page which will need to handle the request and send the email.
You either use AJAX or you
create and append an iframe to the document
set the iframes name to 'foo'
set the forms target to 'foo'
submit
have the forms action render javascript with 'parent.notify(...)' to give feedback
optionally you can remove the iframe
Fastest and easiest way is to use an iframe.
Put a frame at the bottom of your page.
<iframe name="frame"></iframe>
And in your form do this.
<form target="frame">
</form>
and to make the frame invisible in your css.
iframe{
display: none;
}
SUBMITTING THE FORM WITHOUT RELOADING THE PAGE AND GET THE RESULT OF SUBMITTED DATA ON THE SAME PAGE.
Here's some of the code I found on the internet that solves this problem :
1.) IFRAME
When the form is submitted, The action will be executed and target the specific iframe to reload.
index.php
<iframe name="content" style="">
</iframe>
<form action="iframe_content.php" method="post" target="content">
<input type="text" name="Name" value="">
<input type="submit" name="Submit" value="Submit">
</form>
iframe_content.php
<?php
$Submit = isset($_POST['Submit']) ? $_POST['Submit'] : false;
$Name = isset($_POST['Name']) ? $_POST['Name'] : '';
if($Submit){
echo $Name;
}
?>
2.) AJAX
Index.php:
<form >
<input type="" name="name" id="name">
<input type="" name="descr" id="descr">
<input type="submit" name="" value="submit" onclick="return clickButton();">
</form>
<p id="msg"></p>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.4.1/jquery.min.js"></script>
<script type="text/javascript">
function clickButton(){
var name=document.getElementById('name').value;
var descr=document.getElementById('descr').value;
$.ajax({
type:"post",
url:"server_action.php",
data:
{
'name' :name,
'descr' :descr
},
cache:false,
success: function (html)
{
alert('Data Send');
$('#msg').html(html);
}
});
return false;
}
</script>
server_action.php
<?php
$name = isset($_POST['name']) ? $_POST['name'] : '';
$descr = isset($_POST['descr']) ? $_POST['descr'] : '';
echo $name;
echo $descr;
?>
Tags: phpajaxjqueryserversidehtml
A further possibility is to make a direct javascript link to your function:
<form action="javascript:your_function();" method="post">
...
It's a must to take help of jquery-ajax in this case. Without ajax, there is currently no solution.
First, call a JavaScript function when the form is submitted. Just set onsubmit="func()". Even if the function is called, the default action of the submission would be performed. If it is performed there would be no way of stoping the page from refreshing or redirecting. So, next task is to prevent the default action. Insert the following line at the start of func().
event.preventDefault()
Now, there will be no redirecting or refreshing. So, you simply make an ajax call from func() and do whatever you want to do when call ends.
Example:
Form:
<form id="form-id" onsubmit="func()">
<input id="input-id" type="text">
</form>
Javascript:
function func(){
event.preventDefault();
var newValue = $('#input-field-id').val();
$.ajax({
type: 'POST',
url: '...',
data: {...},
datatype: 'JSON',
success: function(data){...},
error: function(){...},
});
}
this is exactly how it CAN work without jQuery and AJAX and it's working very well using a simple iFrame. I LOVE IT, works in Opera10, FF3 and IE6. Thanks to some of the above posters pointing me the right direction, that's the only reason I am posting here:
<select name="aAddToPage[65654]"
onchange="
if (bCanAddMore) {
addToPage(65654,this);
}
else {
alert('Could not add another, wait until previous is added.');
this.options[0].selected = true;
};
" />
<option value="">Add to page..</option>
[more options with values here]</select>
<script type="text/javascript">
function addToPage(iProduct, oSelect){
iPage = oSelect.options[oSelect.selectedIndex].value;
if (iPage != "") {
bCanAddMore = false;
window.hiddenFrame.document.formFrame.iProduct.value = iProduct;
window.hiddenFrame.document.formFrame.iAddToPage.value = iPage;
window.hiddenFrame.document.formFrame.submit();
}
}
var bCanAddMore = true;</script>
<iframe name="hiddenFrame" style="display:none;" src="frame.php?p=addProductToPage" onload="bCanAddMore = true;"></iframe>
the php code generating the page that is being called above:
if( $_GET['p'] == 'addProductToPage' ){ // hidden form processing
if(!empty($_POST['iAddToPage'])) {
//.. do something with it..
}
print('
<html>
<body>
<form name="formFrame" id="formFrameId" style="display:none;" method="POST" action="frame.php?p=addProductToPage" >
<input type="hidden" name="iProduct" value="" />
<input type="hidden" name="iAddToPage" value="" />
</form>
</body>
</html>
');
}
This should solve your problem.In this code after submit button click we call jquery ajax and we pass url to posttype POST/GET
data: data information you can select input fields or any other.
sucess: callback if everything is ok from server
function parameter text, html or json, response from server
in sucess you can write write warnings if data you got is in some kind of state and so on. or execute your code what to do next.
<form id='tip'>
Tip somebody: <input name="tip_email" id="tip_email" type="text" size="30" onfocus="tip_div(1);" onblur="tip_div(2);"/>
<input type="submit" id="submit" value="Skicka Tips"/>
<input type="hidden" id="ad_id" name="ad_id" />
</form>
<script>
$( "#tip" ).submit(function( e ) {
e.preventDefault();
$.ajax({
url: tip.php,
type:'POST',
data:
{
tip_email: $('#tip_email').val(),
ad_id: $('#ad_id').val()
},
success: function(msg)
{
alert('Email Sent');
}
});
});
</script>
You can try setting the target attribute of your form to a hidden iframe, so the page containing the form won't get reloaded.
I tried it with file uploads (which we know can't be done via AJAX), and it worked beautifully.
Have you tried using an iFrame? No ajax, and the original page will not load.
You can display the submit form as a separate page inside the iframe, and when it gets submitted the outer/container page will not reload. This solution will not make use of any kind of ajax.
function Foo(){
event.preventDefault();
$.ajax( {
url:"<?php echo base_url();?>Controllername/ctlr_function",
type:"POST",
data:'email='+$("#email").val(),
success:function(msg) {
alert('You are subscribed');
}
} );
}
I tried many times for a good solution and answer by #taufique helped me to arrive at this answer.
NB : Don't forget to put event.preventDefault(); at the beginning of the body of the function .
I did something similar to the jquery above, but I needed to reset my form data and graphic attachment canvases.
So here is what I came up with:
<script>
$(document).ready(function(){
$("#text_only_radio_button_id").click(function(){
$("#single_pic_div").hide();
$("#multi_pic_div").hide();
});
$("#pic_radio_button_id").click(function(){
$("#single_pic_div").show();
$("#multi_pic_div").hide();
});
$("#gallery_radio_button_id").click(function(){
$("#single_pic_div").hide();
$("#multi_pic_div").show();
});
$("#my_Submit_button_ID").click(function() {
$("#single_pic_div").hide();
$("#multi_pic_div").hide();
var url = "script_the_form_gets_posted_to.php";
$.ajax({
type: "POST",
url: url,
data: $("#html_form_id").serialize(),
success: function(){
document.getElementById("html_form_id").reset();
var canvas=document.getElementById("canvas");
var canvasA=document.getElementById("canvasA");
var canvasB=document.getElementById("canvasB");
var canvasC=document.getElementById("canvasC");
var canvasD=document.getElementById("canvasD");
var ctx=canvas.getContext("2d");
var ctxA=canvasA.getContext("2d");
var ctxB=canvasB.getContext("2d");
var ctxC=canvasC.getContext("2d");
var ctxD=canvasD.getContext("2d");
ctx.clearRect(0, 0,480,480);
ctxA.clearRect(0, 0,480,480);
ctxB.clearRect(0, 0,480,480);
ctxC.clearRect(0, 0,480,480);
ctxD.clearRect(0, 0,480,480);
} });
return false;
}); });
</script>
That works well for me, for your application of just an html form, we can simplify this jquery code like this:
<script>
$(document).ready(function(){
$("#my_Submit_button_ID").click(function() {
var url = "script_the_form_gets_posted_to.php";
$.ajax({
type: "POST",
url: url,
data: $("#html_form_id").serialize(),
success: function(){
document.getElementById("html_form_id").reset();
} });
return false;
}); });
</script>
I don't know JavaScript and I just started to learn PHP, so what helped for me from all those responses was:
Create inedx.php and insert:
<iframe name="email" style=""></iframe>
<form action="email.php" method="post" target="email">
<input type="email" name="email" >
<input type="submit" name="Submit" value="Submit">
</form>
Create email.php and insert this code to check if you are getting the data (you should see it on index.php in the iframe):
<?php
if (isset($_POST['Submit'])){
$email = $_POST['email'];
echo $email;
}
?>
If everything is ok, change the code on email.php to:
<?php
if (isset($_POST['Submit'])){
$to = $_POST['email'];
$subject = "Test email";
$message = "Test message";
$headers = "From: test#test.com \r\n";
$headers .= "Reply-To: test#test.com \r\n";
$headers .= "MIME-Version: 1.0\r\n";
$headers .= "Content-Type: text/html; charset=ISO-8859-1\r\n";
mail($to, $subject, $message, $headers);
}
?>
Hope this helps for all other rookies like me :)
Modern Answer without XHR or jQuery
It's 2022, we don't need to use old tools like XHR or jQuery when we have the Fetch API and the FormData API!
The first thing we need to do is prevent the default form submission behavior from occurring with event.preventDefault():
form.addEventListener("submit", function(event){
event.preventDefault();
// ...
});
Now we need to replace the submission behavior with our own AJAX request. The Fetch API makes it pretty simple to post form data - just create a new FormData object, populating it with the form's values, and use it as the body of a fetch request:
fetch(form.action, {
method: "post",
body: new URLSearchParams(new FormData(form))
});
Note that this submits an HTTP request using the multipart/form-data format. If you need to post the data using application/x-www-form-urlencoded, create a new URLSearchParams object from the FormData object and use that as the fetch's body.
fetch(form.action, {
method: "post",
body: new URLSearchParams(new FormData(form))
});
Here's a full code example:
let form = document.querySelector("form");
form.addEventListener("submit", function(event){
event.preventDefault();
fetch(form.action, {
method: "post",
body: //new FormData(form) // for multipart/form-data
new URLSearchParams(new FormData(form)) //for application/x-www-form-urlencoded
});
});
<form method="POST">
<input name="name" placeholder="Name" />
<input name="phone" type="tel" placeholder="Phone" />
<input name="email" type="email" placeholder="Email" />
<input name="submit" type="submit" />
</form>
The page will get reloaded if you don't want to use javascript
You will need to use JavaScript without resulting to an iframe (ugly approach).
You can do it in JavaScript; using jQuery will make it painless.
I suggest you check out AJAX and Posting.
if you're submitting to the same page where the form is you could write the form tags with out an action and it will submit, like this
<form method='post'> <!-- you can see there is no action here-->
Here is some jQuery for posting to a php page and getting html back:
$('form').submit(function() {
$.post('tip.php', function(html) {
// do what you need in your success callback
}
return false;
});
I have a registration form and I want to display all of the registrants. I want to output whatever records are in the database and then once the form is submitted to register another display that record as well.
I can successfully register the records and display them using ajax however It does not load the last registered record until you reload/comeback to the page. I want the last record to just join its brethren right after the form submits. I appreciate anything you can suggest.
home.php
<form id="register-student" method="post" action="process_student_registration.php" class="basic-form not-toggled">
<h2>Enter Student Info to Register</h2>
<fieldset id="student-name-group" class="form-group">
<div class="split">
<fieldset id="student-firstname-group">
<label for="student-first-name">First Name:</label>
<input id="student-first-name" type="text" name="student_first_name">
</fieldset>
</div>
<div class="split">
<fieldset id="student-lastname-group">
<label for="student-last-name">Last Name:</label>
<input id="student-last-name" type="text" name="student_last_name">
</fieldset>
</div>
</fieldset>
<fieldset class="submit-button">
<div id="loading" class="hidethis"><img id="loading-image" src="../../images/ajax-loader.gif" alt="Loading..." /></div>
<button id="register-student-button" type="submit" class="btn btn-success" name="register-student-button">Register Student</button>
</fieldset>
</form>
<script>
$(document).ready(function() {
var students = $.ajax({ //create an ajax request to load_page.php
type: "GET",
url: "fetch_students.php",
dataType: "html", //expect html to be returned
success: function(response){
$("#registered-students").html(response);
//alert(response);
}
});
});
</script>
<div id="registered-students"></div><!--End # registered-students-->
fetch_students.php
<?php
//Fetch the Students
//First lets make sure the user is allowed
require_once('../auth/agency_session.php');
//App Functions
require_once('../../includes/functions/app_functions.php');
//Agents Home Page
require_once('../../db_config.php');
$db_connect = connectDB($mysqli);
$agency_id = $_SESSION['ID'];
//Here we display all the students the agent has registered
//First check the connection
if(!mysqli_connect_errno()){
if($stmt = $db_connect->prepare("SELECT student_id, student_first_name, student_last_name, student_email FROM students WHERE agency_id = ?")){
//Bind Parameters
$stmt->bind_param('i', $agency_id);
//Execute
$stmt->execute();
//Store Results
$stmt->store_result();
//Get the rows
$num_rows = $stmt->num_rows;
//Bind the results
$stmt->bind_result($student_id, $student_first_name, $student_last_name, $student_email);
if($stmt->num_rows < 1){
echo'<h3>No Students Registered</h3>';
}
else{
//Fetch the values
echo'<h3>Registered Students</h3>';
echo'<ul class="grid">';
while($stmt->fetch()){
echo '<li id="'.$student_id.'" class="col">'.$student_first_name.' '.$student_last_name.'<span>'.$student_email.'</span></li>';
}//End While
echo'</ul>';
}//End else
}//End if no prepare statment happens
}//End if No connection
?>
process_student_registration.php
jQuery(document).ready(function($){
// Get the form and place it into a variable
var form = $('#register-student');
//Creating an Event Listener for the submit buttom on the contact form
$(form).submit(function(event){
$('.form-group').removeClass('.has-error');//Remove the error class on the things that have the error class
$('.error-message').remove();//Remove the error messages completeley
//Serialize the Form Data (Converts the data the user has entered into a key/value string that can be sent with an AJAX request)
var formData = $(form).serialize();
//Submit the form using AJAX
$.ajax({
type: 'POST',
url: $(form).attr('action'),
data: formData,
dataType :'json',
encode:true
//.done refers to a successful completion of the form
})
.done(function(data){
//Log the data into the console so that we can be sure what is happening
console.log(data);
//If we do have errors create the
if(!data.successmessage){
if(data.errors){
$('.error').remove();
$('.error-message').remove();
$('#register-student').addClass('form-has-error'); // add the form-has-error-class
$('#register-student-button').after('<p class="error">Please check the errors above.</p>');
$(form).removeClass('success');
$('.submit-success').remove();
if(data.errors.student_first_name){
$('#student-firstname-group').addClass('has-error'); // add the error class to show red input
$('#student-firstname-group').append('<div class="error-message"><p>' + data.errors.student_first_name + '</p></div>'); // add the actual error message under our input
}
if(data.errors.student_last_name){
$('#student-lastname-group').addClass('has-error'); // add the error class to show red input
$('#student-lastname-group').append('<div class="error-message"><p>' + data.errors.student_last_name + '</p></div>'); // add the actual error message under our input
}
}
} else if(data.successmessage){
//Remove the errors stuff
$('.error').remove();
$('.error-message').remove();
$('#register-student').removeClass('form-has-error'); // add the form-has-error-class
$('#blocking').removeClass('hidethis').addClass('showthis');
$('#loading').removeClass('hidethis').addClass('showthis');
$('.submit-success').remove();
//Add the success stuff
$(form).addClass('success');
setTimeout(function(){
$('#blocking').removeClass('showthis').addClass('hidethis');
$('#loading').removeClass('showthis').addClass('hidethis');
$('#register-student').append('<div class="submit-success"><p>' + data.successmessage + '</p></div>');
$(form).find('input, :text').val('');
//Run the Get operation on the database to add newly added records to the list
}, 5000);
//Clear the form upon successful completion
}
//.fail referes to an unsuccessful completion of the form
})
.fail(function(data){
//If there is a failed submission lets log the errors
console.log(data);
});
//Stop the broweser from submitting the form
event.preventDefault();
});
});
I had a similar issue... you are processing from two different php file:
process_student_registration.php and fetch_students.php
I believe your problem might be solved if you do all the processing from one file:
You are only passing two pieces of data. Rather than collecting the data from a form you can collect the data through inputs and go straight to the jQuery.
Your Collection HTML would look like this: NOTICE the dashes replaced with underscores.
<h2>Enter Student Info to Register</h2>
<input type="hidden" id="processStudent" value="process_student_registration.php">
<fieldset id="student-name-group" class="form-group">
<div class="split">
<fieldset id="student_firstname_group">
<label for="student_first_name">First Name:</label>
<input id="student_first_name" type="text" name="student_first_name">
</fieldset>
</div>
<div class="split">
<fieldset id="student_lastname_group">
<label for="student_last_name">Last Name:</label>
<input id="student_last_name" type="text" name="student_last_name">
</fieldset>
</div>
</fieldset>
<fieldset class="submit_button">
<div id="loading" class="hidethis"><img id="loading_image" src="../../images/ajax_loader.gif" alt="Loading..." /></div>
<button id="register_student_button" type="submit" class="btn btn_success" name="register_student_button">Register Student</button>
</fieldset>
<div id="registered-students"></div>
Your jQuery...
<script>
$(document).ready(function() {
$( "#register-student-button" ).click(function(){
var url = $('#processStudent').val();
var student_first_name = $('#student_first_name').val();
var student_last_name = $('#student_last_name').val();
var postit = $.post( url, {student_first_name:student_first_name,student_last_name:student_last_name});
postit.done(function( data ) {
alert('Student has been processed');
$('#registered-students').html(data);
});
});
});
Your PHP...
<?php
$student_first_name = $_POST['student_first_name'];
$student_last_name = $_POST['student_last_name'];
// PROCESS REGISTRATION HERE AS YOU ARE
// FETCH STUDENTS HERE AS YOU ARE
?>
I have figured out a solution. Basically I run the script to display records fomr the database on once on page load. Then I took basically the same script again and run it once more upon successful completion of the form. This way we only scan the database for new records as we need to. Not sre if it the most elegant or efficient way but she work like a charm.
So in my process_student_registration.php I added this to the success message.
//Run the Get operation on the database to add newly added records to the list
$.ajax({ //create an ajax request to load_page.php
type: "GET",
url: "fetch_students.php",
dataType: "html", //expect html to be returned
success: function(response){
$("#registered-students").html(response);
//alert(response);
}
<?php
'<form method="post" action="postnotice.php");>
<p> <label for="idCode">ID Code (required): </label>
<input type="text" name="idCode" id="idCode"></p>
<p> <input type="submit" value="Post Notice"></p>
</form>'
?>
Alright, so that's part of my php form - very simple. For my second form (postnotice.php):
<?php
//Some other code containing the password..etc for the connection to the database.
$conn = #mysqli_connect($sql_host,$sql_user,$sql_pass,$sql_db);
if (!$conn) {
echo "<font color='red'>Database connection failure</font><br>";
}else{
//Code to verify my form data/add it to the database.
}
?>
I was wondering if you guys know of a simple way - I'm still quite new to php - that I could use to perhaps hide the form and replace it with a simple text "Attempting to connect to database" until the form hears back from the database and proceeds to the next page where I have other code to show the result of the query and verification of "idCode" validity. Or even database connection failure. I feel it wrong to leave a user sitting there unsure if his/her button click was successful while it tries to connect to the database, or waits for time out.
Thanks for any ideas in advance,
Luke.
Edit: To clarify what I'm after here was a php solution - without the use of ajax or javascript (I've seen methods using these already online, so I'm trying to look for additional routes)
what you need to do is give form a div and then simply submit the form through ajax and then hide the div and show the message after you get the data from server.
<div id = "form_div">
'<form method="post" id = "form" action="postnotice.php";>
<p> <label for="idCode">ID Code (required): </label>
<input type="text" name="idCode" id="idCode"></p>
<p> <input type="submit" value="Post Notice"></p>
</form>'
?>
</div>
<script src="http://code.jquery.com/jquery-1.9.1.js"></script>
<script>
$(function () {
$('form').on('submit', function (e) {
$.ajax({
type: 'post',
url: 'postnotice.php',
data: $('form').serialize(),
success: function (data) {
if(data == 'success'){
echo "success message";
//hide the div
$('#form_div').hide(); //or $('#form').hide();
}
}
});
e.preventDefault();
});
});
</script>
postnotice.php
$idCode = $_POST['idCode'];
// then do whatever you want to do, for example if you want to insert it into db
if(saveSuccessfulIntoDb){
echo 'success';
}
try using AJAX. this will allow you to wait for a response from the server and you can choose what you want to do based on the reponse you got.
http://www.w3schools.com/ajax/default.ASP
AJAX with jQuery:
https://api.jquery.com/jQuery.ajax/